bai 4 - khai thac su dung ewsd

TRNG S QUAN CH-KT THNG TIN KHOA HU TUYN TIP SC

PH DUYT Ngy thng 8 nm 2010

Ch nhim B mn

Thng t Trnh Vn Khch

BI GING Mn hc: Tng i in t k thut s Bi: Khai thc s dng tng i EWSD i tng: VT6 Nm hc: 2010 - 2011

Ging vin: Thng y:Lm Vn Thanh Bnh

Nha Trang, thng 8 nm 2010

B mn Chuyn mch Bi ging Khai thc s dng tng i EWSD

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M U

Tng i EWSD l tng i in t k thut s SPC c sn xut theo cng ngh hin i, n c ng dng trong bt k mng thng tin no bo m cho mt khu vc rng ln.

Bi hc gip hc vin nm c cch khai thc, qun l, iu hnh tng i

EWSD.

PHN NI DUNG

I. Khi to h thng + Bt ngun tng i, phn mm h iu hnh trong CP khi ng. + Bt ngun OMT. + Nhp EWSD - m truy nhp (ngi s dng); (du ; minh ha phm Enter). + Nhp mt khu truy nhp h thng;

Ti mn hnh ca OMT cho php ngi khai thc trc tip nhp lnh MML hay la chn cc chc nng:

- Vn hnh cc chc nng qun l tng i; - Ci t cc chc nng qun l tng i; - Bo dng tng i; + Thot khi h thng:

- End section;

- Chn 1; - Tt ngun OMT.

II. Qun l cc phn cng bng lnh MML 1. Cu trc lnh MML Tn lnh: Tham s, tham s,.........., tham s;

Tn lnh phn bit tham s bng du :. Tham s phn bit tham s bng du ,. Kt thc bng du ;.

Trong : + Tn lnh gm: hnh ng_ch th (i tng). + Tham s gm: Tn tham s = gi tr tham s. + Bn tin ra gm:

- Bn tin li.

- Bn tin yu cu. - Bn tin hi bo.

2. Qun l h thng theo phn cp C 51 cp qun l ng vi cc quyn qun l; cp 0,1,50 l mc nh; cc cp 2 -

49 do ngi qun l t t.

3. Cc lnh qun l phn cng a. Qun l DLU

* Qun l DLU system + Hin th d liu DLU:

Disp DLU: DLU=x (s DLU); + Hin th trng thi DLU: Stat DLU: DLU=x (s DLU); + Thit lp li trng thi hot ng ca DLU (lnh ny ch cho php thc hin vi mt DLUC ti mt thi im):


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Conf DLU: DLU=x (s DLU),

DLUC0=y (nu chuyn cu hnh DLUC0), Hoc DLUC1=y (nu chuyn cu hnh DLUC1), OST= trng thi mi ca DLUC (tun theo bng hin th); + Phn on li ca DLU (lnh ny ch cho php thc hin vi mt DLUC ti mt thi im v DLUC phi l MBL):

Diag DLU: DLU=x (s DLU), DLUC0=y (nu chuyn cu hnh DLUC0), Hoc DLUC1=y (nu chuyn cu hnh DLUC1); + To DLU:

CR DLU: DLU=x (s DLU), Shelf= y,

DLUC0= a-b-c-d,

DLUC1= a-b-c-d;

Trong :

- a-b: s LTG c ng ni vi LTG; - c, d: DIU ni vi DLU thng qua ng PDC; - Nu to mt ng PDC mi gia DLU v LTG: DLUC0/1= a-b-c-d (mt trong hai gi tr c, d phi l DIU c ng dng CCS).

- Khi DLU c to, nhm modul BD/CCG, DLUC v DIU:LDID cng c t ng to theo; cc v tr 0-5, 6-10 l ca cc modul ny. Nhng modul ring l ny khng tc ng c bng lnh MML. + To thm hoc thay i ng ni gia LTG v DLU: EXT DLU: DLU=x (s DLU: 10, 20,....2550), DLUC0= a-b-c-[d],

DLUC1= a-b-c-[d];

Trong : - DLU phi c to trc v trng thi PLA;

- LTG nh ni vi DLU phi trng thi MBL hoc PLA; + Rt gn DLU (xa ng ni gia LTG v DLU): EXT DLU: DLU=x (s DLU: 10, 20,....2550), DLUC0= a-b-c-[d],

