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    I.PERHITUNGAN PEMETAAN (THEODOLITH)

    1. Perhitungan Patok Utama

    Rumus :

    P0= 2711628 022 50=27059 38

    P1 = 16754 0 0 0 0=16754 0

    P2 = 157 43 4000 0=15743 40

    P3=32322 400 0 0=323 22 40

    P4= 225 54 500 0 0=225 54 50

    P5=185 34 500 0 0=185 34 50

    P6=189 1 100 0 0=189 1 10

    P7=279 25 400 0 0=279 25 40

    Jumlah=P0 + P1 + P2 + P3 + P4 + P5 + P6 + P7

    =2705938 + 167540 + 1574340 + 3232240 + 2255450

    +1853450+189110 + 2792540

    =1799 56 28

    . !orek"i #u$ut

    % %

    Jumlah Koreks =1800 0 0 ! 1799 56 28

    =0 3 32

    &. Menghitung !orek"i Per'atok

    Sudut Datar = Sudut Muka Sudut

    18000!" # 8 $ % & '!"n %& '

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    Rumus "mum :

    P0 = 270059

    '38

    }} over {{1799} ^ {0} {56} ^ {'} {28} ^ { # 0 3 32$ = 0 0% 31&92%

    P1 = 1670

    54

    '

    0} over {{1799} ^ {0} {56} ^ {'} {28} ^ { # 0 3 32 $ = 0 0% 19&78%

    P2 =

    }}

    1799056

    '28

    157043

    '40

    ''

    # 0 3% 32% = 0 0% 18&58%

    P3 =

    }}

    1799056

    '28

    323022

    '40

    ' '

    # 0 3% 32 = 0 0% 38&09%

    P4 =

    }}

    1799056'28

    225054

    '50

    ' '

    # 0 3% 32% = 0 0% 26&61%

    P5 = 185034

    '50

    }} over {{1799} ^ {0} {56} ^ {'} {28} ^ { # 0 3 32$ = 0 0% 21&86%

    P6 = 18901

    '10} over {{1799} ^ {0} {56} ^ {'} {28} ^ { # 0 3 32 $ = 0

    1% 22&26%

    P7 =

    }}

    1799056

    '28

    279025

    '40

    ''

    # 0 3% 32% = 0 0% 32&91%

    Koreks Per'a(ok=P0 + P1 + P2 + P3 + P4 + P5 + P6 + P7

    =0 3% 32&01%

    . Menghitung #u$ut Terkorek"i

    Rumus "mum :

    P0=271 16 28 +00 31&29=2710 9&92

    P1 =16754 0+ 0 0 19&78=16757 19&7P2=157 43 40+00 18&58=15743 58&5

    P3= 32322 40 +0 0 38&09= 323 23 18

    P4 =225 54 50+0 0 26&61=225 55 16&6

    P5 =185 34 50+0 0 21&86=185 35 11&8

    Korek)i *erpatok= sudut datar patok

    sudut datar'

    Sudut terkorek)i = )udut datar -

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    P6 =189 1 10+0 0 22&26=189 1 32&26

    P7= 279) 25 40 + 0) 0 32&91 = 279) 26 12*9

    . Menghitung *arak Datar O'ti" (D)

    Rumus "mum :

    P0 P1 = 1&800 1&300, 100 - s.287 2210$ = 49&895 m

    P1 P2 = 3&150 2&65 , 100 - s.287 3640$ = 49&913 m

    P2 P3= 2&518 1&65 , 100 - s.286 5110$ = 50&647 m

    P3 P4 = 0&84 0&561 , 100 - s.293 0800$ = 27&817m

    P4 P5 = 3&460 2&950, 100 - s.291 1200$ = 50&978 m

    P5 P6 = 1&75 1&25 , 100 - s.292 1900$ = 49&918 m

    P6 P7 = 1&698 1&304, 100 - s.287 9630$ = 39&377 m

    P7 P0 = 1&56 1&24 , 100 - s.292 1910$ = 31&948 m

    /= 350&493 m

    +. Menghitung ,e$a tinggi

    Rumus "mum :

