응력검토 샘플
DESCRIPTION
응력검토TRANSCRIPT
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⒜ 단면 제원SM400
B = 0.2000 m H = 0.2000 m= 0.0080 m = 0.0120 m
⒝ 단면 계수6.353000E+03 4.720000E+07 1.600000E+078.620000E+01 5.020000E+01 8.622000E+04
⒞ 작용하중구 분 비 고
100.000 150.000 0.000 0.000 138.000 300.000
⒟ 허용응력 산정①
· 140.000 Mpa
②
· 부재의 유효좌굴길이 == 1.200 × 10000.000 = 12000.000 mm
· 세장비 = 139.211 ≤ 200.000
· 1200000 / (6700+( /r)ℓ = 46.013 Mpa [92.8 < /r]ℓ
· 부재의 유효좌굴길이 == 2.100 × 3000.000 = 6300.000 mm
· 세장비 = 125.498 ≤ 200.000
· 1200000 / (6700+( /r)ℓ = 53.453 Mpa [92.8 < /r]ℓ
· = 46.013 ∙ 140.000 / 140.000 = 46.013 Mpa
③
압축플랜지 고정점간 거리 ℓ = 10000.000 mm
압축플랜지 폭 b = 200.000 mm
사용강종 :tw tf
A (mm2) Iyy (mm4) Izz (mm4)ry (mm) rz (mm) K (mm4)
Fx (kN) Fy (kN) Fz (kN) Mx (kN∙m) My (kN∙m) Mz (kN∙m)
허용휨인장응력 (fta) [도기 P3-10, 표3.3.1]fta =
허용축방향압축응력 (fca) [도기 P3-11, 표3.3.2]- Y 축(강축) : 국부좌굴을 고려하지 않은 허용축방향 압축응력
ℓye Kx × ℓy
ℓye /ry
Fcagz =
- Z 축(약축) : 국부좌굴을 고려하지 않은 허용축방향 압축응력ℓze Ky × ℓy
ℓze /rz
Fcagy =
- 허용 축방향압축응력fca fcag ∙ fcal / fcao. =
허용휨압축응력 (fbagy) [도기 P3-16, 표3.3.4]
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복부판의 총단면적 = 1408.000
압축플랜지 총단면적 = 2400.000
= 0.587 ≤ 2.000 , = ### , = 1.815
140 - 2.49×( /b - 4.6)ℓ = 26.954 Mpa [4.6 < /b ≤ 30.0]ℓ
④ 허용 오일러 좌굴응력= 61.920 Mpa= 76.192 Mpa
⑤
### Mpa
⑥ 허용응력 요약구 분
허용응력 140.000 46.013 26.954 140.000 80.000 175.000 57.516 33.692 175.000 100.000
⒠ 응력 검토 ①②③④⑤⑥
① 축방향력에 의한 응력 = P / A = -24.878 / 3.9011E+03 = -6.377 MPa
② 휨모멘트에 의한 응력= = -2.724 MPa= = 6.745 MPa
③
-6.377 +-2.724
+6.745
( 1 --6.377
) ( 1 --6.377
)1323.814 249.610
= -2.193 MPa ≤ = 140.000 MPa④
-6.377 +
-2.724 +
6.745 98.396
109.954 ( 1 --6.377
) 140.000 ( 1 --6.377
)1323.814 249.610
= -0.040 ≤ 1.000
10) 전단응력에 대한 검토=
Aw mm2
Ac mm2
fbagy =
[도기 P3-47, 식3.4.13~14]fEy = 1200000/(ly/ry)2
fEz = 1200000/(lz/rz)2
허용전단응력 (υa) [도기 P3-18, 표3.3.5]υa =
fta fca fbag fcal υa
가설시 할증(1.25)
fc × 103
fby My × z / Iyy
fbz Mz × y1 / Izz
fcal
υz Fz / Aw + Mx × t / K
w
c
AA
lb
32
w
c
AK
A
11
bcy bczc cal
cc
EzEy
f ff fffff
1.011
bcyc bcz
caz ccbaobagy
EzEy
ff ff ff ff ff
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= 1.268 / 1164.000 + 0.011 × 6.000E+00 / 8.6220E+04= 1.869 MPa ≤ = 80.000 MPa== 0.860 / 1800.000 + 0.011 × 9.000E+00 / 8.6220E+04= 1.648 MPa ≤ = 80.000 MPa
t =
11) 합성응력에 대한 검토= (
-9.469 + (
1.869 = 0.005 < 1.200
140.000 80.000
× 103 × 106
υa
υy Fy / Af + Mx × t / K× 103 × 106
υa
여기서, 복부 두께 .
)2 )22 2
b b
a a
f vf v
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...... OK
...... OK
Mpa
도기 P3-10, 표3.3.1]
도기 P3-11, 표3.3.2]
도기 P3-16, 표3.3.4]
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80.000 100.000
...... OK
...... OK
P3-47, 식3.4.13~14]
P3-18, 표3.3.5]
υa
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8.6220E+04...... OK
8.6220E+04...... OK
...... OK
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SM400= 0.1500 m = 0.1500 m= 0.0720 m = 0.0720 m= 0.0090 m = 0.0090 m= 0.0060 m H = 0.1940 m
3.901071E+03 2.689735E+07 5.071587E+068.303531E+01 3.605620E+01 8.622000E+04
검토위치 -75.0 97.0 75.0 97.0 75.0 -97.0 -75.0 -97.0
구 분 비 고-25.202 0.682 2.274 0.010 -3.558 2.490
1)
구 분 SM400Top Flange 140.000
Bottom Flange 140.000 Left Web 140.000
2)
부재의 유효좌굴길이 = 2500.000 mm부재 총단면의 단면회전반경 = 83.035 mm세장비 = 30.108
부재의 유효좌굴길이 = 2500.000 mm
부재 총단면의 단면회전반경 = 36.056 mm
세장비 = 69.336
▶ 세장비 검토세장비 / rℓ = 69.336 ≤ 120.000 ...... OK
구 분 SM400
Top Flange18.6 < /r ≤ 92.8ℓ
Fcagz = 140 - 0.82×( /r - 18.6) = 98.396ℓ
Bottom Flange18.6 < /r ≤ 92.8ℓ
2.1 단면 제원사용강종 :B1 B2
b1 b2
tf1 tf2
tw
2.2 단면 계수A (mm2) Iyy (mm4) Izz (mm4)ry (mm) rz (mm) K (mm4)
y1 (mm) z1 (mm) y2 (mm) z2 (mm)y3 (mm) z3 (mm) y4 (mm) z4 (mm)
2.3 작용하중Fx (kN) Fy (kN) Fz (kN) Mx (kN∙m) My (kN∙m) Mz (kN∙m)
작동시 교축풍하중(63max)
2.4 응력검토[1] 작동시 교축풍하중(63max)
허용휨인장응력 (fta) [도기 P3-10, 표3.3.1]
40 이하40 이하40 이하
국부좌굴을 고려하지 않은 허용축방향압축응력 (fcag) [도기 P3-11, 표3.3.2] ▶ Y 축에 대한 유효좌굴길이
ℓy
ry
ℓy /ry
▶ Z 축에 대한 유효좌굴길이ℓz
rz
ℓz /rz
40 이하40 이하
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Bottom FlangeFcagz = 140 - 0.82×( /r - 18.6) = 98.396ℓ
Left Web18.6 < /r ≤ 92.8ℓ
Fcagz = 140 - 0.82×( /r - 18.6) = 98.396ℓ
Top Flange18.6 < /r ≤ 92.8ℓ
Fcagy = 140 - 0.82×( /r - 18.6) = 130.564ℓ
Bottom Flange18.6 < /r ≤ 92.8ℓ
Fcagy = 140 - 0.82×( /r - 18.6) = 130.564ℓ
Left Web18.6 < /r ≤ 92.8ℓ
Fcagy = 140 - 0.82×( /r - 18.6) = 130.564ℓ
3) ▶ Top Flange
압축플랜지 고정점간 거리 ℓ = 2500.000 mm압축플랜지 폭 b = 150.000 mm복부판의 총단면적 = 1056.000 압축플랜지 총단면적 = 1350.000
= 0.782 ≤ 2.000 , = ### , = 1.841
구 분 SM400
≤ 2.0 4.6 < /b ≤ 30.0ℓ
140 - 2.49×( /b - 4.6) = 109.954ℓ
▶ Bottom Flange
압축플랜지 고정점간 거리 ℓ = 2500.000 mm
압축플랜지 폭 b = 150.000 mm
복부판의 총단면적 = 1056.000
압축플랜지 총단면적 = 1350.000
= 0.782 ≤ 2.000 , = ### , = 1.841
구 분 SM400
≤ 2.0 4.6 < /b ≤ 30.0ℓ
140 - 2.49×( /b - 4.6) = 109.954ℓ
▶ Left Web압축플랜지 고정점간 거리 ℓ = 2500.000 mm압축플랜지 폭 b = 176.000 mm복부판의 총단면적 = 2700.000 압축플랜지 총단면적 = 1056.000
= 2.557 > 2.000 , = ### , = 2.068
구 분 SM400
> 2.0 9.3/K < /b ≤ 30.0ℓ
140 - 1.24×(K× /b - 9.3) = 115.099ℓ
4) 허용 오일러 좌굴응력1323.814 249.610
40 이하40 이하40 이하40 이하40 이하
허용휨압축응력 (fbagy) [도기 P3-16, 표3.3.4]
Aw mm2
Ac mm2
40 이하
Aw mm2
Ac mm2
40 이하
Aw mm2
Ac mm2
40 이하
[도기 P3-47, 식3.4.13~14]fEy (MPa) 1200000/(ly/ry)2
fEz (MPa) 1200000/(lz/rz)2
w
c
AA
lb
w
c
AA
32
w
c
AK
A
w
c
AA
lb
w
c
AA
32
w
c
AK
A
w
c
AA
lb
w
c
AA
32
w
c
AK
A
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5)
구 분 SM400Top Flange 80.000
Bottom Flange 80.000 Left Web 80.000
6) 자유돌출판의 국부좌굴에 대한 허용응력 ▶ 압축응력을 받는 자유돌출판의 최소두께
Top Flange(L)= b / 16 = 72.0 / 16.0 = 4.500 mm ≤ = 9.000 mm ...... OK
Top Flange(R)= b / 16 = 72.0 / 16.0 = 4.500 mm ≤ = 9.000 mm ...... OK
Bottom Flange(L)= b / 16 = 72.0 / 16.0 = 4.500 mm ≤ = 9.000 mm ...... OK
Bottom Flange(R)= b / 16 = 72.0 / 16.0 = 4.500 mm ≤ = 9.000 mm ...... OK
▶Top Flange(L) t = 9.000 mm
= b / 12.9 = 72.0 / 12.9 = 5.581 mm
구 분 SM400b/12.9 ≤ t140.000
Top Flange(R) t = 9.000 mm= b / 12.9 = 72.0 / 12.9 = 5.581 mm
구 분 SM400b/12.9 ≤ t140.000
Bottom Flange(L) t = 9.000 mm= b / 12.9 = 72.0 / 12.9 = 5.581 mm
구 분 SM400b/12.9 ≤ t140.000
Bottom Flange(R) t = 9.000 mm= b / 12.9 = 72.0 / 12.9 = 5.581 mm
구 분 SM400b/12.9 ≤ t140.000
7) 보강된판 및 양연지지판의 국부좌굴에 대한 허용응력▶ Left Web
판두께 t = 6.0 mm
판의 고정연 사이의 거리 b = 176.0 mm
응력구배계수 i = = 2.243
응력구배 Φ = = 1.286
판의 양연에서의 응력 = -18.102 MPa, = 5.181 MPa
압축응력을 받는 양연지지판의 최소두께t ≤ 40mm
허용전단응력 (υa) [도기 P3-18, 표3.3.5]
40 이하40 이하40 이하
[도기 P3-37]tmin tf
tmin tf
tmin tf
tmin tf
자유돌출판의 국부좌굴에 대한 허용응력 (fcal) [도기 P3-38, 표3.4.4]
t1
40 이하
t1
40 이하
t1
40 이하
t1
40 이하
0.65Φ2 + 0.13Φ + 1.0(f1 - f2) / f1
f1 f2
[도기 P3-35, 표3.4.2]
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= b / 56i = 176 / 125.58 = 1.4 ≤ t = 6.0 mm ...... OK
구 분 SM400b/39.3i ≤ t140.000
8) 허용응력 요약구 분
Top Flange 140.000 98.396 130.564 140.000 80.000 Bottom Flange 140.000 98.396 130.564 140.000 80.000
Left Web 140.000 98.396 130.564 140.000 80.000 =
9) 축방향력 및 휨모멘트를 받는 부재의 허용응력 검토▶ 축방향력에 의한 응력
= P / A = -25.202 / 3.9011E+03 = -6.460 MPa
▶ 휨모멘트에 의한 응력= = 12.832 MPa = = 36.829 MPa= = 12.832 MPa = = -36.829 MPa= = -12.832 MPa = = -36.829 MPa= = -12.832 MPa = = 36.829 MPa
43.200 -30.457 -56.121 17.536
▶ Position 1 (y-direction)
-6.460 +12.832
+36.829
( 1 --6.460
) ( 1 --6.460
)1323.814 249.610
= 44.242 MPa ≤ = 140.000 MPa ...... OK
▶ Position 2 (y-direction)
-6.460 +12.832
+-36.829
( 1 --6.460
) ( 1 --6.460
)1323.814 249.610
= -31.373 MPa ≤ = 140.000 MPa ...... OK
-6.460 +
12.832 +
-36.829
tmin
양연지지판의 국부좌굴에 대한 허용응력 (fcal) [도기 P3-36, 표3.4.3]
40 이하
fcal fcaz fcay fta υa
fca fcag ∙ fcal / fcao.
fc × 103
fby1 My × z1 / Iyy fbz1 Mz × y1 / Izz
fby2 My × z2 / Iyy fbz2 Mz × y2 / Izz
fby3 My × z3 / Iyy fbz3 Mz × y3 / Izz
fby4 My × z4 / Iyy fbz4 Mz × y4 / Izz
f11 (y1, z1) f22 (y2, z2)f33 (y3, z3) f44 (y4, z4)
fta
fcal
11
bcy bczc cal
cc
EzEy
f ff fffff
11
bcy bczc cal
cc
EzEy
f ff fffff
1.011
bcyc bcz
caz ccbaobagy
EzEy
ff ff ff ff
ff
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98.396 +
109.954 ( 1 --6.460
)+
140.000 ( 1 --6.460
)1323.814 249.610
= -0.218 ≤ 1.000 ...... OK
▶ Position 3 (y-direction)
-6.460 +-12.832
+-36.829
( 1 --6.460
) ( 1 --6.460
)1323.814 249.610
= -57.162 MPa ≤ = 140.000 MPa ...... OK
-6.460 +
-12.832 +
-36.829 98.396
109.954 ( 1 --6.460
) 140.000 ( 1 --6.460
)1323.814 249.610
= -0.453 ≤ 1.000 ...... OK
▶ Position 4 (y-direction)
-6.460 +-12.832
+36.829
( 1 --6.460
) ( 1 --6.460
)1323.814 249.610
= 18.452 MPa ≤ = 140.000 MPa ...... OK
▶ Position 1 (z-direction)
-6.460 +36.829
+12.832
( 1 --6.460
) ( 1 --6.460
)249.610 1323.814
= 44.242 MPa ≤ = 140.000 MPa ...... OK
▶ Position 2 (z-direction)
-6.460 +-36.829
+12.832
( 1 --6.460
) ( 1 --6.460
)249.610 1323.814
= -31.373 MPa ≤ = 140.000 MPa ...... OK
fcal
fta
fta
fcal
11
bcy bczc cal
cc
EzEy
f ff fffff
1.011
bcyc bcz
caz ccbaobagy
EzEy
ff ff ff ff
ff
11
bcy bczc cal
cc
EzEy
f ff fffff
1 1
bcybczc cal
c c
Ez Ey
fff ff ff f
1 1
bcybczc cal
c c
Ez Ey
fff ff ff f
1.01 1
bcyc bcz
cay c cbagz bao
Ez Ey
ff ff f ff f
f f
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-6.460 +
-36.829 +
12.832 130.564
115.099 ( 1 --6.460
) 140.000 ( 1 --6.460
)249.610 1323.814
= -0.286 ≤ 1.0 ...... OK
▶ Position 3 (z-direction)
-6.460 +-36.829
+-12.832
( 1 --6.460
) ( 1 --6.460
)249.610 1323.814
= -57.162 MPa ≤ = 140.000 MPa ...... OK
-6.460 +
-36.829 +
-12.832 130.564
115.099 ( 1 --6.460
) 140.000 ( 1 --6.460
)249.610 1323.814
= -0.470 ≤ 1.0 ...... OK
▶ Position 4 (z-direction)
-6.460 +36.829
+-12.832
( 1 --6.460
) ( 1 --6.460
)249.610 1323.814
= 18.452 MPa ≤ = 140.000 MPa ...... OK
10) 전단응력에 대한 검토== 2.274 / 1164.000 + 0.010 × 6.000E+00 / 8.6220E+04= 2.679 MPa ≤ = 80.000 MPa ...... OK== 0.682 / 1800.000 + 0.010 × 9.000E+00 / 8.6220E+04= 1.467 MPa ≤ = 80.000 MPa ...... OK
t =
11) 합성응력에 대한 검토= (
49.661 + (
2.679 = 0.127 < 1.200 ...... OK
140.000 80.000
fcal
fta
υz Fz / Aw + Mx × t / K× 103 × 106
υa
υy Fy / Af + Mx × t / K× 103 × 106
υa
여기서, 복부 두께 .
