3 newtonlaws & inertia .ppt
TRANSCRIPT
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Born: 4 Jan 1643 in Woolsthorpe, Lincolnshire, EnglandDied: 31 March 1727 in London, England
Let us dedicate ournext one hourto the great scientist & mathematician
“Sir Isaac Newton”
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Summary
Distance: total length of travel
Displacement: change in position
Average speed: distance / time
Average velocity: displacement / time
Instantaneous velocity: average velocity measured over an infinitesimally small time
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Summary Instantaneous acceleration: average acceleration measured over an infinitesimally small time Average acceleration: change in velocity divided by change in time Deceleration: velocity and acceleration have opposite signs Equatiojna of motion: equations of motion relate position, velocity, acceleration, and time Freely falling objects: constant acceleration
g = 9.81 m/s2
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Newton
For an object to CHANGE its motion we need force
Newtons mechanics applies for motion in
an inertial frame of reference!
???????
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NEWTONS 1st LAW MOTION –LAW OF INERTIA • Mass occupies space Inertial property• Unless acted upon by external imbalanced
force mass continues to be in state of rest (velocity=0 ) or uniform motion in straight line ie.
• Without force Velocity and/or Direction of motion does not change•Eg – A rolling ball will continue to roll with same velocity for ever on a frictionless surface
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Inertia( Measure of mass) More mass more inertia
• Season & tennis ball:, • Inertia at rest
• Suddenly Starting or stopping train• Cleaning carpet by heating• Fruits/ flowers fall down when we shake tree• Pile of carom coins• Coin over card
• Inertia of motion • Jumping from running train, Car stops suddenly• Ball thrown up in running train• Start by fast bowler / long jump athlete
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ForceForce causes acceleration?Force: push or pullForce is a vector – it has magnitude and direction
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Calibrating Spring ForceTwo equal weights exert twice the force of one; this is used for calibration of a spring:
We can measure force by using spring balance
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Points to Remember about force:1.Force must have an agent that produces
it;2.Contact force will act at the point of
contact3.The normal force acts only
perpendicular to the surface in contact;
4.The friction force acts only parallel to the surface in contact;
5.The tension force from a string or rope acts only along the line of the string or rope.
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• Weight is measure of earth’s gravitational force
• In space weight will be zero but mass will not change
• Newton's laws will be still valid
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NEWTONS 2st LAW – Measurability
– By definition three terms are involved, namely•Force , Mass & Velocity
– Hence a new term ,Momentum is defined as• Momentum P = Mass Velocity = mv
–‘ P ‘ does not change if there is no external force.This is called law of conservation of momentum
Inertial property
• Definition Rate of change of momentum is proportional
to the applied external imbalance force & takes place in direction of force
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Normal application : Only velocity changes
M M
U VF
.t sec
F
Newton made the constant of proportionality one by suitably selecting the units and hence the formula becomes F = aM
t1
F M V – M U
Now Mass is constant
t1
F ( V – U)M
F aM
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ImpulseChange in momentum may be produced by a force acting for a instantaneously for short time) , it is called impulse
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A solid object resists the action of force which compresses .This is called normal force. It always acts outward and perpendicular to the surface of the compressed object. The symbol for the normal force is n.
Normal Force (Denoted by n )
n
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Units: Mass has SI units of kg, and acceleration has SI units of m/s2. We define the SI unit of force as:1 newton = 1 N = 1kg m/s2.
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Example: Accelerated Mass
A net force of 3.0 N produces an acceleration of 2.0 m/s2 on an object of unknown mass. What is the mass of the object?
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(3.0 N)= 1.5 kg(2.0 m/s )
Fma
m1
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Example:Three Forces
Mira, Lata, and Kamal push a 600kg boat, each exerting a 100 N force parallel to the dock.(a) What is the acceleration of the boat if they all push in the same direction?
3 x 100 = 300 N .a = F / M = 300 N / 600Kg = 0.5 m / sec2
DOCK
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Mira, Lata, and Kamal push a 600kg boat, each exerting a 100 N force parallel to the dock.(b) What is the acceleration if Mira & Lata pushes in the opposite direction from Kamal?
Example: Three Forces
100 – 100 – 100 = – 100N.a = F / M = -100 N / 600Kg = - 0.167 m / sec2
DOCK
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Newton’s third law
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• For every action (force) there is a reaction (force)
• Action (force) and reaction forces are in opposite direction and act on two different bodies
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Action
Reaction
Action Reaction
ActionReaction
Reaction
F
Two forces act on man F & -F will cancel each other hence man will not move
F
Action
Understanding action-reaction pairs:Will man move?
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Understanding action-reaction pairs:Will man move if he is on skates ?
Action
Action
ActionReaction
GroundReaction
If man stand on skates, ground reaction F will not be there. Hence man will move back due to cupboard reaction force
Action
CupboardReaction
F
No ground reaction
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Understanding action-reaction pairs:Will coup bard move?
