tcxdvn... 2006 (27 - 12- 2006)
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Tcxdvn 389:2007Tcxdvn 389:2007
Tcxdvn tiu chun xy dng vit nam Tcxdvn 389:2007 Sn phm b tng ng lc trc - Yu cu k thut v nghim thuPrecast prestressed concrete products
- technical requirements and acceptanceH ni - 2007 Tcxdvn 389:2007 tiu chun xy dng vit nam
Tcxdvn 389:2007Sn phm b tng ng lc trc - Yu cu k thut v nghim thu Precast prestressed concrete products - technical requirements and acceptanceH ni - 2007Li ni u Tcxdvn 389:2007 do Hi cng nghip b tng Vit Nam (VCA) bin son.
V khoa hc cng ngh trnh B xy dng ban hnh theo quyt nh s 10/ Q - BXD ngy 06 / 3 / 2007Tiu chun xy dng vit nam tcxdvn 389:2007Bin son ln 1Sn phm b tng ng lc trc - Yu cu k thut v nghim thu Precast prestressed concrete products
technical requirements and acceptance1. Phm vi p dng Tiu chun ny quy nh yu cu k thut v quy trnh kim tra nghim thu cc sn phm bng b tng c sn ng lc cng trc dng cho lp ghp cc cng trnh dn dng v cng nghip.2. Ti liu Vin dn TCVN 2682:1999. Ximng Pooclng. Yu cu k thut. TCVN 6260:1997. Ximng Pooclng hn hp. Yu cu k thut. TCVN 4787:1989. Ximng. Phng php ly mu v chun b mu th. TCVN 4031:1985. Ximng. Phng php xc nh thi gian ng kt. TCVN 6016:1995. Ximng. Phng php xc nh bn. TCVN 7570:2006. Ct liu cho b tng v va. Yu cu k thut
TCXD 199:1997. Nh cao tng - K thut ch to b tng mc 400 ( 600 TCXDVN 324: 2004. Nc trn b tng v va. Yu cu k thut. TCXDVN 325:2004. Ph gia ho hc cho b tng
TCVN 3105 : 1993. Hn hp b tng nng v b tng nng. Ly mu ch to v bo dng mu th. TCXDVN 225 :2000. B tng nng - nh gi cht lng b tng Ch dn phng
php xc nh vn tc xung siu m. TCVN 3118:1993. B tng nng. Phng php xc nh cng nn. TCVN 1651:1985. Thp ct b tng cn nng.
TCVN 5709:1993. Thp Cacbon cn nng dng cho xy dng. Yu cu k thut.
TCVN 3101:1979. Dy thp Cacbon thp ko ngui dng lm ct thp b tng. TCVN 6284 - 1:1997. Thp ct b tng d ng lc - Phn I : Yu cu chung TCVN 6284 - 2:1997.Thp ct b tng d ng lc-Phn 2:Dy ko ngui (ISO 6934-2) TCVN 6284 - 3:1997. Thp ct b tng d ng lc - Phn 3 : Dy ti v ram
TCVN 6284 - 4:1997. Thp ct b tng d ng lc - Phn 4 : Dnh TCVN 4452:1987. Kt cu b tng v b tng ct thp lp ghp. Quy phm thi cng v nghim thu. TCXDVN 356 - 2005. Kt cu b tng v b tng ct thp - Tiu chun thit k TCXDVN 327 2004. Kt cu b tng v b tng ct thp yu cu bo v chng n
mn trong mi trng bin. TCXDVN 239:2006. B tng nng Ch dn nh gi cng b tng trn kt cu
cng trnh.
TCXDVN 274:2002. Cu kin b tng v b tng ct thp c sn - Phng php th
nghim gia ti nh gi bn, cng v kh nng chng nt.
