tekton bekesting 2
DESCRIPTION
Teknologi beton tentang bekestingTRANSCRIPT
![Page 1: Tekton Bekesting 2](https://reader036.vdocuments.pub/reader036/viewer/2022071804/563db8df550346aa9a97bc0e/html5/thumbnails/1.jpg)
Diket : Mutu Kayu = F = 1000000Lendutan Ijin = L/300
Tinggi Lebar Panjang Balok A = Balok B = 8 16 400Bangunan Beban Lantai = 250 Kg/cm2
t multiplex = 20 mm = 0,02 m b = 1 m
(Statis Momen) = W = S = 0,00006666667 m3Beban yang dipikul = b = 100 1 m1. Beban Lantai = 250 Kg/m22. Berat Sendiri = 0,02 m x 400 Kg/m3
= 8 Kg/m23. Beban Pelaksanaan = 100 Kg/m24. Berat Total = qu = Kombinasi = 358 Kg/m2
Mu = 1/8 x qu x L^2 M = S x F
M>Mu M = S x F
S x F > 1/8 x qu x L^2 = 66,7
L = ( S x F x 8 / qu) ^ 0,5L = 1,2206 m
L Mu M0,2 1,79
0,252,79687
5 0,3 4,0275
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0,355,48187
5 0,4 7,16
0,459,06187
5 0,5 11,1875
0,5513,5368
8 0,6 16,11
0,6518,9068
8 0,7 21,9275
0,7525,1718
8 0,8 28,64
0,8532,3318
8 0,9 36,2475
0,9540,3868
8 1 44,75
1,0549,3368
8 1,1 54,1475
1,1559,1818
8 1,2 64,44
1,2569,9218
8 1,3 75,6275
1,3581,5568
8 1,4 87,71
1,4594,0868
8
1,5100,687
5
1,55107,511
9 1,6 114,56
1,65121,831
9
1,7129,327
5
1,75137,046
9