thuyet minh da

7/30/2019 Thuyet Minh Da

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I. PHN TCH CHI TITTn chi tit: Gi Cng dng v iu kinlm vic ca chi tit gia cng

Chi tit dng cc ngng trc, gia gi v ngng trc c bc hoc clp bi.

Khi lm vic chi tit chu lc nn ca ngng trc l chnhVt liu v c tnh yu cuVt liu: Gang xm (GX15-32), c cc thng s k thut sau:+b = 15(kG/mm

2)

+n = 32(kG/mm2)

+ cng 190HB + Gang xm l hp kim st vi cacbon v c cha mt s nguyn t khc nh (0,

54, 5)%Si, (0, 40, 6)%Mn, 0, 8%P, 0, 12%S, ngoi ra cn c thm Cr, Cu, Ni, Al

+ Gang xm c bn nn cao chu mi mn, tnh c tt, gia cng c d, nh,r v gim rung ng, c tnh chy lng cao, t c thin tch, t ha tan khc thc trong nhiuloi khun khc nhau.

+Trong qu trnh lm vic, gi chu lc nn l ch yu, nn ta thy gang xmc th p ng c yu cu lm vic ca chi tit.Phn tch yu cu k thut

* Dung sai kch thc:+90 0.175: sai s cho php ca khong cch ng tm ca hai l lp vt vo

lp rp u gi vo thn gi . Vi dung sai IT =0.35 ng vi cp chnh xc

12 l cho vic lp rp chun khng rung ng gia hai chi tit u v thn gi.+ 50 0.125: sai s cho php tm b mt lm vic vi b mt y ca thn gi

. Vi dung sai IT=0.25 l cp chnh xc 12 m bo cho kh nng lm vicca b mt ng tm khi lp trc, khng to o ca trc khi lm vic.

+160 0.2: sai s cho php ca hai tm ca hai llp bulng nh v thn gi vi cm my. Vi dung sai IT=0.4 l cp chnh xc cp 12 dm bo cho thn gi khng b x dch va khng dao ng to sai s h thng.

* Dung sai v tr:Dung sai song song b mt y vi ng tm ca b

mt lm vic l 0.015, m bo chnh xc khi c nh thn gi vi thn cmmy to c chnh xc cho b mt lm vic t yu cu.

+Theo iu kin lm vic c nu trn th ta cn quan tm n cc yu cu kthut sau:

B mt lm vic chnh ca chi tit l b mt l(9), v vy yu cu ca b mt(9)l cao nht. V kch thc:

+ 04,060 , c dung sai l l H8- V nhn ca b mt gia cng:+ Mt tr trong ca l c ng knh 60 c nhm b mt l Ra=2, 5 (

nhm cp 6) chi tit m bo c kh nng lm vic tt.+ R

z40 l cp b mt gia cng th

// 0.015 A


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II.XC NH DNH SN XUT:Sn lng chi tit cn ch to trong mt nm:

1001

10010

mNN chi tit/nm [hddamhcnctm, trang 24]

N0 = 10000: s lng sn phm trong mt nm.

m = 1: s chi tit nh nhau trong 1 sn phm= 1020%: lng d tr. Chn = 15%= 25%: ph phm. Chn= 4%

=> N = 10000.1. (1+

) (1+

)= 11960 chi tit/nmN=11960 chi tit/nmKhi lng chi tit c xc nh bng phn mm inventor 2012:

Hinh 1.1 Hnh v th hin thng s khi lng chi titDa vo hnh v,ta xc nh c khi lng chi tit l 1,652 kg

Vi sn lng chi tit ( 11960 ) v khi lng ca chi tit (m = 1, 652 kg), datheo ti liu [1, trang 25, bng 2.1] ta c hnh thc sn xuti vi chi titthucdng sn xut lot va(1000 50000 chi tit/nm)

III. CHN PHI & PHNG PHP CH TO PHI3.1 Dng phi

- Trong gia cng c khcc dng phi c th l: phi c, rn, dp, cn.- Xc nh loi v phng php ch to phi phi nhm mc ch bo m hiu

qu kinh t k thut chung ca quy trnh ch to chi tit, ng thi tng ph tn

ch to chi tit k t cng on ch to phi cho ti cng on gia cng chi tit phithp nht. V vt liu l gang xm GX15_32 nn ta chn phng php c c tnhhiu qu v t tn km nht. Thng thng, c cho ta phi liu c kt cu phc tpm ccphng php khc kh thchin c.


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Ta chn phng php c v:+ gi thnh ch to vt c r+ thit b u t phng php ny tng i n gin, cho nn u t thp+ph hp vi sn xut hng lot va+ nhm b mt, chnh xc sau khi c c th chp nhn c th tip tc

gia cng tip theo+ V vt liu l gang3.2 Phng php ch to phi

Trong c phi c nhng phng php sau:3.2.1. c trong khun ct mu g

Cht lng b mt vt c khng cao, ga thnh thp, trang thit b n gin,thch hp cho dng sn xut n chic v lot nh.

Loi phi ny c cp chnh xc IT16 IT17. nhm b mt: Rz=160m.

=> Phng php ny cho nng sut trung bnh , cht lng b mt khng cao, gykh khn trong cc bc gia cng tip theo.3.2.2. c trong khun ct mu kim loi:

Nu cng vic lm khun c thc hin bng my th c cp chnh xc kh cao,gi thnh cao hn so vi c trong khun ct mu g, v gi to khun cao.

Cp chnh xc ca phi: IT15 IT16. nhm b mt: Rz=80m.=> Cht lng b mt ca chi tit tt hn phng

php c vi mu g, c c cc chi tit c hnh dng phc tp, nng sut phhp vi dng sn xut lot va v ln.

3.2.3. c trong khun kim loi: chnh xc cao, gi thnh u t thit b ln,phi c hnh dng gn ging vichi tit nn lng d nh, tit kim c vt liu nhng gi thnh sn phm cao.

Cp chnh xc ca phi: IT14 IT15. nhm b mt: Rz=40m.=>Phng php nay cho nng sut cao, c tnh k thut ca chi tit tt nhng

gi thnh cao nn khng ph hp vi tnh kinh t trong sn sut lot va.3.2.4. c ly tm:

Loi ny ch ph hp vi chi tit dng trn xoay, rng, i xng, c bit l ccchi tit hnh ng hay hnh xuyn.

Kh nhn c ng knh l bn trongvt c chnh xc v kh nh clng kim loi rt vo khun chnh xc

Cht lng b mt trong vt c km (i vi vt c trn xoay) v cha nhiutp cht v x.3.2.5. c p lc:

Dng p lc in y kim loi trong lng khunHp kim c di p lcthng l hp kim Thic, Ch, Km, Mg, Al, Cu.c di p lc dng ch to cc chi tit phc tp nh v bm xng, du, np

bung p, van dn kh

Trang thit b t nn gi thnh sn phm cao.c tnh k thut tt nhng i vidng sn sut lot va th hiu qu kinh t khng cao.3.2.6. c trong khun v mng:


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L dng c trong khun ct nhng thnh khun mng chng 6-8mmC th c c gang, thp, kim loi mu nh khun ct, khi lng vt c n

100 kg

Dng trong sn xut lot ln v hng khi.3.2.7. c lin tc:

L qu trnh rt kim loi lng u v lin tc vo moat khun bng kim loi ,xung quanh hoc bn trong khun c nc lu thng lm ngui (cn gi l bnh kttinh).Nh truyn nhit nhanh nn kim loi lng sau khi rt vo khun c kt tinhngay, vt c c ko lin tc ra khi khun bng c cu c bit nh con ln

Thng dng c ng, c thi, c tmKt lun:

-Vi nhng yu cu ca chi tit cho, tnh kinh t cng nh dng sn xut ta schn phng php ch to phi c trong khun ct mu kim loai, lm khun

bng my.