)2 )2
1.01 1
bcyc bcz
cay c cbagz bao
Ez Ey
ff ff f ff f
f f
1 1
bcybczc cal
c c
Ez Ey
fff ff ff f
1.01 1
bcyc bcz
cay c cbagz bao
Ez Ey
ff ff f ff f
f f
1 1
bcybczc cal
c c
Ez Ey
fff ff ff f
2 2
b b
a a
f vf v
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5.071587E+068.622000E+04
97.0 -97.0
비 고
SM400140.000 140.000 140.000
...... OK
SM40018.6 < /r ≤ 92.8ℓ
Fcagz = 140 - 0.82×( /r - 18.6) = 98.396ℓ
18.6 < /r ≤ 92.8ℓ
도기 P3-10, 표3.3.1]
도기 P3-11, 표3.3.2]
![Page 14: 응력검토 샘플](https://reader033.vdocuments.pub/reader033/viewer/2022061114/545fa8e7b1af9f673b8b4bc4/html5/thumbnails/14.jpg)
Fcagz = 140 - 0.82×( /r - 18.6) = 98.396ℓ
18.6 < /r ≤ 92.8ℓ
Fcagz = 140 - 0.82×( /r - 18.6) = 98.396ℓ
18.6 < /r ≤ 92.8ℓ
Fcagy = 140 - 0.82×( /r - 18.6) = 130.564ℓ
18.6 < /r ≤ 92.8ℓ
Fcagy = 140 - 0.82×( /r - 18.6) = 130.564ℓ
18.6 < /r ≤ 92.8ℓ
Fcagy = 140 - 0.82×( /r - 18.6) = 130.564ℓ
SM4004.6 < /b ≤ 30.0ℓ
140 - 2.49×( /b - 4.6) = 109.954ℓ
SM4004.6 < /b ≤ 30.0ℓ
140 - 2.49×( /b - 4.6) = 109.954ℓ
SM4009.3/K < /b ≤ 30.0ℓ
140 - 1.24×(K× /b - 9.3) = 115.099ℓ
1323.814 249.610
도기 P3-16, 표3.3.4]
P3-47, 식3.4.13~14]
![Page 15: 응력검토 샘플](https://reader033.vdocuments.pub/reader033/viewer/2022061114/545fa8e7b1af9f673b8b4bc4/html5/thumbnails/15.jpg)
SM40080.000 80.000 80.000
...... OK
...... OK
...... OK
...... OK
SM400b/12.9 ≤ t140.000
SM400b/12.9 ≤ t140.000
SM400b/12.9 ≤ t140.000
SM400b/12.9 ≤ t140.000
P3-18, 표3.3.5]
도기 P3-37]
P3-38, 표3.4.4]
도기 P3-35, 표3.4.2]
![Page 16: 응력검토 샘플](https://reader033.vdocuments.pub/reader033/viewer/2022061114/545fa8e7b1af9f673b8b4bc4/html5/thumbnails/16.jpg)
...... OK
SM400b/39.3i ≤ t140.000
80.000 80.000 80.000
-30.457 17.536
...... OK
...... OK
도기 P3-36, 표3.4.3]
υa
![Page 17: 응력검토 샘플](https://reader033.vdocuments.pub/reader033/viewer/2022061114/545fa8e7b1af9f673b8b4bc4/html5/thumbnails/17.jpg)
...... OK
...... OK
...... OK
...... OK
...... OK
...... OK
![Page 18: 응력검토 샘플](https://reader033.vdocuments.pub/reader033/viewer/2022061114/545fa8e7b1af9f673b8b4bc4/html5/thumbnails/18.jpg)
...... OK
...... OK
...... OK
...... OK
8.6220E+04...... OK
8.6220E+04...... OK
...... OK
![Page 19: 응력검토 샘플](https://reader033.vdocuments.pub/reader033/viewer/2022061114/545fa8e7b1af9f673b8b4bc4/html5/thumbnails/19.jpg)
SM400= 0.0500 m H = 0.0500 m= 0.0060 m = 0.0060 m
5.640000E+02 1.312580E+05 1.312580E+051.525539E+01 1.525539E+01 6.768000E+03
검토위치 -14.7 14.7 35.3 14.7 -8.7 -35.3 -14.7 -35.3
구 분 비 고-5.039 0.000 0.082 -0.001 0.000 0.000
1)
구 분 SM400Top Flange 140.000 Left Web 140.000
2)
부재의 유효좌굴길이 = 1453.893 mm부재 총단면의 단면회전반경 = 15.255 mm세장비 = 95.304
부재의 유효좌굴길이 = 1453.893 mm
부재 총단면의 단면회전반경 = 15.255 mm
세장비 = 95.304
▶ 세장비 검토세장비 / rℓ = 95.304 ≤ 120.000 ...... OK
구 분 SM400
Top Flange92.8 < /rℓ
Fcagz = 1200000 / (6700+( /r)²) = 76.032ℓ
Left Web92.8 < /rℓ
Fcagz = 1200000 / (6700+( /r)²) = 76.032ℓ
3.1 단면 제원사용강종 :B1
tf1 tw
3.2 단면 계수A (mm2) Iyy (mm4) Izz (mm4)ry (mm) rz (mm) K (mm4)
y1 (mm) z1 (mm) y2 (mm) z2 (mm)y3 (mm) z3 (mm) y4 (mm) z4 (mm)
3.3 작용하중Fx (kN) Fy (kN) Fz (kN) Mx (kN∙m) My (kN∙m) Mz (kN∙m)
작동시 교축풍하중(63min)
3.4 응력검토[1] 작동시 교축풍하중(63min)
허용휨인장응력 (fta) [도기 P3-10, 표3.3.1]
40 이하40 이하
국부좌굴을 고려하지 않은 허용축방향압축응력 (fcag) [도기 P3-11, 표3.3.2] ▶ Y 축에 대한 유효좌굴길이
ℓy
ry
ℓy /ry
▶ Z 축에 대한 유효좌굴길이ℓz
rz
ℓz /rz
40 이하40 이하
![Page 20: 응력검토 샘플](https://reader033.vdocuments.pub/reader033/viewer/2022061114/545fa8e7b1af9f673b8b4bc4/html5/thumbnails/20.jpg)
Top Flange92.8 < /rℓ
Fcagy = 1200000 / (6700+( /r)²) = 76.032ℓ
Left Web92.8 < /rℓ
Fcagy = 1200000 / (6700+( /r)²) = 76.032ℓ
3) ▶ Top Flange
압축플랜지 고정점간 거리 ℓ = 1453.893 mm
압축플랜지 폭 b = 50.000 mm복부판의 총단면적 = 264.000 압축플랜지 총단면적 = 300.000
= 0.880 ≤ 2.000 , = ### , = 1.855
구 분 SM400
≤ 2.0 4.6 < /b ≤ 30.0ℓ
140 - 2.49×( /b - 4.6) = 79.050ℓ
▶ Left Web
압축플랜지 고정점간 거리 ℓ = 1453.893 mm
압축플랜지 폭 b = 50.000 mm
복부판의 총단면적 = 300.000
압축플랜지 총단면적 = 300.000
= 1.000 ≤ 2.000 , = ### , = 1.871
구 분 SM400
≤ 2.0 4.6 < /b ≤ 30.0ℓ
140 - 2.49×( /b - 4.6) = 79.050ℓ
4) 허용 오일러 좌굴응력132.118 132.118
5)구 분 SM400
Top Flange 80.000 Left Web 80.000
6) 자유돌출판의 국부좌굴에 대한 허용응력 ▶ 압축응력을 받는 자유돌출판의 최소두께
Top Flange(L)= b / 16 = 50.0 / 16.0 = 3.125 mm ≤ = 6.000 mm ...... OK
Left Web(T)= b / 16 = 50.0 / 16.0 = 3.125 mm ≤ = 6.000 mm ...... OK
▶Top Flange(L) t = 6.000 mm
= b / 12.9 = 50.0 / 12.9 = 3.876 mm
구 분 SM400
40 이하40 이하
허용휨압축응력 (fbagy) [도기 P3-16, 표3.3.4]
Aw mm2
Ac mm2
40 이하
Aw mm2
Ac mm2
40 이하
[도기 P3-47, 식3.4.13~14]fEy (MPa) 1200000/(ly/ry)2
fEz (MPa) 1200000/(lz/rz)2
허용전단응력 (υa) [도기 P3-18, 표3.3.5]
40 이하40 이하
[도기 P3-37]tmin tf
tmin tf
자유돌출판의 국부좌굴에 대한 허용응력 (fcal) [도기 P3-38, 표3.4.4]
t1
w
c
AA
lb
w
c
AA
32
w
c
AK
A
w
c
AA
lb
w
c
AA
32
w
c
AK
A
![Page 21: 응력검토 샘플](https://reader033.vdocuments.pub/reader033/viewer/2022061114/545fa8e7b1af9f673b8b4bc4/html5/thumbnails/21.jpg)
b/12.9 ≤ t140.000
Left Web(T) t = 6.000 mm= b / 12.9 = 50.0 / 12.9 = 3.876 mm
구 분 SM400b/12.9 ≤ t140.000
7) 허용응력 요약구 분
Top Flange 140.000 76.032 76.032 140.000 80.000 Left Web 140.000 76.032 76.032 140.000 80.000
=
8) 축방향력 및 휨모멘트를 받는 부재의 허용응력 검토▶ 축방향력에 의한 응력
= P / A = -5.039 / 5.6400E+02 = -8.934 MPa
▶ 휨모멘트에 의한 응력= = 0.000 MPa = = 0.000 MPa= = 0.000 MPa = = 0.000 MPa= = 0.000 MPa = = 0.000 MPa= = 0.000 MPa = = 0.000 MPa
-8.934 -8.934 -8.934 -8.934
▶ Position 1 (y-direction)
-8.934 +0.000
+0.000
( 1 --8.934
) ( 1 --8.934
)132.118 132.118
= -8.934 MPa ≤ = 140.000 MPa ...... OK
-8.934 +
0.000 +
0.000 76.032
79.050 ( 1 --8.934
) 140.000 ( 1 --8.934
)132.118 132.118
= -0.118 ≤ 1.000 ...... OK
▶ Position 2 (y-direction)
-8.934 +0.000
+0.000
40 이하
t1
40 이하
fcal fcaz fcay fta υa
fca fcag ∙ fcal / fcao.
fc × 103
fby1 My × z1 / Iyy fbz1 Mz × y1 / Izz
fby2 My × z2 / Iyy fbz2 Mz × y2 / Izz
fby3 My × z3 / Iyy fbz3 Mz × y3 / Izz
fby4 My × z4 / Iyy fbz4 Mz × y4 / Izz
f11 (y1, z1) f22 (y2, z2)f33 (y3, z3) f44 (y4, z4)
fcal
11
bcy bczc cal
cc
EzEy
f ff fffff
1.011
bcyc bcz
caz ccbaobagy
EzEy
ff ff ff ff
ff
11
bcy bczc cal
cc
EzEy
f ff fffff
![Page 22: 응력검토 샘플](https://reader033.vdocuments.pub/reader033/viewer/2022061114/545fa8e7b1af9f673b8b4bc4/html5/thumbnails/22.jpg)
-8.934 +( 1 -
-8.934 )
+( 1 -
-8.934 )
132.118 132.118 = -8.934 MPa ≤ = 140.000 MPa ...... OK
-8.934 +
0.000 +
0.000 76.032
79.050 ( 1 --8.934
) 140.000 ( 1 --8.934
)132.118 132.118
= -0.118 ≤ 1.000 ...... OK
▶ Position 3 (y-direction)
-8.934 +0.000
+0.000
( 1 --8.934
) ( 1 --8.934
)132.118 132.118
= -8.934 MPa ≤ = 140.000 MPa ...... OK
-8.934 +
0.000 +
0.000 76.032
79.050 ( 1 --8.934
) 140.000 ( 1 --8.934
)132.118 132.118
= -0.118 ≤ 1.000 ...... OK
▶ Position 4 (y-direction)
-8.934 +0.000
+0.000
( 1 --8.934
) ( 1 --8.934
)132.118 132.118
= -8.934 MPa ≤ = 140.000 MPa ...... OK
-8.934 +
0.000 +
0.000 76.032
79.050 ( 1 --8.934
) 140.000 ( 1 --8.934
)132.118 132.118
= -0.118 ≤ 1.000 ...... OK
▶ Position 1 (z-direction)
-8.934 +0.000
+0.000
( 1 --8.934
) ( 1 --8.934
)
fcal
fcal
fcal
1.011
bcyc bcz
caz ccbaobagy
EzEy
ff ff ff ff
ff
11
bcy bczc cal
cc
EzEy
f ff fffff
1.011
bcyc bcz
caz ccbaobagy
EzEy
ff ff ff ff
ff
11
bcy bczc cal
cc
EzEy
f ff fffff
1.011
bcyc bcz
caz ccbaobagy
EzEy
ff ff ff ff ff
1 1
bcybczc cal
c c
Ez Ey
fff ff ff f
![Page 23: 응력검토 샘플](https://reader033.vdocuments.pub/reader033/viewer/2022061114/545fa8e7b1af9f673b8b4bc4/html5/thumbnails/23.jpg)
( 1 -132.118
) ( 1 -132.118
)
= -8.934 MPa ≤ = 140.000 MPa ...... OK
-8.934 +
0.000 +
0.000 76.032
79.050 ( 1 --8.934
) 140.000 ( 1 --8.934
)132.118 132.118
= -0.118 ≤ 1.0 ...... OK
▶ Position 2 (z-direction)
-8.934 +0.000
+0.000
( 1 --8.934
) ( 1 --8.934
)132.118 132.118
= -8.934 MPa ≤ = 140.000 MPa ...... OK
-8.934 +
0.000 +
0.000 76.032
79.050 ( 1 --8.934
) 140.000 ( 1 --8.934
)132.118 132.118
= -0.118 ≤ 1.0 ...... OK
▶ Position 3 (z-direction)
-8.934 +0.000
+0.000
( 1 --8.934
) ( 1 --8.934
)132.118 132.118
= -8.934 MPa ≤ = 140.000 MPa ...... OK
-8.934 +
0.000 +
0.000 76.032
79.050 ( 1 --8.934
) 140.000 ( 1 --8.934
)132.118 132.118
= -0.118 ≤ 1.0 ...... OK
▶ Position 4 (z-direction)
-8.934 +0.000
+0.000
( 1 --8.934
) ( 1 --8.934
)132.118 132.118
fcal
fcal
fcal
1.01 1
bcyc bcz
cay c cbagz bao
Ez Ey
ff ff f ff f
f f
1 1
bcybczc cal
c c
Ez Ey
fff ff ff f
1.01 1
bcyc bcz
cay c cbagz bao
Ez Ey
ff ff f ff f
f f
1 1
bcybczc cal
c c
Ez Ey
fff ff ff f
1.01 1
bcyc bcz
cay c cbagz bao
Ez Ey
ff ff f ff f
f f
1 1
bcybczc cal
c c
Ez Ey
fff ff ff f
![Page 24: 응력검토 샘플](https://reader033.vdocuments.pub/reader033/viewer/2022061114/545fa8e7b1af9f673b8b4bc4/html5/thumbnails/24.jpg)
= -8.934 MPa ≤ = 140.000 MPa ...... OK
-8.934 +
0.000 +
0.000 76.032
79.050 ( 1 --8.934
) 140.000 ( 1 --8.934
)132.118 132.118
= -0.118 ≤ 1.0 ...... OK
9) 전단응력에 대한 검토== 0.082 / 200.000 + -0.001 × 6.000E+00 / 6.7680E+03= -0.099 MPa ≤ = 80.000 MPa ...... OK== 0.000 / 200.000 + -0.001 × 6.000E+00 / 6.7680E+03= -0.509 MPa ≤ = 80.000 MPa ...... OK
t =
10) 합성응력에 대한 검토= (
0.000 + (
-0.509 = 0.000 < 1.200 ...... OK
140.000 80.000
fcal
υz Fz / Aw + Mx × t / K× 103 × 106
υa
υy Fy / Af + Mx × t / K× 103 × 106
υa
여기서, 복부 두께 .
)2 )2
1.01 1
bcyc bcz
cay c cbagz bao
Ez Ey
ff ff f ff f
f f
2 2
b b
a a
f vf v
![Page 25: 응력검토 샘플](https://reader033.vdocuments.pub/reader033/viewer/2022061114/545fa8e7b1af9f673b8b4bc4/html5/thumbnails/25.jpg)
1.312580E+056.768000E+03
14.7 -35.3
비 고
SM400140.000 140.000
...... OK
SM40092.8 < /rℓ
Fcagz = 1200000 / (6700+( /r)²) = 76.032ℓ
92.8 < /rℓ
Fcagz = 1200000 / (6700+( /r)²) = 76.032ℓ
도기 P3-10, 표3.3.1]
도기 P3-11, 표3.3.2]
![Page 26: 응력검토 샘플](https://reader033.vdocuments.pub/reader033/viewer/2022061114/545fa8e7b1af9f673b8b4bc4/html5/thumbnails/26.jpg)
92.8 < /rℓ
Fcagy = 1200000 / (6700+( /r)²) = 76.032ℓ
92.8 < /rℓ
Fcagy = 1200000 / (6700+( /r)²) = 76.032ℓ
SM4004.6 < /b ≤ 30.0ℓ
140 - 2.49×( /b - 4.6) = 79.050ℓ
SM4004.6 < /b ≤ 30.0ℓ
140 - 2.49×( /b - 4.6) = 79.050ℓ
132.118 132.118
SM40080.000 80.000
...... OK
...... OK
SM400
도기 P3-16, 표3.3.4]
P3-47, 식3.4.13~14]
P3-18, 표3.3.5]
도기 P3-37]
P3-38, 표3.4.4]
![Page 27: 응력검토 샘플](https://reader033.vdocuments.pub/reader033/viewer/2022061114/545fa8e7b1af9f673b8b4bc4/html5/thumbnails/27.jpg)
b/12.9 ≤ t140.000
SM400b/12.9 ≤ t140.000
80.000 80.000
-8.934 -8.934
...... OK
...... OK
υa
![Page 28: 응력검토 샘플](https://reader033.vdocuments.pub/reader033/viewer/2022061114/545fa8e7b1af9f673b8b4bc4/html5/thumbnails/28.jpg)
...... OK
...... OK
...... OK
...... OK
...... OK
...... OK
![Page 29: 응력검토 샘플](https://reader033.vdocuments.pub/reader033/viewer/2022061114/545fa8e7b1af9f673b8b4bc4/html5/thumbnails/29.jpg)
...... OK
...... OK
...... OK
...... OK
...... OK
...... OK
![Page 30: 응력검토 샘플](https://reader033.vdocuments.pub/reader033/viewer/2022061114/545fa8e7b1af9f673b8b4bc4/html5/thumbnails/30.jpg)
...... OK
...... OK
6.7680E+03...... OK
6.7680E+03...... OK
...... OK
![Page 31: 응력검토 샘플](https://reader033.vdocuments.pub/reader033/viewer/2022061114/545fa8e7b1af9f673b8b4bc4/html5/thumbnails/31.jpg)
SM400= 0.0500 m H = 0.0500 m= 0.0060 m = 0.0060 m
5.640000E+02 1.312580E+05 1.312580E+051.525539E+01 1.525539E+01 6.768000E+03
검토위치 -14.7 14.7 35.3 14.7 -8.7 -35.3 -14.7 -35.3
구 분 비 고-5.039 0.000 0.000 -0.001 -0.060 0.000
1)
구 분 SM400Top Flange 140.000 Left Web 140.000
2)
부재의 유효좌굴길이 = 1453.893 mm부재 총단면의 단면회전반경 = 15.255 mm세장비 = 95.304
부재의 유효좌굴길이 = 1453.893 mm
부재 총단면의 단면회전반경 = 15.255 mm
세장비 = 95.304
▶ 세장비 검토세장비 / rℓ = 95.304 ≤ 120.000 ...... OK
구 분 SM400
Top Flange92.8 < /rℓ
Fcagz = 1200000 / (6700+( /r)²) = 76.032ℓ
Left Web92.8 < /rℓ
Fcagz = 1200000 / (6700+( /r)²) = 76.032ℓ
4.1 단면 제원사용강종 :B1
tf1 tw
4.2 단면 계수A (mm2) Iyy (mm4) Izz (mm4)ry (mm) rz (mm) K (mm4)
y1 (mm) z1 (mm) y2 (mm) z2 (mm)y3 (mm) z3 (mm) y4 (mm) z4 (mm)
4.3 작용하중Fx (kN) Fy (kN) Fz (kN) Mx (kN∙m) My (kN∙m) Mz (kN∙m)
작동시 교축풍하중(63min)
4.4 응력검토[1] 작동시 교축풍하중(63min)
허용휨인장응력 (fta) [도기 P3-10, 표3.3.1]
40 이하40 이하
국부좌굴을 고려하지 않은 허용축방향압축응력 (fcag) [도기 P3-11, 표3.3.2] ▶ Y 축에 대한 유효좌굴길이
ℓy
ry
ℓy /ry
▶ Z 축에 대한 유효좌굴길이ℓz
rz
ℓz /rz
40 이하40 이하
![Page 32: 응력검토 샘플](https://reader033.vdocuments.pub/reader033/viewer/2022061114/545fa8e7b1af9f673b8b4bc4/html5/thumbnails/32.jpg)
Top Flange92.8 < /rℓ
Fcagy = 1200000 / (6700+( /r)²) = 76.032ℓ
Left Web92.8 < /rℓ
Fcagy = 1200000 / (6700+( /r)²) = 76.032ℓ
3) ▶ Top Flange
압축플랜지 고정점간 거리 ℓ = 1453.893 mm
압축플랜지 폭 b = 50.000 mm복부판의 총단면적 = 264.000 압축플랜지 총단면적 = 300.000
= 0.880 ≤ 2.000 , = ### , = 1.855
구 분 SM400
≤ 2.0 4.6 < /b ≤ 30.0ℓ
140 - 2.49×( /b - 4.6) = 79.050ℓ
▶ Left Web
압축플랜지 고정점간 거리 ℓ = 1453.893 mm
압축플랜지 폭 b = 50.000 mm
복부판의 총단면적 = 300.000
압축플랜지 총단면적 = 300.000
= 1.000 ≤ 2.000 , = ### , = 1.871
구 분 SM400
≤ 2.0 4.6 < /b ≤ 30.0ℓ
140 - 2.49×( /b - 4.6) = 79.050ℓ
4) 허용 오일러 좌굴응력132.118 132.118
5)구 분 SM400
Top Flange 80.000 Left Web 80.000
6) 자유돌출판의 국부좌굴에 대한 허용응력 ▶ 압축응력을 받는 자유돌출판의 최소두께
Top Flange(L)= b / 16 = 50.0 / 16.0 = 3.125 mm ≤ = 6.000 mm ...... OK
Left Web(T)= b / 16 = 50.0 / 16.0 = 3.125 mm ≤ = 6.000 mm ...... OK
▶Top Flange(L) t = 6.000 mm
= b / 12.9 = 50.0 / 12.9 = 3.876 mm
구 분 SM400
40 이하40 이하
허용휨압축응력 (fbagy) [도기 P3-16, 표3.3.4]
Aw mm2
Ac mm2
40 이하
Aw mm2
Ac mm2
40 이하
[도기 P3-47, 식3.4.13~14]fEy (MPa) 1200000/(ly/ry)2
fEz (MPa) 1200000/(lz/rz)2
허용전단응력 (υa) [도기 P3-18, 표3.3.5]
40 이하40 이하
[도기 P3-37]tmin tf
tmin tf
자유돌출판의 국부좌굴에 대한 허용응력 (fcal) [도기 P3-38, 표3.4.4]
t1
w
c
AA
lb
w
c
AA
32
w
c
AK
A
w
c
AA
lb
w
c
AA
32
w
c
AK
A
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b/12.9 ≤ t140.000
Left Web(T) t = 6.000 mm= b / 12.9 = 50.0 / 12.9 = 3.876 mm
구 분 SM400b/12.9 ≤ t140.000
7) 허용응력 요약구 분
Top Flange 140.000 76.032 76.032 140.000 80.000 Left Web 140.000 76.032 76.032 140.000 80.000
=
8) 축방향력 및 휨모멘트를 받는 부재의 허용응력 검토▶ 축방향력에 의한 응력
= P / A = -5.039 / 5.6400E+02 = -8.934 MPa
▶ 휨모멘트에 의한 응력= = 6.686 MPa = = 0.000 MPa= = 6.686 MPa = = 0.000 MPa= = -16.053 MPa = = 0.000 MPa= = -16.053 MPa = = 0.000 MPa
-2.247 -2.247 -24.987 -24.987
▶ Position 1 (y-direction)
-8.934 +6.686
+0.000
( 1 --8.934
) ( 1 --8.934
)132.118 132.118
= -1.762 MPa ≤ = 140.000 MPa ...... OK
-8.934 +
6.686 +
0.000 76.032
79.050 ( 1 --8.934
) 140.000 ( 1 --8.934
)132.118 132.118
= -0.027 ≤ 1.000 ...... OK
▶ Position 2 (y-direction)
-8.934 +6.686
+0.000
40 이하
t1
40 이하
fcal fcaz fcay fta υa
fca fcag ∙ fcal / fcao.