BS 5896 - 1980. Thp si dng cho b tng ct thp ng lc trc
ASTM. A 416 - 90 a Grade 270. Tao cp dng cho b tng ct thp ng sut trc
DIN 50049 - 3.1 B. Kim tra vt liu neo
3. Cc loi sn phm Bao gm cc sn phm: Cc c c tit din vung, Ct, Dm, Tng, Sn, Bn thang, Dm mi v X g. S hnh dng v cu to cc sn phm th hin cc hnh 3.1 n 3.73.1. Cc (Cc c c tit din vung)
Hnh 3.1- S hnh dng v cu to Cc3.2. Cc Dm
3.2.1. Dm ch T n
Hnh 3.2.a- S hnh dng v cu to Dm ch T n3.2.2. Dm ch T i
Hnh 3.2.b -S hnh dng v cu to Dm ch T i3.2.3. Dm mng v dm tng lng
Hnh 3.2.c - S hnh dng v cu to Dm mng v Dm tng lng3.2.4. Dm ch I
Hnh 3.2.d - S hnh dng v cu to Dm ch I3.2.5. Dm hp
Hnh 3.2. e- S hnh dng v cu to Dm hp3.3. Ct
Hnh 3.3 - S hnh dng v cu to Ct3.4. Bn thang
Hnh 3.4 - S hnh dng v cu to Bn thang3.5. Tm tng3.5.1. Tm tng c sn
Hnh 3.5.a- S hnh dng v cu to tm Tng c sn
3.5.2. Tm tng cch m- nhit
Hnh 3.5.b- S hnh dng v cu to tm Tng cch m nhit3.6. X g ch T (hoc hnh thang)
Hnh 3.6 - S hnh dng v cu to X g ch T v X g hnh thang3.7. Tm sn 3.7.1. Tm sn rng
Hnh 3.7.1 - S hnh dng v cu to tm Sn rng3.7.2. Tm sn c lp xp
Hnh 3.7.2 - S hnh dng v cu to tm Sn c lp xp
3.7.3. Tm sn c
Hnh 3.7.3 - S hnh dng v cu to tm Sn c
4. Yu cu k thut - Ngoi cc yu cu trong tiu chun ny, trong thi cng v nghim thu cn phi tun theo cc tiu chun trong mc 2 v cc tiu chun hin hnh c lin quan.4.1. Yu cu i vi hn hp b tng
Vt liu s dng phi p ng c cc yu cu ca cc tiu chun Vit Nam hin hnh nu trong mc 2.4.1.1. Xi mng v hm lng xi mngXi mng dng cho b tng phi m bo cht lng theo cc tiu chun xi mng ghi trong mc 2. Lng xi mng ca b tng cp B30 (M400) tr ln tun theo TCXD 199:1997. 4.1.2. Ct liu cho b tng phi m bo yu cu k thut nu trong TCVN 7570:2006
4.1.3. Nc trn b tng phi tho mn yu cu ca TCXDVN 324:20064.1.4. Tng hm lng Ion Clo (Quy i ra hm lng mui Clorua) trong b tng do cc loi vt liu ca b tng dn vo khng vt qu 0,3( /1m3 b tng theo TCXDVN 327:2004.
4.1.5. Hn hp b tng c thit k c thnh phn ng nht v c st thch hp ng vi thit k.
4.2. Yu cu i vi ph gia dng cho hn hp b tng
Ph gia c s dng cho hn hp b tng phi tun th theo TCXDVN 325:2004 nu trong mc 2.4.3. Yu cu cng b tng B tng cn t c cp bn chu nn theo ph lc A - TCXDVN 356:2005. Cng b tng ct thp ng lc trc khng nh hn 80( cng thit k. Vic nh gi cht lng b tng phi da trn kt qu th nghim p mu c c mu cng lc khi b tng. C th s dng phng php th nghim khng ph hoi ghi trong mc 2 tham kho. 4.4. Yu cu i vi thp ct b tng ng lc trc
Ct thp ng lc trc phi t c cc ch tiu k thut theo cc TCVN hin hnh hoc theo tiu chun nc ngoi tng ng nu trong mc 2.4.5. Yu cu i vi neo thp Neo ct thp ng lc trc v cc ph kin ca neo phi m bo theo ng cc quy nh trong n thit k. Trc khi a vo s dng trong thi cng hoc i vo sn xut phi qua th nghim v phi t c cc yu cu k thut.
