chap. 2 force vectors - 921&88數位典藏|921&88 … and vectors vector operations vector addition...

35
Chap. 2 Force Vectors

Upload: ngodiep

Post on 19-May-2018

233 views

Category:

Documents


0 download

TRANSCRIPT

  • Chap. 2 Force Vectors

  • 2

    Chapter Outline

    Scalars and VectorsVector OperationsVector Addition of ForcesAddition of a System of Coplanar ForcesCartesian VectorsAddition and Subtraction of Cartesian VectorsPosition VectorsForce Vector Directed along a LineDot Product

  • 3

    Scalar and Vectors

  • 4

    Vector Operations Multiplication and Division by a Scalar

    Vector Addition

  • 5

    Vector OperationsVector Subtraction

    * draw the vector from the head of B to the head of A

  • 6

    Vector Operations

    Resolution of a Vector

    1. RAB

    2. RAB

  • 7

    Vector Operations

    Vector Addition of Forces

  • p.29, Problem 2-17Resolve the force F2 into components acting along the u and v axes and determine the magnitudes of the components.

  • 9

  • 10

    p.31, Problem 2-29The beam is to be hoisted using two chains. If the resultant force is to be 600 N directed along the positive y axis, determine the magnitudes of forces FA and FB acting on each chain and the angle of FB so that the magnitude of FB is a minimum. FA acts at 30

    from the y axis as shown.

  • 11

  • 12

    Addition of a System of Coplanar Forces

    Cartesian VectorF = Fx i + Fy j

    Resultants

    j )(F i )(F

    j )FF F ( i )FF (F

    F

    RyRx

    3y2y1y

    3x2x1x

    R

    +=

    +++++=++= 321 FFF

  • 13

    Addition of a System of Coplanar Forces

    yRy

    xxR

    F FFF

    =

    =

    Rx

    Ry

    FF1

    Ry2

    RxR

    tan

    FFF 2

    =

    +=

  • 14

    p.41, Problem 2-50The three forces are applied to the bracket. Determine the range of values for the magnitude of force P so that the resultant of the three forces does not exceed 2400 N.

  • 15

  • 16

    Cartesian Vectors

    Right-Handed Coordinate SystemRectangular Components of a Vector

    A=Ax+Ay+Az

    Unit VectorCartesian Unit Vector i , j , k

    uA = = AA

    AA

  • 17

    Cartesian Vectors

    Cartesian Vector Representation

    A = Ax i + Ay j + Az k

    Magnitude

    222zyx AAA ++

    22'zAA +|A| = =

    Axy

  • 18

    Cartesian Vectors

    Direction

    (unit vector)A

    A = cos A

    A=cos

    AA=cos

    cosine) (direction ,,

    zyx

    k A+ j A+ i A =k Acos j Acos i Acos =

    uA = A1=cos+cos +cos

    k cos j cos i cos=

    kA

    A+ jA

    A+i

    AA =

    AA =

    zyx

    A

    222

    zyxA

    ++

    ++

    u

  • 19

    Cartesian Vectors

    Addition and Subtraction of Cartesian VectorsR = A+B = (Ax+Bx)i + (Ay+By)j

    + (Az+Bz)kR= A-B = (Ax - Bx)i + (Ay - By)j

    + (Az - Bz)k

    Concurrent Force SystemskFjFiFF zyx ++==RF

  • 20

    p.55, Problem 2-84Determine the coordinate direction angles of F1 and FR .

  • 21

  • 22

    Position Vectors

    x, y, z Coordinates ()

    (6,-1,4) (0,2,0)

    (4,2,-6)

  • 23

    Position Vectors

    Position Vector

    Relative Position Vector

    O

    r = xi + yj +zk

  • 24

    Force Vector Directed along a Line

    )ABAB( F = uF = F

    r-r =AB

    F

    AB

  • 25

    p.62, Ex.2-15,

    Determine the resultant force acting at A.

    ( )( )( )

    mACAC

    mABAB

    CBA

    0.6)4,2,4(

    657.5)4,0,4(

    0,2,40,0,44,0,0

    ==

    ==

    L

    L

    N ) 80- , 40 , 80 (=

    (4,2,-4)6

    120 =

    ACAC F = F

    N ) 70.71- , 0 , 70.71 (=

    (4,0,-4)5.657100=

    ABAB

    F =F

    ACAC

    ABAB

    N 217 =(-150.71)40150.71=R

    N 150.71)- , 40 , (150.71 = F + F = R 222

    ACAB

    ++

  • 26

    p.65, Problem 2-93The chandelier is supported by three chains which are concurrent at point O. If the force in each chain has a magnitude of 300 N, express each force as a Cartesian vector and determine the magnitude and coordinate direction angles of the resultant force.

  • 27

  • 28

    Dot Product

    Cartesian Vector Formulation

    0

    01

    =

    ==

    ik

    ijii

    A

    B = AB cos , oo 1800

    ex: Work = F

    r

    0

    1

    0

    =

    =

    =

    jk

    jj

    ji

    1

    00

    =

    ==

    kk

    kjki

    )()( kBjBiBkAjAiABA ZyxZyx ++++=

    zzyyxx BABABA ++=

  • 29

    Dot Product

    Applications

    ABBA

    0=BA BA

    1. angle = cos-1( )

    when = 90o , cos = 0 , 2. components of a vector parallel and perpendicular to a line

    sin

    )(coscos

    ||

    ||

    ||

    AAAAA

    uuAuAAuAAA

    =

    =

    ==

    ==

  • 30

    p.72, Ex. 2-17, Determine the parallel and perpendicular components of the force to member AB.

    7.154)2.110(80)5.73(

    257110.222073.5F

    N ) 110.2- , 80 , 73.5- ( F-FF

    N ) 110.2 , 220 , 73.5 (

    (2,6,3)71

    76300

    )(

    )3,6,2(71

    362)3,6,2(

    ABAB u

    ) 3 , 6 , 2 B( ) 0 , 0 , 0 A(

    222

    222AB

    AB

    222AB

    NF

    N

    uuFF ABABAB

    =++=

    =++=

    ===

    =

    =

    =++

    ==

  • 31

    p.76, Problem 2-116Two forces act on the hook. Determine the angle between them.Also, what are the projections of F1 and F2 along the y axis?

  • 32

  • 33

    p.78, Problem 2-133Two cables exert forces on the pipe. Determine the magnitude of the projected component of F1 along the line of action of F2 .

  • 34

  • Chap. 2 Force Vectors Chapter OutlineScalar and VectorsVector Operations Vector OperationsVector OperationsVector Operations 8 9 10 11Addition of a System of Coplanar Forces Addition of a System of Coplanar Forces 14 15Cartesian VectorsCartesian VectorsCartesian VectorsCartesian Vectors 20 21Position VectorsPosition VectorsForce Vector Directed along a Line 25 26 27Dot ProductDot Product 30 31 32 33 34 35