-Phi c t cp chnh xc l II.-Cp chnh xc kch thc IT15 IT16.

- nhm b mt: Rz=80m.3.3 Xc nh lng d gia cng

-Chi tit c ch to bng gang xm, c c trong khun ct mu kim loi,lm khun bng my, mt phn khun (nm ngang).

-Lng d pha trn: 4mm-Lng d pha di v mt bn: 3 mm-Gc nghing thot khun: 10-Bn knh gc ln: 3 mm.

Hnh1.2 Bn v phi


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Hnh 1.3 Bn v lng khun

IV. TIN TRNH GIA CNG CC B MT1.nh s cc b mt chi tit

Hnh 1.4 Bn v nh s cc b mt


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2.Thit k tin trnh nguyn cngPhng n 1

Tn nguyn

cng

Bc gia cng S ca b mtgia cng

S ca b mtnh v

Dng mycng ngh

1 Phay th 1 4, 14 My phayPhay tinh 1 4, 14 My phay

2phay th 3, 15 1 My phay

Phay tinh 3, 15 1 My phay

3Khoan 2, 16 1 Mykhoan

Khot 2, 16 1 Mykhoan

4Phay th 4, 14 1, 2, 16 My phay

Phay tinh 4, 14 1, 2, 16 My phay

5Phay th 8, 10 1, 2, 16 My phay


6Phay th 5, 13 1, 2, 16 My phay


7Phay th 6, 12 1, 2, 16 My phay


8Phay th 17, 20 1, 2, 16 My phay


9 Khoan 7, 11 1, 2, 16 My khoan

10 Taro 7, 11 1, 2, 16 Tay quay taro

11 Phay th 18, 19 1, 2, 16 My phayPhay tinh 18, 19 1, 2, 16 My phay

12Khot 9 1, 2, 16 My khot

Doa 9 1, 2, 16 Ma doa


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Phng n 2Tn nguyn

cngBc gia

cngS cab mt

gia cngS ca b mt

nh vDng mycng ngh

1Phay th 1 4, 14 My phay

Phay tinh 1 4, 14 My phay

2 Phay th 3, 15 1 My phayPhay tinh 3, 15 1 My phay

3Phay th 4, 14 1 My phay












9Khoan 2, 16 1 Mykhoan

Khot 2, 16 1 Mykhoan

10 Khoan 7, 11 1 My khoan

11 Taro 7, 11 1 Tay quay taro

12 Khot 9 1 My khotDoa 9 1 Ma doa

Nhn xt:So vi phng n 2, phng n 1 s dng b mt (1), (2), (16) lm chun tinh gia cng chi tit. Vic s dng cc b mt trn nh v khng ch 6 bc tdo cn thit cho qu trnh gia cng nn g s dng trong qu trnh gia cng chitit s khng phc tp v ch cn s dng mt loi g l , t gim thi giang t, nng sut gia cngnng cao, tit kim c chi ph v mang li hiu qukinh t hn. V vy m cc qu trnh nguyn cng sau ny s c thc hin da

vo phng n 1.


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Nguyn Cng 1: Phayb mt (1)a. S g t:

Hnh 1.5 S nguyn cng 1

b.Phng php gia cng:Nguyn cng ny l gia cng mt phng nn c th la chn cc phng php

gia cng sau: bo, phay.

Ta s dng phng php bo c u im l nng sut my nh, nhng nhcim ln ca phng php bo l nng sut ct b nn thi gian gia cng ln.Phng php gia cng bos ph hp hn vi gia cng mt phng nh.

khc phc nhc im ca phng php bo ta s dng phng php phay .B mt gia cng (1) l mt phng c din tch trug bnh nn ta s dng phng

php phay vi dao phay mt u.c.Tin trnh gia cng:

Phay th b mt (1) vi cp chnh xc 12-14 , nhm b mt Rz 25-50Phay tinh b mt (1) vi cp chnh xc 12-14 , nhm b mt Rz 40

d. nh v:y l nguyn cng u sau khi c nnta chn mt nh v l mt(4), (14)

m bo tiu chun chn chun th.y l nguyn cng gia cng th nn ta nh v mt y bng phim t kha

nhm, khng ch 3 bc t do ( Toz, Qox, Qoy ) xc nh kch thc trn bnmy ta nh v thm b mt bn bng m tnh

ca t, khng ch 2 bc t do ( Tox, Qoz)Phng php kp cht:Kp bng t, v tr im t lc trn b mt bn. Hng lc kpvung gc vi

trc ca daoe.Chn my:

Kch thc b mt gia cng: 40x200Chiu cao chi tit: 55(mm)Ta chn my phay 6H12Thng s ca my: tra bng 9.38 (s tay CNCTM tp 3)( trang 7275)


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S cp tc trc chnh: 18Phm vi tc trc chnh: 301500 (vg/pht)Cng sut ng c chnh: 7 (KW)Hiu sut my: 0, 75Cng sut ng c chy dao: 1, 7 (KW)

Khi lng my: 2900 (kg)Khong cch t trc chnh ti bn my: 30-400(mm)Kch thc ph b ca my: Di 2100 (mm)Rng: 2440 (mm)Cao: 1875 (mm)

Kch thc b mt lm vic ca my:B

1=320 (mm)

L=1250 (mm)

S rnh ch T: 3

Chiu rng rnh ch T: b 1 =18 (mm)Khong cch gia hai rnh ch T: l1=70 (mm)

Dch chuyn ln nht ca bn my: Dc 700 (mm)Ngang: 260 (mm)

Thng ng: 370 (mm)Dch chuyn nhanh cabn my: Dc 2300 (mm)

Ngang: 2300 (mm)

Thng ng : 770 (mm)S cp bc tin bn my: Dc 23, 51180 (mm)

Ngang: 23, 51180 (mm)f.Chn dao:

V vt liu chi tit l gang nn vt liu ct chn l thp hp kim cng BK6. Vgia cng b mt c b rng l 40mm chn loi dao phay mt u c gn hp kimcng.

Thng s ca dao: ( Bng 4.95 (2)Trang 376 )ng knh ngoi ca dao: D = 200(mm)Chiu dy ca dao: B = 60(mm)ng knh trong ca dao: d = 50 (mm)

S rng ca dao: 12 rngg.Dng c kim tra:Thckp

h.Dung dch trn ngui:Khan

Nguyn Cng 2: Phay mt bc(3), (15)


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a.S g t:


b.Phng php gia cng:

S dng phng php phay bng dao phay a. V gia cng cng lc hai mtphng (3)v(15)nn ta c ths dng hai dao gn trn cng mt trc. Khi nngsut ct s tng ln, v gim c thi gian gia cng ph.c.Tin trnh gia cng:

Phay th b mt (3),(15), cp chnh xc 12-14 , nhm b mt Rz 25-50Phay tinh b mt (3),(15) vi cp chnh xc 12-14 , nhm b mt Rz 40

d. nh v:Theo nguyn tc gia cng mt phng bc ta ch cn nh v 4 bc t do.

tng nng sut khi gia cng(g t v kp cht nhanh) ta nh v thm 2 bc t do

nh v b mt (2) bng phim t khng ch 3 bc t do(Toz, Qoy, Qox)S dng cht tr nh v mt u khng ch 1 bc t do (Tox)S dng 2 cht t khng ch 2 bc t do (Toy, Qoz)Phng n kp cht:S dng c cu kp cht bng ren vt.V tr im t lc: im thp nht ca b mt trHng ca lc kp: t trn hng xungS dng u kp c dng tr nn n cng c tc dng nh v.Nn khi kp ta vn

t t vo chi tit c nh v. Sau mi kp cht

e. Chn my:S dng my phay 6H12Thng s ca my c xc nh nguyn cng 1

f. Chn dng c ct:S dng dao phay a ba mt rng gn mnh thp giKch thc dao:ng knh ngoi: D=200(mm)Chiu dy ca dao: b=40(mm)ng knh trong: d=50(mm)S rng z=18(rng)

g. Dng c kim tra:Thc cp


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h. Dung dch trn ngui:Khan

Nguyn Cng 3: khoan +khot + doa l (2), (16)a.S g t:


b. Phng php gia cng: khoan, khot, doa l 18 ta c th s dng phng php khoan trn my tin,

trn my phay hoc s dng my khoan cn chuyn dng. trng hpny, titkim chi ph v d dng cho vic khot v doa sau ny,ta chn phng n khoantrn my khoan chuyn dng.