    P0 P1 = 1&47 1&550, + 49*895 (a. 87 22 10 = 2*212

    P1 P2 = 1&50 2&900, + 49*913 (a. 87 36 40 = 0&682

    P2 P3 = 1&43 1&900, +50&647 (a. 86 51 10 = 3&585

    P3 P4 = 1&52 0&700, +27*817 (a. 93 08 00 = !0&703

    P4 P5 = 1&51 3&200, + 50*978 (a. 91 12 00 = !2*258

    P5 P6 = 1&47 1&500, + 49*918 (a. 92 19 00 = !2&049

    P6 P7 = 1&42 1&500, +39*377 (a. 87 96 30 = 0&877

    P7 P0 = 1&549 1&400, + 31*948 (a. 92 19 10 = !1&145

    D = !B. BB& 100

    Beda tinggi = .

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    -.Menghitung aimuth

    Rumus "mum :

    P0 P1 = 240 00 00+ 271 00 9&92, 180 = 331 00 9&92

    P1 P2 = 331 00 9&92 + 167 54 19&7, ! 180 = 318 54 29&6

    P2 P3 = 318 54 29&6 + 157 43 58&5, ! 180 = 296 38 28&1

    P3 P4 = 296 38 28&1 + 323 23 18, ! 180 = 80 1 46&12

    P4 P5 = 80 1 46*12 + 225 55 16&6, ! 180 = 125 57 2&72

    P5 P6 = 125 57 2&72 + 185 35 11&8, ! 180 = 131 32 14&52

    P6 P7 = 131 32 14&52 + 189 1 13&26, ! 180 = 140 33 27*78P7 P0 = 140 33 27*78 + 279 26 12&9, ! 180 = 240 00 00

    /. Menghitung "e0i"ih koor$inat

    Rumus "mum :

    - = P0 P1 = 49&895 # s. 331 00 9&92 = !24&187 m

    P1 P2 = 49&913 # s. 318 54 29&6 = !32&806 m

    P2 P3 = 50&647 - s. 296 38 28&1 = !45&270 mP3 P4 = 27&817 - s. 80 1 46*12 = 27&397 mP4 P5 = 50&978 - s. 125 57 2*72 = 41&268 m

    P5 P6 = 49&918 - s. 131 32 14&52 = 37&365 m

    P6 P7 = 39&377 - s. 140 33 27*78 = 25&016 mP7 P0 = 31&948 - s. 240 00 00 = !27&668 m

    - = 1&115 m

    = P0 P1 = 49&895 - os 331 00 9&96 = 43&640 m

    P1 P2 = 49&913 - os 318 54 29&6 = 37&617 m

    P2 P3 = 50&647 - os 296 38 28&1 = 22&710 mP3 P4 = 27&817 - os 80 1 46*12 = 4&816 m

    P4 P5 = 50&978 - os 125 57 2&72 = !29&929 m

    P5 P6 = 49&918 - os 131 32 14&52 = !33&101 m

    .imut, = 4 a5al $ )udut *n - 1806

    .imut, a5al = 10 $ 80 = "%0

    ' = 9arak datar :)in 4

    =

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    P6 P7 = 39&377 - os 140 33 27&78 = !30&409 mP7 P0 = 31&948 - os 240 00 00 = !15&977 m

    = !0&633 m

    . Menentukan "e0i"ih koor$inat (korek"i ero" 0inear)

    Rumus "mum :

    ".(uk - :

    - = P0 P1 = !1,117

    350,493- 49&895 = !0&159 m

    - = P1 P2 = !1,117

    350,493

    - 45&913 = !0&159 m

    - = P2 P3 = !1,117

    350,493- 50&617 = !0&161 m

    - = P3 P4 = !1,117

    350,493- 27&817 = !0&089 m

    - = P4 P5 = !1,117

    350,493- 50&978 = !0&153 m

    - = P5 P6 = ! 1,117350,493

    - 49&918 = !0&150 m

    - = P6 P7 = !1,117

    350,493- 39&377 = !0&118 m

    - = P7 P0 = !1,117

    350,493- 31&948 = !0&096 m

    +

    - . = !1&085

    ;

