đề gt2 hè
DESCRIPTION
hayTRANSCRIPT
-
TRNG I HC BCH KHOA TPHCM
KHOA KHOC HC NG DNG
B MN TON NG DNG
*
N TP CUI HC K H
TPHCM
Ngy 23 thng 7 nm 2015
-
1
Cu 1) Kho st v v th hm s : y = xe1x2
Cu 2) Tnh th tch vt th to ra khi quay min D quanh trc Ox, vi D c gii hn
bi:
x =4 y2, x y 1, x = 0, y = 0
Cu 3) Tnh tch phn sau: I =+0
arctanx
x2dx
Cu 4) Tm gi tr tch phn hi t: I =+0
cosx+ x
(1 + x)(arctanx x)dxCu 5) Tm nghim cc phng trnh vi phn sau:
a)y =1
x(2y + xex 2ex), tha y(1) = 2
b)(2x+ exy )dx+ (1 x
y)e
xy dy = 0
c) y(1 + x2) + y = arctanx, tha y(0) = 1
Cu 6) Gii h phng trnh vi phn: x(t) = x 4y + ty(t) = x 3y + et 2
Cu 1) Kho st v v th hm s : y =x
3(x 2)2
Cu 2) Tnh th tch vt th to ra khai quay min D quanh trc Oy, vi D c gii hn
bi:
y =3x2, y =
4 x2
Cu 3) Tnh tch phn sau: I =+1
dx
(1 ex)xCu 4) Tm gi tr tp sau hi t: I =
+1
lnx arctan (x 1)(xx) dx.
Cu 5) Tm nghim cc phng trnh vi phn sau y:
a) ydx (x+ y2 sin y)dy = 0b)(
y
x2 + y2 y)dx+ (ey x x
x2 + y2)dy = 0
Cu 6) Gii h phng trnh vi phn sau: x(t) = 5x 3y + tety(t) = 3x y + 4
2