khong cch gia tm 2 l nm trong min dung sai cho php, ta dng bcdn hng ( bc tho nhanh ) gn trn bn my v c iu chnh kch thc

trc, s dng my khoan cn, lp mi khoan, khoan 2 l, sau thay bc, thay daokhot khot 2 l, sau dung dao doa doa 2 l.Dng bc dn hng s lm tng nng sut gia cng v ta d dch chuyn dao

ng v tr, m bo kch thc cn t nm trong min dung sai cho php.c.Tin trnh gia cng:

Khoan l 18 t cp chnh xc 13, bng b mt: Rz=100(m)Khot tinh l 18 t cp chnh xc 11 bng b mt Rz=40(m)Doa tinh l 18 t cp chnh xc 6 bng b mt 2.5(m)

d. nh v:

Yu cu nh v sao cho xc nh c v tr tm l so vi cc b mt chun.B mt (2) nh v bng phim t khng ch 3 bc t do (Toz, Qox, Qoy)Khi V c nh khng ch 2 bc t do (Toy, Tox)Khi V di ng khng ch 1 bc t do( Qoz)

e. Chn my:My khoan cn 2H55c tnh k thut:ng knh l ln nht c th gia cng c: 50(mm)Khong cch t tm trc chnh ti tr my: 4101600(mm)

Khong cch t mt trc chnh ti bn my: 450-1600(mm)Kch thc b mt lm vic ca bn my: 968 1650 (mm) cn trc chnh moc: N 0 5Dch chuyn ln nht ca trc chnh: 350 (mm)


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S cp tc trc chnh: 21Phm vi tc trc chnh: 20-2000S cp bc tin trc chnh: 12Phm vi bc tin: 0, 056-2, 5Dch chuyn ngang ln nht u khoan: 1200 (mm)

Dch chuyn ng ln nht ca cn: 800 (mm)Gc quay ln nht xung quanh trc thng ng: 360 0 Cng sut ng c chnh: 4(kW)Cng sut ng c nng cn: 2, 2 (kW)Khi lng my: 4100 (kg)Kch thc ph b:di: 2530 (mm)

rng; 1000 (mm)cao: 3320 (mm)

f. Chn dng c ct:Mi khoan rut g thp gi: ( [2] bng 4.40 trang 320)ng knh mi khoan: d=17(mm)Chiu di mi khoan: L = 180 (mm)Chiu di phn lm vic: l = 100 (mm)Thng s hnh hc ca mi khoan: ( [2],bng 4.44 trang 330)Gc sau = 11

0

Gc nghing mp ngang: 0

= 500

Mi khot c gn mnh hp kim cng: ( [2],bng 4.47 trang 332)ng knh ca mi khot: d = 17,85 (mm)Chiu di mi khot: L = 180(mm)Chiu di phn lm vic: l = 85(mm)Thng s hnh hc ca mi khot: ( [2],bng 4.48 trang 335)Gc sau: = 10

0

Gc sau cn li: 1=200

Gc nghing ca li ct dng c: = 00Gc trc = 30Mi doa co gn hp kim cng: ([2], bng 4.49 trang 336)ng knh ca mi doa: d =18 (mm)Chiu di mi doa: 180 (mm)Chiu di phn lm vic: l = 16 (mm)Thng s hnh hc ca mi doa: ([2], bng 4.52 trang 340)Gc sau: = 150

Gc sau cn li: 1=250

Gc trc: = 30g. Dng c kim tra:

thc kph. Dung dch trn ngui:

Khan


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Nguyn Cng 4: phay mt (4) v (14):a.S g t:


b. Phng php gia cng:Yu cu Rz40 ca b mt gia cng nn ta ch cn phay th v sau phay tinh

bng dao phay mt u l t yu cu.

c.Tin trnh gia cng:Phay th b mt (4),(14), cp chnh xc 12-14 , nhm b mt Rz 25-50Phay tinh b mt (4),(14) vi cp chnh xc 12-14 , nhm b mt Rz 40

d. nh v:nh v mt (1) bngphim t khng ch 3 bc t do (Toz, Qox, Qoy)nh v l (2) bng chttr ngn khng ch 2 bc t do ( Tox, Toy)nh v l (16) bng chttrm khng ch 1 bc t do (Qoz)Kp cht: S dng c cu kp cht bng ren vt. im c lc ti im thp nht

ca mt l. Hng lc kp t trn xung.e. Chn my:

Ta chn my phay 6H12, thng s ca my xem nguyn cng 1.f. Dng c ct:

S dng dao phay mt u gn mnh hp kim cng BK6 ([2]bng 4-95 trang376)

Kch thc dao:ng knh ngoi ca dao: D=160(mm)Chiu dy ca dao: B= 60 (mm)ng knh trong ca dao: d=50 (mm)S rng 10

g. Dng c kim tra:thc kp.

h. Dung dch trn ngui:


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khan.

Nguyn Cng 5: phay mt (8), (10):a.S g t:


b. Phng php gia cng:Yu cu Rz40 ca b mt gia cng nn ta cn phay th v phay tinh bng dao

phay a ba mt l t yu cu.c.Tin trnh gia cng:

Phay th b mt (8),(10), cp chnh xc 12-14 , nhm b mt Rz 25-50Phay tinh b mt (8),(10) vi cp chnh xc 12-14 , nhm b mt Rz 40d. nh v:

nh v mt (1) bngphim t khng ch 3 bc t do (Toz, Qox, Qoy)nh v l (2) bng chttr ngn khng ch 2 bc t do ( Tox, Toy)nh v l (16) bng cht trm khng ch 1 bc t do (Qoz)Kp cht: S dng c cu kp cht bng ren vt. im c lc ti im thp nht


Ta chn my phay 6H12, thng s ca my xem nguyn cng 1.f. Dng c ct:

S dng dao phay a ba mt rng thp gi([2]bng 4-84 trang 369)Kch thc dao:ng knh ngoi ca dao: D=80(mm)Chiu dy ca dao: B=25 (mm)ng knh trong ca dao: d=27 (mm)S rng : 10


h. Dung dch trn ngui:khan.


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Nguyn Cng 6: phay mt (5), (13) (phay hai l trn):a.S g t:


b. Phng php gia cng:Dng my phay c c so dao xc nh chnh xc v tr dng ca dao. Sau khi

phay xong mt (5), ta cho dao tin ti tip tc phay mt (13), khi n c hnh trnhl xong.

Yu cu Rz40 ca b mt gia cng nn ta cn phay th v phay tinh bng daophay a ba mt l t yu cu.c.Tin trnh gia cng:

Phay th b mt (5),(13), cp chnh xc 12-14 , nhm b mt Rz 25-50Phay tinh b mt (5),(13) vi cp chnh xc 12-14 , nhm b mt Rz 40

d. nh v:nh v mt (1) bngphim t khng ch 3 bc t do (Toz, Qox, Qoy)nh v l (2) bng chttr ngn khng ch 2 bc t do ( Tox, Toy)nh v l (16) bng cht trm khng ch 1 bc t do (Qoz)Kp cht: S dng c cu kp cht bng ren vt. im c lc ti im thp nht


Ta chn my phay 6H12, thng s ca my xem nguyn cng 1.f. Dngc ct:

S dng dao phay ngn chui tr c li ct bng thp gi ([2]bng 4-65 trang356)

Kch thc dao:ng knh ngoi ca dao: d=18(mm)Chiu dy ca dao: L=92 (mm)

ng knh trong ca dao: l=32 (mm)S rng 6g. Dngc kim tra:

thc kp.