4.6. Yu cu khng ch ng sut cng ko - ng sut khng ch ca ct thp ng lc phi ph hp yu cu thit k. Nu cn phi ko vt th ng sut ko vt ln nht l 80( gii hn bn, vi thp si ko ngui l 75% gii hn bn. - Khi ko cng thp to ng lc th ly tr s dn di tin hnh kim tra. chch lch ca tr s dn di thc t so vi tnh ton cho php ( 6(.4.7. Yu cu v dung sai, kch thc ca sn phm Sai s cho php v kch thc hnh hc ca sn phm c quy nh nh sau:
4.7.1. i vi Cc c tit din vung ( Hnh 3.1)kch thc oSai s cho php (mm)
Chiu di (a)( 25
Chiu rng (b) ( 5
cong tnh t ng thng song song vi ng trc ca cu kin (j) ( 5
V tr thp ng lc trc (h) ( 3
vung gc mt phng u cc (g) ( 5
phng cc b b mt trn (w) ( 5
V tr ca mc cu: (r)
+ Song song vi chiu di (r1) + Vung gc vi chiu di (r2)( 50
( 20
4.7.2. i vi Dm ch T n ( Hnh 3.2.a)kch thc oSai s cho php (mm)
Chiu di (a) ( 20
Chiu rng (b)( 5
Chiu cao (c)( 5
Chiu rng thn dm (b1)( 5
dy cnh dm (e)( 5
vung gc mt phng u dm (g, g1) ( 10
vng (f)
+ S sai lch vng so vi thit k
+ Gi tr nh nht f = 0 10
cong tnh t ng thng song song vi ng trc ca cu kin (j) + di cu kin 1220 cm + di cu kin 1220 (1830 cm + di cu kin ln hn 1830 cm( 5( 8 ( 12
V tr thp ng lc trc (h) ( 3
V tr ca neo cp xin (i) ( 20
V tr ca l ch (k, k1) ( 20
Kch thc ca l ch (x) ( 10
V tr ca cc tm thp (m, m1) ( 20
V tr ca tm thp gi (n) ( 10
phng ca cc tm thp ch cnh dm (o)( 3
phng ca cc tm thp ch ti gi (p)( 3
V tr ca mc cu: (r) + Song song vi chiu di (r1) + Vung gc vi chiu di (r2) ( 50 ( 20
phng cc b ca cc mt phng (w)( Khng p dng cho b mt trn g gh lin kt vi lp b tng b hoc cc mt khng c nhn thy)( 5
4.7.3. i vi Dm ch T i ( Hnh 3.2.b)kch thc oSai s cho php (mm)
Chiu di (a) ( 20
Chiu rng (b)( 5
Chiu cao (c)( 5
rng thn dm (b1)( 3
dy cnh dm (e)( 5
Khong cch gia cc thn dm (t) ( 10
vung gc mt phng u dm (g, g1) ( 10
cong tnh t ng thng song song vi ng trc ca cu kin (j) + di cu kin 1220 cm
+ di cu kin 1220(1830 cm
+ di cu kin ln hn 1830 cm( 5( 8 ( 12
vng (f)
+ S sai lch vng so vi thit k
+ Gi tr nh nht f = 0 15
V tr thp ng lc trc (h)( 3
V tr neo cp xin (i) ( 20
V tr l ch (k, k1) ( 20
Kch thc l ch (x) ( 20
V tr ca tm thp (m) ( 20
V tr ca cc tm thp gi (n) ( 10
phng ca cc tm thp ch cnh dm (o)( 3
phng ca cc tm thp ch ti gi (p)( 3
V tr ca mc cu: (r)
+ Song song vi chiu di (r1) + Vung gc vi chiu di (r2) ( 50
( 20
phng cc b ca cc mt phng (w)( Khng p dng cho b mt trn g gh lin kt vi lp b tng b hoc cc mt khng c nhn thy)( 5
4.7.4. i vi Dm mng v Dm tng lng ( Hnh 3.2.c)kch thc oSai s cho php (mm)
Chiu di (a) ( 20
Chiu rng (b)( 5
Chiu cao (c)( 5
Chiu cao (ca vai dm) (c1)( 5
Chiu rng ca thn dm (b1)( 5
Chiu rng ca g dm (b2)( 5