fc × 103
fby1 My × z1 / Iyy fbz1 Mz × y1 / Izz
fby2 My × z2 / Iyy fbz2 Mz × y2 / Izz
fby3 My × z3 / Iyy fbz3 Mz × y3 / Izz
fby4 My × z4 / Iyy fbz4 Mz × y4 / Izz
f11 (y1, z1) f22 (y2, z2)f33 (y3, z3) f44 (y4, z4)
fcal
11
bcy bczc cal
cc
EzEy
f ff fffff
1.011
bcyc bcz
caz ccbaobagy
EzEy
ff ff ff ff
ff
11
bcy bczc cal
cc
EzEy
f ff fffff
![Page 34: 응력검토 샘플](https://reader033.vdocuments.pub/reader033/viewer/2022061114/545fa8e7b1af9f673b8b4bc4/html5/thumbnails/34.jpg)
-8.934 +( 1 -
-8.934 )
+( 1 -
-8.934 )
132.118 132.118 = -1.762 MPa ≤ = 140.000 MPa ...... OK
-8.934 +
6.686 +
0.000 76.032
79.050 ( 1 --8.934
) 140.000 ( 1 --8.934
)132.118 132.118
= -0.027 ≤ 1.000 ...... OK
▶ Position 3 (y-direction)
-8.934 +-16.053
+0.000
( 1 --8.934
) ( 1 --8.934
)132.118 132.118
= -26.151 MPa ≤ = 140.000 MPa ...... OK
-8.934 +
-16.053 +
0.000 76.032
79.050 ( 1 --8.934
) 140.000 ( 1 --8.934
)132.118 132.118
= -0.335 ≤ 1.000 ...... OK
▶ Position 4 (y-direction)
-8.934 +-16.053
+0.000
( 1 --8.934
) ( 1 --8.934
)132.118 132.118
= -26.151 MPa ≤ = 140.000 MPa ...... OK
-8.934 +
-16.053 +
0.000 76.032
79.050 ( 1 --8.934
) 140.000 ( 1 --8.934
)132.118 132.118
= -0.335 ≤ 1.000 ...... OK
▶ Position 1 (z-direction)
-8.934 +0.000
+6.686
( 1 --8.934
) ( 1 --8.934
)
fcal
fcal
fcal
1.011
bcyc bcz
caz ccbaobagy
EzEy
ff ff ff ff
ff
11
bcy bczc cal
cc
EzEy
f ff fffff
1.011
bcyc bcz
caz ccbaobagy
EzEy
ff ff ff ff
ff
11
bcy bczc cal
cc
EzEy
f ff fffff
1.011
bcyc bcz
caz ccbaobagy
EzEy
ff ff ff ff ff
1 1
bcybczc cal
c c
Ez Ey
fff ff ff f
![Page 35: 응력검토 샘플](https://reader033.vdocuments.pub/reader033/viewer/2022061114/545fa8e7b1af9f673b8b4bc4/html5/thumbnails/35.jpg)
( 1 -132.118
) ( 1 -132.118
)
= -1.762 MPa ≤ = 140.000 MPa ...... OK
-8.934 +
0.000 +
6.686 76.032
79.050 ( 1 --8.934
) 140.000 ( 1 --8.934
)132.118 132.118
= -0.066 ≤ 1.0 ...... OK
▶ Position 2 (z-direction)
-8.934 +0.000
+6.686
( 1 --8.934
) ( 1 --8.934
)132.118 132.118
= -1.762 MPa ≤ = 140.000 MPa ...... OK
-8.934 +
0.000 +
6.686 76.032
79.050 ( 1 --8.934
) 140.000 ( 1 --8.934
)132.118 132.118
= -0.066 ≤ 1.0 ...... OK
▶ Position 3 (z-direction)
-8.934 +0.000
+-16.053
( 1 --8.934
) ( 1 --8.934
)132.118 132.118
= -26.151 MPa ≤ = 140.000 MPa ...... OK
-8.934 +
0.000 +
-16.053 76.032
79.050 ( 1 --8.934
) 140.000 ( 1 --8.934
)132.118 132.118
= -0.240 ≤ 1.0 ...... OK
▶ Position 4 (z-direction)
-8.934 +0.000
+-16.053
( 1 --8.934
) ( 1 --8.934
)132.118 132.118
fcal
fcal
fcal
1.01 1
bcyc bcz
cay c cbagz bao
Ez Ey
ff ff f ff f
f f
1 1
bcybczc cal
c c
Ez Ey
fff ff ff f
1.01 1
bcyc bcz
cay c cbagz bao
Ez Ey
ff ff f ff f
f f
1 1
bcybczc cal
c c
Ez Ey
fff ff ff f
1.01 1
bcyc bcz
cay c cbagz bao
Ez Ey
ff ff f ff f
f f
1 1
bcybczc cal
c c
Ez Ey
fff ff ff f
![Page 36: 응력검토 샘플](https://reader033.vdocuments.pub/reader033/viewer/2022061114/545fa8e7b1af9f673b8b4bc4/html5/thumbnails/36.jpg)
= -26.151 MPa ≤ = 140.000 MPa ...... OK
-8.934 +
0.000 +
-16.053 76.032
79.050 ( 1 --8.934
) 140.000 ( 1 --8.934
)132.118 132.118
= -0.240 ≤ 1.0 ...... OK
9) 전단응력에 대한 검토== 0.000 / 200.000 + -0.001 × 6.000E+00 / 6.7680E+03= -0.509 MPa ≤ = 80.000 MPa ...... OK== 0.000 / 200.000 + -0.001 × 6.000E+00 / 6.7680E+03= -0.509 MPa ≤ = 80.000 MPa ...... OK
t =
10) 합성응력에 대한 검토= (
-16.053 + (
-0.509 = 0.013 < 1.200 ...... OK
140.000 80.000
fcal
υz Fz / Aw + Mx × t / K× 103 × 106
υa
υy Fy / Af + Mx × t / K× 103 × 106
υa
여기서, 복부 두께 .
)2 )2
1.01 1
bcyc bcz
cay c cbagz bao
Ez Ey
ff ff f ff f
f f
2 2
b b
a a
f vf v
![Page 37: 응력검토 샘플](https://reader033.vdocuments.pub/reader033/viewer/2022061114/545fa8e7b1af9f673b8b4bc4/html5/thumbnails/37.jpg)
1.312580E+056.768000E+03
14.7 -35.3
비 고
SM400140.000 140.000
...... OK
SM40092.8 < /rℓ
Fcagz = 1200000 / (6700+( /r)²) = 76.032ℓ
92.8 < /rℓ
Fcagz = 1200000 / (6700+( /r)²) = 76.032ℓ
도기 P3-10, 표3.3.1]
도기 P3-11, 표3.3.2]
![Page 38: 응력검토 샘플](https://reader033.vdocuments.pub/reader033/viewer/2022061114/545fa8e7b1af9f673b8b4bc4/html5/thumbnails/38.jpg)
92.8 < /rℓ
Fcagy = 1200000 / (6700+( /r)²) = 76.032ℓ
92.8 < /rℓ
Fcagy = 1200000 / (6700+( /r)²) = 76.032ℓ
SM4004.6 < /b ≤ 30.0ℓ
140 - 2.49×( /b - 4.6) = 79.050ℓ
SM4004.6 < /b ≤ 30.0ℓ
140 - 2.49×( /b - 4.6) = 79.050ℓ
132.118 132.118
SM40080.000 80.000
...... OK
...... OK
SM400
도기 P3-16, 표3.3.4]
P3-47, 식3.4.13~14]
P3-18, 표3.3.5]
도기 P3-37]
P3-38, 표3.4.4]
![Page 39: 응력검토 샘플](https://reader033.vdocuments.pub/reader033/viewer/2022061114/545fa8e7b1af9f673b8b4bc4/html5/thumbnails/39.jpg)
b/12.9 ≤ t140.000
SM400b/12.9 ≤ t140.000
80.000 80.000
-2.247 -24.987
...... OK
...... OK
υa
![Page 40: 응력검토 샘플](https://reader033.vdocuments.pub/reader033/viewer/2022061114/545fa8e7b1af9f673b8b4bc4/html5/thumbnails/40.jpg)
...... OK
...... OK
...... OK
...... OK
...... OK
...... OK
![Page 41: 응력검토 샘플](https://reader033.vdocuments.pub/reader033/viewer/2022061114/545fa8e7b1af9f673b8b4bc4/html5/thumbnails/41.jpg)
...... OK
...... OK
...... OK
...... OK
...... OK
...... OK
![Page 42: 응력검토 샘플](https://reader033.vdocuments.pub/reader033/viewer/2022061114/545fa8e7b1af9f673b8b4bc4/html5/thumbnails/42.jpg)
...... OK
...... OK
6.7680E+03...... OK
6.7680E+03...... OK
...... OK
![Page 43: 응력검토 샘플](https://reader033.vdocuments.pub/reader033/viewer/2022061114/545fa8e7b1af9f673b8b4bc4/html5/thumbnails/43.jpg)
SM400= 0.1000 m = 0.1000 m= 0.0470 m = 0.0470 m= 0.0090 m = 0.0090 m= 0.0060 m H = 0.1480 m
2.683867E+03 1.021183E+07 1.505875E+066.168381E+01 2.368721E+01 5.860800E+04
검토위치 -50.0 74.0 50.0 74.0 50.0 -74.0 -50.0 -74.0
구 분 비 고-53.973 -0.598 -0.138 0.000 -0.174 -1.110
1)
구 분 SM400Top Flange 140.000
Bottom Flange 140.000 Left Web 140.000
2)
부재의 유효좌굴길이 = 2015.000 mm부재 총단면의 단면회전반경 = 61.684 mm세장비 = 32.667
부재의 유효좌굴길이 = 2015.000 mm
부재 총단면의 단면회전반경 = 23.687 mm
세장비 = 85.067
▶ 세장비 검토세장비 / rℓ = 85.067 ≤ 120.000 ...... OK
구 분 SM400
Top Flange18.6 < /r ≤ 92.8ℓ
Fcagz = 140 - 0.82×( /r - 18.6) = 85.497ℓ
Bottom Flange18.6 < /r ≤ 92.8ℓ
5.1 단면 제원사용강종 :B1 B2
b1 b2
tf1 tf2
tw
5.2 단면 계수A (mm2) Iyy (mm4) Izz (mm4)ry (mm) rz (mm) K (mm4)
y1 (mm) z1 (mm) y2 (mm) z2 (mm)y3 (mm) z3 (mm) y4 (mm) z4 (mm)
5.3 작용하중Fx (kN) Fy (kN) Fz (kN) Mx (kN∙m) My (kN∙m) Mz (kN∙m)
작동시 교축풍하중(63min)
5.4 응력검토[1] 작동시 교축풍하중(63min)
허용휨인장응력 (fta) [도기 P3-10, 표3.3.1]
40 이하40 이하40 이하
국부좌굴을 고려하지 않은 허용축방향압축응력 (fcag) [도기 P3-11, 표3.3.2] ▶ Y 축에 대한 유효좌굴길이
ℓy
ry
ℓy /ry
▶ Z 축에 대한 유효좌굴길이ℓz
rz
ℓz /rz
40 이하40 이하
![Page 44: 응력검토 샘플](https://reader033.vdocuments.pub/reader033/viewer/2022061114/545fa8e7b1af9f673b8b4bc4/html5/thumbnails/44.jpg)
Bottom FlangeFcagz = 140 - 0.82×( /r - 18.6) = 85.497ℓ
Left Web18.6 < /r ≤ 92.8ℓ
Fcagz = 140 - 0.82×( /r - 18.6) = 85.497ℓ
Top Flange18.6 < /r ≤ 92.8ℓ
Fcagy = 140 - 0.82×( /r - 18.6) = 128.465ℓ
Bottom Flange18.6 < /r ≤ 92.8ℓ
Fcagy = 140 - 0.82×( /r - 18.6) = 128.465ℓ
Left Web18.6 < /r ≤ 92.8ℓ
Fcagy = 140 - 0.82×( /r - 18.6) = 128.465ℓ
3) ▶ Top Flange
압축플랜지 고정점간 거리 ℓ = 2015.000 mm압축플랜지 폭 b = 100.000 mm복부판의 총단면적 = 780.000 압축플랜지 총단면적 = 900.000
= 0.867 ≤ 2.000 , = ### , = 1.853
구 분 SM400
≤ 2.0 4.6 < /b ≤ 30.0ℓ
140 - 2.49×( /b - 4.6) = 101.280ℓ
▶ Bottom Flange
압축플랜지 고정점간 거리 ℓ = 2015.000 mm
압축플랜지 폭 b = 100.000 mm
복부판의 총단면적 = 780.000
압축플랜지 총단면적 = 900.000
= 0.867 ≤ 2.000 , = ### , = 1.853
구 분 SM400
≤ 2.0 4.6 < /b ≤ 30.0ℓ
140 - 2.49×( /b - 4.6) = 101.280ℓ
▶ Left Web압축플랜지 고정점간 거리 ℓ = 2015.000 mm압축플랜지 폭 b = 130.000 mm복부판의 총단면적 = 1800.000 압축플랜지 총단면적 = 780.000
= 2.308 > 2.000 , = ### , = 2.038
구 분 SM400
> 2.0 9.3/K < /b ≤ 30.0ℓ
140 - 1.24×(K× /b - 9.3) = 112.360ℓ
4) 허용 오일러 좌굴응력1124.536 165.828
40 이하40 이하40 이하40 이하40 이하
허용휨압축응력 (fbagy) [도기 P3-16, 표3.3.4]
Aw mm2
Ac mm2
40 이하
Aw mm2
Ac mm2
40 이하
Aw mm2
Ac mm2
40 이하
[도기 P3-47, 식3.4.13~14]fEy (MPa) 1200000/(ly/ry)2
fEz (MPa) 1200000/(lz/rz)2
w
c
AA
lb
w
c
AA
32
w
c
AK
A
w
c
AA
lb
w
c
AA
32
w
c
AK
A
w
c
AA
lb
w
c
AA
32
w
c
AK
A
![Page 45: 응력검토 샘플](https://reader033.vdocuments.pub/reader033/viewer/2022061114/545fa8e7b1af9f673b8b4bc4/html5/thumbnails/45.jpg)
5)
구 분 SM400Top Flange 80.000
Bottom Flange 80.000 Left Web 80.000
6) 자유돌출판의 국부좌굴에 대한 허용응력 ▶ 압축응력을 받는 자유돌출판의 최소두께
Top Flange(L)= b / 16 = 47.0 / 16.0 = 2.938 mm ≤ = 9.000 mm ...... OK
Top Flange(R)= b / 16 = 47.0 / 16.0 = 2.938 mm ≤ = 9.000 mm ...... OK
Bottom Flange(L)= b / 16 = 47.0 / 16.0 = 2.938 mm ≤ = 9.000 mm ...... OK
Bottom Flange(R)= b / 16 = 47.0 / 16.0 = 2.938 mm ≤ = 9.000 mm ...... OK
▶Top Flange(L) t = 9.000 mm
= b / 12.9 = 47.0 / 12.9 = 3.643 mm
구 분 SM400b/12.9 ≤ t140.000
Top Flange(R) t = 9.000 mm= b / 12.9 = 47.0 / 12.9 = 3.643 mm
구 분 SM400b/12.9 ≤ t140.000
Bottom Flange(L) t = 9.000 mm= b / 12.9 = 47.0 / 12.9 = 3.643 mm
구 분 SM400b/12.9 ≤ t140.000
Bottom Flange(R) t = 9.000 mm= b / 12.9 = 47.0 / 12.9 = 3.643 mm
구 분 SM400b/12.9 ≤ t140.000
7) 보강된판 및 양연지지판의 국부좌굴에 대한 허용응력▶ Left Web
판두께 t = 6.0 mm
판의 고정연 사이의 거리 b = 130.0 mm
응력구배계수 i = = 1.021
응력구배 Φ = = 0.105
판의 양연에서의 응력 = -21.221 MPa, = -18.999 MPa
압축응력을 받는 양연지지판의 최소두께t ≤ 40mm
허용전단응력 (υa) [도기 P3-18, 표3.3.5]
40 이하40 이하40 이하
[도기 P3-37]tmin tf
tmin tf
tmin tf
tmin tf
자유돌출판의 국부좌굴에 대한 허용응력 (fcal) [도기 P3-38, 표3.4.4]
t1
40 이하
t1
40 이하
t1
40 이하
t1
40 이하
0.65Φ2 + 0.13Φ + 1.0(f1 - f2) / f1
f1 f2
[도기 P3-35, 표3.4.2]
![Page 46: 응력검토 샘플](https://reader033.vdocuments.pub/reader033/viewer/2022061114/545fa8e7b1af9f673b8b4bc4/html5/thumbnails/46.jpg)
= b / 56i = 130 / 57.161 = 2.3 ≤ t = 6.0 mm ...... OK
구 분 SM400b/39.3i ≤ t140.000
8) 허용응력 요약구 분
Top Flange 140.000 85.497 128.465 140.000 80.000 Bottom Flange 140.000 85.497 128.465 140.000 80.000
Left Web 140.000 85.497 128.465 140.000 80.000 =
9) 축방향력 및 휨모멘트를 받는 부재의 허용응력 검토▶ 축방향력에 의한 응력
= P / A = -53.973 / 2.6839E+03 = -20.110 MPa
▶ 휨모멘트에 의한 응력= = 1.264 MPa = = -36.843 MPa= = 1.264 MPa = = 36.843 MPa= = -1.264 MPa = = 36.843 MPa= = -1.264 MPa = = -36.843 MPa
-55.688 17.997 15.468 -58.217
▶ Position 1 (y-direction)
-20.110 +1.264
+-36.843
( 1 --20.110
) ( 1 --20.110
)1124.536 165.828
= -60.750 MPa ≤ = 140.000 MPa ...... OK
-20.110 +
1.264 +
-36.843 85.497
101.280 ( 1 --20.110
) 140.000 ( 1 --20.110
)1124.536 165.828
= -0.522 ≤ 1.000 ...... OK
▶ Position 2 (y-direction)
-20.110 +1.264
+36.843
tmin
양연지지판의 국부좌굴에 대한 허용응력 (fcal) [도기 P3-36, 표3.4.3]
40 이하
fcal fcaz fcay fta υa
fca fcag ∙ fcal / fcao.
fc × 103
fby1 My × z1 / Iyy fbz1 Mz × y1 / Izz
fby2 My × z2 / Iyy fbz2 Mz × y2 / Izz
fby3 My × z3 / Iyy fbz3 Mz × y3 / Izz
fby4 My × z4 / Iyy fbz4 Mz × y4 / Izz
f11 (y1, z1) f22 (y2, z2)f33 (y3, z3) f44 (y4, z4)
fcal
11
bcy bczc cal
cc
EzEy
f ff fffff
1.011
bcyc bcz
caz ccbaobagy
EzEy
ff ff ff ff
ff
11
bcy bczc cal
cc
EzEy
f ff fffff
![Page 47: 응력검토 샘플](https://reader033.vdocuments.pub/reader033/viewer/2022061114/545fa8e7b1af9f673b8b4bc4/html5/thumbnails/47.jpg)
-20.110 +( 1 -
-20.110 )
+( 1 -
-20.110 )
1124.536 165.828 = 23.105 MPa ≤ = 140.000 MPa ...... OK
▶ Position 3 (y-direction)
-20.110 +-1.264
+36.843
( 1 --20.110
) ( 1 --20.110
)1124.536 165.828
= 20.530 MPa ≤ = 140.000 MPa ...... OK
▶ Position 4 (y-direction)
-20.110 +-1.264
+-36.843
( 1 --20.110
) ( 1 --20.110
)1124.536 165.828
= -63.325 MPa ≤ = 140.000 MPa ...... OK
-20.110 +
-1.264 +
-36.843 85.497
101.280 ( 1 --20.110
) 140.000 ( 1 --20.110
)1124.536 165.828
= -0.547 ≤ 1.000 ...... OK
▶ Position 1 (z-direction)
-20.110 +-36.843
+1.264
( 1 --20.110
) ( 1 --20.110
)165.828 1124.536
= -60.750 MPa ≤ = 140.000 MPa ...... OK
-20.110 +
-36.843 +
1.264 128.465
112.360 ( 1 --20.110
) 140.000 ( 1 --20.110
)165.828 1124.536
= -0.520 ≤ 1.0 ...... OK
▶ Position 2 (z-direction)
fta
fta
fcal
fcal
11
bcy bczc cal
cc
EzEy
f ff fffff
11
bcy bczc cal
cc
EzEy
f ff fffff
1.011
bcyc bcz
caz ccbaobagy
EzEy
ff ff ff ff ff
1 1
bcybczc cal
c c
Ez Ey
fff ff ff f
1.01 1
bcyc bcz
cay c cbagz bao
Ez Ey
ff ff f ff f
f f
1 1
bcybczc cal
c c
Ez Ey
fff ff ff f
![Page 48: 응력검토 샘플](https://reader033.vdocuments.pub/reader033/viewer/2022061114/545fa8e7b1af9f673b8b4bc4/html5/thumbnails/48.jpg)
-20.110 +36.843
+1.264
( 1 --20.110
) ( 1 --20.110
)165.828 1124.536
= 23.105 MPa ≤ = 140.000 MPa ...... OK
▶ Position 3 (z-direction)
-20.110 +36.843
+-1.264
( 1 --20.110
) ( 1 --20.110
)165.828 1124.536
= 20.530 MPa ≤ = 140.000 MPa ...... OK
▶ Position 4 (z-direction)
-20.110 +-36.843
+-1.264
( 1 --20.110
) ( 1 --20.110
)165.828 1124.536
= -63.325 MPa ≤ = 140.000 MPa ...... OK
-20.110 +
-36.843 +
-1.264 128.465
112.360 ( 1 --20.110
) 140.000 ( 1 --20.110
)165.828 1124.536
= -0.539 ≤ 1.0 ...... OK
10) 전단응력에 대한 검토== -0.138 / 888.000 + 0.000 × 6.000E+00 / 5.8608E+04= -0.160 MPa ≤ = 80.000 MPa ...... OK== -0.598 / 1200.000 + 0.000 × 9.000E+00 / 5.8608E+04= -0.505 MPa ≤ = 80.000 MPa ...... OK
t =
11) 합성응력에 대한 검토= (
38.107 + (
-0.505 = 0.074 < 1.200 ...... OK
140.000 80.000
fta
fta
fcal
υz Fz / Aw + Mx × t / K× 103 × 106
υa
υy Fy / Af + Mx × t / K× 103 × 106
υa
여기서, 복부 두께 .
