riset-operasi-soal-tugas-2

:

Dikumpulkan: Minggu, 03.03.13 (Paling lambat) via Ketua KelasKerjakan soal-soal model tranportasi berikut ini dengan benar !

1. Soal Transportasi:

Selesaikan dengan:

a) Metode North West Corner (NWC)b) Metode Steping Stone2. Soal Transportasi:

Selesaikan dengan metode

a) Metode Biaya Terkecil

b) Metode MODIJawaban:

Nomer 1 :

a) Metode North West Corner (NWC)

Tabel Awal Solusi 1: Metode Aturan Nortwest-Corner

Tabel Awal Solusi 2: Metode Biaya Terendah Intuitif

b) Metode Steping StoneStepstone : Tabel awal Metode Aturan Nortwest-CornerKeGudangGudangGudangKAPTotal Cost

DariABCTC

PabrikRp20Rp5Rp890

W50-40+90Rp1.200

PabrikRp15Rp20Rp1060

H+60-60Rp1.200


P104050Rp860

DT(daya Tampung)50501101104040200Rp3.260

Indeks rute kosong:

Rute dengan Index negatif terbesar yang dipilih yaitu ; H AQuantitas/Jumlah terkecil yang bertanda negatif yg dipilih yaitu 50 (Rute W-A).

Perbaikan 1:

KeGudangGudangGudangKAPTotal Cost

DariABCTC

PabrikRp20Rp5Rp890

W9090Rp450


H5010-+60Rp950


P10+40-50Rp860


Indeks:

Rute dengan Index negatif terbesar yang dipilih yaitu ; H CQuantitas/Jumlah terkecil yang bertanda negatif yg dipilih yaitu 10 (Rute H-B)Perbaikan 2:


DariABCTC

PabrikRp20Rp5Rp890

W90-+90Rp450


H501060Rp850


P20+30-50Rp770


Indeks:

Rute dengan Index negatif terbesar yang dipilih yaitu ; W CQuantitas/Jumlah terkecil yang bertanda negatif yg dipilih yaitu 30 (Rute P-C)Perbaikan 3:


DariABCTC

PabrikRp20Rp5Rp890

W60-30+90Rp540


H501060Rp850


P30+-30Rp300


Indeks:

Solusi sudah optimal karena indeks positif semua.Biaya optimal : Rp 1.690

Nomer 2:

a. Metode biaya terkecil

Tabel metode biaya terkecil

b. Metode MODITabel NWC

Menghitung nilai R dan K pada kolom gudang yang terisi :

Masukkan nilai R dan K

Perbaikan Indeks :

Yang negatif besar : 1-B

Perbaikan tabel 1:

Menghitung R dan K :


Perbaikan Indeks :

Yang negatif besar : 2-C

Perbaikan tabel 2 :

Menghitung nilai R dan K


Perbaikan indeks :

Yang negatif besar 3-A

Perbaikan tabel 3:

Menhitung nilai R dan K


Perbaikan indeks:

Solusi sudah optimum karena Indeks sudah positif semuaBiaya optimum : Rp 1.288.800

1

NWC

Matrik 1

KePabrikPabrikPabrikPabrikPabrikKAPTotal Cost

DariABCDEKAPTC

Gudang10111281340

P202040420

Gudang2108141660

Q10302060620

Gudang14121016780

R4265080806

DT(daya Tampung)20203030343446465050180Rp1,846

Matrik 2


DariABCDEKAPTC

Gudang10111281340

P1520540430

Gudang2108141660

Q510252060590

Gudang14121016780

R04265080806

DT(daya Tampung)202030303434464650501801826

20

Matrik 3


DariABCDEKAPTC

Gudang10111281340

P1025540435

Gudang2108141660

Q105252060550

Gudang14121016780

R04265080806

DT(daya Tampung)202030303434464650501801791

Matrik 4


DariABCDEKAPTC

Gudang10111281340

P530540440

Gudang2108141660

Q150252060510

Gudang14121016780

R04265080806

DT(daya Tampung)202030303434464650501801756

Matrik 5


DariABCDEKAPTC

Gudang10111281340

P0301040450

Gudang2108141660

Q200202060480

Gudang14121016780

R04265080806

DT(daya Tampung)202030303434464650501801736

Matrik 6


DariABCDEKAPTC

Gudang10111281340

P0251540455

Gudang2108141660

Q205152060490

Gudang14121016780

R04265080806

DT(daya Tampung)202030303434464650501801751

Sheet2

Matrik 1


DariABCDEKAPTC

Gudang10111281340

P202000040420

Gudang2108141660

Q0103020501101420

Gudang14121016780

R00426030456

DT(daya Tampung)202030303434464650501802296

Matrik


DariABCDEKAPTC

Gudang10111281340

P201721040419

Gudang2108141660

Q01020141660712

Gudang14121016780

R0312313480890

DT(daya Tampung)202030303434464650501802021

Solusi Awal TM2 Soal1



DariABCKAPTC

PabrikRp20Rp5Rp890

W504090Rp1,200


H6060Rp1,200


P104050Rp860




DariABCKAPTC

PabrikRp20Rp5Rp890

W9090Rp450


H204060Rp700


P302050Rp950


1) Pilih sel dgn biaya terendah dan pilih salah satu jika ada beberapa yang sama.

2) Alokasikan unit sebanyak mungkin u/ sel tsb. tanpa melebihi kapasitas.

3) Coret yang sudah terisi penuh.

4) Pilih sel dengan biaya terendah u/ sel sisanya.

5) Ulangi 2 dan 3.

Soal 1 StepStone

Stepstone : Tabel awal Metode Aturan Nortwest-Corner


DariABCKAPTC

PabrikRp20Rp5Rp890

W50-40+90Rp1,200


H+60-60Rp1,200


P104050Rp860


Indeks rute kosong:

IndeksW - C+ 8 - 5 + 20 - 10 + 20=33

H - A+15 - 20 + 5 - 20=-20

H - C+10 - 19 + 10 - 20 + 5=-14

P - A+25 - 10 + 20 -5 - 20=10

Rute dengan Index negatif terbesar yang dipilih yaitu ; H - A

Quantitas/Jumlah terkecil yang bertanda negatif yg dipilih yaitu 50 (Rute W-A)


DariABCKAPTC

PabrikRp20Rp5Rp890

W9090Rp4505040


H5010-+60Rp950


P10+40-50Rp860


IndeksW - A+20 - 15 + 20 - 5=20

W - C+8 - 5 + 20 - 10 + 19=32

H - C+10 - 19 + 10 - 20 =-14

P - A+25 - 10 + 20 - 15=20

Rute dengan Index negatif terbesar yang dipilih yaitu ; H - C

Quantitas/Jumlah terkecil yang bertanda negatif yg dipilih yaitu 10 (Rute H-B)


DariABCKAPTC

PabrikRp20Rp5Rp890

W90-+90Rp450


H501060Rp850


P20+30-50Rp770


IndeksW -A+20 - 5 + 10 - 15=10

W - C+8 - 5 + 10 - 19=-6

H - B+20 - 10 + 19 - 10=19

P - A+25 - 19 + 10 - 15=1

Rute dengan Index negatif terbesar yang dipilih yaitu ; W - C

Quantitas/Jumlah terkecil yang bertanda negatif yg dipilih yaitu 30 (Rute P-C)


DariABCKAPTC

PabrikRp20Rp5Rp890

W60-30+90Rp540


H501060Rp850


P30+-30Rp300


IndeksW - A+20 - 8 + 10 - 15=7

H - B+20 - 10 + 8 - 5=13

P - A+25 - 10 + 5 - 15=5

P - C+19 - 8 + 5 - 10=6

Solusi sudah optimal karena indeks positif semua.

Sheet1

Tabel Awal : Metode Biaya Terendah Intuitif


DariABCKAPTC

PabrikRp3,200Rp3,300Rp3,400106

1106106Rp339,200


24191132Rp518,000


316111127Rp465,100

DT(daya Tampung)1221221521529191365Rp1,322,300





5) Ulangi 2 dan 3.