cong tnh t ng thng song song vi ng trc ca cu kin (j) + di cu kin 1220 cm
+ di cu kin 1220(1830 cm
+ di cu kin ln hn 1830 cm( 5 ( 10 ( 15
vung gc mt phng u dm (g, g1) ( 10
vng (f) + S sai lch vng so vi thit k + Gi tr nh nht f = 0 20
V tr thp ng lc trc (h)( 3
V tr neo cc si cp xin (i) + Chiu di cu kin ( 915 cm
+ Chiu di cu kin > 915 cm ( 10 ( 20
V tr ca tm thp (m, m1) ( 20
V tr ca cc tm thp gi (n) ( 10
phng ca cc tm thp (o)( 3
phng ca cc tm thp gi (p)( 3
V tr ca mc cu: (r)
+ Song song vi chiu di (r1) + Vung gc vi chiu di (r2) ( 50
( 20
V tr ca thp ch (q) q1: Khong cch theo chiu dc
q2: Khong cch theo chiu thng ng trn mt dm ( 20 ( 10
phng cc b ca cc mt phng (w)( Khng p dng cho b mt trn g gh lin kt vi lp b tng b hoc cc mt khng c nhn thy)( 5
4.7.5. i vi Dm ch I ( Hnh 3.2.d)kch thc oSai s cho php (mm)
Chiu di (a) ( 25
Chiu rng (b)( 5
Chiu cao (c) ( 10
Chiu rng dm bn trn (b1)( 5
Chiu rng ca thn dm (b2)( 5
Chiu cao bu dm trn (ct)( 5
Chiu cao bu dm di (cd)( 5
cong tnh t ng thng song song vi ng trc ca cu kin (j) (10
vung gc mt phng u dm (g, g1) ( 20
vng (f)
+ S sai lch vng so vi thit k
+ Gi tr nh nht f = 0 25
V tr thp ng lc trc (h)( 3
V tr neo cc si cp xin (i) ( 20
V tr ca tm thp (m, m1) ( 20
V tr ca cc tm thp gi (n) ( 10
phng ca cc tm thp (o)( 3
phng ca cc tm thp gi (p)( 3
V tr ca mc cu: (r)
+ Song song vi chiu di (r1) + Vung gc vi chiu di (r2) ( 50
( 20
V tr ca thp ch (q) q1: Khong cch dc
q2: Chiu cao ca thp ch (phn nh khi b tng) ( 20 ( 10
phng cc b (w)( Khng p dng cho b mt vn sn g gh nhn lp b tng b hoc cc b mt khng c nhn thy)( 5
4.7.6. i vi Dm hp ( Hnh 3.2.e)kch thc oSai s cho php (mm)
Chiu di (a) ( 20
Chiu rng (b)( 5
Chiu cao (c)( 5
Chiu dy (bn trn) (d1) ( 10
Chiu dy (bn di) (d2) ( 10
Chiu dy ca thnh dm (d3)( 5
cong tnh t ng thng song song vi ng trc ca cu kin (j) + di cu kin 1220 cm
+ di cu kin 1220(1830 cm
+ di cu kin ln hn 1830 cm ( 10 ( 15 ( 20
vung gc mt phng u dm (g, g1) ( 10
vng (f)
+ S sai lch vng so vi thit k
+ Gi tr nh nht f = 0 15
V tr thp ng lc trc (h)( 3
V tr neo cc si cp xin (i) ( 20
V tr ca cc tm thp (m) ( 10
phng ca cc tm thp (o)( 3
V tr ca thp ch (q)
q1: Khong cch theo chiu dc
q2: Khong cch theo chiu thng ng trn mt dm ( 20
( 10
V tr ca mc cu: (r) ( 50
phng cc b (w)( Khng p dng cho b mt trn ca dm g gh nhn lp b tng b hoc cc b mt khng c nhn thy)( 5
4.7.7. i vi Ct ( Hnh 3.3)kch thc oSai s cho php (mm)
Chiu di (a) ( 10
Cc kch thc mt ct ngang (b, b1)( 5
vung gc mt phng u ct (g, g1)( 5
cong tnh t ng thng song song vi ng trc ca cu kin (j) ( 12
V tr ca thp ng lc trc (h)( 3
V tr ca cc tm thp (m, m1)( 5
