1.6 元素訊號(elementary...

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1.6 元素訊號(Elementary signals) 指數訊號(exponential signals) 弦波訊號(sinusoidal signals) 弦波訊號與複數指數訊號 指數衰退之弦波訊號 步階(Step)函數(訊號) 脈衝(impulse)函數(訊號) 微分 RAMP function ee: P34

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1.6 元素訊號(Elementary signals)指數訊號(exponential signals)弦波訊號(sinusoidal signals)弦波訊號與複數指數訊號

指數衰退之弦波訊號

步階(Step)函數(訊號)脈衝(impulse)函數(訊號)

– 微分

RAMP function

ee: P34

指數訊號(exponential signals)

(a) 自然界中常見之衰退或成長函數, 如:人口自然成長函數, 放射物質之衰退

(b)基本函數型態

衰退

成長

指數蛻變常數

之初值

,0,0

:0:

,)(

<>

==

aaa

tBBetx at

ee: P34

圖例: 指數訊號(p34, F1.28)

(a) (b)

0,)( / >= − ττtBetx

0,)( / >= ττtBetx

ee: P34

計算: 一階RC電路

0)()(

0)()(

=+

=+

tvtvdtdRC

tvtRi

)(一階常微分方程式

)0(,)0()/(1,01

0

0)()(

)(

0 vBBevRCaRCa

BeRCaBe

tvtvdtdRC

Betv

a

atat

at

=∴=→

−=∴=+→=+

=+

=假設

)()0()( RCtevtv −=⇒

ee: P35

離散指數訊號(exponential signals)

(a) (b) (c) 類比於連續指數

10,][ <<= rBrnx n

1,][ >= rBrnx n

αer =

ee: P35

複數指數訊號

若B, r, a為複數(complex)則可定義出複數指數訊號

常見之複數指數訊號

n

at

BrnxBetx

=

=

][)(

( )njnj

tj

eBBenx

BetxΩΩ ==

=

][

)( ϖ

Fourier transform之基本基底訊號連續離散

ee: P36

弦波訊號(sinusoidal signals) ee: P36

)35.1()cos()( φϖ += tAtx

啟始相位

角頻率

振幅

重要參數

:2

::

φπϖ

ϖf

A

=

ϖππϖ

2,2

)()(

=→

∈==+

T

nnTtxTtx

Z

計算: 二階LC電路ee: P36

=+

=+

0)(1)(

0)(1)(

dttiC

tidtdL

dttiC

tv

0)()(2

2

=+ tvtvdtdLC

代入

二階常微分方程式

)cos()0()(0)0(),0(

)sin()cos(,,1)/(1,01

0)(

0

000

02

2

tvtviv

tjAtAaLC

jRLaRCa

BeBeLCaBetv

ir

atat

at

ϖ

ϖϖϖ

ϖ

=⇒=

+=→

=−=∴=+→

=+

=

代入初值

解型態為複數

假設振盪電路之自然頻率

離散弦波訊號 ee: P37,38

)cos(][ φ+Ω= nAnx

( )

整數∈=Ω

=Ω⇒++Ω=+

NmcycleradNmor

radiansmNNnANnx

,,2,2

)(cos][

ππ

φ

基本三角恆等式

( )( ))2cos(1)(sin

)2cos(1)(cos

212212

θθ

θθ

−=

+=

)cos()sin(2)2sin()(sin211)(cos2)2cos( 22

θθθθθθ

=−=−=

)sin()sin()cos()cos()cos()sin()cos()cos()sin()sin(φθφθφθφθφθφθ

=±±=±

[ ][ ][ ])sin()sin()cos()sin(

)cos()cos()cos()cos()cos()cos()sin()sin(

2121

21

φθφθφθφθφθφθφθφθφθ

++−=

++−=

+−−=

ee: P763,

A-1

Ex 1.7( ) [ ]

)cos(][][][(b)period) al(fundament(a)