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    - = P1 P2 = !0,633

    350,493- 45&913 = 0&100 m

    - = P2 P3 = !0,633

    350,493- 50&617 = 0&101 m

    - = P3 P4 = !0,633

    350,493- 27&817 = 0&056 m

    - = P4 P5 = !0,633

    350,493- 50&978 = 0&102 m

    - = P5 P6 = !0,633

    350,493- 49&918 = 0&100 m

    - = P6 P7 = !0,633

    350,493

    - 39&377 = 0&079 m

    - = P7 P0 = !0,633

    350,493- 31&948 = 0&064 m

    + - . = 0&692

    12. Menghitung "e0i"ih koor$inat

    Rumus "mum :

    ;

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    P1 P2 = 37*617 + 0&100, = 37&717P2 P3 = 22&710 + 0&101, = 22&811

    P3 P4 = 4&816 + 0&056, = 4&872

    P4 P5 = !29&929, + 0&102, = !29&827

    P5 P6 = !33&101, + 0&100, = !33&001

    P6 P7 = 30&409, + 0&079, = !30&330P7 P0 = !27&66, + 0&064, = !15&913

    = 0*059

    11. Menghitung koor$inat 'o03gon

    Rumus "mum :

    ke(ahu koor.a( P - & , = 260&260, Koor.a( a>al ((k P

    a* Koor.a(

    P0!P1, = 240*00 + !24&346, = 215&654

    P1-*"&= 215&654 + !34&965, = 180&689P"-*3&= 180&689 + !45&431, = 135&258P3-*%&= 135&258 + 27&308, = 162&566P%-*>&= 162&566 + 41&115, = 203&681

    P5!P6, = 203&681 + 37&215,= 240&896P6!P7, = 240&896 + 24&898, = 267&794

    P7!P0, = 267&794 + !27&762, = 240&00

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    P0 = 240&00 m

    P1 = 240&00 + 2&212, =242&212 m

    P"= 242&212 + 0&682, = 242&894 m

    P3= 242&894 + 3&585, = 246&479 m

    P%= 246&479 + !0&703, = 245&776 m

    P>= 245&776 + !2&258, = 243&518 m

    P6 = 243&518 + !2&049, = 241&469 m

    P7 = 241&469 + 0&877, = 241&346 m

    P0 = 241&346 + !1&145, = 240&00 m

    MODUL II

    PENGU!URAN DENGAN MENGGUNA!AN THEODOLITH

    A.TUJUAN INSTRUKSI UMUM

    1# Ma,a)i)5a dapat mengeta,ui prin)ip penggunaan t,eodolit,#

    "# Ma,a)i)5a dapat melakukan pengukuran )udut ,oriontal dan )udut

    vertikal dan meng,itung 9arak ata) da)ar pemAa@aan )udut ramAu#

    4. TU*UAN IN#TRU!#I !HU#U#

    1* @ahass>a =a'a( melakuka. 'e.Aukura. su=u( =e.Aa. me(o=e 8a.A

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    3# amAu ukur

    %# Kompa)

    ># Baterai !Aagi pe)a5at t,eodolit, digital&

    # nting-unting

    7# *atok kayu

    8# Meteran

    (# .lat tuli)-menuli)

    D. TINJAUAN PUSTAKA1# .rti dan tu9uan Elmu kur ana,Elmu ukur tana, adala, ilmu yang

    Aer,uAungan dengan Aentuk muka Aumi !topograF& artinya ilmu yangAertu9uan menggamAarkan Aentuk topograF muka Aumi dalam )uatupeta dengan )egala )e)uatu yang ada pada permukaan Aumi )eperti kotaG

    9alanG )ungaiG AangunanG dll

    Dengan )kala lingkaran tertentu )e,ingga dengan mempela9ari peta kita

    dapat mengeta,ui 9arakG ara,G dan po)i)i tempat yang kita inginkan#

    mempela9ari ilmu ukur tana, H

    a# MemAuat petaA# Menentukan eleva)i dan ara,

    @# Mengontrol eleva)i dan ara, u9uan

    d# Dan lain-lain#

    "# Dimen)i-Dimen)i ang .kan Diukur

    a# +arak H .dala, gari) ,uAung terpendek antara "titik yang dapat

    di ukurdengan menggunakan alat ukur mi)alH mi)tarG pita

    ukurG t,eodolit,G 5aterpa))G dan lain-lain#

    A# Sudut H .dala, Ae)aran antara " ara, yang Aertemu pada)atu

    titik !untuk menentukan aimut, dan ara,

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    B.

