chap14 mo - 國立臺灣大學

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1 Covalent bonding: Orbitals 14 Hybridization and the localized electron model Ex. CH 4 VSEPR: C H H H H CH H H H tetrahedral Valence orbitals involved in C: 2s, 2p x , 2p y ,2p z Lewis structure: An isolated orbital view one H bonding with 2s of C three H bonding with 2p of C Fact: The four bonds are equal length The bond angles are the same The isolated orbital view is not correct The idea of hybridization Four identical orbitals are generated from 2s, 2p x , 2p y ,2p z Represented as four sp 3 hybridized orbitals

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Microsoft PowerPoint - Chap14_MO.pptEx. CH4
VSEPR: C
Lewis structure:
An isolated orbital view one H bonding with 2s of C three H bonding with 2p of C
Fact: The four bonds are equal length The bond angles are the same
The isolated orbital view is not correct
The idea of hybridization Four identical orbitals are generated from 2s, 2px, 2py, 2pz
Represented as four sp3 hybridized orbitals
2
Related math A linear combination of 2s and 2p to give four new wave functions
1 = ½ [s + px + py
+ pz ] + + + +
– pz ] + + – –
– pz ] + – + –
+ pz ] + – – +
phase
The shape +
s p
Energy diagram
H H
Can not be sp3
sp2 hybridization hybridize one s with two ps and leave one p untouched s: has no directionality p: has directionality
The three sp2 orbitals adopt the directionality of the two ps
Lying on the same plane
120o Divide the plane equally Trigonal planar geometry
The untouched p orbital is orthogonal to this plane
Energy diagram
Form a bond
Has to be on the same plane for maximum overlap
The and bond constitute the double bond
bond: e density is centered between the two nuclei bond: e density is centered on the sideways
C CH H H
Sideway overlap is not so efficient: usually weaker
When the two p orbitals are orthogonal: no overlap No bond
C CH H
5
Two sp orbitals
Two orthogonal p orbitals of C are used in bonding
O C
Fact: electron density is cylindrically symmetrical around the O-C-O axis
Another possibility
Five dsp3
Ex. I3
I II
sp3
B
F
The VB theory can not explain some properties
MO theory: consider a new set of molecular orbitals are formed through the linear combination of atomic orbitals
(LCAO)
2 = 1sA 1sB
1
2
E AO AOMO Anti-bonding MO es are concentrated at the outside 1s*
opposite phase
Bonding MO es are concentrated between the two nuclei 1s
a nodal plane
Electrons are filled from the lowest level
1s 1s
order bond
1 2
E H H2 H
Fact: very unstable, does not exist The model is still too simple
Ex. He2
1s 1s
2 22
order bond
Bonding in homonuclear diatomic molecules
Li2 MOLi Li
1 2

In fact, Li does not exist as Li2 Forms metallic bond
The 2nd period
2p :
2p :
2p* :
2p* :
In a magnetic field: Compound with unpaired electrons
Has a permanent magnetic moment Attracted by a magnetic field Paramagnetic (strong)
Compound with paired electrons A magnetic moment will be induced by external magnetic field Repelled by the magnetic field Diamagnetic (weak)
12
Correction: Mixing of 2s and 2p
B2
a better model
2s
2s*
2p
2p
2p*
2p*
E
dia- dia- para- dia- dia- para- dia- BO 1 2 3 2 1 BE (kJ/mol) 290 620 942 495 154 BL (Å) 1.59 1.31 1.10 1.21 1.43
13
Note: The magnetic property of O2 can not be predicted by localized electron model Difficult to draw proper Lewis structure
Ex. O2, O2 +, O2
(2s)2 (2s*)2 (2p)2 (2p)4 (2p*)1
Electronic config:
1s
2p
E
Large difference in orbital energies (cf. IP: H 1311 kcal/mol; 1681 kcal/mol)
More F2p like Highly polarized bond e density closer to F
Cf. Bond cleavage Homolytic cleavage:
HF H + F H1 = BE Heterolytic cleavage:
HF H+ + F H2
HF H + F+ H3
Note: H1 ≠ H2 ≠ H3
O3
LE model for resonance
The difference of the two resonance structures Only the bond Consider bonds with LE model
Use MO to treat the bonding
O O O
lone pair in sp2
p LE model treats: 5 lone pairs 2 bonds A total of 14 electrons
MO treats: 4 electrons
E MOAO
Nonbonding level
In this MO view: the four electrons are delocalized over the three oxygens
Energy diagram of the MOs of O3
16
NO3
N
O
Benzene
LE ()
C
sp2-sp2
sp2-s
17
MO () Composed of 6 p orbitals provided by the 6 Cs each provides 1 e with a total of 6 es
6 electrons delocalized over 6 carbons in a closed cycle 6 new MOs are generated In fact, highly stabilized
(compared with 3 isolated double bonds)
















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Example of a complicate model:
C
HH
Molecular spectroscopy
When a molecule changing from one electronic state to another electronic state
It absorbs or emits electromagnetic radiation called electronic transition corresponds to ultraviolet (UV) or visible light
There are different vibrational states transitions between these states
correspond to infrared (IR) light
There are rotational states microwave
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1 0
3 2
1 0
0.1 nm 200 400800 250 m
nm
(bond length information)
)1( 2
I : moment of inertia
2 : reduced mass
J = 1 I
Vibrational spectroscopy For simple diatomic molecule
Stretching mode
k
k : force constant : reduced mass
k is related to the bond strength Masses of the atoms involved are
inversely proportional to stretching frequency
21
For molecules, the vibrational states are quantized
E = ho( + ½) o : a characteristic freq of the vibration
= 0, 1, 2, …. (for harmonic oscillator)
When = 0 2
The zero point energy E
r
o
1
Unit used by IR spectroscopy
1


Broad: due to hydrogen bonding

0
max = 171 nm Broad signal due to vibrational and rotational states
MO C C H
Ground state () Excited state () A singlet state ()
Ex. Ethylene
is destroyed
So S1
0
0.2
0.4
0.6
0.8
1.0
Emerging light intensity
Original light intensity
Beer’s law: A = bc concentration in M cell length in cm extinction coefficient (cm1M1)
Observing rate processes
Ex. Taking picture of a moving car The resolution depends on the shutter speed
Recall Heisenberg uncertainty principle:
For UV 10 nm apart t 1.4 × 1018 s
For IR 6 cm1 apart t 2.2 × 1013 s
Lifetime has to be this long to differentiate