)2 )2
1 1
bcybczc cal
c c
Ez Ey
fff ff ff f
1 1
bcybczc cal
c c
Ez Ey
fff ff ff f
1 1
bcybczc cal
c c
Ez Ey
fff ff ff f
1.01 1
bcyc bcz
cay c cbagz bao
Ez Ey
ff ff f ff f
f f
2 2
b b
a a
f vf v
![Page 49: 응력검토 샘플](https://reader033.vdocuments.pub/reader033/viewer/2022061114/545fa8e7b1af9f673b8b4bc4/html5/thumbnails/49.jpg)
1.505875E+065.860800E+04
74.0 -74.0
비 고
SM400140.000 140.000 140.000
...... OK
SM40018.6 < /r ≤ 92.8ℓ
Fcagz = 140 - 0.82×( /r - 18.6) = 85.497ℓ
18.6 < /r ≤ 92.8ℓ
도기 P3-10, 표3.3.1]
도기 P3-11, 표3.3.2]
![Page 50: 응력검토 샘플](https://reader033.vdocuments.pub/reader033/viewer/2022061114/545fa8e7b1af9f673b8b4bc4/html5/thumbnails/50.jpg)
Fcagz = 140 - 0.82×( /r - 18.6) = 85.497ℓ
18.6 < /r ≤ 92.8ℓ
Fcagz = 140 - 0.82×( /r - 18.6) = 85.497ℓ
18.6 < /r ≤ 92.8ℓ
Fcagy = 140 - 0.82×( /r - 18.6) = 128.465ℓ
18.6 < /r ≤ 92.8ℓ
Fcagy = 140 - 0.82×( /r - 18.6) = 128.465ℓ
18.6 < /r ≤ 92.8ℓ
Fcagy = 140 - 0.82×( /r - 18.6) = 128.465ℓ
SM4004.6 < /b ≤ 30.0ℓ
140 - 2.49×( /b - 4.6) = 101.280ℓ
SM4004.6 < /b ≤ 30.0ℓ
140 - 2.49×( /b - 4.6) = 101.280ℓ
SM4009.3/K < /b ≤ 30.0ℓ
140 - 1.24×(K× /b - 9.3) = 112.360ℓ
1124.536 165.828
도기 P3-16, 표3.3.4]
P3-47, 식3.4.13~14]
![Page 51: 응력검토 샘플](https://reader033.vdocuments.pub/reader033/viewer/2022061114/545fa8e7b1af9f673b8b4bc4/html5/thumbnails/51.jpg)
SM40080.000 80.000 80.000
...... OK
...... OK
...... OK
...... OK
SM400b/12.9 ≤ t140.000
SM400b/12.9 ≤ t140.000
SM400b/12.9 ≤ t140.000
SM400b/12.9 ≤ t140.000
P3-18, 표3.3.5]
도기 P3-37]
P3-38, 표3.4.4]
도기 P3-35, 표3.4.2]
![Page 52: 응력검토 샘플](https://reader033.vdocuments.pub/reader033/viewer/2022061114/545fa8e7b1af9f673b8b4bc4/html5/thumbnails/52.jpg)
...... OK
SM400b/39.3i ≤ t140.000
80.000 80.000 80.000
17.997 -58.217
...... OK
...... OK
도기 P3-36, 표3.4.3]
υa
![Page 53: 응력검토 샘플](https://reader033.vdocuments.pub/reader033/viewer/2022061114/545fa8e7b1af9f673b8b4bc4/html5/thumbnails/53.jpg)
...... OK
...... OK
...... OK
...... OK
...... OK
...... OK
![Page 54: 응력검토 샘플](https://reader033.vdocuments.pub/reader033/viewer/2022061114/545fa8e7b1af9f673b8b4bc4/html5/thumbnails/54.jpg)
...... OK
...... OK
...... OK
...... OK
5.8608E+04...... OK
5.8608E+04...... OK
...... OK
![Page 55: 응력검토 샘플](https://reader033.vdocuments.pub/reader033/viewer/2022061114/545fa8e7b1af9f673b8b4bc4/html5/thumbnails/55.jpg)
SM400= 0.1000 m = 0.1000 m= 0.0470 m = 0.0470 m= 0.0090 m = 0.0090 m= 0.0060 m H = 0.1480 m
2.683867E+03 1.021183E+07 1.505875E+066.168381E+01 2.368721E+01 5.860800E+04
검토위치 -50.0 74.0 50.0 74.0 50.0 -74.0 -50.0 -74.0
구 분 비 고-53.852 -0.271 0.405 0.000 -0.449 -0.042
1)
구 분 SM400Top Flange 140.000
Bottom Flange 140.000 Left Web 140.000
2)
부재의 유효좌굴길이 = 2015.000 mm부재 총단면의 단면회전반경 = 61.684 mm세장비 = 32.667
부재의 유효좌굴길이 = 2015.000 mm
부재 총단면의 단면회전반경 = 23.687 mm
세장비 = 85.067
▶ 세장비 검토세장비 / rℓ = 85.067 ≤ 120.000 ...... OK
구 분 SM400
Top Flange18.6 < /r ≤ 92.8ℓ
Fcagz = 140 - 0.82×( /r - 18.6) = 85.497ℓ
Bottom Flange18.6 < /r ≤ 92.8ℓ
6.1 단면 제원사용강종 :B1 B2
b1 b2
tf1 tf2
tw
6.2 단면 계수A (mm2) Iyy (mm4) Izz (mm4)ry (mm) rz (mm) K (mm4)
y1 (mm) z1 (mm) y2 (mm) z2 (mm)y3 (mm) z3 (mm) y4 (mm) z4 (mm)
6.3 작용하중Fx (kN) Fy (kN) Fz (kN) Mx (kN∙m) My (kN∙m) Mz (kN∙m)
작동시 교직풍하중(64min)
6.4 응력검토[1] 작동시 교직풍하중(64min)
허용휨인장응력 (fta) [도기 P3-10, 표3.3.1]
40 이하40 이하40 이하
국부좌굴을 고려하지 않은 허용축방향압축응력 (fcag) [도기 P3-11, 표3.3.2] ▶ Y 축에 대한 유효좌굴길이
ℓy
ry
ℓy /ry
▶ Z 축에 대한 유효좌굴길이ℓz
rz
ℓz /rz
40 이하40 이하
![Page 56: 응력검토 샘플](https://reader033.vdocuments.pub/reader033/viewer/2022061114/545fa8e7b1af9f673b8b4bc4/html5/thumbnails/56.jpg)
Bottom FlangeFcagz = 140 - 0.82×( /r - 18.6) = 85.497ℓ
Left Web18.6 < /r ≤ 92.8ℓ
Fcagz = 140 - 0.82×( /r - 18.6) = 85.497ℓ
Top Flange18.6 < /r ≤ 92.8ℓ
Fcagy = 140 - 0.82×( /r - 18.6) = 128.465ℓ
Bottom Flange18.6 < /r ≤ 92.8ℓ
Fcagy = 140 - 0.82×( /r - 18.6) = 128.465ℓ
Left Web18.6 < /r ≤ 92.8ℓ
Fcagy = 140 - 0.82×( /r - 18.6) = 128.465ℓ
3) ▶ Top Flange
압축플랜지 고정점간 거리 ℓ = 2015.000 mm압축플랜지 폭 b = 100.000 mm복부판의 총단면적 = 780.000 압축플랜지 총단면적 = 900.000
= 0.867 ≤ 2.000 , = ### , = 1.853
구 분 SM400
≤ 2.0 4.6 < /b ≤ 30.0ℓ
140 - 2.49×( /b - 4.6) = 101.280ℓ
▶ Bottom Flange
압축플랜지 고정점간 거리 ℓ = 2015.000 mm
압축플랜지 폭 b = 100.000 mm
복부판의 총단면적 = 780.000
압축플랜지 총단면적 = 900.000
= 0.867 ≤ 2.000 , = ### , = 1.853
구 분 SM400
≤ 2.0 4.6 < /b ≤ 30.0ℓ
140 - 2.49×( /b - 4.6) = 101.280ℓ
▶ Left Web압축플랜지 고정점간 거리 ℓ = 2015.000 mm압축플랜지 폭 b = 130.000 mm복부판의 총단면적 = 1800.000 압축플랜지 총단면적 = 780.000
= 2.308 > 2.000 , = ### , = 2.038
구 분 SM400
> 2.0 9.3/K < /b ≤ 30.0ℓ
140 - 1.24×(K× /b - 9.3) = 112.360ℓ
4) 허용 오일러 좌굴응력1124.536 165.828
40 이하40 이하40 이하40 이하40 이하
허용휨압축응력 (fbagy) [도기 P3-16, 표3.3.4]
Aw mm2
Ac mm2
40 이하
Aw mm2
Ac mm2
40 이하
Aw mm2
Ac mm2
40 이하
[도기 P3-47, 식3.4.13~14]fEy (MPa) 1200000/(ly/ry)2
fEz (MPa) 1200000/(lz/rz)2
w
c
AA
lb
w
c
AA
32
w
c
AK
A
w
c
AA
lb
w
c
AA
32
w
c
AK
A
w
c
AA
lb
w
c
AA
32
w
c
AK
A
![Page 57: 응력검토 샘플](https://reader033.vdocuments.pub/reader033/viewer/2022061114/545fa8e7b1af9f673b8b4bc4/html5/thumbnails/57.jpg)
5)
구 분 SM400Top Flange 80.000
Bottom Flange 80.000 Left Web 80.000
6) 자유돌출판의 국부좌굴에 대한 허용응력 ▶ 압축응력을 받는 자유돌출판의 최소두께
Top Flange(L)= b / 16 = 47.0 / 16.0 = 2.938 mm ≤ = 9.000 mm ...... OK
Top Flange(R)= b / 16 = 47.0 / 16.0 = 2.938 mm ≤ = 9.000 mm ...... OK
Bottom Flange(L)= b / 16 = 47.0 / 16.0 = 2.938 mm ≤ = 9.000 mm ...... OK
Bottom Flange(R)= b / 16 = 47.0 / 16.0 = 2.938 mm ≤ = 9.000 mm ...... OK
▶Top Flange(L) t = 9.000 mm
= b / 12.9 = 47.0 / 12.9 = 3.643 mm
구 분 SM400b/12.9 ≤ t140.000
Top Flange(R) t = 9.000 mm= b / 12.9 = 47.0 / 12.9 = 3.643 mm
구 분 SM400b/12.9 ≤ t140.000
Bottom Flange(L) t = 9.000 mm= b / 12.9 = 47.0 / 12.9 = 3.643 mm
구 분 SM400b/12.9 ≤ t140.000
Bottom Flange(R) t = 9.000 mm= b / 12.9 = 47.0 / 12.9 = 3.643 mm
구 분 SM400b/12.9 ≤ t140.000
7) 보강된판 및 양연지지판의 국부좌굴에 대한 허용응력▶ Left Web
판두께 t = 6.0 mm
판의 고정연 사이의 거리 b = 130.0 mm
응력구배계수 i = = 1.073
응력구배 Φ = = 0.249
판의 양연에서의 응력 = -22.922 MPa, = -17.208 MPa
압축응력을 받는 양연지지판의 최소두께t ≤ 40mm
허용전단응력 (υa) [도기 P3-18, 표3.3.5]
40 이하40 이하40 이하
[도기 P3-37]tmin tf
tmin tf
tmin tf
tmin tf
자유돌출판의 국부좌굴에 대한 허용응력 (fcal) [도기 P3-38, 표3.4.4]
t1
40 이하
t1
40 이하
t1
40 이하
t1
40 이하
0.65Φ2 + 0.13Φ + 1.0(f1 - f2) / f1
f1 f2
[도기 P3-35, 표3.4.2]
![Page 58: 응력검토 샘플](https://reader033.vdocuments.pub/reader033/viewer/2022061114/545fa8e7b1af9f673b8b4bc4/html5/thumbnails/58.jpg)
= b / 56i = 130 / 60.077 = 2.2 ≤ t = 6.0 mm ...... OK
구 분 SM400b/39.3i ≤ t140.000
8) 허용응력 요약구 분
Top Flange 140.000 85.497 128.465 140.000 80.000 Bottom Flange 140.000 85.497 128.465 140.000 80.000
Left Web 140.000 85.497 128.465 140.000 80.000 =
9) 축방향력 및 휨모멘트를 받는 부재의 허용응력 검토▶ 축방향력에 의한 응력
= P / A = -53.852 / 2.6839E+03 = -20.065 MPa
▶ 휨모멘트에 의한 응력= = 3.253 MPa = = -1.378 MPa= = 3.253 MPa = = 1.378 MPa= = -3.253 MPa = = 1.378 MPa= = -3.253 MPa = = -1.378 MPa
-18.191 -15.434 -21.939 -24.696
▶ Position 1 (y-direction)
-20.065 +3.253
+-1.378
( 1 --20.065
) ( 1 --20.065
)1124.536 165.828
= -18.321 MPa ≤ = 140.000 MPa ...... OK
-20.065 +
3.253 +
-1.378 85.497
101.280 ( 1 --20.065
) 140.000 ( 1 --20.065
)1124.536 165.828
= -0.213 ≤ 1.000 ...... OK
▶ Position 2 (y-direction)
-20.065 +3.253
+1.378
tmin
양연지지판의 국부좌굴에 대한 허용응력 (fcal) [도기 P3-36, 표3.4.3]
40 이하
fcal fcaz fcay fta υa
fca fcag ∙ fcal / fcao.
fc × 103
fby1 My × z1 / Iyy fbz1 Mz × y1 / Izz
fby2 My × z2 / Iyy fbz2 Mz × y2 / Izz
fby3 My × z3 / Iyy fbz3 Mz × y3 / Izz
fby4 My × z4 / Iyy fbz4 Mz × y4 / Izz
f11 (y1, z1) f22 (y2, z2)f33 (y3, z3) f44 (y4, z4)
fcal
11
bcy bczc cal
cc
EzEy
f ff fffff
1.011
bcyc bcz
caz ccbaobagy
EzEy
ff ff ff ff
ff
11
bcy bczc cal
cc
EzEy
f ff fffff
![Page 59: 응력검토 샘플](https://reader033.vdocuments.pub/reader033/viewer/2022061114/545fa8e7b1af9f673b8b4bc4/html5/thumbnails/59.jpg)
-20.065 +( 1 -
-20.065 )
+( 1 -
-20.065 )
1124.536 165.828 = -15.185 MPa ≤ = 140.000 MPa ...... OK
-20.065 +
3.253 +
1.378 85.497
101.280 ( 1 --20.065
) 140.000 ( 1 --20.065
)1124.536 165.828
= -0.191 ≤ 1.000 ...... OK
▶ Position 3 (y-direction)
-20.065 +-3.253
+1.378
( 1 --20.065
) ( 1 --20.065
)1124.536 165.828
= -21.809 MPa ≤ = 140.000 MPa ...... OK
-20.065 +
-3.253 +
1.378 85.497
101.280 ( 1 --20.065
) 140.000 ( 1 --20.065
)1124.536 165.828
= -0.256 ≤ 1.000 ...... OK
▶ Position 4 (y-direction)
-20.065 +-3.253
+-1.378
( 1 --20.065
) ( 1 --20.065
)1124.536 165.828
= -24.945 MPa ≤ = 140.000 MPa ...... OK
-20.065 +
-3.253 +
-1.378 85.497
101.280 ( 1 --20.065
) 140.000 ( 1 --20.065
)1124.536 165.828
= -0.279 ≤ 1.000 ...... OK
▶ Position 1 (z-direction)
-20.065 +-1.378
+3.253
( 1 --20.065
) ( 1 --20.065
)
fcal
fcal
fcal
1.011
bcyc bcz
caz ccbaobagy
EzEy
ff ff ff ff ff
11
bcy bczc cal
cc
EzEy
f ff fffff
1.011
bcyc bcz
caz ccbaobagy
EzEy
ff ff ff ff
ff
11
bcy bczc cal
cc
EzEy
f ff fffff
1.011
bcyc bcz
caz ccbaobagy
EzEy
ff ff ff ff ff
1 1
bcybczc cal
c c
Ez Ey
fff ff ff f
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( 1 -165.828
) ( 1 -1124.536
)
= -18.321 MPa ≤ = 140.000 MPa ...... OK
-20.065 +
-1.378 +
3.253 128.465
112.360 ( 1 --20.065
) 140.000 ( 1 --20.065
)165.828 1124.536
= -0.146 ≤ 1.0 ...... OK
▶ Position 2 (z-direction)
-20.065 +1.378
+3.253
( 1 --20.065
) ( 1 --20.065
)165.828 1124.536
= -15.185 MPa ≤ = 140.000 MPa ...... OK
-20.065 +
1.378 +
3.253 128.465
112.360 ( 1 --20.065
) 140.000 ( 1 --20.065
)165.828 1124.536
= -0.119 ≤ 1.0 ...... OK
▶ Position 3 (z-direction)
-20.065 +1.378
+-3.253
( 1 --20.065
) ( 1 --20.065
)165.828 1124.536
= -21.809 MPa ≤ = 140.000 MPa ...... OK
-20.065 +
1.378 +
-3.253 128.465
112.360 ( 1 --20.065
) 140.000 ( 1 --20.065
)165.828 1124.536
= -0.166 ≤ 1.0 ...... OK
▶ Position 4 (z-direction)
-20.065 +-1.378
+-3.253
( 1 --20.065
) ( 1 --20.065
)165.828 1124.536
fcal
fcal
fcal
1.01 1
bcyc bcz
cay c cbagz bao
Ez Ey
ff ff f ff f
f f
1 1
bcybczc cal
c c
Ez Ey
fff ff ff f
1.01 1
bcyc bcz
cay c cbagz bao
Ez Ey
ff ff f ff f
f f
1 1
bcybczc cal
c c
Ez Ey
fff ff ff f
1.01 1
bcyc bcz
cay c cbagz bao
Ez Ey
ff ff f ff f
f f
1 1
bcybczc cal
c c
Ez Ey
fff ff ff f
![Page 61: 응력검토 샘플](https://reader033.vdocuments.pub/reader033/viewer/2022061114/545fa8e7b1af9f673b8b4bc4/html5/thumbnails/61.jpg)
= -24.945 MPa ≤ = 140.000 MPa ...... OK
-20.065 +
-1.378 +
-3.253 128.465
112.360 ( 1 --20.065
) 140.000 ( 1 --20.065
)165.828 1124.536
= -0.194 ≤ 1.0 ...... OK
10) 전단응력에 대한 검토== 0.405 / 888.000 + 0.000 × 6.000E+00 / 5.8608E+04= 0.447 MPa ≤ = 80.000 MPa ...... OK== -0.271 / 1200.000 + 0.000 × 9.000E+00 / 5.8608E+04= -0.239 MPa ≤ = 80.000 MPa ...... OK
t =
11) 합성응력에 대한 검토= (
-4.631 + (
0.447 = 0.001 < 1.200 ...... OK
140.000 80.000
fcal
υz Fz / Aw + Mx × t / K× 103 × 106
υa
υy Fy / Af + Mx × t / K× 103 × 106
υa
여기서, 복부 두께 .