    B

    BB

    2

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    @# Ketinggian H .dala, 9arak tegak diata) atau diAa5a, Aidang reviner)

    yang akan diukur dengan 5aterpa)) dan ramAu ukur#

    3# *rin)ip Da)ar *engukuran

    ntuk meng,indari ke)ala,an-ke)ala,an yang mungkin )a9a ter9adiG maka

    tuga) pengukuran ,aru) dida)arkan pada prin)ip pengukuran yaitu H

    1# *erlu adanya penge@ekan terpi)a,

    "# idak ada ke)ala,an-ke)ala,an dalam pengukuran

    3# *eta dan +eni)-9eni) *eta#

    %# *engukuran *olygon

    Pe.Aukura. 'olAo. maksu me.Ah(u.A koor.a(& ke(.AAa. (a'!(a' ((k 'olAo. u.(uk (u k(a

    me.Aaaka. 'e.Aukura. suu( a. Barak e.Aa.

    me.Aka(ka. 'aa sua(u ((k (e(a' se'er( ((k (ra.Aulas& Bem

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    B. = Benang .ta)B = Benang enga,

    BB = Benang Ba5a,

    2 = *emAa@aan )udut vertikal !,elling&

    +arak miring !D& = !B.-BB& ' 100 ' )in 2

    +arak datar !D& = !B.-BB& ' 100 ' )in"2

    = D1)in 2

    A# Meng,itung Sudut Datar dan Korek)i

    Ce(elah suu( a(ar Bumlah ar semua ((k a.A a'a( ar hasl 'e.Aukura. aka. (erBa

    kesalaha.& maka e.Aa. (u harus koreks sesua e.Aa.

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    C

    D

    .imut,

    diketa,ui

    *oligon Aaru

    .imut,

    diketa,ui

    *oligon erda,ul

    .

    B

    Survey dan Civil engineering13Klompok 7

    *oligon ertutup antara " titik yang diketa,ui

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    .B

    .B

    C

    D

    .B

    B

    C

    Survey dan Civil engineering13Klompok 7

    a* Pe.Aukura. mula ar ((k ;F ma.a aDmu( ;F ke(ahu a. (erakhr ((k G aDmu(

    se

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    DimanaH

    D = 9arak datar

    = aimut,

    'erh(u.Aa. ar mula ar ((k a>al a.A suah ke(ahu koor.a(.a kemua.

    (am

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    dan ung)inya#

    3# *er,atikan Aaik-Aaik tempat dan @ara memAa@a )kala lingkaran Aaik

    ,oriontal maupunvertikalG karena )etiap pe)a5at mempunyai )pe)ivika)i

    )endiri-)endiri#

    %# +angan memutar-mutar )ekrup pengatur )eAelum ta,u Aenar ung)inya#

    ># Dalam memAuka dan mengun@i )ekrup-)ekrup pengatur 9angan terlalu

    longgar dan terlalu ken@ang#

    # Kalau ma)i, ragu di,arapkan Aertanya pada in)truktur#

    F. LANGKAH KERJA

    1. Mengena0 4agian54agian Pe"a6at

    Pasa.A 'esa>a( a(as s(a(*

    @em'erha(ka. e.Aa. seksama

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    4, ua Aars Burusa. a.A me.a(ar a. aka. le(ak er(kal*

    5, @e.Aula.A 'ekerBaa. h.AAa

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    ((k O a. le(ak kak ..A*

    Paa ((k P L 'asa.A ker(as mlme(er a(auker(as skala me.a(ar seemka. ru'a

    h.AAa ((k .ol skala

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    * Ce>ak(u (ero'o.A

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    * Mo.us

    * Qars lurus a.A le.Aka' e.Aa. mrome(er*

    2* a* Fe.(uk Aars lurus (elah

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    3*Faa skala mrome(er a.A (u.Buk oleh .e-

