1 § 1 - 2 quadratic functions the student will learn about: quadratic function equations, quadratic...
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§ 1 - 2 Quadratic Functions
The student will learn about:
Quadratic function equations,
quadratic graphs, and
applications.
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IntroductionA quadratic is an equation of the form
f (x) = a x2 + b x + c , and graphs as a parabola.
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Life has many paths!
There are several ways in which we may study functions.
• Algebraically – as we have been doing.
• Calculus – throughout the upcoming weeks.
• Graphing Calculator – as we have been doing.
We need to be careful of the last method. Many instructors do not permit the use of graphing calculators. For that reason I expect you to be conversant in all three methods!
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Definition
The graph of a quadratic function is called a parabola.
Def: A function f is a quadratic function if f (x) = a x2 + b x + c, where a 0, and a, b, and c are real numbers. The domain of a quadratic function is the set of all real numbers.
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Example 1
f (x) = x2 + x – 2.
1. Find the x intercepts algebraically
Sketch the graph of f (x) in a Cartesian coordinate system.
To find the x intercept, let f (x) = 0 and solve for x. Factor or use the quadratic formula.
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Solving a Quadratic Equation
f (x) = x2 + x – 2.
Solutions may be found algebraically.
Let f (x) = 0 and solve for x :
The solutions of a quadratic (the x-intercepts) are also called roots or zeros.
a. Factor : 0 = (x + 2)(x – 1) and x = 1 and – 2.
OR
b. Use the quadratic formula – Next slide please!
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Solving a Quadratic Equation
f (x) = x2 + x – 2.
b. Use the quadratic formula : a = 1, b = 1, c = -2.
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811x
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Example 1 - Continued
f (x) = x2 + x – 2.
2. Find the y-intercept algebraically
Sketch the graph of f (x) in a Cartesian coordinate system.
To find the y-intercept let x = 0 and solve for f (x). The solution will be c.
3. Using the x-intercepts of 1 and -2 and the y-intercept of -2 we can now sketch this parabola.
A graphing calculator might help!
Knowing the vertex might help!
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2. Enter the function Y1 = x 2 + x – 2 and then press ZOOM and 6 for a standard window.
x-intercepts using CALC and zero giving 1 and -2
Graphing a Quadratic Function: Calculator
1. Turn the calculator on and press the y = button. If something is there press clear.
3. Find the x and y intercepts using the calculator.
y-intercept using CALC and value giving -2OR use table!
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Properties of Quadratics
Many useful properties of the quadratic function can be found by transforming the general equation f (x) = a x2 + b x + c into the form f (x) = a (x – h)2 + k. This second form is called the standard form (or vertex form) and can be derived from the general form by completing the square.
There is a simple (non algebraic) way to do this.
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Example 2 * f (x) = -2x2 + 4x + 6 f (x) = ax2 + bx + c = a(x – h)2 + k
2. Solve f(x) by completing the square:
1. The intercepts can be calculated as previously shown.
y = -2x2 + 4x + 6
Hence a = - 2, h = 1 and k = 8.
(-1, 0), (3, 0), and (0, 6)
y = -2 (x2 - 2x) + 6y = -2 (x2 - 2x + 1) + 6y = -2 (x –1)2 + 8
+ 2
There is a simple way to do this.
? ? ?
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3. The graph is a parabola with:
With intercepts: (-1, 0), (3, 0), and (0, 6) and
• vertex at (h, k), and
a = -2, h = 1 and k = 8.
• axis of symmetry: x = h, and• a minimum if a > 0 or• a maximum if a < 0.
Example 2 Continued * f (x) = -2x2 + 4x + 6 f (x) = ax2 + bx + c = a(x – h)2 + k
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With intercepts: (-1, 0), (3, 0), and (0, 6) and a = -2, h = 1 and k = 8.
4. The graph of f is a transformation of the graph of g (x) = x2 .
• reflected in the x axis since a is negative• stretched double since |a| = 2 > 1• shifted one to the right since h = 1
• shifted eight up since k = 8.
Example 2 Continued * f (x) = -2x2 + 4x + 6 f (x) = ax2 + bx + c = a(x – h)2 + k
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Example 2 Continuedf (x) = -2x2 + 4x + 6
With intercepts: (-1, 0), (3, 0), and (0, 6) and a = -2, h = 1 and k = 8 and• reflected in the x axis
• stretched double
• shifted one to the right• shifted eight up.
There is a simple way to do this.
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Reviewf (x) = ax2 + bx + c OR y = a (x – h)2 + k
x intercepts (x, 0)
opens up if a > 0
y intercept (0, y)
stretch if |a| > 1
squish if |a| < 1
opens down if a < 0
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Reviewf (x) = ax2 + bx + c OR y = a (x – h)2 + k
Has a minimum if a > 0
Domain is all Reals
Has a maximum if a < 0
Range is [k, ) if a > 0
Range is (- , k] if a < 0
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Reviewf (x) = ax2 + bx + c OR y = a (x – h)2 + k
vertex at (h, k)
MAX or min of y = k
symmetry axis x = h
note h = -b/2a
note k = c – b2/4a
MAX or min at x = h
There is a simple way to do this.
So, what is it?
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The simple way!f (x) = ax2 + bx + c OR y = a (x – h)2 + k
From example 2, f (x) = - 2x 2 + 4x + 6 we need to get y = a (x – h) 2 + k.But we already know from the standard form that a = - 2,
The equation must be: y = - 2 (x – 1) 2 + 8. TA DA!
But we already know from the standard form that a = - 2.
Press CALC and 3 for a minimum. Giving h = 1 and k = 8.
I love my calculator!
Graph it!