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h. Dung dch trn ngui:khan.

Nguyn cng 7: Vt mp b mt (6) v (12).a.S g t:


b.Phng n gia cng:S dng dao phay c gc nghing 45 0 , sau khi phay xong b mt (12) th chuyn

dao phay mt (6), dng c hnh trnh gii hn v tr.B mt ny c yu cu v nhm Rz40 ta ch cn phay th l t yu cu

c.Tin trnh gia cng:Phay th b mt (6),(12), cp chnh xc 12-14 , nhm b mt Rz 25-50Phay tinh b mt (6),(12) vi cp chnh xc 12-14 , nhm b mt Rz 40


ca mt l. Hng lc kp t trn xung.e.Chn my:

S dng my phay 6H12Thng s my cho nguyn cng 2.

f.Dng c ct:S dng dao phay gc c kch thc: ([2], Bng 4.88 trang 373)D = 50 (mm)

B = 10 (mm)

= 45o

g.Dng c kim tra:

Thc kp.h.Dung dch trn ngui:

khan.


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Nguyn Cng 8: phay mt (17) v (20).a. S g t:


b. Phng n gia cng:Phay mt phng bng dao phay gc. Vi bng v cp chnh xc yu cu l

IT12, zR 40. Ta thc hin qua 2 bc nguyn cng phay th v phay tinh.c.Tin trnh gia cng:

Phay th b mt (17),(20), cp chnh xc 12-14 , nhm b mt Rz 25-50Phay tinh b mt (17),(20) vi cp chnh xc 11 , nhm b mt Rz 40



chn my phay 6H12 thng s ca my ging nguyn cng 1f. Dng c ct:

Ta s dng dao phay gc c cc thng s k sau:ng knh vng ngoi: D = 40mmng knh vng trong: d = 16 mm

b rng dao: B =10 mm


18/44

gc dao: g. Dng c kim tra:

thc kp.h. Dung dch trn ngui:

khan.

Nguyn cng 9 v nguyn cng 10: Khoan + tar ren 2 l:

a.S g t:

Hnh 1.14 S nguyn cng 10,11

b.Phng n gia cng: giacng 2 l ren (10) v (11), ta s dng phng php khoan trn my khoan

chuyn dng.

khong cch gia tm 2 l nm trong min dung sai cho php , ta dng bcdn hng ( bc tho nhanh ) gn trn bn my v c iu chnh kch thctrc, s dng my khoan cn, lp mi khoan, khoan 2 l, sau tin hnh tar ren.

Dng bc dn hng s lm tng nng sut gia cng v ta d dch chuyn daong v tr, m bo kch thc cn t nm trong min dung sai cho php.c.Tin trnh gia cng:

Khoan l 12 t cp chnh xc 12 - 14, bng b mt: Rz=50(m)Tar l 12 t yu cu.

d. nh v:

nh v mt (1) bngphim t khng ch 3 bc t do (Toz, Qox, Qoy)nh v l (2) bng chttr ngn khng ch 2 bc t do ( Tox, Toy)nh v l (16) bng cht trm khng ch 1 bc t do (Qoz)Kp cht: S dng c cu kp cht bng ren vt. im c lc ti im thp nht

ca mt l. Hng lc kp t trn xung.S dng u kp c dng tr nn n cng c tc dng nh v , nn khi kp ta vn

tt vo chitit nh v sau mi kp cht.u kp l u nhm v b mt nh v 9 cha gia cng.

e.Chn my:

Kch thc l gia cng 12.Chiu su l gia cng 27 (mm).Chn my khoan cn 2H55 c cc thng scho nguyn cng 3.


19/44

f.Dng c ct:Mi khoan rut g thp gi, chn c D = 11 (mm)([2]bng 4-40 trang 319)Mi ta r chn c D=12(mm) ([2]bng 4-136 trang 424)

g.Dng c kim tra:Thc kp:

h.Dung dch trn ngui:khan. Nguyn Cng 11: phay mt (18) v (19).a. S g t:


b. Phng n gia cng: c th thc hin c nguyn cng ny, ta c th s dng phng php tin

hoc phay. Nu s dng phng php tin s mt thi gian g chi tit ln mm cp,cn chnh dao hn so vi phng php phay nn hiu qu v nng sut v kinh tca tin s khng bng phay, do m ta quyt nh chn phng n phay.c.Tin trnh gia cng:

Phay th b mt (18),(19), cp chnh xc 12-14 , nhm b mt Rz 25-50Phay tinh b mt (18),(19) vi cp chnh xc 11 , nhm b mt Rz 40d. nh v:nh v mt (1) bngphim t khng ch 3 bc t do (Toz, Qox, Qoy)nh v l (2) bng chttr ngn khng ch 2 bc t do ( Tox, Toy)nh v l (16) bng cht trm khng ch 1 bc t do (Qoz)Kp cht: S dng c cu kp chtbng ren vt. im c lc ti im thp nht


chn my phay 6H12 thng s ca my ging nguyn cng 1f. Dng c ct:

Ta s dng dao phay gc c cc thng s k sau:ng knh vng ngoi: D = 63mmng knh vng trong: d = 22 mm


20/44

b rng dao: B =12 mmgc dao:


h. Dung dch trn ngui:

khan.

Nguyn cng 12: Khot + doa b mt (9)a S g t:


b Phng n gia cng: gia cng c b mt s (9), ta c th s dng phng php tin nhng skh khan trong vic g t chi tit v t ng t kch thc. do vy m ta s chn

phng php khot v sau l doa c th t c yu cuca l.Khi s dng phng php khot, doa th buc ta phi s dng c na trn ca chi

tit tin hnh gia cng.c.Tin trnh gia cng:

Khot th b mt (9), t cp chnh xc 12-15 , nhm b mt Rz 50-100Khot tinh b mt (9), t cp chnh xc 8-9 , nhm b mt Rz 12.5-25Doa tinh b mt (9), t cp chnh xc 7, nhm b mt Rz 6.3-12.5Doa mng b mt (9), t cp chnh xc 6, nhm b mt 2.5

d. nh v:nh v mt (1) bngphim t khng ch 3 bc t do (Toz, Qox, Qoy)nh v l (2) bng chttr ngn khng ch 2 bc t do ( Tox, Toy)nh v l (16) bng cht trm khng ch 1 bc t do (Qoz)Kp cht: S dng c cu kp cht bng ren vt. im c lc ti b mt s (3)

v (15). Hng lc kp t trn xung.S dng c cu kp cht bng ren vt. V va n gin va m bo lc kp.Lc kp vung gc vi b mt nh v nn lc kp l tt nht.

e.Chn my:My doa ngang 2620B, cc thng s nh sau:ng knh trc chnh: 90(mm)


21/44

cn kp dng c: moc N 0 -5Kch thc b mt lm vic bn my: 1120 1300 (mm)Khi lng ln nht ca chi tit c gia cng: 2000(kg)Khong cch t ng tm trc chnh ti b mt hoc b: 01000(mm)Dch chuyn ngang ln nht ca bn my hoc tr trc: 1000 (mm)

Dch chuyn dc ln nht ca bn my hoc tr trc: 1090 (mm)Dch chuyn thng ng ln nht ca trc chnh: 1090 (mm)Dch chuyn dc ln nht ca trc chnh: 710 (mm)Dch chuyn ln nht ca bn dao hng tm ca mm cp: 170 (mm)S cp bc tin dc trc chnh,bc tin dc, ngang ca bn v tr ng, trc

chnh: 30

Phm vi bc tin trc chnh: 2, 21760 (mm/ph)Bc tin ca bn, tr ng v trc chnh sau mt vng quay trc chnh: 1, 4

1100 (mm)

Bc tin ca bn, tr ng v trc chnh sau mt vng quay mm cp: 1, 4

1100 (mm)

S cp tc trc chnh: 23Phm vi tc trc chnh: 12, 52000 (vg/ph)Phm vi tc mm cp: 8200Cng sut ng c chnh: 10 (KW)Khi lng my: 12500 (kg)Kch thc ph b my: Di: 5700 (mm)Rng: 3200(mm)Cao: 3000 (mm)

fDng c ct:Mi khot thp hp kim cng ([2]bng 4-47 trang 332)Mi doa c gn mnh hp kim cng ([2]bng 4-49 trang 336)ng knh mi doa: D=60 (mm)Chiu di mi doa: L=100 (mm)Chiu di phn lm vic: l=50(mm)Gc ca dao: Gc trc 00 Gc sau: 06

Gc nghing: 03

g Dng c kim tra:Thc kp.

h Dung dch trn ngui:Khan.