)2 )2
1.01 1
bcyc bcz
cay c cbagz bao
Ez Ey
ff ff f ff f
f f
2 2
b b
a a
f vf v
![Page 62: 응력검토 샘플](https://reader033.vdocuments.pub/reader033/viewer/2022061114/545fa8e7b1af9f673b8b4bc4/html5/thumbnails/62.jpg)
1.505875E+065.860800E+04
74.0 -74.0
비 고
SM400140.000 140.000 140.000
...... OK
SM40018.6 < /r ≤ 92.8ℓ
Fcagz = 140 - 0.82×( /r - 18.6) = 85.497ℓ
18.6 < /r ≤ 92.8ℓ
도기 P3-10, 표3.3.1]
도기 P3-11, 표3.3.2]
![Page 63: 응력검토 샘플](https://reader033.vdocuments.pub/reader033/viewer/2022061114/545fa8e7b1af9f673b8b4bc4/html5/thumbnails/63.jpg)
Fcagz = 140 - 0.82×( /r - 18.6) = 85.497ℓ
18.6 < /r ≤ 92.8ℓ
Fcagz = 140 - 0.82×( /r - 18.6) = 85.497ℓ
18.6 < /r ≤ 92.8ℓ
Fcagy = 140 - 0.82×( /r - 18.6) = 128.465ℓ
18.6 < /r ≤ 92.8ℓ
Fcagy = 140 - 0.82×( /r - 18.6) = 128.465ℓ
18.6 < /r ≤ 92.8ℓ
Fcagy = 140 - 0.82×( /r - 18.6) = 128.465ℓ
SM4004.6 < /b ≤ 30.0ℓ
140 - 2.49×( /b - 4.6) = 101.280ℓ
SM4004.6 < /b ≤ 30.0ℓ
140 - 2.49×( /b - 4.6) = 101.280ℓ
SM4009.3/K < /b ≤ 30.0ℓ
140 - 1.24×(K× /b - 9.3) = 112.360ℓ
1124.536 165.828
도기 P3-16, 표3.3.4]
P3-47, 식3.4.13~14]
![Page 64: 응력검토 샘플](https://reader033.vdocuments.pub/reader033/viewer/2022061114/545fa8e7b1af9f673b8b4bc4/html5/thumbnails/64.jpg)
SM40080.000 80.000 80.000
...... OK
...... OK
...... OK
...... OK
SM400b/12.9 ≤ t140.000
SM400b/12.9 ≤ t140.000
SM400b/12.9 ≤ t140.000
SM400b/12.9 ≤ t140.000
P3-18, 표3.3.5]
도기 P3-37]
P3-38, 표3.4.4]
도기 P3-35, 표3.4.2]
![Page 65: 응력검토 샘플](https://reader033.vdocuments.pub/reader033/viewer/2022061114/545fa8e7b1af9f673b8b4bc4/html5/thumbnails/65.jpg)
...... OK
SM400b/39.3i ≤ t140.000
80.000 80.000 80.000
-15.434 -24.696
...... OK
...... OK
도기 P3-36, 표3.4.3]
υa
![Page 66: 응력검토 샘플](https://reader033.vdocuments.pub/reader033/viewer/2022061114/545fa8e7b1af9f673b8b4bc4/html5/thumbnails/66.jpg)
...... OK
...... OK
...... OK
...... OK
...... OK
...... OK
![Page 67: 응력검토 샘플](https://reader033.vdocuments.pub/reader033/viewer/2022061114/545fa8e7b1af9f673b8b4bc4/html5/thumbnails/67.jpg)
...... OK
...... OK
...... OK
...... OK
...... OK
...... OK
![Page 68: 응력검토 샘플](https://reader033.vdocuments.pub/reader033/viewer/2022061114/545fa8e7b1af9f673b8b4bc4/html5/thumbnails/68.jpg)
...... OK
...... OK
5.8608E+04...... OK
5.8608E+04...... OK
...... OK
![Page 69: 응력검토 샘플](https://reader033.vdocuments.pub/reader033/viewer/2022061114/545fa8e7b1af9f673b8b4bc4/html5/thumbnails/69.jpg)
SM400= 0.0500 m = 0.0500 m= 0.0450 m = 0.0450 m= 0.0075 m = 0.0075 m= 0.0050 m H = 0.1000 m
1.175000E+03 1.863698E+06 2.944692E+053.982620E+01 1.583073E+01 1.721354E+04
검토위치 -16.9 50.0 33.1 50.0 33.1 -50.0 -16.9 -50.0
구 분 비 고-56.865 0.000 0.075 -0.001 0.000 0.000
1)
구 분 SM400Top Flange 140.000
Bottom Flange 140.000 Left Web 140.000
2)
부재의 유효좌굴길이 = 1906.856 mm부재 총단면의 단면회전반경 = 39.826 mm세장비 = 47.879
부재의 유효좌굴길이 = 1906.856 mm
부재 총단면의 단면회전반경 = 15.831 mm
세장비 = 120.453
▶ 세장비 검토세장비 / rℓ = 120.453 > 120.000 ...... NG
구 분 SM400
Top Flange92.8 < /rℓ
Fcagz = 1200000 / (6700+( /r)²) = 56.580ℓ
Bottom Flange92.8 < /rℓ
7.1 단면 제원사용강종 :B1 B2
b1 b2
tf1 tf2
tw
7.2 단면 계수A (mm2) Iyy (mm4) Izz (mm4)ry (mm) rz (mm) K (mm4)
y1 (mm) z1 (mm) y2 (mm) z2 (mm)y3 (mm) z3 (mm) y4 (mm) z4 (mm)
7.3 작용하중Fx (kN) Fy (kN) Fz (kN) Mx (kN∙m) My (kN∙m) Mz (kN∙m)
거치시 (7단계)(60min)
7.4 응력검토[1] 거치시 (7단계)(60min)
허용휨인장응력 (fta) [도기 P3-10, 표3.3.1]
40 이하40 이하40 이하
국부좌굴을 고려하지 않은 허용축방향압축응력 (fcag) [도기 P3-11, 표3.3.2] ▶ Y 축에 대한 유효좌굴길이
ℓy
ry
ℓy /ry
▶ Z 축에 대한 유효좌굴길이ℓz
rz
ℓz /rz
40 이하40 이하
![Page 70: 응력검토 샘플](https://reader033.vdocuments.pub/reader033/viewer/2022061114/545fa8e7b1af9f673b8b4bc4/html5/thumbnails/70.jpg)
Bottom FlangeFcagz = 1200000 / (6700+( /r)²) = 56.580ℓ
Left Web92.8 < /rℓ
Fcagz = 1200000 / (6700+( /r)²) = 56.580ℓ
Top Flange18.6 < /r ≤ 92.8ℓ
Fcagy = 140 - 0.82×( /r - 18.6) = 115.991ℓ
Bottom Flange18.6 < /r ≤ 92.8ℓ
Fcagy = 140 - 0.82×( /r - 18.6) = 115.991ℓ
Left Web18.6 < /r ≤ 92.8ℓ
Fcagy = 140 - 0.82×( /r - 18.6) = 115.991ℓ
3) ▶ Top Flange
압축플랜지 고정점간 거리 ℓ = 1906.856 mm압축플랜지 폭 b = 50.000 mm복부판의 총단면적 = 425.000 압축플랜지 총단면적 = 375.000
= 1.133 ≤ 2.000 , = ### , = 1.889
구 분 SM400
≤ 2.0 /b > 30.0 [NG]ℓ
0.000 ▶ Bottom Flange
압축플랜지 고정점간 거리 ℓ = 1906.856 mm
압축플랜지 폭 b = 50.000 mm
복부판의 총단면적 = 425.000
압축플랜지 총단면적 = 375.000
= 1.133 ≤ 2.000 , = ### , = 1.889
구 분 SM400
≤ 2.0 /b > 30.0 [NG]ℓ
0.000 ▶ Left Web
압축플랜지 고정점간 거리 ℓ = 1906.856 mm압축플랜지 폭 b = 100.000 mm복부판의 총단면적 = 675.000 압축플랜지 총단면적 = 500.000
= 1.350 ≤ 2.000 , = ### , = 1.917
구 분 SM400
≤ 2.0 4.6 < /b ≤ 30.0ℓ
140 - 2.49×( /b - 4.6) = 103.973ℓ
4) 허용 오일러 좌굴응력523.459 82.708
40 이하40 이하40 이하40 이하40 이하
허용휨압축응력 (fbagy) [도기 P3-16, 표3.3.4]
Aw mm2
Ac mm2
40 이하
Aw mm2
Ac mm2
40 이하
Aw mm2
Ac mm2
40 이하
[도기 P3-47, 식3.4.13~14]fEy (MPa) 1200000/(ly/ry)2
fEz (MPa) 1200000/(lz/rz)2
w
c
AA
lb
w
c
AA
32
w
c
AK
A
w
c
AA
lb
w
c
AA
32
w
c
AK
A
w
c
AA
lb
w
c
AA
32
w
c
AK
A
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5)
구 분 SM400Top Flange 80.000
Bottom Flange 80.000 Left Web 80.000
6) 자유돌출판의 국부좌굴에 대한 허용응력 ▶ 압축응력을 받는 자유돌출판의 최소두께
Top Flange(L)= b / 16 = 50.0 / 16.0 = 3.125 mm ≤ = 7.500 mm ...... OK
Bottom Flange(L)= b / 16 = 50.0 / 16.0 = 3.125 mm ≤ = 7.500 mm ...... OK
▶Top Flange(L) t = 7.500 mm
= b / 12.9 = 50.0 / 12.9 = 3.876 mm구 분 SM400
b/12.9 ≤ t140.000
Bottom Flange(L) t = 7.500 mm= b / 12.9 = 50.0 / 12.9 = 3.876 mm
구 분 SM400b/12.9 ≤ t140.000
7) 보강된판 및 양연지지판의 국부좌굴에 대한 허용응력▶ Left Web
판두께 t = 5.0 mm
판의 고정연 사이의 거리 b = 85.0 mm
응력구배계수 i = = 1.000 응력구배 Φ = = 0.000 판의 양연에서의 응력 = -48.396 MPa, = -48.396 MPa
압축응력을 받는 양연지지판의 최소두께t ≤ 40mm
= b / 56i = 85 / 56 = 1.5 ≤ t = 5.0 mm ...... OK
구 분 SM400b/39.3i ≤ t140.000
8) 허용응력 요약구 분
Top Flange 140.000 56.580 115.991 140.000 80.000 Bottom Flange 140.000 56.580 115.991 140.000 80.000
Left Web 140.000 56.580 115.991 140.000 80.000 =
허용전단응력 (υa) [도기 P3-18, 표3.3.5]
40 이하40 이하40 이하
[도기 P3-37]tmin tf
tmin tf
자유돌출판의 국부좌굴에 대한 허용응력 (fcal) [도기 P3-38, 표3.4.4]
t1
40 이하
t1
40 이하
0.65Φ2 + 0.13Φ + 1.0(f1 - f2) / f1
f1 f2
[도기 P3-35, 표3.4.2]
tmin
양연지지판의 국부좌굴에 대한 허용응력 (fcal) [도기 P3-36, 표3.4.3]
40 이하
fcal fcaz fcay fta υa
fca fcag ∙ fcal / fcao.
![Page 72: 응력검토 샘플](https://reader033.vdocuments.pub/reader033/viewer/2022061114/545fa8e7b1af9f673b8b4bc4/html5/thumbnails/72.jpg)
9) 축방향력 및 휨모멘트를 받는 부재의 허용응력 검토▶ 축방향력에 의한 응력
= P / A = -56.865 / 1.1750E+03 = -48.396 MPa
▶ 휨모멘트에 의한 응력= = 0.000 MPa = = 0.000 MPa= = 0.000 MPa = = 0.000 MPa= = 0.000 MPa = = 0.000 MPa= = 0.000 MPa = = 0.000 MPa
-48.396 -48.396 -48.396 -48.396
▶ Position 1 (y-direction)
-48.396 +0.000
+0.000
( 1 --48.396
) ( 1 --48.396
)523.459 82.708
= -48.396 MPa ≤ = 140.000 MPa ...... OK
-48.396 +
0.000 +
0.000 56.580
0.000 ( 1 --48.396
) 140.000 ( 1 --48.396
)523.459 82.708
= - ...... NG
▶ Position 2 (y-direction)
-48.396 +0.000
+0.000
( 1 --48.396
) ( 1 --48.396
)523.459 82.708
= -48.396 MPa ≤ = 140.000 MPa ...... OK
-48.396 +
0.000 +
0.000 56.580
0.000 ( 1 --48.396
) 140.000 ( 1 --48.396
)523.459 82.708
= - ...... NG
▶ Position 3 (y-direction)
fc × 103
fby1 My × z1 / Iyy fbz1 Mz × y1 / Izz
fby2 My × z2 / Iyy fbz2 Mz × y2 / Izz
fby3 My × z3 / Iyy fbz3 Mz × y3 / Izz
fby4 My × z4 / Iyy fbz4 Mz × y4 / Izz
f11 (y1, z1) f22 (y2, z2)f33 (y3, z3) f44 (y4, z4)
fcal
∵ fbagy =0 또는 fbagz =0 일 경우 검토식을 적용할 수 없습니다.
fcal
∵ fbagy =0 또는 fbagz =0 일 경우 검토식을 적용할 수 없습니다.
11
bcy bczc cal
cc
EzEy
f ff fffff
1.011
bcyc bcz
caz ccbaobagy
EzEy
ff ff ff ff ff
11
bcy bczc cal
cc
EzEy
f ff fffff
1.011
bcyc bcz
caz ccbaobagy
EzEy
ff ff ff ff
ff
![Page 73: 응력검토 샘플](https://reader033.vdocuments.pub/reader033/viewer/2022061114/545fa8e7b1af9f673b8b4bc4/html5/thumbnails/73.jpg)
-48.396 +0.000
+0.000
( 1 --48.396
) ( 1 --48.396
)523.459 82.708
= -48.396 MPa ≤ = 140.000 MPa ...... OK
-48.396 +
0.000 +
0.000 56.580
0.000 ( 1 --48.396
) 140.000 ( 1 --48.396
)523.459 82.708
= - ...... NG
▶ Position 4 (y-direction)
-48.396 +0.000
+0.000
( 1 --48.396
) ( 1 --48.396
)523.459 82.708
= -48.396 MPa ≤ = 140.000 MPa ...... OK
-48.396 +
0.000 +
0.000 56.580
0.000 ( 1 --48.396
) 140.000 ( 1 --48.396
)523.459 82.708
= - ...... NG
▶ Position 1 (z-direction)
-48.396 +0.000
+0.000
( 1 --48.396
) ( 1 --48.396
)82.708 523.459
= -48.396 MPa ≤ = 140.000 MPa ...... OK
-48.396 +
0.000 +
0.000 115.991
103.973 ( 1 --48.396
) 140.000 ( 1 --48.396
)82.708 523.459
= -0.417 ≤ 1.0 ...... OK
fcal
∵ fbagy =0 또는 fbagz =0 일 경우 검토식을 적용할 수 없습니다.
fcal
∵ fbagy =0 또는 fbagz =0 일 경우 검토식을 적용할 수 없습니다.
fcal
11
bcy bczc cal
cc
EzEy
f ff fffff
1.011
bcyc bcz
caz ccbaobagy
EzEy
ff ff ff ff
ff
11
bcy bczc cal
cc
EzEy
f ff fffff
1.011
bcyc bcz
caz ccbaobagy
EzEy
ff ff ff ff
ff
1 1
bcybczc cal
c c
Ez Ey
fff ff ff f
1.01 1
bcyc bcz
cay c cbagz bao
Ez Ey
ff ff f ff f
f f
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▶ Position 2 (z-direction)
-48.396 +0.000
+0.000
( 1 --48.396
) ( 1 --48.396
)82.708 523.459
= -48.396 MPa ≤ = 140.000 MPa ...... OK
-48.396 +
0.000 +
0.000 115.991
103.973 ( 1 --48.396
) 140.000 ( 1 --48.396
)82.708 523.459
= -0.417 ≤ 1.0 ...... OK
▶ Position 3 (z-direction)
-48.396 +0.000
+0.000
( 1 --48.396
) ( 1 --48.396
)82.708 523.459
= -48.396 MPa ≤ = 140.000 MPa ...... OK
-48.396 +
0.000 +
0.000 115.991
103.973 ( 1 --48.396
) 140.000 ( 1 --48.396
)82.708 523.459
= -0.417 ≤ 1.0 ...... OK
▶ Position 4 (z-direction)
-48.396 +0.000
+0.000
( 1 --48.396
) ( 1 --48.396
)82.708 523.459
= -48.396 MPa ≤ = 140.000 MPa ...... OK
-48.396 +
0.000 +
0.000 115.991
103.973 ( 1 --48.396
) 140.000 ( 1 --48.396
)82.708 523.459
= -0.417 ≤ 1.0 ...... OK
10) 전단응력에 대한 검토
fcal
fcal
fcal
1 1
bcybczc cal
c c
Ez Ey
fff ff ff f
1.01 1
bcyc bcz
cay c cbagz bao
Ez Ey
ff ff f ff f
f f
1 1
bcybczc cal
c c
Ez Ey
fff ff ff f
1.01 1
bcyc bcz
cay c cbagz bao
Ez Ey
ff ff f ff f
f f
1 1
bcybczc cal
c c
Ez Ey
fff ff ff f
1.01 1
bcyc bcz
cay c cbagz bao
Ez Ey
ff ff f ff f
f f
![Page 75: 응력검토 샘플](https://reader033.vdocuments.pub/reader033/viewer/2022061114/545fa8e7b1af9f673b8b4bc4/html5/thumbnails/75.jpg)
== 0.075 / 500.000 + -0.001 × 5.000E+00 / 1.7214E+04= 0.000 MPa ≤ = 80.000 MPa ...... OK== 0.000 / 500.000 + -0.001 × 7.500E+00 / 1.7214E+04= -0.224 MPa ≤ = 80.000 MPa ...... OK
t =
11) 합성응력에 대한 검토= (
0.000 + (
-0.224 = 0.000 < 1.200 ...... OK
140.000 80.000
υz Fz / Aw + Mx × t / K× 103 × 106
υa
υy Fy / Af + Mx × t / K× 103 × 106
υa
여기서, 복부 두께 .
)2 )22 2
b b
a a
f vf v
![Page 76: 응력검토 샘플](https://reader033.vdocuments.pub/reader033/viewer/2022061114/545fa8e7b1af9f673b8b4bc4/html5/thumbnails/76.jpg)
2.944692E+051.721354E+04
50.0 -50.0
비 고
SM400140.000 140.000 140.000
...... NG
SM40092.8 < /rℓ
Fcagz = 1200000 / (6700+( /r)²) = 56.580ℓ
92.8 < /rℓ
도기 P3-10, 표3.3.1]
도기 P3-11, 표3.3.2]
![Page 77: 응력검토 샘플](https://reader033.vdocuments.pub/reader033/viewer/2022061114/545fa8e7b1af9f673b8b4bc4/html5/thumbnails/77.jpg)
Fcagz = 1200000 / (6700+( /r)²) = 56.580ℓ
92.8 < /rℓ
Fcagz = 1200000 / (6700+( /r)²) = 56.580ℓ
18.6 < /r ≤ 92.8ℓ
Fcagy = 140 - 0.82×( /r - 18.6) = 115.991ℓ
18.6 < /r ≤ 92.8ℓ
Fcagy = 140 - 0.82×( /r - 18.6) = 115.991ℓ
18.6 < /r ≤ 92.8ℓ
Fcagy = 140 - 0.82×( /r - 18.6) = 115.991ℓ
SM400/b > 30.0 [NG]ℓ
0.000
SM400/b > 30.0 [NG]ℓ
0.000
SM4004.6 < /b ≤ 30.0ℓ
140 - 2.49×( /b - 4.6) = 103.973ℓ
523.459 82.708
도기 P3-16, 표3.3.4]
P3-47, 식3.4.13~14]
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SM40080.000 80.000 80.000
...... OK
...... OK
SM400b/12.9 ≤ t140.000
SM400b/12.9 ≤ t140.000
...... OK
SM400b/39.3i ≤ t140.000
80.000 80.000 80.000
P3-18, 표3.3.5]
도기 P3-37]
P3-38, 표3.4.4]
도기 P3-35, 표3.4.2]
도기 P3-36, 표3.4.3]
υa
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-48.396 -48.396
...... OK
...... NG
...... OK
...... NG
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...... OK
...... NG
...... OK
...... NG
...... OK
...... OK
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...... OK
...... OK
...... OK
...... OK
...... OK
...... OK
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1.7214E+04...... OK
1.7214E+04...... OK
...... OK
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SM400= 0.0500 m = 0.0500 m= 0.0450 m = 0.0450 m= 0.0075 m = 0.0075 m= 0.0050 m H = 0.1000 m
1.175000E+03 1.863698E+06 2.944692E+053.982620E+01 1.583073E+01 1.721354E+04
검토위치 -16.9 50.0 33.1 50.0 33.1 -50.0 -16.9 -50.0
구 분 비 고-56.693 0.000 -0.075 -0.001 0.000 0.000
1)
구 분 SM400Top Flange 140.000
Bottom Flange 140.000 Left Web 140.000
2)
부재의 유효좌굴길이 = 1906.856 mm부재 총단면의 단면회전반경 = 39.826 mm세장비 = 47.879
부재의 유효좌굴길이 = 1906.856 mm
부재 총단면의 단면회전반경 = 15.831 mm
세장비 = 120.453
▶ 세장비 검토세장비 / rℓ = 120.453 > 120.000 ...... NG
구 분 SM400
Top Flange92.8 < /rℓ
Fcagz = 1200000 / (6700+( /r)²) = 56.580ℓ
Bottom Flange92.8 < /rℓ
8.1 단면 제원사용강종 :B1 B2
b1 b2
tf1 tf2
tw
8.2 단면 계수A (mm2) Iyy (mm4) Izz (mm4)ry (mm) rz (mm) K (mm4)
y1 (mm) z1 (mm) y2 (mm) z2 (mm)y3 (mm) z3 (mm) y4 (mm) z4 (mm)
8.3 작용하중Fx (kN) Fy (kN) Fz (kN) Mx (kN∙m) My (kN∙m) Mz (kN∙m)
거치시 (7단계)(60min)
8.4 응력검토[1] 거치시 (7단계)(60min)
허용휨인장응력 (fta) [도기 P3-10, 표3.3.1]
40 이하40 이하40 이하
국부좌굴을 고려하지 않은 허용축방향압축응력 (fcag) [도기 P3-11, 표3.3.2] ▶ Y 축에 대한 유효좌굴길이
ℓy
ry
ℓy /ry
▶ Z 축에 대한 유효좌굴길이ℓz
rz
ℓz /rz
40 이하40 이하
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Bottom FlangeFcagz = 1200000 / (6700+( /r)²) = 56.580ℓ
Left Web92.8 < /rℓ
Fcagz = 1200000 / (6700+( /r)²) = 56.580ℓ
Top Flange18.6 < /r ≤ 92.8ℓ
Fcagy = 140 - 0.82×( /r - 18.6) = 115.991ℓ
Bottom Flange18.6 < /r ≤ 92.8ℓ
Fcagy = 140 - 0.82×( /r - 18.6) = 115.991ℓ
Left Web18.6 < /r ≤ 92.8ℓ
Fcagy = 140 - 0.82×( /r - 18.6) = 115.991ℓ
3) ▶ Top Flange
압축플랜지 고정점간 거리 ℓ = 1906.856 mm압축플랜지 폭 b = 50.000 mm복부판의 총단면적 = 425.000 압축플랜지 총단면적 = 375.000
= 1.133 ≤ 2.000 , = ### , = 1.889
구 분 SM400
≤ 2.0 /b > 30.0 [NG]ℓ
0.000 ▶ Bottom Flange
압축플랜지 고정점간 거리 ℓ = 1906.856 mm
압축플랜지 폭 b = 50.000 mm
복부판의 총단면적 = 425.000
압축플랜지 총단면적 = 375.000
= 1.133 ≤ 2.000 , = ### , = 1.889
구 분 SM400
≤ 2.0 /b > 30.0 [NG]ℓ
0.000 ▶ Left Web
압축플랜지 고정점간 거리 ℓ = 1906.856 mm압축플랜지 폭 b = 100.000 mm복부판의 총단면적 = 675.000 압축플랜지 총단면적 = 500.000
= 1.350 ≤ 2.000 , = ### , = 1.917
구 분 SM400
≤ 2.0 4.6 < /b ≤ 30.0ℓ
140 - 2.49×( /b - 4.6) = 103.973ℓ
4) 허용 오일러 좌굴응력523.459 82.708
40 이하40 이하40 이하40 이하40 이하
허용휨압축응력 (fbagy) [도기 P3-16, 표3.3.4]
Aw mm2
Ac mm2
40 이하
Aw mm2
Ac mm2
40 이하
Aw mm2
Ac mm2
40 이하
[도기 P3-47, 식3.4.13~14]fEy (MPa) 1200000/(ly/ry)2
fEz (MPa) 1200000/(lz/rz)2
w
c
AA
lb
w
c
AA
32
w
c
AK
A
w
c
AA
lb
w
c
AA
32
w
c
AK
A
w
c
AA
lb
w
c
AA
32
w
c
AK
A
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5)
구 분 SM400Top Flange 80.000
Bottom Flange 80.000 Left Web 80.000
6) 자유돌출판의 국부좌굴에 대한 허용응력 ▶ 압축응력을 받는 자유돌출판의 최소두께
Top Flange(L)= b / 16 = 50.0 / 16.0 = 3.125 mm ≤ = 7.500 mm ...... OK
Bottom Flange(L)= b / 16 = 50.0 / 16.0 = 3.125 mm ≤ = 7.500 mm ...... OK
▶Top Flange(L) t = 7.500 mm
= b / 12.9 = 50.0 / 12.9 = 3.876 mm구 분 SM400
b/12.9 ≤ t140.000
Bottom Flange(L) t = 7.500 mm= b / 12.9 = 50.0 / 12.9 = 3.876 mm
구 분 SM400b/12.9 ≤ t140.000
7) 보강된판 및 양연지지판의 국부좌굴에 대한 허용응력▶ Left Web
판두께 t = 5.0 mm
판의 고정연 사이의 거리 b = 85.0 mm
응력구배계수 i = = 1.000 응력구배 Φ = = 0.000 판의 양연에서의 응력 = -48.250 MPa, = -48.250 MPa
압축응력을 받는 양연지지판의 최소두께t ≤ 40mm
= b / 56i = 85 / 56 = 1.5 ≤ t = 5.0 mm ...... OK
구 분 SM400b/39.3i ≤ t140.000
8) 허용응력 요약구 분
Top Flange 140.000 56.580 115.991 140.000 80.000 Bottom Flange 140.000 56.580 115.991 140.000 80.000
Left Web 140.000 56.580 115.991 140.000 80.000 =
허용전단응력 (υa) [도기 P3-18, 표3.3.5]
40 이하40 이하40 이하
[도기 P3-37]tmin tf
tmin tf
자유돌출판의 국부좌굴에 대한 허용응력 (fcal) [도기 P3-38, 표3.4.4]
t1
40 이하
t1
40 이하
0.65Φ2 + 0.13Φ + 1.0(f1 - f2) / f1
f1 f2
[도기 P3-35, 표3.4.2]
tmin
양연지지판의 국부좌굴에 대한 허용응력 (fcal) [도기 P3-36, 표3.4.3]
40 이하
fcal fcaz fcay fta υa
fca fcag ∙ fcal / fcao.