KeGudang AGudang BGudang CKAPTotal Cost

DariK1K2K3KAPTC

Pabrik 1Rp3,200Rp3,300Rp3,400106

R1106106Rp339,200

Pabrik 2Rp3,600Rp4,200Rp3,800132

R216116132Rp544,800

Pabrik 3Rp3,400Rp3,700Rp4,000127

R33691127Rp497,200


1-A=R1 + K1 = 3200R1 + 0 = 3200R1 = 3200

2-A=R2 + K1 = 3600R2 + 0 = 3600R2 = 3600

2-B=R2 + K2 = 42003600 + K2 = 4200K2 = 600

3-B=R3 + K2 = 3700R3 + 600 = 3700R3 = 3100

3-C=R3 + K3 = 37003100 + K3 = 3700K3 = 600

1-B3300-3200-600-500

1-C3400-3200-600-400

2-C3800-3600-600-400

3-A3400-3100-0300

Yang negatif besar 1-B


DariK1 = 0K2 = 600K3 = 600KAPTC

Pabrik 1Rp3,200Rp3,300Rp3,400106

R1 = 3200106-+106Rp339,200

Pabrik 2Rp3,600Rp4,200Rp3,800132

R2 = 360016+116-132Rp544,800

Pabrik 3Rp3,400Rp3,700Rp4,000127

R3 = 31003691127Rp497,200


1-A=R1 + K1 = 3200=R1 + 0 = 3200R1 = 3200

2-A=R2 + K1 = 3600=R2 + 0 = 3600R2 = 3600

2-B=R2 + K2 = 4200=3600 + K2 = 4200K2 = 600

3-B=R3 + K2 = 3700=R3 + 600 = 3700R3 = 3100

3-C=R3 + K3 = 3700=3100 + K3 = 3700K3 = 600

1-B=3300-3200-600=-500

1-C=3400-3200-600=-400

2-C=3800-3600-600=-400

3-A=3400-3100-0=300



DariK1 = 0K2 = 600K3 = 600KAPTC

Pabrik 1Rp3,200Rp3,300Rp3,400106

R1 = 3200-106+106Rp349,800

Pabrik 2Rp3,600Rp4,200Rp3,800132

R2 = 3600122+10-132Rp481,200

Pabrik 3Rp3,400Rp3,700Rp4,000127

R3 = 31003691127Rp497,200


1-B=R1 + K2 = 33000 + K2 = 3300K2 = 3300

2-A=R2 + K1 = 3600900 + K1 = 3600K1 = 2700

2-B=R2 + K2 = 4200R2 + 3300 = 4200R2 = 900

3-B=R3 + K2 = 3700R3 + 3300 = 3700R3 = 400

3-C=R3 + K3 = 4000400 + K3 = 4000K3 = 3600


DariK1 = 2700K2 = 3300K3 = 3600KAPTC

Pabrik 1Rp3,200Rp3,300Rp3,400106

R1 = 0106106Rp349,800

Pabrik 2Rp3,600Rp4,200Rp3,800132

R2 = 90012210132Rp481,200

Pabrik 3Rp3,400Rp3,700Rp4,000127

R3 = 4003691127Rp497,200


1-A=3200-0-2700500

1-C=3400-0-3600-200

2-C=3800-900-3600-700

3-A=3400-400-2700300

Yang negatif besar 2-C


DariK1 = 2700K2 = 3300K3 = 3600KAPTC

Pabrik 1Rp3,200Rp3,300Rp3,400106

R1 = 0106106Rp349,800

Pabrik 2Rp3,600Rp4,200Rp3,800132

R2 = 900122-10+132Rp477,200

Pabrik 3Rp3,400Rp3,700Rp4,000127

R3 = 40046+81-127Rp494,200


1-B=R1 + K2 = 33000 + K2 = 3300K2 = 3300

2-A=R2 + K1 = 3600200 + K1 = 3600K1 = 3400

2-C=R2 + K3 = 3800R2 + 3600 = 3800R2 = 200

3-B=R3 + K2 = 3700R3 + 3300 = 3700R3 = 400

3-C=R3 + K3 = 4000400 + K3 = 4000K3 = 3600


DariK1 = 3400K2 = 3300K3 = 3600KAPTC

Pabrik 1Rp3,200Rp3,300Rp3,400106

R1 = 0106106Rp349,800

Pabrik 2Rp3,600Rp4,200Rp3,800132

R2 = 200122-10+132Rp477,200

Pabrik 3Rp3,400Rp3,700Rp4,000127

R3 = 40046+81-127Rp494,200


1-A=3200-0-3400=-200

1-C=3400-0-3400=0

2-B=4200-200-3300=700

3-A=3400-400-3400=-400

Negatif besar : 3-A


DariK1 = 3400K2 = 3300K3 = 3600KAPTC

Pabrik 1Rp3,200Rp3,300Rp3,400106

R1 = 0106106Rp349,800

Pabrik 2Rp3,600Rp4,200Rp3,800132

R2 = 200122-10+132Rp477,200

Pabrik 3Rp3,400Rp3,700Rp4,000127

R3 = 40046+-81127Rp480,400


Solusi Stepstone TM2 Soal1

Stepstone Solusi 1: Metode Aturan Nortwest-Corner


DariABCKAPTC

PabrikRp20Rp5Rp890

W9090Rp450


H501060Rp950


P104050Rp860


Stepstone Solusi 2: Metode Biaya Terendah Intuitif


DariABCKAPTC

PabrikRp20Rp5Rp890

W0Rp0


H0Rp0


P0Rp0

DT(daya Tampung)05001100400Rp0





5) Ulangi 2 dan 3.

Solusi Optimal StepStone (2)

Solusi Optimal Metode Stepping-Stone

Dari Tabel Awal Solusi 1: Metode Aturan Nortwest-Corner


DariPQRKAPTC

Pabrik$5$4$3100

A100100$500

Pabrik$8$4$3300

B200100300$2,000

Pabrik$9$7$5300

C1007200300$1,700

DT(daya Tampung)300300200200200200700$4,200

Indek Rute Kosong:

Indeks Rute A-Q= +$4-$5+$8-$4= + $3

Indeks Rute A-R= +$3-$5+$8-$4+$7-$5= + $4

Indeks Rute B-R= +$3-$4+$7-$5= + $1

Indeks Rute C-P= +$9-$7+$4-$8= - $2(Rute dengan Index negatif terbesar yang dipilih).

Quantitas/Jumlah terkecil yang bertanda negatif yg dipilih yaitu 100 (Rute C-Q) bukan 200 (Rute B-P) yg dipindah ke rute yang dipilih.

Matrik Solusi Optimal : Metode Stepping-Stone


DariPQRKAPTC

Pabrik$5$4$3100

A100100$500

Pabrik$8$4$3300

B100_200+300$1,600

Pabrik$9$7$5300

C100+_200300$1,900

DT(daya Tampung)300300200200200200700$4,000

Indeks Rute Kosong:

Indeks A-Q= +$4-$5+$8-$4= + $3

Indeks C-Q= +$7-$4+$8-$9= + $2

Indeks A-R= +$3-$5+$8-$4+$7-$5= + $4

Indeks B-R= +$3-$4+$8-$9+$5= + $3

Berarti solusi sudah optimal karena indeks positif semua.

Solusi Awal ANC dan IM



DariPQRKAPTC

Pabrik$5$4$3100

A100100$500

Pabrik$8$4$3300

B200100300$2,000

Pabrik$9$7$5300

C100200300$1,700

DT(daya Tampung)300300200200200200700$4,200



DariPQRKAPTC

Pabrik$5$4$3100

A100100$300

Pabrik$8$4$3300

B200100300$1,100

Pabrik$9$7$5300

C300300$2,700

DT(daya Tampung)300300200200200200700$4,100





5) Ulangi 2 dan 3.

Solusi Optimal StepStone




DariPQRKAPTC

Pabrik$5$4$3100

A100100$500

Pabrik$8$4$3300

B200100300$2,000

Pabrik$9$7$5300

C99200299$1,693

DT(daya Tampung)300300199200200200699$4,193

Indek Rute Kosong:

Indeks Rute A-Q= +$4-$5+$8-$4= + $3

Indeks Rute A-R= +$3-$5+$8-$4+$7-$5= + $4

Indeks Rute B-R= +$3-$4+$7-$5= + $1





DariPQRKAPTC

Pabrik$5$4$3100

A100100$500

Pabrik$8$4$3300

B100_200+300$1,600

Pabrik$9$7$5300

C100+_200300$1,900

DT(daya Tampung)300300200200200200700$4,000

Indeks Rute Kosong:

Indeks A-Q= +$4-$5+$8-$4= + $3

Indeks C-Q= +$7-$4+$8-$9= + $2

Indeks A-R= +$3-$5+$8-$4+$7-$5= + $4

Indeks B-R= +$3-$4+$8-$9+$5= + $3


Solusi Awal&Optimal StepStone


Dari Matrik Solusi Awal 1: Aturan Nortwest-Corner

KeDepokBogorBekasiSupplyTotal Cost

DariPQRKAPTC

Supplier$200$250$210500

Tangerang (A)500-+500$100,000

Supplier$90$150$1601400

Jakarta (B)100+1100200-1400$206,000

Demand600600110011002002001900$306,000

Indeks rute A-Q= +$250-$200+$90-$150= -$10

Indeks rute A-R= +$210-$200+$90-$160= -$60(Rute dengan Index negatif terbesar yang dipilih).

Jumlah terkecil yang bertanda negatif yg dipilih yaitu 200 bukan 500 yg dipindah ke rute yang dipilih.

Matrik Solusi Optimal 1: Metode Stepping-Stone


DariPQRKAPTC

Supplier$200$250$210500

A300-200+500$102,000

Supplier$90$150$1601400

B300+1100-1400$192,000

Demand600600110011002002001900$294,000

Indeks A-Q= +$250-$200+$90-$150= -$10

Indeks B-R= +$160-$210+$200-$90= $60

Berarti solusi belum optimal karena masih ada indeks negatif.