phng ca cc tm thp (o)( 3
V tr ca mc cu: (r)
+ Song song vi chiu di (r1) + Vung gc vi chiu di (r2) ( 50
( 20
Kch thc v v tr cc vai (v1, v2, v3)( 5
vung gc ca vai (v4)( 5
phng cc b ca cc b mt bt k (w)( Khng p dng cho b mt khng nhn thy)( 5
4.7.8. i vi Bn thang ( Hnh 3.4)kch thc oSai s cho php (mm)
Chiu di theo phng ngang (a) ( 10
Chiu rng (b)( 5
Chiu cao (c) ( 10
dy (d, d1)( 5
Chiu cao bc thang (c1)( 5
Chiu rng bc thang (b1)( 5
vung gc ca mt phng u bn thang (g) ( 10
V tr thp ng lc trc (h)( 3
V tr thp ch (q, q1) ( 10
V tr ca mc cu: (r)
+ Song song vi chiu di (r1) + Vung gc vi chiu di (r2) ( 50
( 20
4.7.9. i vi tm Tng c sn ( Hnh 3.5.a)kch thc oSai s cho php (mm)
Chiu di (a) ( 10
Chiu rng (b)( 5
Chiu cao (c)( 5
Chiu rng ca sn (b1)( 3
Chiu dy ca bn tng (d)( 5
Khong cch gia cc sn (t) ( 10
vng (f)
+ S sai lch vng so vi thit k
+ Gi tr nh nht f = 0 10
vung gc mt phng u tm bn (g, g1)( 5
cong tnh t ng thng song song vi ng trc ca cu kin (j) + di cu kin 1220 cm
+ di cu kin ( 1220 cm ( 10 ( 15
V tr ca thp ng lc trc (h)( 3
V tr ca l ch (k, k1) ( 20
Kch thc ca l ch (x) ( 10
V tr nhng tm thp (m) ( 10
phng ca nhng tm thp (o)( 3
V tr ca cc mc cu (r) + Song song vi chiu di (r1) + Vung gc vi chiu di (r2) ( 50 ( 20
V tr cc vai (v1, v2)( 5
vung gc cc vai (v3)( 3
phng cc b ca bt k mt phng no ( Khng p dng cho nhng mt phng khng nhn thy c) (w)( 5
4.7.10. i vi tm Tng cch nhit - m ( Hnh 3.5.b)kch thc oSai s cho php (mm)
Chiu di (a) ( 10
Chiu rng (b)( 5
Chiu cao (c)( 5
B dy 2 lp b tng ngoi (d)( 5
vung gc mt phng u tm tng (g) ( 10
vng (f)
+ S sai lch vng so vi thit k
+ Gi tr nh nht f = 0 10
cong tnh t ng thng song song vi ng trc ca cu kin (j) ( 10
V tr ca thp ng lc trc (h)( 3
V tr ca l ch (k, k1) ( 20
Kch thc ca l ch (x) ( 10
V tr nhng tm thp (m) ( 10
phng ca nhng tm thp (o)( 3
V tr ca mc cu: (r)
+ Song song vi chiu di (r1) + Vung gc vi chiu di (r2) ( 50
( 20
V tr cc vai (v1, v2)( 5
vung gc cc vai (v3)( 3
phng cc b ca bt k mt phng no ( Khng p dng cho nhng mt phng khng nhn thy c) (w)( 5
4.7.11. i vi X g ch T v X g hnh thang ( Hnh 3.6)kch thc oSai s cho php (mm)
Chiu di (a) ( 20
Chiu rng (b)( 5
Chiu cao (c)( 5
dy cnh x g (d)( 5
rng thn x g (b1)( 3
cong tnh t ng thng song song vi ng trc ca cu kin (j) + di cu kin ti 1220 cm + di cu kin ti 1220(1830 cm + di cu kin ti ln hn 1830 cm ( 15 ( 20 ( 25
vung gc mt phng u cu kin (g) ( 10
vng (f)
+ S sai lch vng so vi thit k
+ Gi tr nh nht f = 0 15
V tr ca thp ng lc trc (h)( 3
V tr nhng tm thp (m, m1) ( 15
V tr ca nhng tm thp gi (n) ( 10
phng ca nhng tm thp (o)( 5
phng ca nhng tm thp gi (p)( 3