Action
Reaction
Action Reaction
ActionReaction
Reaction
Two forces act on cupboard F & -F will cancel each other hence it will not move
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Example: Pulling a Rope
A student pulls horizontally with a force of 100 N on a rope that is attached to a wall.
Two students pulls on opposite ends of a rope with forces of 100 N each.
1 2
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Example --- reaction
The ground pushes man forward –ReactionReaction acts on man
Note: If ground will not give reaction man can not move forward
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Example --- Action & reaction
The man pushes ground back ward –ActionAction acts on ground
The ground pushes man forward –ReactionReaction acts on man
Note: If ground will give reaction man can
move forward
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Action Reaction
If ground is slippery ground can not give reaction & tire will slip
Tier exerts force on ground--Action
Hence no action
If ground is slippery no action,hence no reaction
Ground exerts force on wheel ---Reaction –hence tractor moves
Hence tractor will not move
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Action :Gases moving out under high pressure
Rocket engine
Reaction :Reaction acts on plane due to which it moves
Rocket engine can work in vacuum as it is having its own oxygen supply but jet engine cannot work in vacuum
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Action: Rotating Fan pushes water
Reaction : Water pushes the fan back & hence ship moves forward
For breaking the motion of propeller fan is reversed & reaction force decelerates the ship
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Airplane has landed at point ‘A’ & came to halt point ‘B’
A B
u = 400m/sec a = -50m/sec2
V= 0m/sec
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Time Velocity Distance Acc0 400 0 -501 350 375 -502 300 700 -503 250 975 -504 200 1200 -505 150 1375 -506 100 1500 -507 50 1575 -508 0 1600 -50
U = 400 m/sec, V = 0 , a = -50m/sec2
V =u +at s =ut + ½ at2
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400350
300250
200150
10050
0050
100150200250300350400450
0 1 2 3 4 5 6 7 8 9
Time in sec
Velo
cty
m/s
ec
Velocity time graph
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0
375
700
9751200
13751500 1575 1600
0200400600800
10001200140016001800
0 1 2 3 4 5 6 7 8 9
Time sec
Dis
tanc
e m
eter
sDistance time graph
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• A force of F = 7.50 N pushes three boxes to the left. The boxes have masses = 1.30 kg, 3.20 kg, = 4.90 kg.
•What is the magnitude of the contact force between boxes 2 and 3 (in N)?
g = 10m/sec2
F23?
4.875
EX 1
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g = 10m/sec2
4.875
F23?
Total mass moving = 1.3 +3.2 + 4.875 =9.375 kg
.a = F/M =7.5/9.375 = 0.8m /sec2 for all masses
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g = 10m/sec2
F23?
.a = = 0.8m /sec2 for all masses
Force F23 is pushing blocks 1 & 2 = 4.5kg
4.875
F23 = f x a = 4.5 x 0.8 = 3.6 N
Find contact force between 1 & 2 Ans = 1.04 N
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Ex2
Masses 1.0 kg, 2.0 kg are connected by a string & kept on a frictionless table. They are connected by a string and pulley to a hanging mass 3.0 kg as shown. System is released from rest . Find acceleration of the system in m/ sec2 ?Find tension in stirng at point 1 (T1)
g = 10m/sec2
T1 .a ?
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Ex2
g = 10m/sec2
.a ?
Net force = m3 x g = 3 x 10 = 30 N Force acting is weight of mass m3
Net moving mass = m1+ m2+ m3 = 6 Kg Net a = F / (m1+ m2+ m3) = 30 / 6 Kg = 5m/sec2
F
T1
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You ask the talking horse, to pull a wagon. He replies that he would be glad to, but the laws of physics will not permit it. From Newton’s 3rd Law, if he pulls the wagon, wagon will pull him back with equal reaction force, so the net force on him will be zero and the wagon cannot move. What would you reply? Explain
Ex 3
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When you convince him on his first point the lezzy smart horse says “ the road below wheels is oily. It will not give any reaction .Hence I am not be able to pull the car” What would you reply? Explain
Ex 3
Oily surface
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When you convince him on his second point the smart horse says “ the road below my feet is oily. It will not give any reaction .Hence I am not be able to pull the car” What would you reply? Explain
Ex 3
Oily surface
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An object moves with a constant velocity. Is it safe to conclude that no forces act on the object? Why or why not?
The constant velocity implies that the acceleration is zero, and from Newton's 2nd Law we can infer that the net force on the object is also zero. However, there could be many forces acting on the object, as long as their vector sum is zero, leading to zero net force
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Mass changing with velocity• Mass increases with velocity• However increase in mass is noticeable only
at speed comparable with light speed ie more than 106m/sec (light speed 3 * 108 m/sec)
• Formula is m = mo / √1- (v2/c2), c = velocity of light, m= mass at velocity v, mo= rest mass
• In case of atomic particles moving near to speed the increase is mass can be measured in lab
• However Newton's law are still valid• For all normal situation mass can be
considered constant .