DariPQRKAPTC

Supplier$200$250$210500

A-300+200500$117,000

Supplier$90$150$1601400

B600+800-1400$174,000

Demand600600110011002002001900$291,000

Indeks A-P= +$200-$90+$150-$250= $10

Indeks B-R= +$160-$210+$250-$150= $50


Model Program Linier

X210

9

8

7C(0,6)

6

5B(8,4)

4

3

2

1A(16,0)

012345678910111213141516171819202122232425

X1

X1 + 2X2 16

X1 + 4X2 24

ROP

Dalam Ribuan Unit60

55

50

45

40

35

30

25

20

15

10

5

0123456789101112131415161718192021222324252627282930

Dalam puluhan hari.

Biaya Simpan= =Rp1,458,333,333

7.75

ROP=11

SS = 5

39

45

NWC

Matrik 1


DariABCDEKAPTC

Gudang10111281340

P202040420

Gudang2108141660

Q10302060620

Gudang14121016780

R4265080806


Matrik 2


DariABCDEKAPTC

Gudang10111281340

P1520540430

Gudang2108141660

Q510252060590

Gudang14121016780

R04265080806

DT(daya Tampung)202030303434464650501801826

20

Matrik 3


DariABCDEKAPTC

Gudang10111281340

P1025540435

Gudang2108141660

Q105252060550

Gudang14121016780

R04265080806

DT(daya Tampung)202030303434464650501801791

Matrik 4


DariABCDEKAPTC

Gudang10111281340

P530540440

Gudang2108141660

Q150252060510

Gudang14121016780

R04265080806

DT(daya Tampung)202030303434464650501801756

Matrik 5


DariABCDEKAPTC

Gudang10111281340

P0301040450

Gudang2108141660

Q200202060480

Gudang14121016780

R04265080806

DT(daya Tampung)202030303434464650501801736

Matrik 6


DariABCDEKAPTC

Gudang10111281340

P0251540455

Gudang2108141660

Q205152060490

Gudang14121016780

R04265080806

DT(daya Tampung)202030303434464650501801751

Sheet2

Matrik 1


DariABCDEKAPTC

Gudang10111281340

P202000040420

Gudang2108141660

Q0103020501101420

Gudang14121016780

R00426030456

DT(daya Tampung)202030303434464650501802296

Matrik


DariABCDEKAPTC

Gudang10111281340

P201721040419

Gudang2108141660

Q01020141660712

Gudang14121016780

R0312313480890

DT(daya Tampung)202030303434464650501802021




DariABCKAPTC

PabrikRp20Rp5Rp890

W504090Rp1,200


H6060Rp1,200


P104050Rp860




DariABCKAPTC

PabrikRp20Rp5Rp890

W9090Rp450


H204060Rp700


P302050Rp950






5) Ulangi 2 dan 3.

Soal 1 StepStone



DariABCKAPTC

PabrikRp20Rp5Rp890

W50-40+90Rp1,200


H+60-60Rp1,200


P104050Rp860


Indeks rute kosong:

IndeksW - C+ 8 - 5 + 20 - 10 + 20=33

H - A+15 - 20 + 5 - 20=-20

H - C+10 - 19 + 10 - 20 + 5=-14

P - A+25 - 10 + 20 -5 - 20=10




DariABCKAPTC

PabrikRp20Rp5Rp890

W9090Rp4505040


H5010-+60Rp950


P10+40-50Rp860


IndeksW - A+20 - 15 + 20 - 5=20

W - C+8 - 5 + 20 - 10 + 19=32

H - C+10 - 19 + 10 - 20 =-14

P - A+25 - 10 + 20 - 15=20




DariABCKAPTC

PabrikRp20Rp5Rp890

W90-+90Rp450


H501060Rp850


P20+30-50Rp770


IndeksW -A+20 - 5 + 10 - 15=10

W - C+8 - 5 + 10 - 19=-6

H - B+20 - 10 + 19 - 10=19

P - A+25 - 19 + 10 - 15=1




DariABCKAPTC

PabrikRp20Rp5Rp890

W60-30+90Rp540


H501060Rp850


P30+-30Rp300


IndeksW - A+20 - 8 + 10 - 15=7

H - B+20 - 10 + 8 - 5=13

P - A+25 - 10 + 5 - 15=5

P - C+19 - 8 + 5 - 10=6


Sheet1



DariABCKAPTC


1106106Rp339,200


24191132Rp518,000


316111127Rp465,100






5) Ulangi 2 dan 3.


DariK1K2K3KAPTC

Pabrik 1Rp3,200Rp3,300Rp3,400106

R1106106Rp339,200

Pabrik 2Rp3,600Rp4,200Rp3,800132

R216116132Rp544,800

Pabrik 3Rp3,400Rp3,700Rp4,000127

R33691127Rp497,200


1-A=R1 + K1 = 3200R1 + 0 = 3200R1 = 3200

2-A=R2 + K1 = 3600R2 + 0 = 3600R2 = 3600

2-B=R2 + K2 = 42003600 + K2 = 4200K2 = 600

3-B=R3 + K2 = 3700R3 + 600 = 3700R3 = 3100

3-C=R3 + K3 = 37003100 + K3 = 3700K3 = 600

1-B3300-3200-600-500

1-C3400-3200-600-400

2-C3800-3600-600-400

3-A3400-3100-0300



DariK1 = 0K2 = 600K3 = 600KAPTC

Pabrik 1Rp3,200Rp3,300Rp3,400106

R1 = 3200106-+106Rp339,200

Pabrik 2Rp3,600Rp4,200Rp3,800132

R2 = 360016+116-132Rp544,800

Pabrik 3Rp3,400Rp3,700Rp4,000127

R3 = 31003691127Rp497,200


1-A=R1 + K1 = 3200=R1 + 0 = 3200R1 = 3200

2-A=R2 + K1 = 3600=R2 + 0 = 3600R2 = 3600

2-B=R2 + K2 = 4200=3600 + K2 = 4200K2 = 600

3-B=R3 + K2 = 3700=R3 + 600 = 3700R3 = 3100

3-C=R3 + K3 = 3700=3100 + K3 = 3700K3 = 600

1-B=3300-3200-600=-500

1-C=3400-3200-600=-400

2-C=3800-3600-600=-400

3-A=3400-3100-0=300



DariK1 = 0K2 = 600K3 = 600KAPTC

Pabrik 1Rp3,200Rp3,300Rp3,400106

R1 = 3200-106+106Rp349,800

Pabrik 2Rp3,600Rp4,200Rp3,800132

R2 = 3600122+10-132Rp481,200

Pabrik 3Rp3,400Rp3,700Rp4,000127

R3 = 31003691127Rp497,200


1-B=R1 + K2 = 33000 + K2 = 3300K2 = 3300

2-A=R2 + K1 = 3600900 + K1 = 3600K1 = 2700

2-B=R2 + K2 = 4200R2 + 3300 = 4200R2 = 900

3-B=R3 + K2 = 3700R3 + 3300 = 3700R3 = 400

3-C=R3 + K3 = 4000400 + K3 = 4000K3 = 3600


DariK1 = 2700K2 = 3300K3 = 3600KAPTC

Pabrik 1Rp3,200Rp3,300Rp3,400106

R1 = 0106106Rp349,800

Pabrik 2Rp3,600Rp4,200Rp3,800132

R2 = 90012210132Rp481,200

Pabrik 3Rp3,400Rp3,700Rp4,000127

R3 = 4003691127Rp497,200


1-A=3200-0-2700500

1-C=3400-0-3600-200

2-C=3800-900-3600-700

3-A=3400-400-2700300



DariK1 = 2700K2 = 3300K3 = 3600KAPTC

Pabrik 1Rp3,200Rp3,300Rp3,400106

R1 = 0106106Rp349,800

Pabrik 2Rp3,600Rp4,200Rp3,800132

R2 = 900122-10+132Rp477,200

Pabrik 3Rp3,400Rp3,700Rp4,000127

R3 = 40046+81-127Rp494,200


1-B=R1 + K2 = 33000 + K2 = 3300K2 = 3300

2-A=R2 + K1 = 3600200 + K1 = 3600K1 = 3400

2-C=R2 + K3 = 3800R2 + 3600 = 3800R2 = 200

3-B=R3 + K2 = 3700R3 + 3300 = 3700R3 = 400

3-C=R3 + K3 = 4000400 + K3 = 4000K3 = 3600


DariK1 = 3400K2 = 3300K3 = 3600KAPTC

Pabrik 1Rp3,200Rp3,300Rp3,400106

R1 = 0106106Rp349,800

Pabrik 2Rp3,600Rp4,200Rp3,800132

R2 = 200122-10+132Rp477,200

Pabrik 3Rp3,400Rp3,700Rp4,000127

R3 = 40046+81-127Rp494,200


1-A=3200-0-3400=-200

1-C=3400-0-3400=0

2-B=4200-200-3300=700

3-A=3400-400-3400=-400

Negatif besar : 3-A


DariK1 = 3400K2 = 3300K3 = 3600KAPTC

Pabrik 1Rp3,200Rp3,300Rp3,400106

R1 = 0106106Rp349,800

Pabrik 2Rp3,600Rp4,200Rp3,800132

R2 = 200122-10+132Rp477,200

Pabrik 3Rp3,400Rp3,700Rp4,000127

R3 = 40046+-81127Rp480,400





DariABCKAPTC

PabrikRp20Rp5Rp890

W9090Rp450


H501060Rp950


P104050Rp860




DariABCKAPTC

PabrikRp20Rp5Rp890

W0Rp0


H0Rp0


P0Rp0






5) Ulangi 2 dan 3.