DLUC1= a-b-c-[d];

+ Xa DLU:

EXT DLU: DLU=x (s DLU); Trong : - DLU c xa ang trng thi Database; - C hai DLUC trng thi PLA; khng cn ng ni no n DLU;

- Tt c cc modul trong DLU c xa. * Qun l DLUMOD: + Hin th d liu: Disp DLUMOD: DLU=x (s DLU), MOD= a-b;

Trong : a: s shelf (0-7), b: s modul (0-15); + Hin th trng thi: Stat DLUMOD: DLU=x (s DLU), MOD= a-b;

+ Thit lp trng thi hot ng mi:


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Conf DLUMOD: DLU=x (s DLU),

MOD= a-b, OST= trng thi mi ca DLU; + Phn on li: Diag DLUMOD: DLU=x (s DLU), MOD= a-b;

+ Khi to DLUMOD: Diag DLUMOD: DLU=x (s DLU), MOD= a-b,

TYPE = loi modul;

+ Xa DLUMOD:

Can DLUMOD: DLU=x (s DLU), MOD= a-b;

* Qun l DLU Port + Hin th d liu:

Disp DLUPORT: EQN= a-b-c-d;

Trong : a: s DLU, b: s shelf (0-7), c: s modul (0-15), d: s Port (0-15); + Hin th trng thi: Stat DLUPORT: DLU=x (s DLU),

LC = b-c-d;

+ Thay i trng thi hot ng: Conf DLUPORT: DLU=x (s DLU), LC= b-c-d,

OST= trng thi mi (PLA, MBL, ACT); + La chn cng theo yu cu ca in thoi vin:

Sel DLUPORT: DLU=x (s DLU), LC TYPE= SLCAFPE,

TYPE= Free (ri);

Hoc TYPE= Sub ( ni n ng dy thu bao); Hoc TYPE= PBXLN ( ni n ng dy PBX); + D th mt hoc nhiu mch SLCA: Test DLULC: DLU=x (s DLU),

LC = b-c-d; b. Qun l LTG

* Qun l LTG + Hin th trng thi hot ng: Stat LTG: LTG=x (s LTG); + t li cu hnh, thay i trng thi hot ng:

OST = trng thi mi ca LTG (OST tun theo bng hin th); + Chn on li: Diag LTG: LTG=x (s LTG); * Qun l LTU + Hin th d liu:

Disp LTU: LTG=x (s LTG), LTU= y (s LTU); + Hin th trng thi: Stat DIU: LTG=x (s LTG), DIU= y (s DIU);


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+ Xa LTU:

Can LTU: LTG=x (s LTG), LTU= y (s LTU); + Thay i trng thi hot ng: Conf DIU: LTG=x (s LTG), DIU= y (s DIU),

OST= trng thi mi; + Phn on li: Diag DIU: LTG = x (s LTG), DIU= y (s DIU);

* Qun l Port + Hin th trng thi: Stat PORT: EQN= a-b-c;

Trong : a: s LTG, b: s DIU, c: s Port.

+ Chuyn i trng thi hot ng:

Conf PORT: LTG = x (s LTG), CHPOS = b-c, OST = Trng thi mi; c. Qun l SN

+ Hin th trng thi: Stat SN;

+ Chuyn i trng thi hot ng SN0 hoc SN1: Conf SN: SN = 0,

Hoc SN = 1, OST = trng thi mi (theo bng hin th);

+ Phn on li phn cng (mng SN phi trng thi MBL): Diag SN: SN= 0/1;

+ Kim tra ng ni trong SN:

Test SN: SN= 0/1,

TA= Speech; d. Thay th cc modul trong tng i

* Trong DLU:

* Trong LTG:

* Trong SN: e. Qun l thu bao, trung k

* Khai bo mi: Thu bao: CR Sub;

Trong ta quan tm n cc tham s chnh:

- DN: s thu bao; - EQN: a-b-c-d (s DLU-s shelf- s modul- s cng); - CAT: phn cp thu bao. + Trung k: - To trung k: CR DEST;

Trong quan tm n: DEST: ch kt ni; TRAT: lung cp g (1,2,...). - To nhm cc knh c cng tn gi: CR TGRP; Trong quan tm n:


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TGNO: tn trung k;

OPMODE: kiu trung k; GCOS: kiu bo hiu (R2, CCS). - To ng nh tuyn cho hng gi ra s truyn trn nhm trung k ny: CR ROUTE;

Trong quan tm n:

DEST: ch kt ni; ROUTE: th my; TGNO: tn trung k; SSDI: gi t s my.