V) XC NH LNG D GIA CNG V KCH THC TRUNG GIAN1. Xc nh lng d v kch thc trung gian bng phng php phn tch-Phng php ny tnh cho 1mt, cc mt khc tra bng.-Chn mt lm vic R30+0,030,cp chnh xc : H7 Ra=2,5

+ Gia cng b mt i xng:

min2. 2 ( )b za a bZ R h

a b c th cng theo vect khi bit phng chiu


22/44

V cng theo xc sut khicha bit phng chiu.2 2

a b a b

2 2

min2. 2 ( )b za a bZ R h

Trong : minbZ : lng d b nht ca bc cng ngh th i

zaR : nhm do bc trc li.

aT : chiusu lp bin cng bc trc li.

a : sai s khng gian bc trc li.

b : sai s g t phi.+ Vt liu: GX 15-32+ Chiu di danh ngha: 50 mm+ Kch thc ln nht ca chi tit : 200 mm

- Trnh t cc bc gia cng:

Phi c : + Cp chnh xc phi : II+ Rz0 = 80 m , IT 15+ Rz0 + h0 = 500 m (Bng 3-66 trang 235 s tay 3)

1-Khot th : + IT 11 (Bng 3-87 trang 244 s tay 3)+ Rz1 = h1 = 50 m

2-Khot tinh: + IT 10

+ Rz2 = h2 = 40 m

3- Doa thng : + IT 10+ Ra = 2,5 m (Rz3 = h3 = 10 m )

Sai lch khng gian ca l c :2 2

0 cv vt

Vi :cv

: sai s cng vnh ca phi

vt : sai s v tr tng quan gia mt gia cngv mt chun nhv.

Bng 3-67 trang 236 s tay 3: . 1.200 200cv k L m 2 2

vt ch x

Cc s liu sau:Sai lch kch thc gia phi vi chi tit gia cng:

1.2 1200ch mm m

xin ca l:(3 10). (3 10).50 300x l m

2 21200 300 1237vt m

Vi : L : chiu di ln nht ca chi tit2 2

0 200 (1237) 1253 m

Sai s g t :222

dgkcgd

Vi c : Sai s chun

k : Sai s kp cht


23/44

dg : Sai s g

V chun nh v trng vi chun kch thc nn 0c Sai s kp cht khi hng lc kp thng gc vi mt gia cng:

100k m ([5] trang 38)

B qua sai s g : 0dg m

Vy 100gd m

Sai lch khng gian sau khi khot th:1 00, 06. 0, 06.1253 75, 18 75 m

(cng ngh ctm trang 76)Sai lch khng gian sau khi khot tinh khng cn

2 10, 05. 0, 05.75,18 3, 759 4 m

Lung d gia cng:

Zmini=

2 2

1 1 i-1i i iRz h

Lng d cho bc khot th

Zmin1= 2 20 0 0 1Rz h = 2 2500 1253 100 1757( )m

Lng d cho bc khot tinh:

Zmin2= 2 21 1 1 2Rz h = 2 250 50 75 100 225 m

Lng d cho bc doa tinh:

Zmin3= 2 22 2 2 3Rz h = 2 240 40 4 100 180 m

-Kch thc trung gian:Kch thc ln nht ca chi tit:

Rmax3=30+0,030=30,03 (mm)Kch thc trung gian ln nht ca phi trc khi doa tinh:

Rmax2=Rmax3-Zmin3= 30,030- 0,180 = 29,85 (mm)Kch thc trung gian ln nht ca phi trc khi khot tinh:Rmax1=Rmax2-Zmin2= 29,850,225 = 29,625 (mm)

Kch thc trung gian ln nht ca phi trc khi khot th :Rmax0 = Rmax1-Zmin1 = 29,6251,757 = 27,868 (mm)

-Dung sai kch thc trung gian :+ Dung sai phi : 0= 0,84 (mm) ( IT15) (Bng 3-91,trang 248 s tay 3)+ Dung sai kch thc sau bc khot th : 1 = 0,13 (mm) ( IT11)+ Dung sai kch thc sau bc khot tinh : 2 = 0,084 (mm) ( IT10)

+ Dung sai kch thc sau bc doa thng : 3 = 0,030 (mm) ( H7)-Quy trn cc kch thc tnh ton trn v tnh kch thc nh nht:Rmax0 = 27,868(mm) Rmin0 = Rmax00 = 27,868 0,840 = 27,028(mm)

Rmax1 = 29,625(mm) Rmin1 = Rmax11 = 29,625 0,130 = 29,495(mm)


24/44

Rmax2 = 29,850(mm) Rmin2 = Rmax22 = 29,850 0,084 = 29,766(mm)

Rmax3 = 30,030(mm) Rmin3 = Rmax33 = 30,030 0,030 = 30 (mm)

_ Lng d trung gian b nht v ln nht ca cc bc :+ Bc khot th :

Zmin1 = Rmax1 Rmax0 = 29,625 27,868 = 1,757 mm

Zmax1 = Rmin1 Rmin0 = 29,495 27,028 = 2,467 mm+ Bc khot tinh :

Zmin2 = Rmax2 Rmax1 = 29,850 29,625 = 0,225 mm

Zmax2 = Rmin2 Rmin1 = 29,766 29,495 = 0,271 mm

+ Bcdoa thng :Zmin3 = Rmax3 Rmax2 = 30,030 29,850 = 0,18 mm

Zmax3 = Rmin3 Rmin2 = 30 29,766 = 0,234 mm

_ Lng d tng cng b v ln nht :

Z0min

=3

min1 ii

Z

= 1,757 0,225 0,18 = 2,162 mm

Z0max =3

max

1

i

i

Z

= 2,467 0,271 0,234 = 2,972 mm

_ Th kt qu :Z0max-Z0min = 2,972 2,162 = 0,810 mm

ph ct = 0,840 0,030 = 0,810 mm

_ Lng d tng cng danh ngha :Z0= Z0min ESph ESct

= 2,162 0,5 0,030 = 2,632 mm

Kch thc danh ngha ca phi :R0 = RctZ0 = 30 2,632 = 27,368 mm

Kch thc ghi trn bn v phi :Dph =

0,4227,37 mm


25/44

* Bng tng kt:Trnh t gia

cng l32+0,13

Cc yu t to thnhlng d

Lng dtnh

tonZmini (

m )

Kch

tctnh

ton(mm)

Dun

g saii

(mm

)

Kch thcgii hn

(mm)

Lng dgii hn

(mm)