V tr ca mc cu: (r)
+ Song song vi chiu di (r1) + Vung gc vi chiu di (r2) ( 50
( 20
phng cc b ca bt k mt phng no ( Khng p dng cho nhng mt phng khng nhn thy c) (w)( 5
4.7.12. i vi tm Sn rng, sn c lp xp ( Hnh 3.7.1, hnh 3.7.2.)kch thc oSai s cho php (mm)
Chiu di (a)+15, -10
Chiu rng (b)( 5
Chiu cao (c)( 5
Chiu cao g (c1)( 5
V tr l rng (c2) ( 10
dy ca gn tm sn (d) ( 5
Chiu dy lp b tng bn trn v bn di (d1, d2)( 5
dy ca gn tm sn theo phng dc (d3) ( 10
V tr ca l ch (k, k1) ( 20
Kch thc ca l ch (x) ( 10
vung gc mt phng u tm (g) ( 10
cong tnh t ng thng song song vi ng trc ca cu kin (j) ( 10
V tr tim ca thp ng lc trc (h)( 3
V tr ca cc tm thp (m, m1) ( 10
phng ca nhng tm thp ch (o)( 5
vng (f)
+ S sai lch vng so vi thit k
+ Gi tr nh nht f = 0 15
nghing ca gn ngoi tm sn (s)( 5
V tr thp ch (q)
+ Theo phng ng (q1)
+ Theo phng ngang (q2)
+ Chiu di thp ch (q3) ( 10 ( 10 ( 20
V tr ca mc cu: (r)
+ Song song vi chiu di (r1) + Vung gc vi chiu di (r2) ( 50
( 20
phng cc b ( Khng p dng cho b mt g gh nhn lp b tng b hoc cc b mt khng c nhn thy) (w)( 5
4.7.13. i vi tm Sn c ( Hnh 3.7.3)i lng oSai s cho php (mm)
Chiu di (a)+15, -10
Chiu rng (b)( 5
Chiu cao (c)( 5
Chiu cao g (c1)( 5
vung gc u tm (g) ( 10
cong tnh t ng thng song song vi ng trc ca cu kin (j) ( 10
vng (f)
+ S sai lch vng so vi thit k
+ Gi tr nh nht f = 0 10
V tr tim ca thp ng lc trc (h)( 3
V tr ca mc cu: (r)
+ Song song vi chiu di (r1) + Vung gc vi chiu di (r2) ( 50
( 20
V tr ca l ch (k, k1) ( 20
Kch thc l ch (x) ( 10
V tr thp ch (q, q1) ( 10
phng cc b ( Khng p dng cho b mt g gh nhn lp b tng b hoc cc b mt khng c nhn thy) (w)( 5
4.8. Yu cu v ngoi quan v khuyt tt ca sn phm 4.8.1. phng u ca b mt - B mt bn ngoi ca sn phm phi m bo phng, u n, khng c cc im g ln hoc lm xung qu 5 mm, mu sc ng u. Tr cc ct thp ch t sn, khng c l ct thp ra ngoi mt b tng. Khng c h hng mt ngoi ca b tng nh r, nt v cc cnh gc vt qu mc cho php theo quy nh. i vi cc ch c du vt chng t qua sa cha (qut nc xi mng, trt va, p b tng) khi kim tra phi c bin bn v c vn bn sa cha ca ngi c thm quyn.
- i vi cc b mt c lm nhm phi to nhm ng vi yu cu quy nh.4.8.2. Vt nt b mt trn Vt nt xut hin b mt trn do qu trnh v bo dng b tng phi khng gy tc ng xu n kh nng lm vic ca kt cu. Vt nt ny cn c xoa kn bng h xi mng. Nu cc vt nt xut hin ni khc trn cu kin vi b rng qu 0,1 mm (s khp li hon ton khi c s gia lc ca lc ng sut trc) th phi tm ra v loi b nguyn nhn.4.8.3. Vt st
Cc vt st m nh (quy ra khng qu 50 cm2 ) c th gy ra do trong qu trnh tho d khun hoc vn chuyn, khng gy nh hng xu n kt cu th c hon thin bng va khng co mc tng ng vi mc b tng sn phm.