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    horDo.(al a. er(kal*

    3* Ce(elah ((k F kelha(a.& me.em'a(ka. ((k F erse

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    H1= 2R s.22

    H2= R s. 2

    O(k 2 H2& ?2,

    H2= 2R s.2

    H3= R s. 3

    O(k 3 H3& ?3,

    H3= 2R s.2 32

    H.= R s. .*

    O(k . H.& ?.,

    4* @em

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    Po03gon Ter,uka

    1* @e.e.(uka. ((k 'o(o.A 'olAo. a.A aka. al 'e.Aukura.*

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    2* Pe.Aukura. akhr harus kemal mula

    ar ((k P a.A kemua. akhr ke((k P laA*

    H. Pengukuran #etting Out5#take Out

    1* @emasa.A a. me.Aukur 'esa>a( 'aa ((k ; sam'a sa' 'aka*

    2* @e.olaka. skala l.Akara. me.a(ar kemua. ku. kema( sea( se

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    II. Perhitungan Patok Detai01. Menentukan #u$ut Datar Detai0

    Rumus :

    Sudut Datar = Sudut Muka Sudut Belakang'0 = 'a = 0 11 0$ ! 0 22 50$ = !0 1 50$+ 360

    = 35 5 109 8

    '< = 0 19 50$ ! 0 22 50$ = 0 7 0$' = 358 47 40$ ! 0 22 50$= 358 2450$

    ' = 0 5230$ ! 0 2250$ = 0 29 40$

    '1 ='a = 308 4410$ ! 0 00$ = 308 4410$

    '< =308 620$ ! 0 00$ = 308 620$

    ' =303 4620$! 0 00$ = 16 260$' = 260 00$ ! 0 00$ = 260 00$

    'e = 262 2220$ ! 0 00$ = 262 2220$

    ' = 262 3140$ ! 0 00$ = 262 3140$

    'A = 266 3730$ ! 0 00$ = 266 3730$

    '2 ='a = 268 3620$ ! 0 00$ = 268 3620$

    '< = 266 3750$ ! 0 00$ = 266 3720$

    ' = 263 010$ ! 0 00$ = 263 010$

    ' = 97

    3440$ ! 0

    00$ = 97

    3440$'e = 100 1440$ ! 0 00$ = 100 1440$

    '3 = 'a = 322 320$ ! 0 00$ = 322 320$

    '< = 319 5350$! 0 00$ =319 5350$' = 318 3440$! 0 00$ =318 3440$

    ' = 248 5740$! 0 00$ =248 5740$

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    'e = 166 4740$! 0 00$ =166 4740$' = 119 2320$ ! 0 00$ =119 2320$

    '4 ='a = 132 1856 ! 0 00$ = 132 1856$

    '5 ='a = 263 2540$ ! 0 00$ =263 2540$

    . *arak $atar o'ti" (D)

    Rumus :

    Jarak Datar Optis = (BA - BB x sin!

    P0a = 1*625 ! 1*315, 100 # s.X 87 18 0 = 30*93

    P0< = 1*619 ! 1*319,100 # s.X 92 2 50 = 29*96P0 = 1*570 ! 1*370,100 # s.X 95 41 20= 18*80

    P0 = 1*795 ! 1*715, 100 # s.X 100 20 20 = 7*74

    P1a = 1*700 1*300,100# s.X 94 2230 = 39*76

    P1< = 0*91 0*49,100 # s.X 91 37 28 = 41*97P1 = 1*74 1*26, 100# s.X90 00 00 = 48*00

    P1 = 1*870 1*540,100 # s.X90 38 00 = 32*99

    P1e = 3*220 2*990, 100 - s.X 90) 38 00 = 23*00P1 = 3*275 3*15, 100 - s.X90) 44 40 = 12*50

    P1A = 2*90 2*890, 100 - s.X 104) 45 00 = 7*87

    P2a = 0*440 0*193,100# s.X893000 = 24&70

    P2< = 2*188 1*920,100 # s.X892050 = 26*79

    P2 = 1*736 1*500,100# s.X892530 = 23*60P2 = 1*44 1*37, 100 # s.X893750 = 24*70

    P2e = 0*562 0*438,100# s.X820950 =26*79

    P3a = 1*83 1*61, 100 # s.X930800 = 22

    P3< = 2*650 2*440, 100 #s.X844130 = 20*82

    P3 = 1*730 1*490, 100 - s.X 84)4300 = 24P3 = 1*626 1&574, 100 - s.X 84)2300 = 5*15

