«الشروق» تقدم المراجعة النهائية في الاستاتيكا لطلبة...
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«الشروق» تقدم المراجعة النهائية في الاستاتيكا لطلبة الثانوية العامةTRANSCRIPT
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302 = 0215 04 02 2 + 0061+ 004 =
302 X
X 06 =
035 035
035
545= )(
06 = 1 = 545=
06 = =
021504 2 + 0061 + 2 = 06
) 602 + 02 = ( :
06
3 3
2332 22 5102 5102 .nuJ 22 - 2332 eussI01
0 )( )1( 441 )(
= ) ( = = )(
)(
001 )(
8 )(
6+ 2 = - ) ( )2(
6 = -) 6 ( ) 6+ 2=(- B
3 = 6 = - 6 - 21 B
= )(
) 1(0000 23 = +
) 2(00000000 =
)2( )1(
0 42 = 0 01 =
. ) 6 6( )( )3(
) 7 7 (
09 = 6 7 + 8 6=
09= -
. 9 = B 09 = - 01 -
4 5
3 5
1 4
4 5
3 5
1 4
6
6
7
7
8
6
23
1 4
) )(4(
) 1(00000 7= 4
/ / 7 = / 4
) + - ( 7 = ) - ( 4
= 7+ 7- 7= 4- 4
A) (
= )2 ( B
= 03 061 B
) 1(
005
0 = B 0 = B
) 2( 08 061 + ) 05( = 04 005 B
) 2( )1(
042 = 02= B
05 B
7 11
/ /
4 7 7 /
061
- 05 04 03
2 1
005 061
- 05 04 03
2 1
5 5 5 5
: )( )1( 000000 ) (
: ) (
0000= 000
0000 )(
0000 )(
0000 = 2 1: 05 = 1 2 1 )(
: )(
:
0000= 0000=
)4 7 = ( 6 = ][ )2(
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0
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7 6 7 6 8 = 6 = ] ) [3(
0 .
.
06 ][
0 0215 04 02
545= 0 035 )(
04 0
C C C
C
01
4 4
1 4
4 5
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03
81 42
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7
0
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061 . 04 = 03 =
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. .
01 21 4 = 8 = ) ) (5(
.
.
g 02 )(
05 0 5=
035
0
71= 7= - N : + = 2 = : )) (6(
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0
0
C
7 11
C C C C
1 3
7 01
11 6
: )) (7(
)11( 4 = 2 )1- 2( 4+ 3 = 1
0000 = 1 )2 (0000 = 1 )1(
0000= 000= 2 1 )3(
0000 ) = 7 3( 2 1 )4(
5 = - 3 5+ 6 = 2 2 3 = 1 ) (
0 8 )0 0(
0
0 ) 4 3 = (
h f [ ] . 4 . 1 h f [ ] ))(8 (
h] ] f . R
f [ 515
R . 515
.
. 01 06 h f )(
. . 051 h
. .
.
w [ ] s h f 21 = f [ 01 = h f h f [ ] ))(9 ( . 062 062 002 081 002 081
h h hf [ f [ ] ] w [ s
. .
= f [ 21 = h f 01 = 09 h hR) ( R)f( ] h f [ ] )(h h] f f [ [ ] 62 03 42 02 . 51
. .
C
0 = A ) ( )5(
0 = 4 + 8 01 - B
02 =
0=
6 = 0= 8 4 21
)05 05( )(
02 05 = - 1 035
005 = -
5 = 2 ) (
001 = = = 2 + 1
7 ) = - 1 ( N ) 2- ( )6(
) 1(00000 7 2 = 7 = - 2
) 2(0000 51 = 71 ) = 1 ) ( 2- (
)2( )1(
) 3 5 ) = ( ( ) 01- = ( ) (
21
01
8
05
05
5 5 01
3- 2
4
0 = A ) ( )5(
0 = 4 + 8 01 - B
02 =
0=
6 = 0= 8 4 21
)05 05( )(
02 05 = - 1 035
005 = -
5 = 2 ) (
001 = = = 2 + 1
7 ) = - 1 ( N ) 2- ( )6(
) 1(00000 7 2 = 7 = - 2
) 2(0000 51 = 71 ) = 1 ) ( 2- (
)2( )1(
) 3 5 ) = ( ( ) 01- = ( ) (
21
01
8
05
05
5 5 01
3- 2
4
1 3
1 3
= )(
)2( )1(
=
)3( )(
=
01) 4( 01 3 ) 3 (2) 2 (0) 1) ()(7(
3+ 4= )(
) 0(
8= -
2= 8 = - )3 4 ( ) 0(
=
1
1
2
1
2
3
3 1= 2
4= 3 1 1+ 2
) 1(
) 2(
6= 2 5
81 5
= 1
1 2
3+
1- 1- 3
0= 1
) 3(
1 2
1- 1- 3+ 3
0= 1
7 01
N
=
42 5
4 4 ))(4(
. .
R R
: )(
)1 ) ( h )2 051 )3
051-
. 01= =
065= 0035
06
4 = -14 = -1
= - 2 065
2 = - 2 3
2
3
2 = 0 0
3
2 6 4 4 =
3 =
051= - 03 01-
1= 2
f
R
R
]
[
h
4 4
065
515 1 545
v
03
..051
[
h
f
n
n
.01
03
002 002 ) )(9( 00 0002 = - 01 002 = -1
081 081 00 0612 = 21 081 = 2
062 062
. . 0401 = - 0021 0612 + 0002= -
] i f [ )(
01= =
5 = 01 51 = i [
21 = ] i
] i [
=
= 21 5
31 062 = -3
0 0 0021 = -062 = -3 5
31 21
31= B 52 + 212 = 2) (
= :
0 006 = 21) 51 + 01 (2 2 1 2
2=
002
42
081
f 21
01
[
]
w s
h
u
62
062
062
002
081
51
i
h
f
]
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21
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