4.8.4. vng vng thc t s c o v so snh vi gi tr vng thit k vi dung sai ca cc loi cu kin trong mc 4.7. vng s c o v ghi li thi gian thch hp ngay sau khi tin hnh truyn ng lc trc nhng khng qu 72 gi sau khi truyn ng lc trc.4.9. Yu cu v chi tit lin kt - Cc cu kin trong qu trnh lp t c lin kt vi nhau thnh cc mi lin kt bn vng.
- Cc chi tit ch nh: Thp ch, bn thp ch, l ch... c t trong cc cu kin theo ng v tr yu cu k thut ca thit k.5. Cng tc nghim thu- Cc sn phm c nh gi v nghim thu theo cc yu cu nu trong mc 4 - Vic kim tra cc sn phm c thc hin theo l. Mt l sn phm bao gm cc sn phm c cng kiu loi, sn xut cng thi gian, cng vt liu v cng ngh sn xut v khng qu 100 sn phm. Nu sn phm l n chic th kim tra theo n chic.- Cc sn phm trc khi xut xng phi c y h s chng ch cht lng ca ni sn xut ng vi tng l sn phm.
5.1. Kim tra ngoi quan, khuyt tt, nhn mc
Quan st bng mt thng kim tra mu sc, v pht hin cc sai st trn b mt, hnh dng sn phm. Ch tiu ny p dng kim tra cho tt c cc sn phm trong l. Khi pht hin sn phm c khuyt tt th tin hnh kim tra nh sau:
5.1.1. Dng c v thit b th
- Thc thp cun o di c chnh xc n 1mm
- Thc thp l di 300 ( 500 mm chnh xc n 1mm
- Thc kp chnh xc n 0,1 mm
5.1.2. Tin hnh th
- o chiu su vt lm: t thc trn b mt sn phm ri cm thanh trt ca thc kp n y vt lm, o khong cch t y vt lm n mp di ca thc.
- Cc vt st mp, gc sn phm: Dng thc l o
5.1.3. nh gi kt qu
Nu cc sn phm kim tra t c cc ch tiu theo mc 4.8.1 v 4.8.3 th sn phm t yu cu
5.2. Kim tra kch thc sn phm
5.2.1. Dng c v thit b th
- Thc l, thc thp cun c chnh xc n 1mm
- Thc kp c chnh xc n 1mm
- Eke, dy o khng dn, qu di
- c
5.2.2. Tin hnh th
Mi l sn phm ly ra 3 sn phm i din kim tra
- o chiu di: Dng thc thp cun o 2 u di nht ca sn phm
- o chiu rng: Dng thc thp cun o chiu rng nht ca sn phm
- o chiu cao: Dng thc thp cun o chiu cao nht ca sn phm
- o vung gc: Dng Eke o vung gc u, mt trn v mt y ca sn phm.- o khong cch cc tim thp: Dng thc l o t mp thanh thp ny n mp thanh thp k bn.
- Lp b tng bo v: Dng thc l v mt ke o t mt ke n mp di ca thanh thp.
- o cong: Dng dy ko khng dn c nh 2 u v dng thc o khong cch h ln nht hoc d ln nht t dy n mp ngoi sn phm.- o khong h, tim bn thp ch, mc cu: Dng thc thp cun o t u sn phm n khong h, tim bn thp ch theo hai phng vung gc. - o vung gc thng ng mt trn v mt di, dng dy di di thng ng u mp trn, t ke hoc thc chiu vung gc o.
- o mt phng cc tm thp: t thc thp trn b mt sn phm v dng thc l o khong h ln nht gia b mt sn phm v b mt tm thp.
- o vng: t sn phm trn sn phng c gia cng trc, dng thc l o khong h ln nht t sn n mp di sn phm ti im gia.