- To nhng knh ring l trong nhm trung k: CR TRUNK;

Trong quan tm n: TGNO: tn trung k;

EQN: a-b-c-d; (a: s shelf, b: s modul, c: s lung 0-3, d: s khe thi gian

1-15 hay 17-31).

LCOS: kiu bo hiu. Ch : Khai bo cc lnh trung k tng t CO, E&M gm cc tham s gn ging trn. * Thay i + Thu bao: MOD SUB; ta c mn hnh nh khai bo, nu thay i tham s no th vo tham s . + Trung k: MOD DEST; * Hin th + Thu bao: DISP SUB;

+ Trung k: DISP TRUNK;

* Xa

+ Thu bao: CAN SUB;

+ Trung k: CAN TRUNK;

III. Khai bo cc kt ni chun vi cc tng i trong mng 1. Trung k s dng bo hiu R2

a. Xc nh phn cng c lin quan tng thch phng thc bo hiu Dng cc lnh MML qun l phn cng sao cho trong lnh: CR LTU c APPLIC=

CasCas;

b. Khi to chnh CR DEST;

- DEST,

- TRAT: loi lu thoi; c. Khi to nhm trung k * Nhm gi ra (OG) CR TGRP;

TGNO= tn nhm,

OPMOD= OG,

GCOS= MFCR2 & NONSEQ;

* Nhm gi ra (IG) CR TGRP;

TGNO= tn nhm,

OPMOD= IG,

GCOS= MFCR2 &TRAL & DARALLOW;


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* Nhm gi hai chiu ra, vo (BW) CR TGRP; TGNO= tn nhm,

OPMOD= BW,

GCOS= MFCR2 & th t chim knh, ORIG1= 1: phn chia vng lu thoi;

d. Khi to trung k CR TRUNK;

e. nh tuyn CR ROUTE;

f. To m truy nhp DEST CR CPT;

DEST,

CODE: m truy nhp tng i,

ORIG1= 1: phn chia vng lu thoi;

f. To vng cc CR ZOPT; CODE: m truy nhp DEST, ZOCHA= NOPUSE (khng cp xung cho ng h cc ca hng ny;

2. Trung k s dng bo hiu s 7

- Mng thoi l chuyn mch knh, nhng bo hiu c iu khin bng k thut chuyn mch gi. - Nhng thnh phn DEST, ROUTE, CPT, ZOPT nh bo hiu R2; ngoi ra bo hiu s 7 chia lm hai phn: Phn 1 gm 3 lp di to nn, l phn trung chuyn bn tin MTP.

Phn 2 l lp th t -phn ngi s dng. Ta c th t lnh MML khai bo trung k s dng bo hiu s 7 nh sau: V d: Khai bo trung k SS7 vi mt hng c m im bo hiu l a-b-c (m

quc gia 3 bt-m vng 8 bit- m im BH 3 bit), dung lng 60 knh thoi (2E1) v hai knh bo hiu. a. Chun b phn cng LTG tng ng vi bo hiu SS7 (chun b 2LTU) Chun b tham s trong STAT DIU c: APPLIC= CCSCCS;

b. To m im bo hiu gc (m im bo hiu ca tng i mnh) CRC7OP:

SPC= a-b-c,

NETID= NATO: ch th mng, STPI= STP (SP): giao tip bo hiu; c. To cc nhm knh bo hiu n tng i ch CRC7LSET:

LS NAM= C7VTN: tn quyn u tin gia hai chm knh BH, SPC= a-b-c,

NETID= NATO: ch th mng, LSK= 1: kha chia ti (phn phi lu lng gia cc tuyn bo hiu);

d. To m im bo hiu ch CRC7OP:

DPC= a-b-c, NETID= NATO: ch th mng, PRD= C7 VTN,


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LSK= 0;

e. To phn ngi dng CRC7USER:

USNAME= ISUP,

DPC= a-b-c,

NETID= NATO: ch th mng,

PCMTYP= DIU30;

f. To nhm trung k thoi Ging vin

Lm Vn Thanh Bnh

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