Rzi Ti i i Rmini Rmaxi Zmini Zmaxi

0. Phi c 500 1253

27,87 0,84 27,0

3

27,87

1. Khot th 50 50 75 100 1757 29,62 0,13 29,50

29,62 1,76 2,47

2. Khot

tinh

40 40 4 100 225 29,85 0,08

4

29,7

7

29,85 0,22 0,27

3. Doa tinh 10 10 0 100 180 30,03 0,03 30 30,03 0,18 0,23Tng cng 2,16

2

2,972

2.Xc nh lng d trung gian bng phng php tra bng:Nguyn cng I:Sau khi c: 4,5 mm ([1] bng 3.95 trang 252)Phay th: 3,5 mm

Phay tinh: 1 mm Dung sai: +0,3 ([1) bng 3.142 trang 282)Nguyn cng II:Sau khi c: 3 mm ([1] bng 3.95 trang 252)Phay th: 2 mm

Phay tinh: 1mm Dung sai: +0,3 ([1) bng 3.142 trang 282)Nguyn cng III:Khoan: 1 mm

Khot: 0,15 mm

Nguyn cng IV:Sau c: 3,5 mm ([1] bng 3.95 trang 252)Phay th: 2,5 mmPhay tinh: 1 mm Dung sai: + 0,3 ([1) bng 3.142 trang 282)Nguyn cng VIII:Sau khi c: 3 mm ([1] bng 3.95 trang 252)Phay th: 2mm

Phay tinh: 1 mm Dung sai: +0,3 ([1) bng 3.142 trang 282)


26/44

VI) TNH CH CT CHO CC NGUYN CNG:

Nguyn cng1: phay mt y ( b mt 1)

n S

Chn my 6H12, b rng gia cng B = 40mm dao phay mt u,12rng gn hp kimcng BK6, D =200mm, B=60 mm, d=50mm, khng dung dch trn ngui.Phay th:

Chiu su ct:t = 3,5 mm

Lng chy dao:Sz = 0,140.24 => chn Sz=0,2mm (bng 5-33 trang 29, s tay CNCTM 2)

Do B>30mm => Sz=0,2 - 0,2*30% = 0,14 mm

=>S = Sz*12 = 1,68mm/vngTa c:

Tra bng 5-39, tr.32 s tay CNCTM tp 2, ta c:Cv = 445 x = 0,15 u = 0,2 p = 0

m = 0,32 y = 0,35 q = 0,2

Kv = Kmv.Knv.Kuv

( )

()

Kuv = 1 (bng 5.6, trang 8, s tay CNCTM tp 2)Knv= 0,8 (bng 5.5, trang 8, s tay CNCTM tp 2)=> Kv = 0,8

T = 240 pht (bng 5.40, trang 34, s tay CNCTM tp 2)


27/44

Theo my chn n=240 v/ph

Trong : Z- s rng dao phay

n- s vngquay ca dao,(v/p)C p v cc s m tra bng 5.41 trang 34 (s tay CNCTM tp 2)

Tha mn yu cu v chn my.

Phay tinh:

Chiu su ct: t =1mmLng chy dao:S = 0,51,0 => chn S = 0,8mm/vng (bng 5-37 trang 31, s tay CNCTM tp 2)

Do B>30mm => S=0,8 - 0,8*30% = 0,56 mm=>Sz =S/12 = 0,0467 (mm/rng)

Ta c:


m = 0,32 y = 0,35 q = 0,2

Kv = Kmv.Knv.Kuv

( )

()

Kuv = 1 (bng 5.6, trang 8, s tay CNCTM tp 2)Knv = 0,8 (bng 5.5, trang 8, s tay CNCTM tp 2)=> Kv = 0,8


Theo my chn n = 400 v/ph


28/44

Nguyn cng 2:phay 2 mt bc ( b mt 3 v 15)

S

n

Chn my 6H12,b rng gia cng B = 32mm dao phay agn thp gi P6M5, khngdung dch trn ngui.

D=200 mm

B=40 mm

d =50 mm

Z =16 rngPhay th:Chiu su ct:

t =2mmLng chy dao:S = 0,20,4 mm/vng, chn S

z=0,2mm (bng 5-34 trang 29 s tay CNCTM tp 2)

Do B>30mm => Sz=0,2 - 0,2*30% = 0,14 mm

chn S = 2mm/vngTa c:

Tra bng 5.39, tr.32 s tay CNCTM tp 2, ta c:Cv = 85 x = 0,5 u = 0,1 p = 0,1


29/44

m = 0,15 y = 0,4 q = 0,2

Kv = Kmv.Knv.Kuv

( )

()

Kuv = 1 (trang 8,bng 5.6, s tay CNCTM tp 2)Knv = 0,8 (trang 8,bng 5.5, s tay CNCTM tp 2)=> Kv = 0,8T = 180 pht ( trang 34,bng 5.40,s tay CNCTM tp 2)

n =1000. V /D = 119,2 (v/ph)

Theo my chn n = 120 (v/p)


n- s vng quay ca dao,(v/p)C p v cc s m tra bng 5.41 trang 34 (s tay CNCTM tp 2)

Tha mn yu cu v chn my.Phay tinh:Chiu su ct:

t=1mm

Lng chy dao:S=1,22,7 => chn S =1,2mm/vng (bng 5.37, trang 31, s tay CNCTM tp 2)=>Sz =S/Z = 0,075 (mm/rng)

Ta c:


m = 0,15 y = 0,4 q = 0,2

Kv = Kmv.Knv.Kuv

( )

()

Kuv = 1 (trang 8,bng 5.6, s tay CNCTM tp 2)

Knv = 0,8 (trang 8,bng 5.5, s tay CNCTM tp 2)=> Kv = 0,8T = 180 pht ( trang 34,bng 5.40,s tay CNCTM tp 2)


30/44

n = 1000.V /D = 216,45 (v/ph)Theo my chn: n = 235 (v/ph)

Nguyn cng 3 : Khoan- khot-doa tinh 2 l ( b mt 2 v 16).S g t:

n

n

Chn my khoan cn: 2H55Khoan:

Dng mi khoan rut g thp gi P6M5, c D = 17mm, khng dung dch trnngui.Chiu su ct:t =0,5D = 8,5 mm

Lng chy dao:S = 0,410,47 ,chn S = 0,45 mm/vng (bng 5.25 trang 2, s tay CNCTM tp 2)Ta c:

Tra bng 5.28, tr.23 , s tay CNCTM tp 2, ta c:Cv = 17,1 y = 0,4 q = 0,25 m = 0,125Kv = Kmv.Klv.Kuv


31/44

( )

()

Kuv = 1 (bng 5.6, trang 8, s tay CNCTM tp 2)Klv = 1 (bng 5.31, trang 24, s tay CNCTM tp 2)=> Kv = 1

T = 60 pht (bng 5.30, trang 24, s tayCNCTM tp 2)

n = 1000.V /D = 536,45 (v/ph)Chn theo my n = 600 (v/ph)

Khot :

Dng mi khot D = 17,85 mm, bng hp kim BK8 chui cn, khng dung dchtrn ngui.Chiu su ct:t = 0,5(D - d) = 0,425 (mm)

Lng chy dao:S = 0,91.1 =>chn S = 1( mm/vng(bng 5.26 trang 2, s tay CNCTM tp 2)Ta c:

Tra bng 5.29, tr.23 , s tay CNCTM tp 2, ta c:Cv = 105,0 q = 0,4 x = 0,15 y = 0,45 m = 0,4Kv = Kmv.Klv.Kuv

( )

()

Kuv = 0,83 (bng5.6, trang 8, s tay CNCTM tp 2)Klv = 1 (bng5.31, trang 24, s tay CNCTM tp 2)=> Kv = 0,83


n = 1000.V /D = 1435,5 (v/ph)

Chn theo my n =1500 (v/ph)

Doa tinh :

Dng mi doa D = 18 mm, bnghp kim cng BK8, khng dung dch trn ngui.Chiu su ct:t = 0,5(D - d) = 0,075 (mm)Lng chy dao:S = 2,6 ( mm/vng)(bng 5.27 trang 2, s tay CNCTM tp 2)