DariPQRKAPTC

Pabrik$5$4$3100

A100100$500

Pabrik$8$4$3300

B200100300$2,000

Pabrik$9$7$5300

C1007200300$1,700

DT(daya Tampung)300300200200200200700$4,200

Indek Rute Kosong:

Indeks Rute A-Q= +$4-$5+$8-$4= + $3

Indeks Rute A-R= +$3-$5+$8-$4+$7-$5= + $4

Indeks Rute B-R= +$3-$4+$7-$5= + $1





DariPQRKAPTC

Pabrik$5$4$3100

A100100$500

Pabrik$8$4$3300

B100_200+300$1,600

Pabrik$9$7$5300

C100+_200300$1,900

DT(daya Tampung)300300200200200200700$4,000

Indeks Rute Kosong:

Indeks A-Q= +$4-$5+$8-$4= + $3

Indeks C-Q= +$7-$4+$8-$9= + $2

Indeks A-R= +$3-$5+$8-$4+$7-$5= + $4

Indeks B-R= +$3-$4+$8-$9+$5= + $3





DariPQRKAPTC

Pabrik$5$4$3100

A100100$500

Pabrik$8$4$3300

B200100300$2,000

Pabrik$9$7$5300

C100200300$1,700

DT(daya Tampung)300300200200200200700$4,200



DariPQRKAPTC

Pabrik$5$4$3100

A100100$300

Pabrik$8$4$3300

B200100300$1,100

Pabrik$9$7$5300

C300300$2,700

DT(daya Tampung)300300200200200200700$4,100





5) Ulangi 2 dan 3.





DariPQRKAPTC

Pabrik$5$4$3100

A100100$500

Pabrik$8$4$3300

B200100300$2,000

Pabrik$9$7$5300

C99200299$1,693

DT(daya Tampung)300300199200200200699$4,193

Indek Rute Kosong:

Indeks Rute A-Q= +$4-$5+$8-$4= + $3

Indeks Rute A-R= +$3-$5+$8-$4+$7-$5= + $4

Indeks Rute B-R= +$3-$4+$7-$5= + $1





DariPQRKAPTC

Pabrik$5$4$3100

A100100$500

Pabrik$8$4$3300

B100_200+300$1,600

Pabrik$9$7$5300

C100+_200300$1,900

DT(daya Tampung)300300200200200200700$4,000

Indeks Rute Kosong:

Indeks A-Q= +$4-$5+$8-$4= + $3

Indeks C-Q= +$7-$4+$8-$9= + $2

Indeks A-R= +$3-$5+$8-$4+$7-$5= + $4

Indeks B-R= +$3-$4+$8-$9+$5= + $3






DariPQRKAPTC

Supplier$200$250$210500

Tangerang (A)500-+500$100,000

Supplier$90$150$1601400

Jakarta (B)100+1100200-1400$206,000

Demand600600110011002002001900$306,000

Indeks rute A-Q= +$250-$200+$90-$150= -$10





DariPQRKAPTC

Supplier$200$250$210500

A300-200+500$102,000

Supplier$90$150$1601400

B300+1100-1400$192,000

Demand600600110011002002001900$294,000

Indeks A-Q= +$250-$200+$90-$150= -$10

Indeks B-R= +$160-$210+$200-$90= $60





DariPQRKAPTC

Supplier$200$250$210500

A-300+200500$117,000

Supplier$90$150$1601400

B600+800-1400$174,000

Demand600600110011002002001900$291,000

Indeks A-P= +$200-$90+$150-$250= $10

Indeks B-R= +$160-$210+$250-$150= $50



X210

9

8

7C(0,6)

6

5B(8,4)

4

3

2

1A(16,0)

012345678910111213141516171819202122232425

X1

X1 + 2X2 16

X1 + 4X2 24

ROP

Dalam Ribuan Unit60

55

50

45

40

35

30

25

20

15

10

5

0123456789101112131415161718192021222324252627282930

Dalam puluhan hari.


7.75

ROP=11

SS = 5

39

45

NWC

Matrik 1


DariABCDEKAPTC

Gudang10111281340

P202040420

Gudang2108141660

Q10302060620

Gudang14121016780

R4265080806


Matrik 2


DariABCDEKAPTC

Gudang10111281340

P1520540430

Gudang2108141660

Q510252060590

Gudang14121016780

R04265080806

DT(daya Tampung)202030303434464650501801826

20

Matrik 3


DariABCDEKAPTC

Gudang10111281340

P1025540435

Gudang2108141660

Q105252060550

Gudang14121016780

R04265080806

DT(daya Tampung)202030303434464650501801791

Matrik 4


DariABCDEKAPTC

Gudang10111281340

P530540440

Gudang2108141660

Q150252060510

Gudang14121016780

R04265080806

DT(daya Tampung)202030303434464650501801756

Matrik 5


DariABCDEKAPTC

Gudang10111281340

P0301040450

Gudang2108141660

Q200202060480

Gudang14121016780

R04265080806

DT(daya Tampung)202030303434464650501801736

Matrik 6


DariABCDEKAPTC

Gudang10111281340

P0251540455

Gudang2108141660

Q205152060490

Gudang14121016780

R04265080806

DT(daya Tampung)202030303434464650501801751

Sheet2

Matrik 1


DariABCDEKAPTC

Gudang10111281340

P202000040420

Gudang2108141660

Q0103020501101420

Gudang14121016780

R00426030456

DT(daya Tampung)202030303434464650501802296

Matrik


DariABCDEKAPTC

Gudang10111281340

P201721040419

Gudang2108141660

Q01020141660712

Gudang14121016780

R0312313480890

DT(daya Tampung)202030303434464650501802021




DariABCKAPTC

PabrikRp20Rp5Rp890

W504090Rp1,200


H6060Rp1,200


P104050Rp860




DariABCKAPTC

PabrikRp20Rp5Rp890

W9090Rp450


H204060Rp700


P302050Rp950






5) Ulangi 2 dan 3.

Soal 1 StepStone



DariABCKAPTC

PabrikRp20Rp5Rp890

W50-40+90Rp1,200


H+60-60Rp1,200


P104050Rp860


Indeks rute kosong:

IndeksW - C+ 8 - 5 + 20 - 10 + 20=33

H - A+15 - 20 + 5 - 20=-20

H - C+10 - 19 + 10 - 20 + 5=-14

P - A+25 - 10 + 20 -5 - 20=10




DariABCKAPTC

PabrikRp20Rp5Rp890

W9090Rp4505040


H5010-+60Rp950


P10+40-50Rp860


IndeksW - A+20 - 15 + 20 - 5=20

W - C+8 - 5 + 20 - 10 + 19=32

H - C+10 - 19 + 10 - 20 =-14

P - A+25 - 10 + 20 - 15=20




DariABCKAPTC

PabrikRp20Rp5Rp890

W90-+90Rp450


H501060Rp850


P20+30-50Rp770


IndeksW -A+20 - 5 + 10 - 15=10

W - C+8 - 5 + 10 - 19=-6

H - B+20 - 10 + 19 - 10=19

P - A+25 - 19 + 10 - 15=1




DariABCKAPTC

PabrikRp20Rp5Rp890

W60-30+90Rp540


H501060Rp850


P30+-30Rp300


IndeksW - A+20 - 8 + 10 - 15=7

H - B+20 - 10 + 8 - 5=13

P - A+25 - 10 + 5 - 15=5

P - C+19 - 8 + 5 - 10=6


Sheet1



DariABCKAPTC


1106106Rp339,200


24191132Rp518,000


316111127Rp465,100






5) Ulangi 2 dan 3.