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9) 축방향력 및 휨모멘트를 받는 부재의 허용응력 검토▶ 축방향력에 의한 응력
= P / A = -56.693 / 1.1750E+03 = -48.250 MPa
▶ 휨모멘트에 의한 응력= = 0.000 MPa = = 0.000 MPa= = 0.000 MPa = = 0.000 MPa= = 0.000 MPa = = 0.000 MPa= = 0.000 MPa = = 0.000 MPa
-48.250 -48.250 -48.250 -48.250
▶ Position 1 (y-direction)
-48.250 +0.000
+0.000
( 1 --48.250
) ( 1 --48.250
)523.459 82.708
= -48.250 MPa ≤ = 140.000 MPa ...... OK
-48.250 +
0.000 +
0.000 56.580
0.000 ( 1 --48.250
) 140.000 ( 1 --48.250
)523.459 82.708
= - ...... NG
▶ Position 2 (y-direction)
-48.250 +0.000
+0.000
( 1 --48.250
) ( 1 --48.250
)523.459 82.708
= -48.250 MPa ≤ = 140.000 MPa ...... OK
-48.250 +
0.000 +
0.000 56.580
0.000 ( 1 --48.250
) 140.000 ( 1 --48.250
)523.459 82.708
= - ...... NG
▶ Position 3 (y-direction)
fc × 103
fby1 My × z1 / Iyy fbz1 Mz × y1 / Izz
fby2 My × z2 / Iyy fbz2 Mz × y2 / Izz
fby3 My × z3 / Iyy fbz3 Mz × y3 / Izz
fby4 My × z4 / Iyy fbz4 Mz × y4 / Izz
f11 (y1, z1) f22 (y2, z2)f33 (y3, z3) f44 (y4, z4)
fcal
∵ fbagy =0 또는 fbagz =0 일 경우 검토식을 적용할 수 없습니다.
fcal
∵ fbagy =0 또는 fbagz =0 일 경우 검토식을 적용할 수 없습니다.
11
bcy bczc cal
cc
EzEy
f ff fffff
1.011
bcyc bcz
caz ccbaobagy
EzEy
ff ff ff ff ff
11
bcy bczc cal
cc
EzEy
f ff fffff
1.011
bcyc bcz
caz ccbaobagy
EzEy
ff ff ff ff
ff
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-48.250 +0.000
+0.000
( 1 --48.250
) ( 1 --48.250
)523.459 82.708
= -48.250 MPa ≤ = 140.000 MPa ...... OK
-48.250 +
0.000 +
0.000 56.580
0.000 ( 1 --48.250
) 140.000 ( 1 --48.250
)523.459 82.708
= - ...... NG
▶ Position 4 (y-direction)
-48.250 +0.000
+0.000
( 1 --48.250
) ( 1 --48.250
)523.459 82.708
= -48.250 MPa ≤ = 140.000 MPa ...... OK
-48.250 +
0.000 +
0.000 56.580
0.000 ( 1 --48.250
) 140.000 ( 1 --48.250
)523.459 82.708
= - ...... NG
▶ Position 1 (z-direction)
-48.250 +0.000
+0.000
( 1 --48.250
) ( 1 --48.250
)82.708 523.459
= -48.250 MPa ≤ = 140.000 MPa ...... OK
-48.250 +
0.000 +
0.000 115.991
103.973 ( 1 --48.250
) 140.000 ( 1 --48.250
)82.708 523.459
= -0.416 ≤ 1.0 ...... OK
fcal
∵ fbagy =0 또는 fbagz =0 일 경우 검토식을 적용할 수 없습니다.
fcal
∵ fbagy =0 또는 fbagz =0 일 경우 검토식을 적용할 수 없습니다.
fcal
11
bcy bczc cal
cc
EzEy
f ff fffff
1.011
bcyc bcz
caz ccbaobagy
EzEy
ff ff ff ff
ff
11
bcy bczc cal
cc
EzEy
f ff fffff
1.011
bcyc bcz
caz ccbaobagy
EzEy
ff ff ff ff
ff
1 1
bcybczc cal
c c
Ez Ey
fff ff ff f
1.01 1
bcyc bcz
cay c cbagz bao
Ez Ey
ff ff f ff f
f f
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▶ Position 2 (z-direction)
-48.250 +0.000
+0.000
( 1 --48.250
) ( 1 --48.250
)82.708 523.459
= -48.250 MPa ≤ = 140.000 MPa ...... OK
-48.250 +
0.000 +
0.000 115.991
103.973 ( 1 --48.250
) 140.000 ( 1 --48.250
)82.708 523.459
= -0.416 ≤ 1.0 ...... OK
▶ Position 3 (z-direction)
-48.250 +0.000
+0.000
( 1 --48.250
) ( 1 --48.250
)82.708 523.459
= -48.250 MPa ≤ = 140.000 MPa ...... OK
-48.250 +
0.000 +
0.000 115.991
103.973 ( 1 --48.250
) 140.000 ( 1 --48.250
)82.708 523.459
= -0.416 ≤ 1.0 ...... OK
▶ Position 4 (z-direction)
-48.250 +0.000
+0.000
( 1 --48.250
) ( 1 --48.250
)82.708 523.459
= -48.250 MPa ≤ = 140.000 MPa ...... OK
-48.250 +
0.000 +
0.000 115.991
103.973 ( 1 --48.250
) 140.000 ( 1 --48.250
)82.708 523.459
= -0.416 ≤ 1.0 ...... OK
10) 전단응력에 대한 검토
fcal
fcal
fcal
1 1
bcybczc cal
c c
Ez Ey
fff ff ff f
1.01 1
bcyc bcz
cay c cbagz bao
Ez Ey
ff ff f ff f
f f
1 1
bcybczc cal
c c
Ez Ey
fff ff ff f
1.01 1
bcyc bcz
cay c cbagz bao
Ez Ey
ff ff f ff f
f f
1 1
bcybczc cal
c c
Ez Ey
fff ff ff f
1.01 1
bcyc bcz
cay c cbagz bao
Ez Ey
ff ff f ff f
f f
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== -0.075 / 500.000 + -0.001 × 5.000E+00 / 1.7214E+04= -0.298 MPa ≤ = 80.000 MPa ...... OK== 0.000 / 500.000 + -0.001 × 7.500E+00 / 1.7214E+04= -0.224 MPa ≤ = 80.000 MPa ...... OK
t =
11) 합성응력에 대한 검토= (
0.000 + (
-0.298 = 0.000 < 1.200 ...... OK
140.000 80.000
υz Fz / Aw + Mx × t / K× 103 × 106
υa
υy Fy / Af + Mx × t / K× 103 × 106
υa
여기서, 복부 두께 .
)2 )22 2
b b
a a
f vf v
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2.944692E+051.721354E+04
50.0 -50.0
비 고
SM400140.000 140.000 140.000
...... NG
SM40092.8 < /rℓ
Fcagz = 1200000 / (6700+( /r)²) = 56.580ℓ
92.8 < /rℓ
도기 P3-10, 표3.3.1]
도기 P3-11, 표3.3.2]
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Fcagz = 1200000 / (6700+( /r)²) = 56.580ℓ
92.8 < /rℓ
Fcagz = 1200000 / (6700+( /r)²) = 56.580ℓ
18.6 < /r ≤ 92.8ℓ
Fcagy = 140 - 0.82×( /r - 18.6) = 115.991ℓ
18.6 < /r ≤ 92.8ℓ
Fcagy = 140 - 0.82×( /r - 18.6) = 115.991ℓ
18.6 < /r ≤ 92.8ℓ
Fcagy = 140 - 0.82×( /r - 18.6) = 115.991ℓ
SM400/b > 30.0 [NG]ℓ
0.000
SM400/b > 30.0 [NG]ℓ
0.000
SM4004.6 < /b ≤ 30.0ℓ
140 - 2.49×( /b - 4.6) = 103.973ℓ
523.459 82.708
도기 P3-16, 표3.3.4]
P3-47, 식3.4.13~14]
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SM40080.000 80.000 80.000
...... OK
...... OK
SM400b/12.9 ≤ t140.000
SM400b/12.9 ≤ t140.000
...... OK
SM400b/39.3i ≤ t140.000
80.000 80.000 80.000
P3-18, 표3.3.5]
도기 P3-37]
P3-38, 표3.4.4]
도기 P3-35, 표3.4.2]
도기 P3-36, 표3.4.3]
υa
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-48.250 -48.250
...... OK
...... NG
...... OK
...... NG
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...... OK
...... NG
...... OK
...... NG
...... OK
...... OK
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...... OK
...... OK
...... OK
...... OK
...... OK
...... OK
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1.7214E+04...... OK
1.7214E+04...... OK
...... OK
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SM400= 0.0750 m H = 0.0750 m= 0.0090 m = 0.0090 m
1.269000E+03 6.644934E+05 6.644934E+052.288308E+01 2.288308E+01 3.426300E+04
검토위치 -22.1 22.1 52.9 22.1 -13.1 -52.9 -22.1 -52.9
구 분 비 고-4.504 -0.059 0.118 -0.002 -0.059 -0.022
1)
구 분 SM400Top Flange 140.000 Left Web 140.000
2)
부재의 유효좌굴길이 = 1131.371 mm부재 총단면의 단면회전반경 = 22.883 mm세장비 = 49.441
부재의 유효좌굴길이 = 1131.371 mm
부재 총단면의 단면회전반경 = 22.883 mm
세장비 = 49.441
▶ 세장비 검토세장비 / rℓ = 49.441 ≤ 120.000 ...... OK
구 분 SM400
Top Flange18.6 < /r ≤ 92.8ℓ
Fcagz = 140 - 0.82×( /r - 18.6) = 114.710ℓ
Left Web18.6 < /r ≤ 92.8ℓ
Fcagz = 140 - 0.82×( /r - 18.6) = 114.710ℓ
9.1 단면 제원사용강종 :B1
tf1 tw
9.2 단면 계수A (mm2) Iyy (mm4) Izz (mm4)ry (mm) rz (mm) K (mm4)
y1 (mm) z1 (mm) y2 (mm) z2 (mm)y3 (mm) z3 (mm) y4 (mm) z4 (mm)
9.3 작용하중Fx (kN) Fy (kN) Fz (kN) Mx (kN∙m) My (kN∙m) Mz (kN∙m)
작동시 교축풍하중(63min)
9.4 응력검토[1] 작동시 교축풍하중(63min)
허용휨인장응력 (fta) [도기 P3-10, 표3.3.1]
40 이하40 이하
국부좌굴을 고려하지 않은 허용축방향압축응력 (fcag) [도기 P3-11, 표3.3.2] ▶ Y 축에 대한 유효좌굴길이
ℓy
ry
ℓy /ry
▶ Z 축에 대한 유효좌굴길이ℓz
rz
ℓz /rz
40 이하40 이하
![Page 98: 응력검토 샘플](https://reader033.vdocuments.pub/reader033/viewer/2022061114/545fa8e7b1af9f673b8b4bc4/html5/thumbnails/98.jpg)
Top Flange18.6 < /r ≤ 92.8ℓ
Fcagy = 140 - 0.82×( /r - 18.6) = 114.710ℓ
Left Web18.6 < /r ≤ 92.8ℓ
Fcagy = 140 - 0.82×( /r - 18.6) = 114.710ℓ
3) ▶ Top Flange
압축플랜지 고정점간 거리 ℓ = 1131.371 mm
압축플랜지 폭 b = 75.000 mm복부판의 총단면적 = 594.000 압축플랜지 총단면적 = 675.000
= 0.880 ≤ 2.000 , = ### , = 1.855
구 분 SM400
≤ 2.0 4.6 < /b ≤ 30.0ℓ
140 - 2.49×( /b - 4.6) = 113.892ℓ
▶ Left Web
압축플랜지 고정점간 거리 ℓ = 1131.371 mm
압축플랜지 폭 b = 75.000 mm
복부판의 총단면적 = 675.000
압축플랜지 총단면적 = 675.000
= 1.000 ≤ 2.000 , = ### , = 1.871
구 분 SM400
≤ 2.0 4.6 < /b ≤ 30.0ℓ
140 - 2.49×( /b - 4.6) = 113.892ℓ
4) 허용 오일러 좌굴응력490.908 490.908
5)구 분 SM400
Top Flange 80.000 Left Web 80.000
6) 자유돌출판의 국부좌굴에 대한 허용응력 ▶ 압축응력을 받는 자유돌출판의 최소두께
Top Flange(L)= b / 16 = 75.0 / 16.0 = 4.688 mm ≤ = 9.000 mm ...... OK
Left Web(T)= b / 16 = 75.0 / 16.0 = 4.688 mm ≤ = 9.000 mm ...... OK
▶Top Flange(L) t = 9.000 mm
= b / 12.9 = 75.0 / 12.9 = 5.814 mm
구 분 SM400
40 이하40 이하
허용휨압축응력 (fbagy) [도기 P3-16, 표3.3.4]
Aw mm2
Ac mm2
40 이하
Aw mm2
Ac mm2
40 이하
[도기 P3-47, 식3.4.13~14]fEy (MPa) 1200000/(ly/ry)2
fEz (MPa) 1200000/(lz/rz)2
허용전단응력 (υa) [도기 P3-18, 표3.3.5]
40 이하40 이하
[도기 P3-37]tmin tf
tmin tf
자유돌출판의 국부좌굴에 대한 허용응력 (fcal) [도기 P3-38, 표3.4.4]
t1
w
c
AA
lb
w
c
AA
32
w
c
AK
A
w
c
AA
lb
w
c
AA
32
w
c
AK
A
![Page 99: 응력검토 샘플](https://reader033.vdocuments.pub/reader033/viewer/2022061114/545fa8e7b1af9f673b8b4bc4/html5/thumbnails/99.jpg)
b/12.9 ≤ t140.000
Left Web(T) t = 9.000 mm= b / 12.9 = 75.0 / 12.9 = 5.814 mm
구 분 SM400b/12.9 ≤ t140.000
7) 허용응력 요약구 분
Top Flange 140.000 114.710 114.710 140.000 80.000 Left Web 140.000 114.710 114.710 140.000 80.000
=
8) 축방향력 및 휨모멘트를 받는 부재의 허용응력 검토▶ 축방향력에 의한 응력
= P / A = -4.504 / 1.2690E+03 = -3.549 MPa
▶ 휨모멘트에 의한 응력= = 1.970 MPa = = -0.728 MPa= = 1.970 MPa = = 1.749 MPa= = -4.731 MPa = = -0.431 MPa= = -4.731 MPa = = -0.728 MPa
-2.307 0.170 -8.711 -9.008
▶ Position 1 (y-direction)
-3.549 +1.970
+-0.728
( 1 --3.549
) ( 1 --3.549
)490.908 490.908
= -2.298 MPa ≤ = 140.000 MPa ...... OK
-3.549 +
1.970 +
-0.728 114.710
113.892 ( 1 --3.549
) 140.000 ( 1 --3.549
)490.908 490.908
= -0.019 ≤ 1.000 ...... OK
▶ Position 2 (y-direction)
-3.549 +1.970
+1.749
40 이하
t1
40 이하
fcal fcaz fcay fta υa
fca fcag ∙ fcal / fcao.
fc × 103
fby1 My × z1 / Iyy fbz1 Mz × y1 / Izz
fby2 My × z2 / Iyy fbz2 Mz × y2 / Izz
fby3 My × z3 / Iyy fbz3 Mz × y3 / Izz
fby4 My × z4 / Iyy fbz4 Mz × y4 / Izz
f11 (y1, z1) f22 (y2, z2)f33 (y3, z3) f44 (y4, z4)
fcal
11
bcy bczc cal
cc
EzEy
f ff fffff
1.011
bcyc bcz
caz ccbaobagy
EzEy
ff ff ff ff
ff
11
bcy bczc cal
cc
EzEy
f ff fffff
![Page 100: 응력검토 샘플](https://reader033.vdocuments.pub/reader033/viewer/2022061114/545fa8e7b1af9f673b8b4bc4/html5/thumbnails/100.jpg)
-3.549 +( 1 -
-3.549 )
+( 1 -
-3.549 )
490.908 490.908 = 0.197 MPa ≤ = 140.000 MPa ...... OK
▶ Position 3 (y-direction)
-3.549 +-4.731
+-0.431
( 1 --3.549
) ( 1 --3.549
)490.908 490.908
= -8.748 MPa ≤ = 140.000 MPa ...... OK
-3.549 +
-4.731 +
-0.431 114.710
113.892 ( 1 --3.549
) 140.000 ( 1 --3.549
)490.908 490.908
= -0.076 ≤ 1.000 ...... OK
▶ Position 4 (y-direction)
-3.549 +-4.731
+-0.728
( 1 --3.549
) ( 1 --3.549
)490.908 490.908
= -9.048 MPa ≤ = 140.000 MPa ...... OK
-3.549 +
-4.731 +
-0.728 114.710
113.892 ( 1 --3.549
) 140.000 ( 1 --3.549
)490.908 490.908
= -0.078 ≤ 1.000 ...... OK
▶ Position 1 (z-direction)
-3.549 +-0.728
+1.970
( 1 --3.549
) ( 1 --3.549
)490.908 490.908
= -2.298 MPa ≤ = 140.000 MPa ...... OK
-3.549 +
-0.728 +
1.970 114.710
113.892 ( 1 --3.549
) 140.000 ( 1 --3.549
)
fta
fcal
fcal
fcal
11
bcy bczc cal
cc
EzEy
f ff fffff
1.011
bcyc bcz
caz ccbaobagy
EzEy
ff ff ff ff
ff
11
bcy bczc cal
cc
EzEy
f ff fffff
1.011
bcyc bcz
caz ccbaobagy
EzEy
ff ff ff ff ff
1 1
bcybczc cal
c c
Ez Ey
fff ff ff f
1.01 1
bcyc bcz
cay c cbagz bao
Ez Ey
ff ff f ff f
f f
![Page 101: 응력검토 샘플](https://reader033.vdocuments.pub/reader033/viewer/2022061114/545fa8e7b1af9f673b8b4bc4/html5/thumbnails/101.jpg)
113.892 ( 1 -490.908
) 140.000 ( 1 -490.908
)
= -0.023 ≤ 1.0 ...... OK
▶ Position 2 (z-direction)
-3.549 +1.749
+1.970
( 1 --3.549
) ( 1 --3.549
)490.908 490.908
= 0.197 MPa ≤ = 140.000 MPa ...... OK
▶ Position 3 (z-direction)
-3.549 +-0.431
+-4.731
( 1 --3.549
) ( 1 --3.549
)490.908 490.908
= -8.748 MPa ≤ = 140.000 MPa ...... OK
-3.549 +
-0.431 +
-4.731 114.710
113.892 ( 1 --3.549
) 140.000 ( 1 --3.549
)490.908 490.908
= -0.069 ≤ 1.0 ...... OK
▶ Position 4 (z-direction)
-3.549 +-0.728
+-4.731
( 1 --3.549
) ( 1 --3.549
)490.908 490.908
= -9.048 MPa ≤ = 140.000 MPa ...... OK
-3.549 +
-0.728 +
-4.731 114.710
113.892 ( 1 --3.549
) 140.000 ( 1 --3.549
)490.908 490.908
= -0.071 ≤ 1.0 ...... OK
9) 전단응력에 대한 검토== 0.118 / 450.000 + -0.002 × 9.000E+00 / 3.4263E+04= -0.361 MPa ≤ = 80.000 MPa ...... OK=
fta
fcal
fcal
υz Fz / Aw + Mx × t / K× 103 × 106
υa
υy Fy / Af + Mx × t / K
1 1
bcybczc cal
c c
Ez Ey
fff ff ff f
1 1
bcybczc cal
c c
Ez Ey
fff ff ff f
1.01 1
bcyc bcz
cay c cbagz bao
Ez Ey
ff ff f ff f
f f
1 1
bcybczc cal
c c
Ez Ey
fff ff ff f
1.01 1
bcyc bcz
cay c cbagz bao
Ez Ey
ff ff f ff f
f f
![Page 102: 응력검토 샘플](https://reader033.vdocuments.pub/reader033/viewer/2022061114/545fa8e7b1af9f673b8b4bc4/html5/thumbnails/102.jpg)
= -0.059 / 450.000 + -0.002 × 9.000E+00 / 3.4263E+04= -0.755 MPa ≤ = 80.000 MPa ...... OK
t =
10) 합성응력에 대한 검토= (
-5.459 + (
-0.755 = 0.002 < 1.200 ...... OK
140.000 80.000
× 103 × 106
υa
여기서, 복부 두께 .