    P3e = 0*943 0*858, 100 - s.X 73)2410 = 7*81

    P3 = 2*973 2*83, 100 - s.X 71)1310 = 12*82

    P4a = 0*739 0*661, 100 - s.X 76) 26 50 = 7*37

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    P5a = 1*295 1*142, 100 - s.X 95) 05 40 = 11*61

    &. Aimuth

    Rumus:a"imut# $n % sudut datar detail - &');Dmu(h a>al = 160

    P0a = 16000 + 3595810 ! 180 = 3395810

    P0< = 16000+ 00700! 180 = 19530

    P0 = 16000 + 3582450 ! 180 = 3382450P0 = 16000 + 002940! 180 =3402940

    P1a = 25109*92 + 3084410 !180 = 194419*9

    P1< = 25109*92 + 308620 ! 180 = 19629*92P1 = 25109*92 + 3034620 ! 180 = 144629*92

    P1 = 25109*92 +2600000 !180 = 33109*92

    P1e = 25109*92 + 2622220 !180 = 3332229*9P1 = 25109*92 + 2623140 ! 180 = 3333149*9

    P1A = 25109*92 + 2663730 ! 180 = 3373739*9

    P2a = 2385729*6 + 2683620 !180 = 3273349*6

    P2< = 2385729*6 + 2663750 ! 180 = 3253519*6P2 = 2385729*6 + 2630010 ! 180 = 3215739*6P2 = 2385729*6 + 973440 !180 = 156329*6

    P2e = 2385729*6 + 1001440 ! 180 = 159129*6

    P3a = 2164128*1 + 322320 ! 180= 3591328*1

    P3< = 2164128*1 + 3195350 ! 180 = 3563518*1P3 = 2164128*1 + 3183440 ! 180 =355168*1

    P3 = 2164128*1 + 2485740 ! 180 = 285398*1

    P3e = 2164128*1 + 1664740 ! 180= 203298*1

    P3 = 2164128*1 + 1192320 ! 180 = 156448*1

    P4a = 360446*12 + 1321856 ! 180= 3122342*1

    P5a = 4602*72 + 2632540 ! 180 = 1292542*7

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    . #e0i"ih koor$inat

    Rumus :

    *x = +arak datar ,ptis sin a"imut#

    *. = +arak datar ,ptis /,s a"imut#

    9: ;

    P0a = 30*93 # s. 3395810, = !10*594

    P0< = 29*69 # s. 195300, = 10*097P0 = 19*80 # s. 3382450, = !7*284

    P0 = 7*74 # s. 3402940 , = !2*584

    P1a = 39*76 # s. 194419*9, = 13*428

    P1< = 41*97 # s. 19629*92, = 13*739

    P1 = 48*00 # s. 144629*92, = 12*241P1 = 32*99# s. 33109*92 , = !15*992

    P1e = 23*00 # s. 3332229*9, = !10*307

    P1 = 12*50 # s. 3333149*9, = !5*571

    P1A = 7&87 # s. 3373739*9, = !2*995

    P2a = 24*70 # s. 3273349*6, = !13*248

    P2< = 26*76 # s. 3253519*6, = !15*122P2 = 23*60 # s. 3215739*6, = !14*542

    P2 = 24*70 # s. 156329*6 , = 9*834

    P2e = 26*79 # s. 159129*6, = 9*512

    P3a = 22 # s. 3591328*1, = !0*297

    P3< = 20*82 # s. 3563518*1, = !1*239P3 = 24 # s. 355168*1, = !1*979

    P3 = 5*15 # s. 285398*1, = !4*959

    P3e = 7*81 # s. 203298*1, = !3*112

    P3 = 12*82 # s. 156448*1, = 9*198

    P4a = 7*37 # s. 312442*1, = !5*198

    P5a = 11*61 # s. 1292542*7, = 8*976

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    93 ;P0a = 30*93 # os 3395810, = 29*059