DariK1K2K3KAPTC

Pabrik 1Rp3,200Rp3,300Rp3,400106

R1106106Rp339,200

Pabrik 2Rp3,600Rp4,200Rp3,800132

R216116132Rp544,800

Pabrik 3Rp3,400Rp3,700Rp4,000127

R33691127Rp497,200


1-A=R1 + K1 = 3200R1 + 0 = 3200R1 = 3200

2-A=R2 + K1 = 3600R2 + 0 = 3600R2 = 3600

2-B=R2 + K2 = 42003600 + K2 = 4200K2 = 600

3-B=R3 + K2 = 3700R3 + 600 = 3700R3 = 3100

3-C=R3 + K3 = 37003100 + K3 = 3700K3 = 600

1-B3300-3200-600-500

1-C3400-3200-600-400

2-C3800-3600-600-400

3-A3400-3100-0300



DariK1 = 0K2 = 600K3 = 600KAPTC

Pabrik 1Rp3,200Rp3,300Rp3,400106

R1 = 3200106-+106Rp339,200

Pabrik 2Rp3,600Rp4,200Rp3,800132

R2 = 360016+116-132Rp544,800

Pabrik 3Rp3,400Rp3,700Rp4,000127

R3 = 31003691127Rp497,200


1-A=R1 + K1 = 3200=R1 + 0 = 3200R1 = 3200

2-A=R2 + K1 = 3600=R2 + 0 = 3600R2 = 3600

2-B=R2 + K2 = 4200=3600 + K2 = 4200K2 = 600

3-B=R3 + K2 = 3700=R3 + 600 = 3700R3 = 3100

3-C=R3 + K3 = 3700=3100 + K3 = 3700K3 = 600

1-B=3300-3200-600=-500

1-C=3400-3200-600=-400

2-C=3800-3600-600=-400

3-A=3400-3100-0=300



DariK1 = 0K2 = 600K3 = 600KAPTC

Pabrik 1Rp3,200Rp3,300Rp3,400106

R1 = 3200-106+106Rp349,800

Pabrik 2Rp3,600Rp4,200Rp3,800132

R2 = 3600122+10-132Rp481,200

Pabrik 3Rp3,400Rp3,700Rp4,000127

R3 = 31003691127Rp497,200


1-B=R1 + K2 = 33000 + K2 = 3300K2 = 3300

2-A=R2 + K1 = 3600900 + K1 = 3600K1 = 2700

2-B=R2 + K2 = 4200R2 + 3300 = 4200R2 = 900

3-B=R3 + K2 = 3700R3 + 3300 = 3700R3 = 400

3-C=R3 + K3 = 4000400 + K3 = 4000K3 = 3600


DariK1 = 2700K2 = 3300K3 = 3600KAPTC

Pabrik 1Rp3,200Rp3,300Rp3,400106

R1 = 0106106Rp349,800

Pabrik 2Rp3,600Rp4,200Rp3,800132

R2 = 90012210132Rp481,200

Pabrik 3Rp3,400Rp3,700Rp4,000127

R3 = 4003691127Rp497,200


1-A=3200-0-2700500

1-C=3400-0-3600-200

2-C=3800-900-3600-700

3-A=3400-400-2700300



DariK1 = 2700K2 = 3300K3 = 3600KAPTC

Pabrik 1Rp3,200Rp3,300Rp3,400106

R1 = 0106106Rp349,800

Pabrik 2Rp3,600Rp4,200Rp3,800132

R2 = 900122-10+132Rp477,200

Pabrik 3Rp3,400Rp3,700Rp4,000127

R3 = 40046+81-127Rp494,200


1-B=R1 + K2 = 33000 + K2 = 3300K2 = 3300

2-A=R2 + K1 = 3600200 + K1 = 3600K1 = 3400

2-C=R2 + K3 = 3800R2 + 3600 = 3800R2 = 200

3-B=R3 + K2 = 3700R3 + 3300 = 3700R3 = 400

3-C=R3 + K3 = 4000400 + K3 = 4000K3 = 3600


DariK1 = 3400K2 = 3300K3 = 3600KAPTC

Pabrik 1Rp3,200Rp3,300Rp3,400106

R1 = 0106106Rp349,800

Pabrik 2Rp3,600Rp4,200Rp3,800132

R2 = 200122-10+132Rp477,200

Pabrik 3Rp3,400Rp3,700Rp4,000127

R3 = 40046+81-127Rp494,200


1-A=3200-0-3400=-200

1-C=3400-0-3400=0

2-B=4200-200-3300=700

3-A=3400-400-3400=-400

Negatif besar : 3-A


DariK1 = 3400K2 = 3300K3 = 3600KAPTC

Pabrik 1Rp3,200Rp3,300Rp3,400106

R1 = 0106106Rp349,800

Pabrik 2Rp3,600Rp4,200Rp3,800132

R2 = 200122-10+132Rp477,200

Pabrik 3Rp3,400Rp3,700Rp4,000127

R3 = 40046+-81127Rp480,400





DariABCKAPTC

PabrikRp20Rp5Rp890

W9090Rp450


H501060Rp950


P104050Rp860




DariABCKAPTC

PabrikRp20Rp5Rp890

W0Rp0


H0Rp0


P0Rp0






5) Ulangi 2 dan 3.





DariPQRKAPTC

Pabrik$5$4$3100

A100100$500

Pabrik$8$4$3300

B200100300$2,000

Pabrik$9$7$5300

C1007200300$1,700

DT(daya Tampung)300300200200200200700$4,200

Indek Rute Kosong:

Indeks Rute A-Q= +$4-$5+$8-$4= + $3

Indeks Rute A-R= +$3-$5+$8-$4+$7-$5= + $4

Indeks Rute B-R= +$3-$4+$7-$5= + $1





DariPQRKAPTC

Pabrik$5$4$3100

A100100$500

Pabrik$8$4$3300

B100_200+300$1,600

Pabrik$9$7$5300

C100+_200300$1,900

DT(daya Tampung)300300200200200200700$4,000

Indeks Rute Kosong:

Indeks A-Q= +$4-$5+$8-$4= + $3

Indeks C-Q= +$7-$4+$8-$9= + $2

Indeks A-R= +$3-$5+$8-$4+$7-$5= + $4

Indeks B-R= +$3-$4+$8-$9+$5= + $3





DariPQRKAPTC

Pabrik$5$4$3100

A100100$500

Pabrik$8$4$3300

B200100300$2,000

Pabrik$9$7$5300

C100200300$1,700

DT(daya Tampung)300300200200200200700$4,200



DariPQRKAPTC

Pabrik$5$4$3100

A100100$300

Pabrik$8$4$3300

B200100300$1,100

Pabrik$9$7$5300

C300300$2,700

DT(daya Tampung)300300200200200200700$4,100





5) Ulangi 2 dan 3.





DariPQRKAPTC

Pabrik$5$4$3100

A100100$500

Pabrik$8$4$3300

B200100300$2,000

Pabrik$9$7$5300

C99200299$1,693

DT(daya Tampung)300300199200200200699$4,193

Indek Rute Kosong:

Indeks Rute A-Q= +$4-$5+$8-$4= + $3

Indeks Rute A-R= +$3-$5+$8-$4+$7-$5= + $4

Indeks Rute B-R= +$3-$4+$7-$5= + $1





DariPQRKAPTC

Pabrik$5$4$3100

A100100$500

Pabrik$8$4$3300

B100_200+300$1,600

Pabrik$9$7$5300

C100+_200300$1,900

DT(daya Tampung)300300200200200200700$4,000

Indeks Rute Kosong:

Indeks A-Q= +$4-$5+$8-$4= + $3

Indeks C-Q= +$7-$4+$8-$9= + $2

Indeks A-R= +$3-$5+$8-$4+$7-$5= + $4

Indeks B-R= +$3-$4+$8-$9+$5= + $3






DariPQRKAPTC

Supplier$200$250$210500

Tangerang (A)500-+500$100,000

Supplier$90$150$1601400

Jakarta (B)100+1100200-1400$206,000

Demand600600110011002002001900$306,000

Indeks rute A-Q= +$250-$200+$90-$150= -$10





DariPQRKAPTC

Supplier$200$250$210500

A300-200+500$102,000

Supplier$90$150$1601400

B300+1100-1400$192,000

Demand600600110011002002001900$294,000

Indeks A-Q= +$250-$200+$90-$150= -$10

Indeks B-R= +$160-$210+$200-$90= $60





DariPQRKAPTC

Supplier$200$250$210500

A-300+200500$117,000

Supplier$90$150$1601400

B600+800-1400$174,000

Demand600600110011002002001900$291,000

Indeks A-P= +$200-$90+$150-$250= $10

Indeks B-R= +$160-$210+$250-$150= $50



X210

9

8

7C(0,6)

6

5B(8,4)

4

3

2

1A(16,0)

012345678910111213141516171819202122232425

X1

X1 + 2X2 16

X1 + 4X2 24

ROP

Dalam Ribuan Unit60

55

50

45

40

35

30

25

20

15

10

5

0123456789101112131415161718192021222324252627282930

Dalam puluhan hari.