- o chiu dy cc lp b tng bo v tm xp: Cc tm xp to rng c nh hnh sn v c kim tra trc khi a vo s dng. Dng c c lp b tng b mt, trn mt xp din tch t 10 ( 15 cm2 kim tra dy lp b tng v kim tra v tr ca xp theo phng ng. Dng thc v ke o chiu cao lp b tng mt xp. Lp b tng chu lc pha di (d2) l kt qu ca hiu s chiu cao tm (c) v chiu cao xp cng vi chiu dy lp b tng trn mt lp xp (d1) d2 = [ c - (d1 + chiu cao xp) ] ( xem hnh 3.7.2). Sau dng va chy khng co hon thin li vt c.
5.2.3. nh gi kt qu
Nu c 3 sn phm t yu cu, th l sn phm t cht lng quy nh, cn nu trong 3 sn phm c mt sn phm khng t, th trong l li chn tip 3 sn phm khc kim tra. Nu li c mt sn phm khng t, th i vi l sn phm ny phi nghim thu tng sn phm.
5.3. Kim tra cng b tng
B tng phi c ly mu, bo dng v xc nh cng theo TCVN 3105 : 1993, TCVN 3118 : 1993. Trn mi mt l phi ly t nht 09 vin mu chun xc nh cng ct thp, cng 28 ngy v mu lu. Cng c th s dng phng php khng ph hoi xc nh cng b tng trn sn phm theo TCXDVN 239:2006.5.4. Th kh nng chu ti
Nu theo yu cu cn nh gi bn, cng v kh nng chng nt ca sn phm th tin hnh th nghim gia ti tnh theo TCXDVN 274 : 2002.6. Ghi nhn, bo qun v vn chuyn
6.1. Ni dung nhn mc Mi cu kin c ghi nhn mc r rng vi ni dung sau y:
- Tn cng trnh - Tn sn phm
- Ngy b tng - Du cht lng t yu cu6.2. Vt liu dng ghi nhn mc Vt liu ghi l sn, mc in khng b ho tan trong nc v khng phai mu6.3. Yu cu v vn chuyn v bo qun - Cc cu kin ch c bc xp vn chuyn khi cng b tng t ti thiu 70( cng thit k.
- Cc cu kin phi c xp d bng cn cu vi mc dy cp mm hoc thit b kp thch hp.
- Cc cu kin sau khi kim tra c xp thnh tng l cng chng loi, gia cc lp sn phm t chng ln nhau phi c k bng cc thanh g thch hp.
- Khi vn chuyn, cc cu kin phi c lin kt cht ch vi phng tin vn chuyn trnh x y, va p gy h hng. - Khi xp kho phi k xp cc sn phm tht n nh v cc n k phi thng hng t trn xung di. Khng xp mt chng cao qu 4 tng i vi dm, tm tng, ct, ring i vi tm sn khng xp qu 8 tng. Khi k xp phi theo th t thi gian sn xut d bo qun v s dng. Nu xp kho qu lu cn c bin php chng g cho cc mc cu v cc chi tit thp ch. -
Mc lcTrang
1Phm vi p dng4
2Ti liu Vin dn4
3Cc loi sn phm5
3.1Cc (Cc c c tit din vung)5
3.2Cc Dm5
3.3Ct8
3.4Bn thang8
3.5Tm tng9
3.6X g ch T (hoc hnh thang)10
3.7Tm sn 10
4Yu cu k thut12
4.1Yu cu i vi hn hp b tng12
4.1.1Xi mng v hm lng xi mng12
4.1.2Ct liu cho b tng12
4.1.3Nc cho b tng12
4.1.4Tng hm lng ion Clo 12
4.1.5Hn hp b tng12
4.2Yu cu i vi ph gia dng cho hn hp b tng12
4.3Yu cu v cng b tng12
4.4Yu cu i vi thp ct b tng ng lc trc12
4.5Yu cu v neo thp12
4.6Yu cu khng ch ng sut cng ko12
4.7Yu cu v dung sai, kch thc sn phm13
4.8Yu cu v ngoi quan v khuyt tt ca sn phm20
4.9Yu cu v chi tit lin kt20
5Cng tc nghim thu21
5.1Kim tra ngoi quan, khuyt tt, nhn mc21
5.2Kim tra kch thc sn phm21
5.3Kim tra cng b tng22
5.4Th kh nng chu ti22
6Ghi nhn, bo qun v vn chuyn22
4 3