    P0< = 29*69 # os 195300, = 27*920P0 = 19*80 # os 3382450, = 18*411

    P0 = 7*74 # os 3402940 , = 7*295

    P1a = 39*76 # os 194419*9, = 37&423P1< = 41*97 # os 19629*92, = 39*657

    P1 = 48*00 # os 144629*92, = 46*412

    P1 = 32*99 # os 331009*92 , = 28*854P1e = 23*00 # os 3332229*9, = 20*561

    P1 = 12*50 # os 3333149*9, = 11*189P1A = 7*87 # os 3373739*9, = 7*277

    P2a = 24*70 # os 3273349*6, = 20*846

    P2< = 26*76 # os 3253519*6, = 22*077

    P2 = 23*60 # os 3215739*6, = 18*587

    P2 = 24*70 # os 156329*6 , = !22*657P2e = 26*79 # os 159129*6, = !25*044

    P3a = 22 # os 3591328*1, = 21*998

    P3< = 20*82 # os 3563518*1, = 21*818P3 = 24# os 355168*1, = 23*918P3 = 5*15 # os 285398*1, = 1*389

    P3e = 7*81 # os 203298*1, = !7*163

    P3 = 12*82 # os 156448*1, = !11&718

    P4a = 7*37 # os 3122342&1, = 4*969

    P5a = 11*61 # os 1292542*7, = 4&194

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    . !oor$inat 'o0igon $etai0

    Rumus:

    X = X0+ x

    Y = y0 + y

    Dik koordinat po (xo.yo) = (160.160)

    Koordinat awal di p7

    '0 = 'a = 170*828 + !10*594 = 160*234

    '< = 170*828 + 10*097 = 180*925

    ' = 170*828 + !7*284 = 163*544

    ' = 170*828 + !2*584 = 168*244

    '1 = 'a = 123*533 + 13*428 = 136*961

    '< = 123*533 + 13*739 = 137*272

    ' = 123*533 + 12*241 = 135*774

    ' = 123*533 + !15*992 = 107*541'e = 123*533 + !10*307 = 113*226

    ' = 123*533+ !5*571 = 117*962

    'A = 123*533+ !2*995 = 120*538

    '2 = 'a = 80*660 + !13&248 = 67*412

    '< = 80*660 + !15*122 = 65*538

    ' = 80*660 + !14*542 = 66*118

    ' = 80*660 + 9*834 = 90*494'e = 80*660 + 9*512 = 90*172

    '3 = 'a = 50*280 + !0*297 = 49*983

    '< = 50*280 + !1*239 = 49*041

    ' = 50*280 + !1*979 = 42*301

    ' = 50*280 + !4*959 = 45*321'e = 50*280 + !3*112 = 47*168

    ' = 50*280 + 5*198 = 55*478

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    '4 = 'a = 50*253 + !5*442 = 44*811

    '5= 'a = 86*804 + 8*967 = 95*771

    y= y0+ y

    '0 = 'a = 129*870 + 29*059 = 158*929

    '< = 129*870 + 27*920 = 157*790

    ' = 129*870 + 18*441 = 148*281

    ' = 129*870 + 7*295 = 137*165

    '1 = 'a = 113*490 + 37*423 = 150*913

    '< = 113*490 + 39*657 = 153*147

    ' = 113*490 + 46*412 = 159*902

    ' = 113*490 + 28*854 = 142*344'e = 113*490 + 20*561 = 134*051

    ' = 113*490 + 11*189 = 124*679

    'A = 113*490 + 7*277 = 120*767

    '2 = 'a = 87*607 + 20*846 = 108*453

    '< = 87*607 + 22*077 = 109*684' = 87*607 + 18*587 = 106*194

    ' = 87*607 + !22*657 = 64*950

    'e = 87*607 + !25*044 = 62*563

    '3 = 'a = 46*977 + 21*998 = 68*975

    '< = 46*977 + 21*818 = 68*795

    ' = 46*977 + 23*918 = 70*895

    ' = 46*977 + 1*389 = 48*366'e = 46*977 + !7*163 = 39*814

    ' = 46*977 + !11*718 = 35*259

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    '4 = 'a = 74*707 + 4*969 = 79*676

    '5= 'a = 110*057 + !7*367 = 102*690

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    +. menghitung ,e$a tinggi $etai0