)2 )22 2
b b
a a
f vf v
![Page 103: 응력검토 샘플](https://reader033.vdocuments.pub/reader033/viewer/2022061114/545fa8e7b1af9f673b8b4bc4/html5/thumbnails/103.jpg)
6.644934E+053.426300E+04
22.1 -52.9
비 고
SM400140.000 140.000
...... OK
SM40018.6 < /r ≤ 92.8ℓ
Fcagz = 140 - 0.82×( /r - 18.6) = 114.710ℓ
18.6 < /r ≤ 92.8ℓ
Fcagz = 140 - 0.82×( /r - 18.6) = 114.710ℓ
도기 P3-10, 표3.3.1]
도기 P3-11, 표3.3.2]
![Page 104: 응력검토 샘플](https://reader033.vdocuments.pub/reader033/viewer/2022061114/545fa8e7b1af9f673b8b4bc4/html5/thumbnails/104.jpg)
18.6 < /r ≤ 92.8ℓ
Fcagy = 140 - 0.82×( /r - 18.6) = 114.710ℓ
18.6 < /r ≤ 92.8ℓ
Fcagy = 140 - 0.82×( /r - 18.6) = 114.710ℓ
SM4004.6 < /b ≤ 30.0ℓ
140 - 2.49×( /b - 4.6) = 113.892ℓ
SM4004.6 < /b ≤ 30.0ℓ
140 - 2.49×( /b - 4.6) = 113.892ℓ
490.908 490.908
SM40080.000 80.000
...... OK
...... OK
SM400
도기 P3-16, 표3.3.4]
P3-47, 식3.4.13~14]
P3-18, 표3.3.5]
도기 P3-37]
P3-38, 표3.4.4]
![Page 105: 응력검토 샘플](https://reader033.vdocuments.pub/reader033/viewer/2022061114/545fa8e7b1af9f673b8b4bc4/html5/thumbnails/105.jpg)
b/12.9 ≤ t140.000
SM400b/12.9 ≤ t140.000
80.000 80.000
0.170 -9.008
...... OK
...... OK
υa
![Page 106: 응력검토 샘플](https://reader033.vdocuments.pub/reader033/viewer/2022061114/545fa8e7b1af9f673b8b4bc4/html5/thumbnails/106.jpg)
...... OK
...... OK
...... OK
...... OK
...... OK
...... OK
![Page 107: 응력검토 샘플](https://reader033.vdocuments.pub/reader033/viewer/2022061114/545fa8e7b1af9f673b8b4bc4/html5/thumbnails/107.jpg)
...... OK
...... OK
...... OK
...... OK
...... OK
...... OK
3.4263E+04...... OK
![Page 108: 응력검토 샘플](https://reader033.vdocuments.pub/reader033/viewer/2022061114/545fa8e7b1af9f673b8b4bc4/html5/thumbnails/108.jpg)
3.4263E+04...... OK
...... OK
![Page 109: 응력검토 샘플](https://reader033.vdocuments.pub/reader033/viewer/2022061114/545fa8e7b1af9f673b8b4bc4/html5/thumbnails/109.jpg)
SM400= 0.0750 m H = 0.0750 m= 0.0090 m = 0.0090 m
1.269000E+03 6.644934E+05 6.644934E+052.288308E+01 2.288308E+01 3.426300E+04
검토위치 -22.1 22.1 52.9 22.1 -13.1 -52.9 -22.1 -52.9
구 분 비 고-4.504 -0.059 -0.025 -0.002 -0.112 0.021
1)
구 분 SM400Top Flange 140.000 Left Web 140.000
2)
부재의 유효좌굴길이 = 1131.371 mm부재 총단면의 단면회전반경 = 22.883 mm세장비 = 49.441
부재의 유효좌굴길이 = 1131.371 mm
부재 총단면의 단면회전반경 = 22.883 mm
세장비 = 49.441
▶ 세장비 검토세장비 / rℓ = 49.441 ≤ 120.000 ...... OK
구 분 SM400
Top Flange18.6 < /r ≤ 92.8ℓ
Fcagz = 140 - 0.82×( /r - 18.6) = 114.710ℓ
Left Web18.6 < /r ≤ 92.8ℓ
Fcagz = 140 - 0.82×( /r - 18.6) = 114.710ℓ
10.1 단면 제원사용강종 :B1
tf1 tw
10.2 단면 계수A (mm2) Iyy (mm4) Izz (mm4)ry (mm) rz (mm) K (mm4)
y1 (mm) z1 (mm) y2 (mm) z2 (mm)y3 (mm) z3 (mm) y4 (mm) z4 (mm)
10.3 작용하중Fx (kN) Fy (kN) Fz (kN) Mx (kN∙m) My (kN∙m) Mz (kN∙m)
작동시 교축풍하중(63min)
10.4 응력검토[1] 작동시 교축풍하중(63min)
허용휨인장응력 (fta) [도기 P3-10, 표3.3.1]
40 이하40 이하
국부좌굴을 고려하지 않은 허용축방향압축응력 (fcag) [도기 P3-11, 표3.3.2] ▶ Y 축에 대한 유효좌굴길이
ℓy
ry
ℓy /ry
▶ Z 축에 대한 유효좌굴길이ℓz
rz
ℓz /rz
40 이하40 이하
![Page 110: 응력검토 샘플](https://reader033.vdocuments.pub/reader033/viewer/2022061114/545fa8e7b1af9f673b8b4bc4/html5/thumbnails/110.jpg)
Top Flange18.6 < /r ≤ 92.8ℓ
Fcagy = 140 - 0.82×( /r - 18.6) = 114.710ℓ
Left Web18.6 < /r ≤ 92.8ℓ
Fcagy = 140 - 0.82×( /r - 18.6) = 114.710ℓ
3) ▶ Top Flange
압축플랜지 고정점간 거리 ℓ = 1131.371 mm
압축플랜지 폭 b = 75.000 mm복부판의 총단면적 = 594.000 압축플랜지 총단면적 = 675.000
= 0.880 ≤ 2.000 , = ### , = 1.855
구 분 SM400
≤ 2.0 4.6 < /b ≤ 30.0ℓ
140 - 2.49×( /b - 4.6) = 113.892ℓ
▶ Left Web
압축플랜지 고정점간 거리 ℓ = 1131.371 mm
압축플랜지 폭 b = 75.000 mm
복부판의 총단면적 = 675.000
압축플랜지 총단면적 = 675.000
= 1.000 ≤ 2.000 , = ### , = 1.871
구 분 SM400
≤ 2.0 4.6 < /b ≤ 30.0ℓ
140 - 2.49×( /b - 4.6) = 113.892ℓ
4) 허용 오일러 좌굴응력490.908 490.908
5)구 분 SM400
Top Flange 80.000 Left Web 80.000
6) 자유돌출판의 국부좌굴에 대한 허용응력 ▶ 압축응력을 받는 자유돌출판의 최소두께
Top Flange(L)= b / 16 = 75.0 / 16.0 = 4.688 mm ≤ = 9.000 mm ...... OK
Left Web(T)= b / 16 = 75.0 / 16.0 = 4.688 mm ≤ = 9.000 mm ...... OK
▶Top Flange(L) t = 9.000 mm
= b / 12.9 = 75.0 / 12.9 = 5.814 mm
구 분 SM400
40 이하40 이하
허용휨압축응력 (fbagy) [도기 P3-16, 표3.3.4]
Aw mm2
Ac mm2
40 이하
Aw mm2
Ac mm2
40 이하
[도기 P3-47, 식3.4.13~14]fEy (MPa) 1200000/(ly/ry)2
fEz (MPa) 1200000/(lz/rz)2
허용전단응력 (υa) [도기 P3-18, 표3.3.5]
40 이하40 이하
[도기 P3-37]tmin tf
tmin tf
자유돌출판의 국부좌굴에 대한 허용응력 (fcal) [도기 P3-38, 표3.4.4]
t1
w
c
AA
lb
w
c
AA
32
w
c
AK
A
w
c
AA
lb
w
c
AA
32
w
c
AK
A
![Page 111: 응력검토 샘플](https://reader033.vdocuments.pub/reader033/viewer/2022061114/545fa8e7b1af9f673b8b4bc4/html5/thumbnails/111.jpg)
b/12.9 ≤ t140.000
Left Web(T) t = 9.000 mm= b / 12.9 = 75.0 / 12.9 = 5.814 mm
구 분 SM400b/12.9 ≤ t140.000
7) 허용응력 요약구 분
Top Flange 140.000 114.710 114.710 140.000 80.000 Left Web 140.000 114.710 114.710 140.000 80.000
=
8) 축방향력 및 휨모멘트를 받는 부재의 허용응력 검토▶ 축방향력에 의한 응력
= P / A = -4.504 / 1.2690E+03 = -3.549 MPa
▶ 휨모멘트에 의한 응력= = 3.718 MPa = = 0.707 MPa= = 3.718 MPa = = -1.697 MPa= = -8.925 MPa = = 0.418 MPa= = -8.925 MPa = = 0.707 MPa
0.875 -1.529 -12.056 -11.768
▶ Position 1 (y-direction)
-3.549 +3.718
+0.707
( 1 --3.549
) ( 1 --3.549
)490.908 490.908
= 0.907 MPa ≤ = 140.000 MPa ...... OK
▶ Position 2 (y-direction)
-3.549 +3.718
+-1.697
( 1 --3.549
) ( 1 --3.549
)490.908 490.908
= -1.514 MPa ≤ = 140.000 MPa ...... OK
-3.549 +
3.718 +
-1.697
40 이하
t1
40 이하
fcal fcaz fcay fta υa
fca fcag ∙ fcal / fcao.
fc × 103
fby1 My × z1 / Iyy fbz1 Mz × y1 / Izz
fby2 My × z2 / Iyy fbz2 Mz × y2 / Izz
fby3 My × z3 / Iyy fbz3 Mz × y3 / Izz
fby4 My × z4 / Iyy fbz4 Mz × y4 / Izz
f11 (y1, z1) f22 (y2, z2)f33 (y3, z3) f44 (y4, z4)
fta
fcal
11
bcy bczc cal
cc
EzEy
f ff fffff
11
bcy bczc cal
cc
EzEy
f ff fffff
1.011
bcyc bcz
caz ccbaobagy
EzEy
ff ff ff ff ff
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114.710 +
113.892 ( 1 --3.549
)+
140.000 ( 1 --3.549
)490.908 490.908
= -0.010 ≤ 1.000 ...... OK
▶ Position 3 (y-direction)
-3.549 +-8.925
+0.418
( 1 --3.549
) ( 1 --3.549
)490.908 490.908
= -12.118 MPa ≤ = 140.000 MPa ...... OK
-3.549 +
-8.925 +
0.418 114.710
113.892 ( 1 --3.549
) 140.000 ( 1 --3.549
)490.908 490.908
= -0.107 ≤ 1.000 ...... OK
▶ Position 4 (y-direction)
-3.549 +-8.925
+0.707
( 1 --3.549
) ( 1 --3.549
)490.908 490.908
= -11.827 MPa ≤ = 140.000 MPa ...... OK
-3.549 +
-8.925 +
0.707 114.710
113.892 ( 1 --3.549
) 140.000 ( 1 --3.549
)490.908 490.908
= -0.105 ≤ 1.000 ...... OK
▶ Position 1 (z-direction)
-3.549 +0.707
+3.718
( 1 --3.549
) ( 1 --3.549
)490.908 490.908
= 0.907 MPa ≤ = 140.000 MPa ...... OK
▶ Position 2 (z-direction)
fcal
fcal
fta
11
bcy bczc cal
cc
EzEy
f ff fffff
1.011
bcyc bcz
caz ccbaobagy
EzEy
ff ff ff ff
ff
11
bcy bczc cal
cc
EzEy
f ff fffff
1.011
bcyc bcz
caz ccbaobagy
EzEy
ff ff ff ff ff
1 1
bcybczc cal
c c
Ez Ey
fff ff ff f
1 1
bcybczc cal
c c
Ez Ey
fff ff ff f
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-3.549 +-1.697
+3.718
( 1 --3.549
) ( 1 --3.549
)490.908 490.908
= -1.514 MPa ≤ = 140.000 MPa ...... OK
-3.549 +
-1.697 +
3.718 114.710
113.892 ( 1 --3.549
) 140.000 ( 1 --3.549
)490.908 490.908
= -0.019 ≤ 1.0 ...... OK
▶ Position 3 (z-direction)
-3.549 +0.418
+-8.925
( 1 --3.549
) ( 1 --3.549
)490.908 490.908
= -12.118 MPa ≤ = 140.000 MPa ...... OK
-3.549 +
0.418 +
-8.925 114.710
113.892 ( 1 --3.549
) 140.000 ( 1 --3.549
)490.908 490.908
= -0.091 ≤ 1.0 ...... OK
▶ Position 4 (z-direction)
-3.549 +0.707
+-8.925
( 1 --3.549
) ( 1 --3.549
)490.908 490.908
= -11.827 MPa ≤ = 140.000 MPa ...... OK
-3.549 +
0.707 +
-8.925 114.710
113.892 ( 1 --3.549
) 140.000 ( 1 --3.549
)490.908 490.908
= -0.089 ≤ 1.0 ...... OK
9) 전단응력에 대한 검토== -0.025 / 450.000 + -0.002 × 9.000E+00 / 3.4263E+04= -0.680 MPa ≤ = 80.000 MPa ...... OK=
fcal
fcal
fcal
υz Fz / Aw + Mx × t / K× 103 × 106
υa
υy Fy / Af + Mx × t / K
1 1
bcybczc cal
c c
Ez Ey
fff ff ff f
1.01 1
bcyc bcz
cay c cbagz bao
Ez Ey
ff ff f ff f
f f
1 1
bcybczc cal
c c
Ez Ey
fff ff ff f
1.01 1
bcyc bcz
cay c cbagz bao
Ez Ey
ff ff f ff f
f f
1 1
bcybczc cal
c c
Ez Ey
fff ff ff f
1.01 1
bcyc bcz
cay c cbagz bao
Ez Ey
ff ff f ff f
f f
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= -0.059 / 450.000 + -0.002 × 9.000E+00 / 3.4263E+04= -0.755 MPa ≤ = 80.000 MPa ...... OK
t =
10) 합성응력에 대한 검토= (
-8.507 + (
-0.755 = 0.004 < 1.200 ...... OK
140.000 80.000
× 103 × 106
υa
여기서, 복부 두께 .
)2 )22 2
b b
a a
f vf v
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6.644934E+053.426300E+04
22.1 -52.9
비 고
SM400140.000 140.000
...... OK
SM40018.6 < /r ≤ 92.8ℓ
Fcagz = 140 - 0.82×( /r - 18.6) = 114.710ℓ
18.6 < /r ≤ 92.8ℓ
Fcagz = 140 - 0.82×( /r - 18.6) = 114.710ℓ
도기 P3-10, 표3.3.1]
도기 P3-11, 표3.3.2]
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18.6 < /r ≤ 92.8ℓ
Fcagy = 140 - 0.82×( /r - 18.6) = 114.710ℓ
18.6 < /r ≤ 92.8ℓ
Fcagy = 140 - 0.82×( /r - 18.6) = 114.710ℓ
SM4004.6 < /b ≤ 30.0ℓ
140 - 2.49×( /b - 4.6) = 113.892ℓ
SM4004.6 < /b ≤ 30.0ℓ
140 - 2.49×( /b - 4.6) = 113.892ℓ
490.908 490.908
SM40080.000 80.000
...... OK
...... OK
SM400
도기 P3-16, 표3.3.4]
P3-47, 식3.4.13~14]
P3-18, 표3.3.5]
도기 P3-37]
P3-38, 표3.4.4]
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b/12.9 ≤ t140.000
SM400b/12.9 ≤ t140.000
80.000 80.000
-1.529 -11.768
...... OK
...... OK
υa
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...... OK
...... OK
...... OK
...... OK
...... OK
...... OK
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...... OK
...... OK
...... OK
...... OK
...... OK
...... OK
3.4263E+04...... OK
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3.4263E+04...... OK
...... OK
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SM400= 0.0400 m = 0.0400 m= 0.0350 m = 0.0350 m= 0.0070 m = 0.0070 m= 0.0050 m H = 0.0750 m
8.650000E+02 7.442221E+05 1.357732E+052.933210E+01 1.252850E+01 1.140833E+04
검토위치 -13.8 37.5 26.2 37.5 26.2 -37.5 -13.8 -37.5
구 분 비 고-6.475 0.000 0.000 0.000 0.000 0.000
1)
구 분 SM400Top Flange 140.000
Bottom Flange 140.000 Left Web 140.000
2)
부재의 유효좌굴길이 = 1232.234 mm부재 총단면의 단면회전반경 = 29.332 mm세장비 = 42.010
부재의 유효좌굴길이 = 1232.234 mm
부재 총단면의 단면회전반경 = 12.528 mm
세장비 = 98.354
▶ 세장비 검토세장비 / rℓ = 98.354 ≤ 120.000 ...... OK
구 분 SM400
Top Flange92.8 < /rℓ
Fcagz = 1200000 / (6700+( /r)²) = 73.289ℓ
Bottom Flange92.8 < /rℓ
11.1 단면 제원사용강종 :B1 B2
b1 b2
tf1 tf2
tw
11.2 단면 계수A (mm2) Iyy (mm4) Izz (mm4)ry (mm) rz (mm) K (mm4)
y1 (mm) z1 (mm) y2 (mm) z2 (mm)y3 (mm) z3 (mm) y4 (mm) z4 (mm)
11.3 작용하중Fx (kN) Fy (kN) Fz (kN) Mx (kN∙m) My (kN∙m) Mz (kN∙m)
최초거치시R4(53min)
11.4 응력검토[1] 최초거치시R4(53min)
허용휨인장응력 (fta) [도기 P3-10, 표3.3.1]
40 이하40 이하40 이하
국부좌굴을 고려하지 않은 허용축방향압축응력 (fcag) [도기 P3-11, 표3.3.2] ▶ Y 축에 대한 유효좌굴길이
ℓy
ry
ℓy /ry
▶ Z 축에 대한 유효좌굴길이ℓz
rz
ℓz /rz
40 이하40 이하
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Bottom FlangeFcagz = 1200000 / (6700+( /r)²) = 73.289ℓ
Left Web92.8 < /rℓ
Fcagz = 1200000 / (6700+( /r)²) = 73.289ℓ
Top Flange18.6 < /r ≤ 92.8ℓ
Fcagy = 140 - 0.82×( /r - 18.6) = 120.804ℓ
Bottom Flange18.6 < /r ≤ 92.8ℓ
Fcagy = 140 - 0.82×( /r - 18.6) = 120.804ℓ
Left Web18.6 < /r ≤ 92.8ℓ
Fcagy = 140 - 0.82×( /r - 18.6) = 120.804ℓ
3) ▶ Top Flange
압축플랜지 고정점간 거리 ℓ = 1232.234 mm압축플랜지 폭 b = 40.000 mm복부판의 총단면적 = 305.000 압축플랜지 총단면적 = 280.000
= 1.089 ≤ 2.000 , = ### , = 1.883
구 분 SM400
≤ 2.0 /b > 30.0 [NG]ℓ
0.000 ▶ Bottom Flange
압축플랜지 고정점간 거리 ℓ = 1232.234 mm
압축플랜지 폭 b = 40.000 mm
복부판의 총단면적 = 305.000
압축플랜지 총단면적 = 280.000
= 1.089 ≤ 2.000 , = ### , = 1.883
구 분 SM400
≤ 2.0 /b > 30.0 [NG]ℓ
0.000 ▶ Left Web
압축플랜지 고정점간 거리 ℓ = 1232.234 mm압축플랜지 폭 b = 75.000 mm복부판의 총단면적 = 490.000 압축플랜지 총단면적 = 375.000
= 1.307 ≤ 2.000 , = ### , = 1.911
구 분 SM400
≤ 2.0 4.6 < /b ≤ 30.0ℓ
140 - 2.49×( /b - 4.6) = 110.544ℓ
4) 허용 오일러 좌굴응력679.957 124.049
40 이하40 이하40 이하40 이하40 이하
허용휨압축응력 (fbagy) [도기 P3-16, 표3.3.4]
Aw mm2
Ac mm2
40 이하
Aw mm2
Ac mm2
40 이하
Aw mm2
Ac mm2
40 이하
[도기 P3-47, 식3.4.13~14]fEy (MPa) 1200000/(ly/ry)2
fEz (MPa) 1200000/(lz/rz)2
w
c
AA
lb
w
c
AA
32
w
c
AK
A
w
c
AA
lb
w
c
AA
32
w
c
AK
A
w
c
AA
lb
w
c
AA
32
w
c
AK
A
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5)
구 분 SM400Top Flange 80.000
Bottom Flange 80.000 Left Web 80.000
6) 자유돌출판의 국부좌굴에 대한 허용응력 ▶ 압축응력을 받는 자유돌출판의 최소두께
Top Flange(L)= b / 16 = 40.0 / 16.0 = 2.500 mm ≤ = 7.000 mm ...... OK
Bottom Flange(L)= b / 16 = 40.0 / 16.0 = 2.500 mm ≤ = 7.000 mm ...... OK
▶Top Flange(L) t = 7.000 mm
= b / 12.9 = 40.0 / 12.9 = 3.101 mm구 분 SM400
b/12.9 ≤ t140.000
Bottom Flange(L) t = 7.000 mm= b / 12.9 = 40.0 / 12.9 = 3.101 mm
구 분 SM400b/12.9 ≤ t140.000
7) 보강된판 및 양연지지판의 국부좌굴에 대한 허용응력▶ Left Web
판두께 t = 5.0 mm
판의 고정연 사이의 거리 b = 61.0 mm
응력구배계수 i = = 1.000 응력구배 Φ = = 0.000 판의 양연에서의 응력 = -7.485 MPa, = -7.485 MPa
압축응력을 받는 양연지지판의 최소두께t ≤ 40mm
= b / 56i = 61 / 56 = 1.1 ≤ t = 5.0 mm ...... OK
구 분 SM400b/39.3i ≤ t140.000
8) 허용응력 요약구 분
Top Flange 140.000 73.289 120.804 140.000 80.000 Bottom Flange 140.000 73.289 120.804 140.000 80.000
Left Web 140.000 73.289 120.804 140.000 80.000 =
허용전단응력 (υa) [도기 P3-18, 표3.3.5]
40 이하40 이하40 이하
[도기 P3-37]tmin tf
tmin tf
자유돌출판의 국부좌굴에 대한 허용응력 (fcal) [도기 P3-38, 표3.4.4]
t1
40 이하
t1
40 이하
0.65Φ2 + 0.13Φ + 1.0(f1 - f2) / f1
f1 f2
[도기 P3-35, 표3.4.2]
tmin
양연지지판의 국부좌굴에 대한 허용응력 (fcal) [도기 P3-36, 표3.4.3]
40 이하
fcal fcaz fcay fta υa
fca fcag ∙ fcal / fcao.