32/44

Ta c:

Tra bng 5.29, tr.23 , s tay CNCTM tp 2, ta c:Cv = 109 q = 0,2 x = 0 y = 0,5 m = 0,45

Kv = Kmv.Klv.Kuv

( )

()

Kuv = 0,83 (bng5.6, trang 8, s tay CNCTM tp 2)Klv = 1 (bng5.31, trang 24, s tay CNCTM tp 2)=> Kv = 0,83

T = 60 pht (bng5.30, trang 24, s tay CNCTM tp 2)

n = 1000.V /

D = 279,4 (v/ph)Chn theo my n = 275 (v/ph)

Nguyn cng 4: phay mt 4 v 14

S

Chn my phay 6H12, b rng gia cng B = 50 (mm)dao phay mt u gn hp kim BK6,khng dung dich trn ngui.Kch thc dao: ng knh ngoi ca dao: D=160(mm)

Chiu dy ca dao: B= 60 (mm)ng knh trong ca dao: d=50 (mm)S rng 10

Chiu su ct:t = 2,5 mm

Lng chy dao:Sz = 0,140.24 => chn Sz=0,2mm (bng 5-33 trang 29, s tay CNCTM 2)


33/44

Do B>30mm => Sz=0,2 - 0,2*30% = 0,14 mm

=>S = Sz*10 = 1,4mm/vngTa c:


m = 0,32 y = 0,35 q = 0,2

Kv = Kmv.Knv.Kuv

( )

()

Kuv= 1 (bng 5.6, trang 8, s tay CNCTM tp 2)Knv= 0,8 (bng 5.5, trang 8, s tay CNCTM tp 2)=> K

v= 0,8


Theo my chn n=290 v/ph




Phay tinh:

Chiu su ct: t =1mmLng chy dao:S = 0,51,0 => chn S = 0,8mm/vng (bng 5-37 trang 31, s tay CNCTM tp 2)

Do B>30mm => S=0,8 - 0,8*30% = 0,56 mm=>Sz =S/10 = 0,056 (mm/rng)

Ta c:


34/44


m = 0,32 y = 0,35 q = 0,2

Kv = Kmv.Knv.Kuv

(

)

(

)

Kuv= 1 (bng 5.6, trang 8, s tay CNCTM tp 2)Knv= 0,8 (bng 5.5, trang 8, s tay CNCTM tp 2)=> Kv = 0,8


Theo my chn n = 575 v/ph

Nguyn cng 5:phay 2 bmt (8), (10)Chn my phay vn nng 6H12,b rng gia cng B = 15mm dao phay agn thp giP6M5, khng dung dch trn ngui.

D=160 mm

B=25 mm

d=40 mm

Z=16 rng

Phay th:Chiu su ct:

t =2mm

Lng chy dao:S = 0,20,4 mm/vng, chn S

z=0,2mm (bng 5-34 trang 29 s tay CNCTM tp 2)

chn S = 2mm/vngTa c:


m = 0,15 y = 0,4 q = 0,2

Kv = Kmv.Knv.Kuv

( )

()

Kuv = 1 (trang 8,bng 5.6, s tay CNCTM tp 2)Knv = 0,8 (trang 8,bng 5.5, s tay CNCTM tp 2)=> Kv = 0,8

T = 150 pht ( trang 34,bng 5.40,s tay CNCTM tp 2) n =1000. V /D = 137,1 (v/ph)


35/44

Theo my chn n = 130 (v/p)



Tha mn yu cu v chn my.Ta phay th thm 1 ln na nh trn. Phay tinh:Chiu su ct:

t=1mm

Lng chy dao:S=1,22,7 => chn S = 2,5mm/vng (bng5.37, trang 31, s tay CNCTM tp 2)=>Sz =S/Z = 0,156 (mm/rng)

Ta c:


m = 0,15 y = 0,4 q = 0,2

Kv = Kmv.Knv.Kuv

( )

()

Kuv = 1 (trang 8,bng 5.6, s tay CNCTM tp 2)Knv = 0,8 (trang 8,bng 5.5, s tay CNCTM tp 2)=> Kv = 0,8T = 150 pht ( trang 34,bng 5.40,s tay CNCTM tp 2)

n = 1000.V /D = 267,5 (v/ph)

Theo my chn: n = 250 (v/ph)

Nguyn Cng 6:phay mt (5), (13) (phay hai l trn) :Chn my phay vn nng 6H12, S dng dao phay ngn chui tr c li ct bng thpgi (bng 4-65 trang 356, s tay CNCTM tp 1)


36/44

Kch thc dao:ng knh ngoi ca dao: d=16(mm)Chiu dy ca dao: L=92 (mm)ng knh trong ca dao: l=32 (mm)S rng 5Phay th:

Chiu su ct:t = 4mm

Lng chy dao:S

z= 0,070,04 mm/rng, chn S

z= 0,05mm/rng (bng 5-34 trang 29 s tay CNCTM tp 2)

Ta c:

Tra bng 5.39, tr.32 s tay CNCTM tp 2, ta c:

Cv = 72 x = 0,5 u = 0,3 p = 0,3m = 0,25 y = 0,2 q = 0,7

Kv = Kmv.Knv.Kuv

( )

()


T = 80 pht ( trang 34,bng 5.40,s tay CNCTM tp 2)

n =1000. V /D = 652,5 (v/ph)Theo my chn n = 645 (v/p)

Trong : Z- s rng dao phayn- s vng quay ca dao,(v/p)C p v cc s m tra bng 5.41 trang 34 (s tay CNCTM tp 2)


Phay tinh:

Chiu su ct:t =1mm


37/44

Sz= 0,070,04 mm/rng, chn S

z= 0,05mm/rng (bng 5-35 trang 30 s tay CNCTM tp 2)

Ta c:

Tra bng 5.39, tr.32 s tay CNCTM tp 2, ta c:Cv = 72 x = 0,5 u = 0,1 p = 0,1m = 0,15 y = 0,2 q = 0,2Kv = Kmv.Knv.Kuv

( )

()



n = 1000.V /D = 1305 (v/ph)Theo my chn: n = 1290 (v/ph)

Nguyn cng 7:phay vt mp (b mt 6 v 12).

Chn my 6H12, b rng gia cng B = 2,82mm dao phay gc,bn rng gng mnh hp kimcng, D = 20mm, khng dung dch trn nguiPhay th:

Chiu su ct:t =1,4 mm

Lng chy dao:Sz =0,140,24 => chn Sz=0,15mm(trang 29,bng 5.33, s tay CNCTM tp 2)=> S = Sz.4 = 0,6

Ta c:

Tra bng 5.39, tr.32 stay CNCTM tp 2, ta c:Cv = 445 x = 0,15 u = 0,2 p = 0

m = 0,32 y = 0,35 q = 0,2

Kv = Kmv.Knv.Kuv

( )

()

Kuv = 1 (trang 8,bng 5.6, s tay CNCTM tp 2)Knv = 0,8 (trang 8,bng 5.5, s tay CNCTM tp 2)

=> Kv = 0,8T = 120 pht ( trang 34,bng 5.40,s tay CNCTM tp 2)


38/44


Phay tinh:

Chiu su ct:t = 0,6mm

Lng chy dao:S = 0,51,2 => chn S = 0,75mm/vng (trang 31,bng 5.37, s tay CNCTM tp 2)=> Sz = S/4 = 0,1875 mm/rngTa c:

Tra bng 5.39, tr.32 stay CNCTM tp 2, ta c:Cv = 445 x = 0,15 u = 0,2 p = 0

m = 0,32 y = 0,35 q = 0,2Kv = Kmv.Knv.Kuv

( )

()




Nguyn cng 8 v Nguyn cng 9: Khoan + tar 2 l ( b mt 7 v 11).


39/44

Chn my khoan cn: 2H55Khoan:Dng mi khoan hp kim BK8, c D = 10 mm, khng dung dch trn ngui.