7.75

ROP=11

SS = 5

39

45

NWC

Matrik 1


DariABCDEKAPTC

Gudang10111281340

P202040420

Gudang2108141660

Q10302060620

Gudang14121016780

R4265080806


Matrik 2


DariABCDEKAPTC

Gudang10111281340

P1520540430

Gudang2108141660

Q510252060590

Gudang14121016780

R04265080806

DT(daya Tampung)202030303434464650501801826

20

Matrik 3


DariABCDEKAPTC

Gudang10111281340

P1025540435

Gudang2108141660

Q105252060550

Gudang14121016780

R04265080806

DT(daya Tampung)202030303434464650501801791

Matrik 4


DariABCDEKAPTC

Gudang10111281340

P530540440

Gudang2108141660

Q150252060510

Gudang14121016780

R04265080806

DT(daya Tampung)202030303434464650501801756

Matrik 5


DariABCDEKAPTC

Gudang10111281340

P0301040450

Gudang2108141660

Q200202060480

Gudang14121016780

R04265080806

DT(daya Tampung)202030303434464650501801736

Matrik 6


DariABCDEKAPTC

Gudang10111281340

P0251540455

Gudang2108141660

Q205152060490

Gudang14121016780

R04265080806

DT(daya Tampung)202030303434464650501801751

Sheet2

Matrik 1


DariABCDEKAPTC

Gudang10111281340

P202000040420

Gudang2108141660

Q0103020501101420

Gudang14121016780

R00426030456

DT(daya Tampung)202030303434464650501802296

Matrik


DariABCDEKAPTC

Gudang10111281340

P201721040419

Gudang2108141660

Q01020141660712

Gudang14121016780

R0312313480890

DT(daya Tampung)202030303434464650501802021




DariABCKAPTC

PabrikRp20Rp5Rp890

W504090Rp1,200


H6060Rp1,200


P104050Rp860




DariABCKAPTC

PabrikRp20Rp5Rp890

W9090Rp450


H204060Rp700


P302050Rp950






5) Ulangi 2 dan 3.

Soal 1 StepStone



DariABCKAPTC

PabrikRp20Rp5Rp890

W50-40+90Rp1,200


H+60-60Rp1,200


P104050Rp860


Indeks rute kosong:

IndeksW - C+ 8 - 5 + 20 - 10 + 20=33

H - A+15 - 20 + 5 - 20=-20

H - C+10 - 19 + 10 - 20 + 5=-14

P - A+25 - 10 + 20 -5 - 20=10




DariABCKAPTC

PabrikRp20Rp5Rp890

W9090Rp4505040


H5010-+60Rp950


P10+40-50Rp860


IndeksW - A+20 - 15 + 20 - 5=20

W - C+8 - 5 + 20 - 10 + 19=32

H - C+10 - 19 + 10 - 20 =-14

P - A+25 - 10 + 20 - 15=20




DariABCKAPTC

PabrikRp20Rp5Rp890

W90-+90Rp450


H501060Rp850


P20+30-50Rp770


IndeksW -A+20 - 5 + 10 - 15=10

W - C+8 - 5 + 10 - 19=-6

H - B+20 - 10 + 19 - 10=19

P - A+25 - 19 + 10 - 15=1




DariABCKAPTC

PabrikRp20Rp5Rp890

W60-30+90Rp540


H501060Rp850


P30+-30Rp300


IndeksW - A+20 - 8 + 10 - 15=7

H - B+20 - 10 + 8 - 5=13

P - A+25 - 10 + 5 - 15=5

P - C+19 - 8 + 5 - 10=6


Sheet1



DariABCKAPTC


1106106Rp339,200


24191132Rp518,000


316111127Rp465,100






5) Ulangi 2 dan 3.


DariK1K2K3KAPTC

Pabrik 1Rp3,200Rp3,300Rp3,400106

R1106106Rp339,200

Pabrik 2Rp3,600Rp4,200Rp3,800132

R216116132Rp544,800

Pabrik 3Rp3,400Rp3,700Rp4,000127

R33691127Rp497,200


1-A=R1 + K1 = 3200R1 + 0 = 3200R1 = 3200

2-A=R2 + K1 = 3600R2 + 0 = 3600R2 = 3600

2-B=R2 + K2 = 42003600 + K2 = 4200K2 = 600

3-B=R3 + K2 = 3700R3 + 600 = 3700R3 = 3100

3-C=R3 + K3 = 37003100 + K3 = 3700K3 = 600

1-B3300-3200-600-500

1-C3400-3200-600-400

2-C3800-3600-600-400

3-A3400-3100-0300



DariK1 = 0K2 = 600K3 = 600KAPTC

Pabrik 1Rp3,200Rp3,300Rp3,400106

R1 = 3200106-+106Rp339,200

Pabrik 2Rp3,600Rp4,200Rp3,800132

R2 = 360016+116-132Rp544,800

Pabrik 3Rp3,400Rp3,700Rp4,000127

R3 = 31003691127Rp497,200


1-A=R1 + K1 = 3200=R1 + 0 = 3200R1 = 3200

2-A=R2 + K1 = 3600=R2 + 0 = 3600R2 = 3600

2-B=R2 + K2 = 4200=3600 + K2 = 4200K2 = 600

3-B=R3 + K2 = 3700=R3 + 600 = 3700R3 = 3100

3-C=R3 + K3 = 3700=3100 + K3 = 3700K3 = 600

1-B=3300-3200-600=-500

1-C=3400-3200-600=-400

2-C=3800-3600-600=-400

3-A=3400-3100-0=300



DariK1 = 0K2 = 600K3 = 600KAPTC

Pabrik 1Rp3,200Rp3,300Rp3,400106

R1 = 3200-106+106Rp349,800

Pabrik 2Rp3,600Rp4,200Rp3,800132

R2 = 3600122+10-132Rp481,200

Pabrik 3Rp3,400Rp3,700Rp4,000127

R3 = 31003691127Rp497,200


1-B=R1 + K2 = 33000 + K2 = 3300K2 = 3300

2-A=R2 + K1 = 3600900 + K1 = 3600K1 = 2700

2-B=R2 + K2 = 4200R2 + 3300 = 4200R2 = 900

3-B=R3 + K2 = 3700R3 + 3300 = 3700R3 = 400

3-C=R3 + K3 = 4000400 + K3 = 4000K3 = 3600


DariK1 = 2700K2 = 3300K3 = 3600KAPTC

Pabrik 1Rp3,200Rp3,300Rp3,400106

R1 = 0106106Rp349,800

Pabrik 2Rp3,600Rp4,200Rp3,800132

R2 = 90012210132Rp481,200

Pabrik 3Rp3,400Rp3,700Rp4,000127

R3 = 4003691127Rp497,200


1-A=3200-0-2700500

1-C=3400-0-3600-200

2-C=3800-900-3600-700

3-A=3400-400-2700300


Tabel perbaikan


DariK1 = 2700K2 = 3300K3 = 3600KAPTC

Pabrik 1Rp3,200Rp3,300Rp3,400106

R1 = 0106106Rp349,800

Pabrik 2Rp3,600Rp4,200Rp3,800132

R2 = 900122-10+132Rp477,200

Pabrik 3Rp3,400Rp3,700Rp4,000127

R3 = 40046+81-127Rp494,200


1-B=R1 + K2 = 33000 + K2 = 3300K2 = 3300

2-A=R2 + K1 = 3600200 + K1 = 3600K1 = 3400

2-C=R2 + K3 = 3800R2 + 3600 = 3800R2 = 200

3-B=R3 + K2 = 3700R3 + 3300 = 3700R3 = 400

3-C=R3 + K3 = 4000400 + K3 = 4000K3 = 3600



DariK1 = 3400K2 = 3300K3 = 3600KAPTC

Pabrik 1Rp3,200Rp3,300Rp3,400106

R1 = 0106106Rp349,800

Pabrik 2Rp3,600Rp4,200Rp3,800132

R2 = 200122-10+132Rp477,200

Pabrik 3Rp3,400Rp3,700Rp4,000127

R3 = 40046+81-127Rp494,200


1-A=3200-0-3400=-200

1-C=3400-0-3400=0

2-B=4200-200-3300=700

3-A=3400-400-3400=-400

Negatif besar : 3-A


DariK1 = 3400K2 = 3300K3 = 3600KAPTC

Pabrik 1Rp3,200Rp3,300Rp3,400106

R1 = 0106106Rp349,800

Pabrik 2Rp3,600Rp4,200Rp3,800132

R2 = 20041-91+132Rp493,400

Pabrik 3Rp3,400Rp3,700Rp4,000127

R3 = 40081+46-127Rp445,600


1-B=R1 + K2 = 33000 + K2 = 3300K2 = 3300

2-A=R2 + K1 = 3600

2-C=R2 + K3 = 3800

3-A=R3 + K1 = 3400

3-B=R3 + K2 = 3700R3 + 3300 = 3700R3 = 400




DariABCKAPTC

PabrikRp20Rp5Rp890

W9090Rp450


H501060Rp950


P104050Rp860




DariABCKAPTC

PabrikRp20Rp5Rp890

W0Rp0


H0Rp0


P0Rp0






5) Ulangi 2 dan 3.