)5cos(3,5sin][

21

21

φ

ππ

+Ω=+=

==

nAnxnxny

nnxnnx

求主週期

225,2

= →Ω

=

=Ω=Ω

NmN

mN

最小整數πππ

( )[ ])sin()sin()cos()cos()cos(][

)5cos(35sin][][][ 21

φφφππ

nnAnAnynnnxnxny

Ω−Ω=+Ω=+=+=

3)cos(

,1)sin(,5

=→

−=→=Ω→

φ

φπ

A

A( ) 2sin11)sin(

3,31)tan(

)cos()sin(

3 =−=→−=

−=∴−

==→

−πφ

πφφφφ

AAAA

ee: P38~39

Ex: 1.7

弦波訊號與複數指數訊號

)sin()cos( '

θθθ jeidentitysEuler

j +=

( )

tj

tj

tjtjjtj

jtj

BetABetA

AeeAeBeAeBBe

ϖ

ϖ

φϖϖφϖ

φϖ

φϖ

φϖ

Im)sin(Re)cos(

,

=+ →

=+ →

==

=+

取虛部

取實部

其中

複數指數訊號

離散弦波訊號與複數指數訊號ee: P41

Fig 1.34

( )

nj

nj

njnjjnj

jnj

BenABenA

AeeAeBeAeBBe

Ω

Ω

+ΩΩΩ

Ω

=+Ω →

=+Ω →

==

=

Im)sin(Re)cos(

,

φ

φ

φφ

φ

取虛部

取實部

其中

複數指數訊號

N=8

指數衰退之弦波訊號ee: P41

Fig 1.35

)sin()( φϖ += − tAetx at

0 0.1 0.2 0.3 0.4 0.5 0.6 0.7 0.8 0.9 1-40

-30

-20

-10

0

10

20

30

40

50

60

)()()()sin()(

)(

21

2

1

txtxtxttx

Aetx at

=+=

= −

φϖ

with A = 60 and α = 6.

計算: RLC電路ee: P42

Fig 1.36

∫ ∞−

tdv

Lττ )(1

0)(1)(1)(

:

=++ ∫ ∞−

tdv

Ltv

Rtv

dtdC

KCL

ττ

0)(1)(1)(2

2

=++ tvL

tvdtd

Rtv

dtdC

AAevCRLCRC

CRLCj

RCRLCLCRLLj

RjLjRLCAetv tj

==

−=−

=∴

−±−

=−±−

=+→

=++++

= +

0

22

22

22

2

)(

)0(4

11,2

14

112

12

4

0)()()(

初值

ωσ

ωσ

ϖσωσ

ϖσ假設解

節點總流出電流=0

)4( CLRassume >

單位步階訊號, unit-step signal

<≥

=00

,0,1

)(tt

tu

<≥

=00

,0,1

][nn

nu

ee: P43

Fig 1.38

0 1 2 3 4-1-2-3

以單位步階訊號表示下列訊號ee: P44

Fig 1.39

))5.0(()5.0()()5.0()(

2

1

−−=+=−=

tututxtutx

)5.0()5.0()()()( 12 −−+=−=∴ tututxtxtx

以步階訊號描述開關動作ee: P45

Fig 1.40

)()1()(

,0)(,0)0(

)/(1

,)(

)(0

0

0

tueVtv

vBvVBvVvv

RCavBevtv

RCt

ppp

pat

P

−−=

−=→==+→=∞=

−=

+=

為特解

描述開關動作後之輸出

離散脈衝(Discrete-time form of impulse.) ee: P46

Fig 1.41

][nδ

≠=

=00

,0,1

][nn

脈衝(Dirac delta) ee: P46

Fig 1.42

∫∞

∞−=

≠=

1)(

0 ,0)(

dtt

andtfort

δ

δ

)()( lim0

txt ∆→∆

Dirac delta & unit step

∫ ∞−=

=

tdtu

tudtdt

ττδ

δ

)()(

)()(

∫∞

∞−=

≠=

1)(

0 ,0)(

dtt

andtfort

δ

δ

<≥

=00

,0,1

)(tt

tu

Ex 1.10 ee: P47

Fig 1.43

)()()()(

)()(

0

0

tCVtituVtv

dttdvCti

δ=∴=

=

Dirac delta之時間變數運算ee: P48

∫∞

∞−−=− )()()(

:&

00 ttxtttx

shifting

δ

積分

0),(1)(

:

>= ata

at

scaling

δδ

Dirac delta 可視 為 一 shiftoperator

圖解脈衝訊號之scaling 運算ee: P48

Fig. 1.44

)(1)( ta

at δδ =

)(1)()( limlim00

txa

atxat ∆→∆

∆→∆

==δ

Parallel LRC ee: P49

Fig. 1.45

+= 0at )( voltage theof value thefind )( ttva

CIVCvtI

tvR

tvdtdCdttv

LtIa

ttdt

/,)0()(

)(1)()(1)( )(

)()(

00

0

00

0

=∴= →

++=

=

+

∞−

∞−

∫+

+

δ

δ

δ

兩邊積分至

P1.23 series LCR ee: P49

Fig. 1.45

+

+

=

0for ofequation aldifferenti-integro the write)(0at )(current theof value thefind )(

ti(t)bttia

LVILitV

tRidiC

tidtdLtVa

ttdt

/,)0()(

)()(1)()( )(

)()(

00

0

00

0

=∴= →

++=

=

+

∞−

∞−

∫+

+

δ

ττδ

δ

兩邊積分至

0)()(1)(

)()(1)()( )(

0

0

=++→

++=

∞−

∞−

+

tRidiC

tidtdL

tRidiC

tidtdLtVb

tt

t

ττ

ττδ

Derivatives of the Impulse( ) ( )[ ]22

1)()( lim0

)1( ∆−−∆+∆

==→∆

ttdt

tdt δδδδ

0

)()()(

0)(

0)1(

)1(

tt

tfdtddttttf

dtt

doublet

=

∞−

∞−

=−

=

∫δ

δ

性質

( ) ( )∆

∆−−∆+=

=

→∆

22

)()(

)1()1(

0

2

2)1(

lim tt

tdtdt

dtd

doublet

δδ

δδ

微分

( ) ( ) 0221110

lim =

∫ ∆−−∫ ∆+∆

==

∞∞−

=

∞∞−

→∆

dttdtt δδ

( ) ( )[ ]( ) ( )[ ]

0

)(221

221)(

000

000

lim

lim

tt

tfdtdttfttf

dttttttf

=→∆

∞−→∆

=∆−−−∆+−∆

=

∆−−−∆+−∆

= ∫ δδ

ee: P50

P1.24( ) ( )

∆∆−−∆+

==→∆

22)()()1()1(

0

)1()2( lim tttdtdt δδδδ

( ) ( )

0

)()()(

2)(2)(

)()()(

2020

0

0)1(

0)1(

0

0)2(

lim

lim

tt

tdd

tdd

tfdtd

dtdtftf

dttttfdttttf

dttttfa

=

∆−=∆+=

→∆

∞−

∞−

→∆

∞−

=

−−−=

∆−−−∆+−=

∫∫∫

ττττ ττ

δδ

δ

性質)()2( tδ

ee: P51

( ) ( )

0

)(...

2)(2)(

)()()(

0)1(

0)1(

0

0)(

lim

ttn

n

nn

n

tfdtd

dttttfdttttf

dttttfb

=

∞−

−∞

∞−

→∆

∞−

==

∆−−−∆+−=

∫∫∫

δδ

δ

Ramp Signal ee: P51,52

Fig. 1.46,47

)(00

,0,

)( ttuttt

tr =

<≥

=

][00

,0,

][ nnunnn

nr =

<≥

=

1 2 3 4-1-2

Ex 1.11 ee: P52

Fig 1.48

)()( 0 tuIti =

)(

)(1

)(1)(

0

0

trCI

duIC

diC

tv

t

t

=

=

=

∞−

∞−

ττ

ττ