Chiu su ct:t = 0,5D = 5 mm

Lng chy dao:S = 0,310,35 mm/vng ,chn S = 0,35 mm/vng (trang 21,bng 5.25,s tay CNCTM tp 2)Ta c:

Tra bng 5.28, tr.23 s tay CNCTM tp 2, ta c:Cv = 34,2 y = 0,30 q = 0,45 m = 0,20Kv = Kmv.Klv.Kuv

( )

()

Kuv = 0,83 (trang 8,bng 5.6, s tay CNCTM tp 2)Klv = 1 (trang 24,bng 5.31, s tay CNCTM tp 2)=> Kv = 0,83

T = 25 pht (trang 24,bng 5.30, s tay CNCTM tp 2)

n = 1000.V /D = 1833,5 (v/ph)

Chn theo my: n = 2000 (v/ph)

Tar:

Chn my tar ren 2H55

Dng mi tar D =12mm bng thp gi P6M5, c dung dch trn ngui.T bng 5-188 trang 171 s tay CNCTM tp 2 ta c:Kch thc danh ngha ca ren: M12Bc ren: p = 1mm.


40/44

Ta tra c tc ct: V=10 (m/ph).

Chn theo my: n = 254 (vg/pht)

( bng 2.25 trang 111, Hng dn n CNCTM)

Nguyn cng 10: phay mt (17) v (20).Chn myphay 6H12 b rng gia cng B= 50 (mm), dao phay a ba mt rng gn mnhthp gi P6M5 c: D = 200 (mm), B = 40 (mm), d =50 (mm), z=16 (rng), khng dungdch trn ngui.Phay th:Chiu su ct:t = 2mm

Lng chy dao:S = 0,20,4 mm/vng, chn S

z=0,2mm (trang 29,bng 5.34, s tay CNCTM tp 2)

.16 3, 2 /zS S mm vng

chn S = 2 mm/vngTa c:


m = 0,15 y = 0,4 q = 0,2Kv = Kmv.Knv.Kuv

( )

()



n = 1000. V /D = 101,1 (v/ph)

Theo my chn n =120 (v/p)




41/44

Tha mn yu cu v chn my.Phay tinh:Chiu su ct:t =1mm

Lng chy dao:S=1,22,7 => chn S=1,2(mm/vng) (trang 31,bng 5.37, s tay CNCTM tp 2)=>Sz =S/Z = 0,075 (mm/rng)Ta c:

Tra bng 5.39, tr.32 stay CNCTM tp 2, ta c:Cv = 85 x = 0,5 u = 0,1 p = 0,1

m = 0,15 y = 0,4 q = 0,2Kv = Kmv.Knv.Kuv

( )

()



n = 1000. V /D = 211,7 (v/ph)Theo my chn: n = 240 (v/ph)

Nguyn cng 11:phay vt mp (b mt 18 v 19).Chn my 6H12, b rng gia cng B = 4,24 mm dao phay gc, D = 63mm, B =10mm,

d=16mm khng dung dch trn ngui, c 4 rng v vt liu dao l thp gi P6M5Phay th:Chiu su ct:t =2mm

Lng chy dao:Sz =0,20,3 => chn Sz=0,2mm(trang 29,bng 5.33, s tay CNCTM tp 2)=> S = Sz.4 = 0,8

Ta c:

Tra bng 5.39, tr.32 s tay CNCTM tp 2, ta c:Cv = 27 x = 0,5 u = 0,3 p = 0,3m = 0,25 y = 0,6 q = 0,7

Kv = Kmv.Knv.Kuv


42/44

( )

()

Kuv = 1 (trang 8,bng 5.6, s tay CNCTM tp 2)Knv = 1 (trang 8,bng 5.5, s tay CNCTM tp 2)=> Kv = 1


n = 1000.V / .D = 529,5 (v/ph).Chn theo my: n = 480 (v/ph)

Phay tinh:Chiu su ct:t = 2mm

Lng chy dao:S = 12,7 => chn S = 1mm/vng ([3], trang31 bng 5-37)=> Sz = S/4 = 0,25 mm/rngTa c:

vK

pZuB

yz

SxtmT

qD

vC

V

Trabng 5-39, [3], ta c:Cv = 27 x = 0,5 u = 0,3 p = 0,3

m = 0,25 y = 0,6 q = 0,7

Kv = Kmv.Knv.Kuv

( )

()

Kuv = 1 (trang 8,bng 5.6, s tay CNCTM tp 2)Knv = 1 (trang 8,bng 5.5, s tay CNCTM tp 2)=> Kv = 1


n = 1000.V / .D = 859,4 (v/ph).Chn theo my: n = 960 (v/ph)

Nguyn cng 12: khot + doa b mt lm vic ( b mt 9)Khot th:Gia cng trn my doa ngang 2620B


43/44

Dng mi khot D = 59 mm L=40 65 mm, lp mnh hp kim BK8 chui cn, khngdung dch trn ngui.Chiu su ct:

t =0,5(D-d) = 0,5(59-54) = 2,5 (mm)

Lng chy dao:S = 1,82,2 =>chn S = 2( mm/vng) (trang 22,bng 5.26, s tay CNCTM tp 2)

Ta c:

Tra bng 5.29, tr.23 , s tay CNCTM tp 2, ta cCv = 105 q = 0,4 x = 0,15 y = 0,45 m = 0,4

Kv = Kmv.Klv.Kuv

( )

()

K

uv= 0,83 (trang 8,bng 5.6, s tay CNCTM tp 2)

Knv = 1 (trang 24,bng 5.31, s tay CNCTM tp 2)=> Kv = 0,83


n = 1000.V /D = 265,4 (v/ph)

Chn n = 252 (v/ph)

Khot tinh:

Dng mi khot D = 59,85 mm L=40 65 mm, lp mnh hp kim BK8 chui cn,khng dung dch trn ngui.Chiu su ct:

t =0,5(D-d) = 0,5(59,85-59) = 0,425 (mm)

Lng chy dao:S = 1,82,2 =>chn S = 2( mm/vng) (trang 22,bng 5.26, s tay CNCTM tp 2)

Ta c:

Tra bng 5.29, tr.23 , s tay CNCTM tp 2, ta cCv = 105 q = 0,4 x = 0,15 y = 0,45 m = 0,4

Kv = Kmv.Klv.Kuv

( )

()

Kuv = 0,83 (trang 8,bng 5.6, s tay CNCTM tp 2)Knv = 1 (trang 24,bng 5.31, s tay CNCTM tp 2)

=> Kv = 0,83T = 80 pht ( trang 24,bng 5.30,s tay CNCTM tp 2)


44/44

n = 1000.V /D = 413,8 (v/ph)

Chn n = 400 (v/ph)

Doa tinh:Dng mi doa lp ghp c cc li dao rt ngn, gn mnh hp kim cng BK8 c: D =

60 mm, L=50 100 mm, l=50mm, khng dung dch trn ngui.Chiu su ct:

t =0,5(D-d) = 0,5(60-59,85) = 0,075 (mm)

Lng chy dao:S = 4,3.0,8 = 3,44( mm/vng) (trang 22,bng 5.27, s tay CNCTM tp 2)

Ta c:

Tra bng 5.29, tr.23 , s tay CNCTM tp 2, ta c:Cv = 109 q = 0,2 x = 0 y = 0,5 m = 0,45

Kv = Kmv.Klv.Kuv

( )

()

Kuv = 0,83 (trang 8,bng 5.6, s tay CNCTM tp 2)Knv = 1 (trang 24,bng 5.31, s tay CNCTM tp 2)=> Kv = 0,83

T = 165 pht ( trang 24,bng 5.30,s tay CNCTM tp 2) n = 1000.V /D = 399,5 (v/ph)

Chn n = 400 (v/ph)

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