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9) 축방향력 및 휨모멘트를 받는 부재의 허용응력 검토▶ 축방향력에 의한 응력
= P / A = -6.475 / 8.6500E+02 = -7.485 MPa
▶ 휨모멘트에 의한 응력= = 0.000 MPa = = 0.000 MPa= = 0.000 MPa = = 0.000 MPa= = 0.000 MPa = = 0.000 MPa= = 0.000 MPa = = 0.000 MPa
-7.485 -7.485 -7.485 -7.485
▶ Position 1 (y-direction)
-7.485 +0.000
+0.000
( 1 --7.485
) ( 1 --7.485
)679.957 124.049
= -7.485 MPa ≤ = 140.000 MPa ...... OK
-7.485 +
0.000 +
0.000 73.289
0.000 ( 1 --7.485
) 140.000 ( 1 --7.485
)679.957 124.049
= - ...... NG
▶ Position 2 (y-direction)
-7.485 +0.000
+0.000
( 1 --7.485
) ( 1 --7.485
)679.957 124.049
= -7.485 MPa ≤ = 140.000 MPa ...... OK
-7.485 +
0.000 +
0.000 73.289
0.000 ( 1 --7.485
) 140.000 ( 1 --7.485
)679.957 124.049
= - ...... NG
▶ Position 3 (y-direction)
fc × 103
fby1 My × z1 / Iyy fbz1 Mz × y1 / Izz
fby2 My × z2 / Iyy fbz2 Mz × y2 / Izz
fby3 My × z3 / Iyy fbz3 Mz × y3 / Izz
fby4 My × z4 / Iyy fbz4 Mz × y4 / Izz
f11 (y1, z1) f22 (y2, z2)f33 (y3, z3) f44 (y4, z4)
fcal
∵ fbagy =0 또는 fbagz =0 일 경우 검토식을 적용할 수 없습니다.
fcal
∵ fbagy =0 또는 fbagz =0 일 경우 검토식을 적용할 수 없습니다.
11
bcy bczc cal
cc
EzEy
f ff fffff
1.011
bcyc bcz
caz ccbaobagy
EzEy
ff ff ff ff ff
11
bcy bczc cal
cc
EzEy
f ff fffff
1.011
bcyc bcz
caz ccbaobagy
EzEy
ff ff ff ff
ff
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-7.485 +0.000
+0.000
( 1 --7.485
) ( 1 --7.485
)679.957 124.049
= -7.485 MPa ≤ = 140.000 MPa ...... OK
-7.485 +
0.000 +
0.000 73.289
0.000 ( 1 --7.485
) 140.000 ( 1 --7.485
)679.957 124.049
= - ...... NG
▶ Position 4 (y-direction)
-7.485 +0.000
+0.000
( 1 --7.485
) ( 1 --7.485
)679.957 124.049
= -7.485 MPa ≤ = 140.000 MPa ...... OK
-7.485 +
0.000 +
0.000 73.289
0.000 ( 1 --7.485
) 140.000 ( 1 --7.485
)679.957 124.049
= - ...... NG
▶ Position 1 (z-direction)
-7.485 +0.000
+0.000
( 1 --7.485
) ( 1 --7.485
)124.049 679.957
= -7.485 MPa ≤ = 140.000 MPa ...... OK
-7.485 +
0.000 +
0.000 120.804
110.544 ( 1 --7.485
) 140.000 ( 1 --7.485
)124.049 679.957
= -0.062 ≤ 1.0 ...... OK
fcal
∵ fbagy =0 또는 fbagz =0 일 경우 검토식을 적용할 수 없습니다.
fcal
∵ fbagy =0 또는 fbagz =0 일 경우 검토식을 적용할 수 없습니다.
fcal
11
bcy bczc cal
cc
EzEy
f ff fffff
1.011
bcyc bcz
caz ccbaobagy
EzEy
ff ff ff ff
ff
11
bcy bczc cal
cc
EzEy
f ff fffff
1.011
bcyc bcz
caz ccbaobagy
EzEy
ff ff ff ff
ff
1 1
bcybczc cal
c c
Ez Ey
fff ff ff f
1.01 1
bcyc bcz
cay c cbagz bao
Ez Ey
ff ff f ff f
f f
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▶ Position 2 (z-direction)
-7.485 +0.000
+0.000
( 1 --7.485
) ( 1 --7.485
)124.049 679.957
= -7.485 MPa ≤ = 140.000 MPa ...... OK
-7.485 +
0.000 +
0.000 120.804
110.544 ( 1 --7.485
) 140.000 ( 1 --7.485
)124.049 679.957
= -0.062 ≤ 1.0 ...... OK
▶ Position 3 (z-direction)
-7.485 +0.000
+0.000
( 1 --7.485
) ( 1 --7.485
)124.049 679.957
= -7.485 MPa ≤ = 140.000 MPa ...... OK
-7.485 +
0.000 +
0.000 120.804
110.544 ( 1 --7.485
) 140.000 ( 1 --7.485
)124.049 679.957
= -0.062 ≤ 1.0 ...... OK
▶ Position 4 (z-direction)
-7.485 +0.000
+0.000
( 1 --7.485
) ( 1 --7.485
)124.049 679.957
= -7.485 MPa ≤ = 140.000 MPa ...... OK
-7.485 +
0.000 +
0.000 120.804
110.544 ( 1 --7.485
) 140.000 ( 1 --7.485
)124.049 679.957
= -0.062 ≤ 1.0 ...... OK
10) 전단응력에 대한 검토
fcal
fcal
fcal
1 1
bcybczc cal
c c
Ez Ey
fff ff ff f
1.01 1
bcyc bcz
cay c cbagz bao
Ez Ey
ff ff f ff f
f f
1 1
bcybczc cal
c c
Ez Ey
fff ff ff f
1.01 1
bcyc bcz
cay c cbagz bao
Ez Ey
ff ff f ff f
f f
1 1
bcybczc cal
c c
Ez Ey
fff ff ff f
1.01 1
bcyc bcz
cay c cbagz bao
Ez Ey
ff ff f ff f
f f
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== 0.000 / 375.000 + 0.000 × 5.000E+00 / 1.1408E+04= 0.102 MPa ≤ = 80.000 MPa ...... OK== 0.000 / 373.333 + 0.000 × 7.000E+00 / 1.1408E+04= 0.143 MPa ≤ = 80.000 MPa ...... OK
t =
11) 합성응력에 대한 검토= (
0.000 + (
0.143 = 0.000 < 1.200 ...... OK
140.000 80.000
υz Fz / Aw + Mx × t / K× 103 × 106
υa
υy Fy / Af + Mx × t / K× 103 × 106
υa
여기서, 복부 두께 .
)2 )22 2
b b
a a
f vf v
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1.357732E+051.140833E+04
37.5 -37.5
비 고
SM400140.000 140.000 140.000
...... OK
SM40092.8 < /rℓ
Fcagz = 1200000 / (6700+( /r)²) = 73.289ℓ
92.8 < /rℓ
도기 P3-10, 표3.3.1]
도기 P3-11, 표3.3.2]
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Fcagz = 1200000 / (6700+( /r)²) = 73.289ℓ
92.8 < /rℓ
Fcagz = 1200000 / (6700+( /r)²) = 73.289ℓ
18.6 < /r ≤ 92.8ℓ
Fcagy = 140 - 0.82×( /r - 18.6) = 120.804ℓ
18.6 < /r ≤ 92.8ℓ
Fcagy = 140 - 0.82×( /r - 18.6) = 120.804ℓ
18.6 < /r ≤ 92.8ℓ
Fcagy = 140 - 0.82×( /r - 18.6) = 120.804ℓ
SM400/b > 30.0 [NG]ℓ
0.000
SM400/b > 30.0 [NG]ℓ
0.000
SM4004.6 < /b ≤ 30.0ℓ
140 - 2.49×( /b - 4.6) = 110.544ℓ
679.957 124.049
도기 P3-16, 표3.3.4]
P3-47, 식3.4.13~14]
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SM40080.000 80.000 80.000
...... OK
...... OK
SM400b/12.9 ≤ t140.000
SM400b/12.9 ≤ t140.000
...... OK
SM400b/39.3i ≤ t140.000
80.000 80.000 80.000
P3-18, 표3.3.5]
도기 P3-37]
P3-38, 표3.4.4]
도기 P3-35, 표3.4.2]
도기 P3-36, 표3.4.3]
υa
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-7.485 -7.485
...... OK
...... NG
...... OK
...... NG
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...... OK
...... NG
...... OK
...... NG
...... OK
...... OK
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...... OK
...... OK
...... OK
...... OK
...... OK
...... OK
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1.1408E+04...... OK
1.1408E+04...... OK
...... OK
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SM400= 0.0400 m = 0.0400 m= 0.0350 m = 0.0350 m= 0.0070 m = 0.0070 m= 0.0050 m H = 0.0750 m
8.650000E+02 7.442221E+05 1.357732E+052.933210E+01 1.252850E+01 1.140833E+04
검토위치 -13.8 37.5 26.2 37.5 26.2 -37.5 -13.8 -37.5
구 분 비 고-6.475 0.000 0.000 0.000 0.000 0.000
1)
구 분 SM400
형강 140.000
2)
부재의 유효좌굴길이 = 1232.234 mm부재 총단면의 단면회전반경 = 29.332 mm세장비 = 42.010
부재의 유효좌굴길이 = 1232.234 mm부재 총단면의 단면회전반경 = 12.528 mm
세장비 = 98.354
▶ 세장비 검토세장비 / rℓ = 98.354 ≤ 120.000 ...... OK
구 분 SM40092.8 < /rℓ
Fcagz = 1200000 / (6700+( /r)²) = 73.289ℓ
18.6 < /r ≤ 92.8ℓ
Fcagy = 140 - 0.82×( /r - 18.6) = 120.804ℓ
12.1 단면 제원사용강종 :B1 B2
b1 b2
tf1 tf2
tw
12.2 단면 계수A (mm2) Iyy (mm4) Izz (mm4)ry (mm) rz (mm) K (mm4)
y1 (mm) z1 (mm) y2 (mm) z2 (mm)y3 (mm) z3 (mm) y4 (mm) z4 (mm)
12.3 작용하중Fx (kN) Fy (kN) Fz (kN) Mx (kN∙m) My (kN∙m) Mz (kN∙m)
최초거치시R4(53min)
12.4 응력검토[1] 최초거치시R4(53min)
허용휨인장응력 (fta) [도기 P3-10, 표3.3.1]
40 이하국부좌굴을 고려하지 않은 허용축방향압축응력 (fcag) [도기 P3-11, 표3.3.2]
▶ Y 축에 대한 유효좌굴길이ℓy
ry
ℓy /ry
▶ Z 축에 대한 유효좌굴길이ℓz
rz
ℓz /rz
40 이하40 이하
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3)
압축플랜지 고정점간 거리 ℓ = 1232.234 mm
압축플랜지 폭 b = 75.000 mm
복부판의 총단면적 = 490.000
압축플랜지 총단면적 = 375.000
= 1.307 ≤ 2.000 , = ### , = 1.911
구 분 SM400
≤ 2.0 4.6 < /b ≤ 30.0ℓ
140 - 2.49×( /b - 4.6) = 110.544ℓ
4) 허용 오일러 좌굴응력679.957 124.049
5)
구 분 SM40080.000
8) 허용응력 요약구 분
Left Web 140.000 73.289 120.804 140.000 80.000 =
9) 축방향력 및 휨모멘트를 받는 부재의 허용응력 검토▶ 축방향력에 의한 응력
= P / A = -6.475 / 8.6500E+02 = -7.485 MPa
▶ 휨모멘트에 의한 응력= = 0.000 MPa = = 0.000 MPa= = 0.000 MPa = = 0.000 MPa= = 0.000 MPa = = 0.000 MPa= = 0.000 MPa = = 0.000 MPa
-7.485 -7.485 -7.485 -7.485
▶ Position 1 (y-direction)
-7.485 +0.000
+0.000
( 1 --7.485
) ( 1 --7.485
)679.957 124.049
= -7.485 MPa ≤ = 140.000 MPa ...... OK
허용휨압축응력 (fbagy) [도기 P3-16, 표3.3.4]
Aw mm2
Ac mm2
40 이하
[도기 P3-47, 식3.4.13~14]fEy (MPa) 1200000/(ly/ry)2
fEz (MPa) 1200000/(lz/rz)2
허용전단응력 (υa) [도기 P3-18, 표3.3.5]
40 이하
fcal fcaz fcay fta υa
fca fcag ∙ fcal / fcao.
fc × 103
fby1 My × z1 / Iyy fbz1 Mz × y1 / Izz
fby2 My × z2 / Iyy fbz2 Mz × y2 / Izz
fby3 My × z3 / Iyy fbz3 Mz × y3 / Izz
fby4 My × z4 / Iyy fbz4 Mz × y4 / Izz
f11 (y1, z1) f22 (y2, z2)f33 (y3, z3) f44 (y4, z4)
fcal
32
w
c
AK
A32
w
c
AK
A
w
c
AA
lb
w
c
AA
32
w
c
AK
A
11
bcy bczc cal
cc
EzEy
f ff fffff
1.011
bcyc bcz
caz ccbaobagy
EzEy
ff ff ff ff ff
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-7.485 +
0.000 +
0.000 73.289
0.000 ( 1 --7.485
) 140.000 ( 1 --7.485
)679.957 124.049
= - ...... NG
▶ Position 2 (y-direction)
-7.485 +0.000
+0.000
( 1 --7.485
) ( 1 --7.485
)679.957 124.049
= -7.485 MPa ≤ = 140.000 MPa ...... OK
-7.485 +
0.000 +
0.000 73.289
0.000 ( 1 --7.485
) 140.000 ( 1 --7.485
)679.957 124.049
= - ...... NG
▶ Position 3 (y-direction)
-7.485 +0.000
+0.000
( 1 --7.485
) ( 1 --7.485
)679.957 124.049
= -7.485 MPa ≤ = 140.000 MPa ...... OK
-7.485 +
0.000 +
0.000 73.289
0.000 ( 1 --7.485
) 140.000 ( 1 --7.485
)679.957 124.049
= - ...... NG
▶ Position 4 (y-direction)
-7.485 +0.000
+0.000
( 1 --7.485
) ( 1 --7.485
)679.957 124.049
= -7.485 MPa ≤ = 140.000 MPa ...... OK
∵ fbagy =0 또는 fbagz =0 일 경우 검토식을 적용할 수 없습니다.
fcal
∵ fbagy =0 또는 fbagz =0 일 경우 검토식을 적용할 수 없습니다.
fcal
∵ fbagy =0 또는 fbagz =0 일 경우 검토식을 적용할 수 없습니다.
fcal
1.011
bcyc bcz
caz ccbaobagy
EzEy
ff ff ff ff ff
11
bcy bczc cal
cc
EzEy
f ff fffff
1.011
bcyc bcz
caz ccbaobagy
EzEy
ff ff ff ff ff
11
bcy bczc cal
cc
EzEy
f ff fffff
1.011
bcyc bcz
caz ccbaobagy
EzEy
ff ff ff ff ff
11
bcy bczc cal
cc
EzEy
f ff fffff
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-7.485 +
0.000 +
0.000 73.289
0.000 ( 1 --7.485
) 140.000 ( 1 --7.485
)679.957 124.049
= - ...... NG
▶ Position 1 (z-direction)
-7.485 +0.000
+0.000
( 1 --7.485
) ( 1 --7.485
)124.049 679.957
= -7.485 MPa ≤ = 140.000 MPa ...... OK
-7.485 +
0.000 +
0.000 120.804
110.544 ( 1 --7.485
) 140.000 ( 1 --7.485
)124.049 679.957
= -0.062 ≤ 1.0 ...... OK
▶ Position 2 (z-direction)
-7.485 +0.000
+0.000
( 1 --7.485
) ( 1 --7.485
)124.049 679.957
= -7.485 MPa ≤ = 140.000 MPa ...... OK
-7.485 +
0.000 +
0.000 120.804
110.544 ( 1 --7.485
) 140.000 ( 1 --7.485
)124.049 679.957
= -0.062 ≤ 1.0 ...... OK
▶ Position 3 (z-direction)
-7.485 +0.000
+0.000
( 1 --7.485
) ( 1 --7.485
)124.049 679.957
= -7.485 MPa ≤ = 140.000 MPa ...... OK
∵ fbagy =0 또는 fbagz =0 일 경우 검토식을 적용할 수 없습니다.
fcal
fcal
fcal
1.011
bcyc bcz
caz ccbaobagy
EzEy
ff ff ff ff
ff
1 1
bcybczc cal
c c
Ez Ey
fff ff ff f
1.01 1
bcyc bcz
cay c cbagz bao
Ez Ey
ff ff f ff f
f f
1 1
bcybczc cal
c c
Ez Ey
fff ff ff f
1.01 1
bcyc bcz
cay c cbagz bao
Ez Ey
ff ff f ff f
f f
1 1
bcybczc cal
c c
Ez Ey
fff ff ff f
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-7.485 +
0.000 +
0.000 120.804
110.544 ( 1 --7.485
) 140.000 ( 1 --7.485
)124.049 679.957
= -0.062 ≤ 1.0 ...... OK
▶ Position 4 (z-direction)
-7.485 +0.000
+0.000
( 1 --7.485
) ( 1 --7.485
)124.049 679.957
= -7.485 MPa ≤ = 140.000 MPa ...... OK
-7.485 +
0.000 +
0.000 120.804
110.544 ( 1 --7.485
) 140.000 ( 1 --7.485
)124.049 679.957
= -0.062 ≤ 1.0 ...... OK
10) 전단응력에 대한 검토== 0.000 / 375.000 + 0.000 × 5.000E+00 / 1.1408E+04= 0.102 MPa ≤ = 80.000 MPa ...... OK== 0.000 / 373.333 + 0.000 × 7.000E+00 / 1.1408E+04= 0.143 MPa ≤ = 80.000 MPa ...... OK
t =
11) 합성응력에 대한 검토= (
0.000 + (
0.143 = 0.000 < 1.200 ...... OK
140.000 80.000
fcal
υz Fz / Aw + Mx × t / K× 103 × 106
υa
υy Fy / Af + Mx × t / K× 103 × 106
υa
여기서, 복부 두께 .
)2 )2
1.01 1
bcyc bcz
cay c cbagz bao
Ez Ey
ff ff f ff f
f f
1 1
bcybczc cal
c c
Ez Ey
fff ff ff f
1.01 1
bcyc bcz
cay c cbagz bao
Ez Ey
ff ff f ff f
f f
2 2
b b
a a
f vf v
![Page 140: 응력검토 샘플](https://reader033.vdocuments.pub/reader033/viewer/2022061114/545fa8e7b1af9f673b8b4bc4/html5/thumbnails/140.jpg)
1.357732E+051.140833E+04
37.5 -37.5
비 고
SM400140.000
...... OK
SM40092.8 < /rℓ
Fcagz = 1200000 / (6700+( /r)²) = 73.289ℓ
18.6 < /r ≤ 92.8ℓ
Fcagy = 140 - 0.82×( /r - 18.6) = 120.804ℓ
도기 P3-10, 표3.3.1]
도기 P3-11, 표3.3.2]
![Page 141: 응력검토 샘플](https://reader033.vdocuments.pub/reader033/viewer/2022061114/545fa8e7b1af9f673b8b4bc4/html5/thumbnails/141.jpg)
SM4004.6 < /b ≤ 30.0ℓ
140 - 2.49×( /b - 4.6) = 110.544ℓ
679.957 124.049
SM40080.000
80.000
-7.485 -7.485
...... OK
도기 P3-16, 표3.3.4]
P3-47, 식3.4.13~14]
P3-18, 표3.3.5]
υa
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...... NG
...... OK
...... NG
...... OK
...... NG
...... OK
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...... NG
...... OK
...... OK
...... OK
...... OK
...... OK
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...... OK
...... OK
...... OK
1.1408E+04...... OK
1.1408E+04...... OK
...... OK