DariPQRKAPTC

Pabrik$5$4$3100

A100100$500

Pabrik$8$4$3300

B200100300$2,000

Pabrik$9$7$5300

C1007200300$1,700

DT(daya Tampung)300300200200200200700$4,200

Indek Rute Kosong:

Indeks Rute A-Q= +$4-$5+$8-$4= + $3

Indeks Rute A-R= +$3-$5+$8-$4+$7-$5= + $4

Indeks Rute B-R= +$3-$4+$7-$5= + $1





DariPQRKAPTC

Pabrik$5$4$3100

A100100$500

Pabrik$8$4$3300

B100_200+300$1,600

Pabrik$9$7$5300

C100+_200300$1,900

DT(daya Tampung)300300200200200200700$4,000

Indeks Rute Kosong:

Indeks A-Q= +$4-$5+$8-$4= + $3

Indeks C-Q= +$7-$4+$8-$9= + $2

Indeks A-R= +$3-$5+$8-$4+$7-$5= + $4

Indeks B-R= +$3-$4+$8-$9+$5= + $3





DariPQRKAPTC

Pabrik$5$4$3100

A100100$500

Pabrik$8$4$3300

B200100300$2,000

Pabrik$9$7$5300

C100200300$1,700

DT(daya Tampung)300300200200200200700$4,200



DariPQRKAPTC

Pabrik$5$4$3100

A100100$300

Pabrik$8$4$3300

B200100300$1,100

Pabrik$9$7$5300

C300300$2,700

DT(daya Tampung)300300200200200200700$4,100





5) Ulangi 2 dan 3.





DariPQRKAPTC

Pabrik$5$4$3100

A100100$500

Pabrik$8$4$3300

B200100300$2,000

Pabrik$9$7$5300

C99200299$1,693

DT(daya Tampung)300300199200200200699$4,193

Indek Rute Kosong:

Indeks Rute A-Q= +$4-$5+$8-$4= + $3

Indeks Rute A-R= +$3-$5+$8-$4+$7-$5= + $4

Indeks Rute B-R= +$3-$4+$7-$5= + $1





DariPQRKAPTC

Pabrik$5$4$3100

A100100$500

Pabrik$8$4$3300

B100_200+300$1,600

Pabrik$9$7$5300

C100+_200300$1,900

DT(daya Tampung)300300200200200200700$4,000

Indeks Rute Kosong:

Indeks A-Q= +$4-$5+$8-$4= + $3

Indeks C-Q= +$7-$4+$8-$9= + $2

Indeks A-R= +$3-$5+$8-$4+$7-$5= + $4

Indeks B-R= +$3-$4+$8-$9+$5= + $3






DariPQRKAPTC

Supplier$200$250$210500

Tangerang (A)500-+500$100,000

Supplier$90$150$1601400

Jakarta (B)100+1100200-1400$206,000

Demand600600110011002002001900$306,000

Indeks rute A-Q= +$250-$200+$90-$150= -$10





DariPQRKAPTC

Supplier$200$250$210500

A300-200+500$102,000

Supplier$90$150$1601400

B300+1100-1400$192,000

Demand600600110011002002001900$294,000

Indeks A-Q= +$250-$200+$90-$150= -$10

Indeks B-R= +$160-$210+$200-$90= $60





DariPQRKAPTC

Supplier$200$250$210500

A-300+200500$117,000

Supplier$90$150$1601400

B600+800-1400$174,000

Demand600600110011002002001900$291,000

Indeks A-P= +$200-$90+$150-$250= $10

Indeks B-R= +$160-$210+$250-$150= $50



X210

9

8

7C(0,6)

6

5B(8,4)

4

3

2

1A(16,0)

012345678910111213141516171819202122232425

X1

X1 + 2X2 16

X1 + 4X2 24

ROP

Dalam Ribuan Unit60

55

50

45

40

35

30

25

20

15

10

5

0123456789101112131415161718192021222324252627282930

Dalam puluhan hari.


7.75

ROP=11

SS = 5

39

45

NWC

Matrik 1


DariABCDEKAPTC

Gudang10111281340

P202040420

Gudang2108141660

Q10302060620

Gudang14121016780

R4265080806


Matrik 2


DariABCDEKAPTC

Gudang10111281340

P1520540430

Gudang2108141660

Q510252060590

Gudang14121016780

R04265080806

DT(daya Tampung)202030303434464650501801826

20

Matrik 3


DariABCDEKAPTC

Gudang10111281340

P1025540435

Gudang2108141660

Q105252060550

Gudang14121016780

R04265080806

DT(daya Tampung)202030303434464650501801791

Matrik 4


DariABCDEKAPTC

Gudang10111281340

P530540440

Gudang2108141660

Q150252060510

Gudang14121016780

R04265080806

DT(daya Tampung)202030303434464650501801756

Matrik 5


DariABCDEKAPTC

Gudang10111281340

P0301040450

Gudang2108141660

Q200202060480

Gudang14121016780

R04265080806

DT(daya Tampung)202030303434464650501801736

Matrik 6


DariABCDEKAPTC

Gudang10111281340

P0251540455

Gudang2108141660

Q205152060490

Gudang14121016780

R04265080806

DT(daya Tampung)202030303434464650501801751

Sheet2

Matrik 1


DariABCDEKAPTC

Gudang10111281340

P202000040420

Gudang2108141660

Q0103020501101420

Gudang14121016780

R00426030456

DT(daya Tampung)202030303434464650501802296

Matrik


DariABCDEKAPTC

Gudang10111281340

P201721040419

Gudang2108141660

Q01020141660712

Gudang14121016780

R0312313480890

DT(daya Tampung)202030303434464650501802021




DariABCKAPTC

PabrikRp20Rp5Rp890

W504090Rp1,200


H6060Rp1,200


P104050Rp860




DariABCKAPTC

PabrikRp20Rp5Rp890

W9090Rp450


H204060Rp700


P302050Rp950






5) Ulangi 2 dan 3.

Soal 1 StepStone



DariABCKAPTC

PabrikRp20Rp5Rp890

W50-40+90Rp1,200


H+60-60Rp1,200


P104050Rp860


Indeks rute kosong:

IndeksW - C+ 8 - 5 + 20 - 10 + 20=33

H - A+15 - 20 + 5 - 20=-20

H - C+10 - 19 + 10 - 20 + 5=-14

P - A+25 - 10 + 20 -5 - 20=10




DariABCKAPTC

PabrikRp20Rp5Rp890

W9090Rp4505040


H5010-+60Rp950


P10+40-50Rp860


IndeksW - A+20 - 15 + 20 - 5=20

W - C+8 - 5 + 20 - 10 + 19=32

H - C+10 - 19 + 10 - 20 =-14

P - A+25 - 10 + 20 - 15=20




DariABCKAPTC

PabrikRp20Rp5Rp890

W90-+90Rp450


H501060Rp850


P20+30-50Rp770


IndeksW -A+20 - 5 + 10 - 15=10

W - C+8 - 5 + 10 - 19=-6

H - B+20 - 10 + 19 - 10=19

P - A+25 - 19 + 10 - 15=1




DariABCKAPTC

PabrikRp20Rp5Rp890

W60-30+90Rp540


H501060Rp850


P30+-30Rp300


IndeksW - A+20 - 8 + 10 - 15=7

H - B+20 - 10 + 8 - 5=13

P - A+25 - 10 + 5 - 15=5

P - C+19 - 8 + 5 - 10=6


Sheet1



DariABCKAPTC


1106106Rp339,200


24191132Rp518,000


316111127Rp465,100






5) Ulangi 2 dan 3.