    1, Pa(ok P0

    P0a = 1&47 1&47 +

    87 18'00}}

    tan

    30,93

    = 1&459

    P0< = 1&47 1&47 +

    92 2'50}}

    tan

    29,96

    = !1&071

    P0 = 1&47 1&47 +

    95 41'20}}

    tan

    18,80

    = !1&873

    P0 = 1&47 1&75 +

    100 20'20}}

    tan

    7,74

    = !1&692

    2, Pa(ok P1

    P1a = 1&50 1&50 +

    94 22'30}}

    tan

    39,76

    = !3&042

    P1< = 1&50 0&70 +

    91 37'28}}

    tan

    41,97

    = !0&390

    P1 = 1&50 1&50 +

    90 0'20}}tan

    48,00

    = !0&004

    I, = . - Bm $

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    P1 = 1&50 1&705 +

    90 38'00}}

    tan

    32,99

    = !0&570

    P1e = 1&50 3&10 +

    90 38'00}}

    tan 23,00

    = !1&854

    P1 = 1&50 3&20 +

    90 44'40}}

    tan

    12,50

    = !1&862

    P1A = 1&50 2&90 +

    104 45'00}}

    tan

    7,87

    = !3&472

    3, Pa(ok P2

    P2a = 1&43 0&316 +

    89 30'0}}

    tan

    24,70

    = 1&330

    P2< = 1&43 2&054 +

    89 20'50}}

    tan

    26,79

    = !0&319

    P2 = 1&43 1&618 +

    89 25'30}}

    tan

    23,60

    = 0&049

    P2 = 1&43 1&400 +

    89 37'50}}

    tan

    24,70

    = 0&189

    P2e = 1&43 0&500 +

    82 09'50}}

    tan

    26,79

    = 4&617

    4, Pa(ok P3

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    P3a = 1&52 1&72 +

    93 08'00}}

    tan

    22

    = !1&404

    P3< = 1&52 2&545 +

    84 41'30}}

    tan

    20,82

    = 0&909

    P3 = 1&52 1&610 +

    84 43'00}}

    tan

    24

    = 2&129

    P3 = 1&52 1&6 +

    84 23'30}}

    tan

    5,15

    = 0&426

    P3e = 1&52 0&9 +

    73 24'10}}

    tan

    7,81

    = 2&948

    P3 = 1&52 2&9 +

    71 13'10}}

    tan

    12,82

    = 2&979

    5, Pa(ok P4

    P4a = 1&51 0&7 +

    76 26'50}}

    tan

    7,37

    = 2&587

    6, Pa(ok P5

    P5a = 1&47 1&52 +

    95 05'40}}

    tan

    11,61

    = !1&085

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    -. menghitung tinggi titik

    1, Pa(ok P0

    P0a = 162&202 + 1&459 =163&661

    P0< = 162&202 + !1&071, = 161&131P0 = 162&202 + !1&873, = 160&329

    P0 = 162&202 + !1&692, = 160&510

    2, Pa(ok P1

    P1a = 162&884 + !3&042, = 159&842

    P1< = 162&884 + !0&390, = 162&494

    P1 = 162&884 + !0&004, = 162&880

    P1 = 162&884 + !0&570, = 162&315

    P1e = 162&884 + !1&854, = 161&030

    P1 = 162&884 + !1&862, = 161& 022

    P1A = 162&884 + !3&472, = 159&412

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    3, Pa(ok P2

    P2a = 166&469 + 1&330 = 167&799

    P2< = 166&469 + !0&319, = 166&150

    P2 = 166&469 + 0&049 =166&518

    P2 = 166&469 + 0&189 = 166&658

    P2e = 166&469 + 4&617 = 171&086

    4, Pa(ok P3

    P3a = 165&766 + !1&404, = 164&362

    P3< = 165&766 + 0&909 = 166&675

    P3 = 165&766 + 2&129 = 167&895

    P3 = 165&766 + 0&426 = 166&192

    P3e = 165&766 + 2&948 = 168&714

    P3 = 165&766 + 2&979 = 168&745

    5, Pa(ok P4

    P4a = 163&508 + 2&587 = 166&0956, 'a(ok P5

    P5a = 161&459 + !1&085, = 160&374

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