DariK1K2K3KAPTC

Pabrik 1Rp3,200Rp3,300Rp3,400106

R1106106Rp339,200

Pabrik 2Rp3,600Rp4,200Rp3,800132

R216116132Rp544,800

Pabrik 3Rp3,400Rp3,700Rp4,000127

R33691127Rp497,200


1-A=R1 + K1 = 3200R1 + 0 = 3200R1 = 3200

2-A=R2 + K1 = 3600R2 + 0 = 3600R2 = 3600

2-B=R2 + K2 = 42003600 + K2 = 4200K2 = 600

3-B=R3 + K2 = 3700R3 + 600 = 3700R3 = 3100

3-C=R3 + K3 = 37003100 + K3 = 3700K3 = 600

1-B3300-3200-600-500

1-C3400-3200-600-400

2-C3800-3600-600-400

3-A3400-3100-0300



DariK1 = 0K2 = 600K3 = 600KAPTC

Pabrik 1Rp3,200Rp3,300Rp3,400106

R1 = 3200106-+106Rp339,200

Pabrik 2Rp3,600Rp4,200Rp3,800132

R2 = 360016+116-132Rp544,800

Pabrik 3Rp3,400Rp3,700Rp4,000127

R3 = 31003691127Rp497,200


1-A=R1 + K1 = 3200=R1 + 0 = 3200R1 = 3200

2-A=R2 + K1 = 3600=R2 + 0 = 3600R2 = 3600

2-B=R2 + K2 = 4200=3600 + K2 = 4200K2 = 600

3-B=R3 + K2 = 3700=R3 + 600 = 3700R3 = 3100

3-C=R3 + K3 = 3700=3100 + K3 = 3700K3 = 600

1-B=3300-3200-600=-500

1-C=3400-3200-600=-400

2-C=3800-3600-600=-400

3-A=3400-3100-0=300



DariK1 = 0K2 = 600K3 = 600KAPTC

Pabrik 1Rp3,200Rp3,300Rp3,400106

R1 = 3200-106+106Rp349,800

Pabrik 2Rp3,600Rp4,200Rp3,800132

R2 = 3600122+10-132Rp481,200

Pabrik 3Rp3,400Rp3,700Rp4,000127

R3 = 31003691127Rp497,200


1-B=R1 + K2 = 33000 + K2 = 3300K2 = 3300

2-A=R2 + K1 = 3600900 + K1 = 3600K1 = 2700

2-B=R2 + K2 = 4200R2 + 3300 = 4200R2 = 900

3-B=R3 + K2 = 3700R3 + 3300 = 3700R3 = 400

3-C=R3 + K3 = 4000400 + K3 = 4000K3 = 3600


DariK1 = 2700K2 = 3300K3 = 3600KAPTC

Pabrik 1Rp3,200Rp3,300Rp3,400106

R1 = 0106106Rp349,800

Pabrik 2Rp3,600Rp4,200Rp3,800132

R2 = 90012210132Rp481,200

Pabrik 3Rp3,400Rp3,700Rp4,000127

R3 = 4003691127Rp497,200


1-A=3200-0-2700500

1-C=3400-0-3600-200

2-C=3800-900-3600-700

3-A=3400-400-2700300


Tabel perbaikan


DariK1 = 2700K2 = 3300K3 = 3600KAPTC

Pabrik 1Rp3,200Rp3,300Rp3,400106

R1 = 0106106Rp349,800

Pabrik 2Rp3,600Rp4,200Rp3,800132

R2 = 900122-10+132Rp477,200

Pabrik 3Rp3,400Rp3,700Rp4,000127

R3 = 40046+81-127Rp494,200


1-B=R1 + K2 = 33000 + K2 = 3300K2 = 3300

2-A=R2 + K1 = 3600200 + K1 = 3600K1 = 3400

2-C=R2 + K3 = 3800R2 + 3600 = 3800R2 = 200

3-B=R3 + K2 = 3700R3 + 3300 = 3700R3 = 400

3-C=R3 + K3 = 4000400 + K3 = 4000K3 = 3600



DariK1 = 3400K2 = 3300K3 = 3600KAPTC

Pabrik 1Rp3,200Rp3,300Rp3,400106

R1 = 0106106Rp349,800

Pabrik 2Rp3,600Rp4,200Rp3,800132

R2 = 200122-10+132Rp477,200

Pabrik 3Rp3,400Rp3,700Rp4,000127

R3 = 40046+81-127Rp494,200


1-A=3200-0-3400=-200

1-C=3400-0-3400=0

2-B=4200-200-3300=700

3-A=3400-400-3400=-400

Negatif besar : 3-A


DariK1 = 3400K2 = 3300K3 = 3600KAPTC

Pabrik 1Rp3,200Rp3,300Rp3,400106

R1 = 0106106Rp349,800

Pabrik 2Rp3,600Rp4,200Rp3,800132

R2 = 20041-91+132Rp493,400

Pabrik 3Rp3,400Rp3,700Rp4,000127

R3 = 40081+46-127Rp445,600


1-B=R1 + K2 = 33000 + K2 = 3300K2 = 3300

2-A=R2 + K1 = 3600R2 + 3000 = 3600R2 = 600

2-C=R2 + K3 = 3800600 + K3 = 3800K3 = 3200

3-A=R3 + K1 = 3400400 + K1 = 3400K1 = 3000

3-B=R3 + K2 = 3700R3 + 3300 = 3700R3 = 400



DariK1 = 3000K2 = 3300K3 = 3200KAPTC

Pabrik 1Rp3,200Rp3,300Rp3,400106

R1 = 0106106Rp349,800

Pabrik 2Rp3,600Rp4,200Rp3,800132

R2 = 60041-91+132Rp493,400

Pabrik 3Rp3,400Rp3,700Rp4,000127

R3 = 40081+46-127Rp445,600


Indeks1-A=3200-0-3000200

1-C=3400-0-3200200

2-B=4200-600-3300300

3-C=4000-400-3200400

Sudah optimum karena Indeks sudah positif semua




DariABCKAPTC

PabrikRp20Rp5Rp890

W9090Rp450


H501060Rp950


P104050Rp860




DariABCKAPTC

PabrikRp20Rp5Rp890

W0Rp0


H0Rp0


P0Rp0






5) Ulangi 2 dan 3.





DariPQRKAPTC

Pabrik$5$4$3100

A100100$500

Pabrik$8$4$3300

B200100300$2,000

Pabrik$9$7$5300

C1007200300$1,700

DT(daya Tampung)300300200200200200700$4,200

Indek Rute Kosong:

Indeks Rute A-Q= +$4-$5+$8-$4= + $3

Indeks Rute A-R= +$3-$5+$8-$4+$7-$5= + $4

Indeks Rute B-R= +$3-$4+$7-$5= + $1





DariPQRKAPTC

Pabrik$5$4$3100

A100100$500

Pabrik$8$4$3300

B100_200+300$1,600

Pabrik$9$7$5300

C100+_200300$1,900

DT(daya Tampung)300300200200200200700$4,000

Indeks Rute Kosong:

Indeks A-Q= +$4-$5+$8-$4= + $3

Indeks C-Q= +$7-$4+$8-$9= + $2

Indeks A-R= +$3-$5+$8-$4+$7-$5= + $4

Indeks B-R= +$3-$4+$8-$9+$5= + $3





DariPQRKAPTC

Pabrik$5$4$3100

A100100$500

Pabrik$8$4$3300

B200100300$2,000

Pabrik$9$7$5300

C100200300$1,700

DT(daya Tampung)300300200200200200700$4,200



DariPQRKAPTC

Pabrik$5$4$3100

A100100$300

Pabrik$8$4$3300

B200100300$1,100

Pabrik$9$7$5300

C300300$2,700

DT(daya Tampung)300300200200200200700$4,100





5) Ulangi 2 dan 3.





DariPQRKAPTC

Pabrik$5$4$3100

A100100$500

Pabrik$8$4$3300

B200100300$2,000

Pabrik$9$7$5300

C99200299$1,693

DT(daya Tampung)300300199200200200699$4,193

Indek Rute Kosong:

Indeks Rute A-Q= +$4-$5+$8-$4= + $3

Indeks Rute A-R= +$3-$5+$8-$4+$7-$5= + $4

Indeks Rute B-R= +$3-$4+$7-$5= + $1





DariPQRKAPTC

Pabrik$5$4$3100

A100100$500

Pabrik$8$4$3300

B100_200+300$1,600

Pabrik$9$7$5300

C100+_200300$1,900

DT(daya Tampung)300300200200200200700$4,000

Indeks Rute Kosong:

Indeks A-Q= +$4-$5+$8-$4= + $3

Indeks C-Q= +$7-$4+$8-$9= + $2

Indeks A-R= +$3-$5+$8-$4+$7-$5= + $4

Indeks B-R= +$3-$4+$8-$9+$5= + $3






DariPQRKAPTC

Supplier$200$250$210500

Tangerang (A)500-+500$100,000

Supplier$90$150$1601400

Jakarta (B)100+1100200-1400$206,000

Demand600600110011002002001900$306,000

Indeks rute A-Q= +$250-$200+$90-$150= -$10





DariPQRKAPTC

Supplier$200$250$210500

A300-200+500$102,000

Supplier$90$150$1601400

B300+1100-1400$192,000

Demand600600110011002002001900$294,000

Indeks A-Q= +$250-$200+$90-$150= -$10

Indeks B-R= +$160-$210+$200-$90= $60





DariPQRKAPTC

Supplier$200$250$210500

A-300+200500$117,000

Supplier$90$150$1601400

B600+800-1400$174,000

Demand600600110011002002001900$291,000

Indeks A-P= +$200-$90+$150-$250= $10

Indeks B-R= +$160-$210+$250-$150= $50



X210

9

8

7C(0,6)

6

5B(8,4)

4

3

2

1A(16,0)

012345678910111213141516171819202122232425

X1

X1 + 2X2 16

X1 + 4X2 24

ROP

Dalam Ribuan Unit60

55

50

45

40

35

30

25

20

15

10

5

0123456789101112131415161718192021222324252627282930

Dalam puluhan hari.


7.75

ROP=11

SS = 5

39

45

NWC

Matrik 1


DariABCDEKAPTC

Gudang10111281340

P202040420

Gudang2108141660

Q10302060620

Gudang14121016780

R4265080806


Matrik 2


DariABCDEKAPTC

Gudang10111281340

P1520540430

Gudang2108141660

Q510252060590

Gudang14121016780

R04265080806

DT(daya Tampung)202030303434464650501801826

20

Matrik 3


DariABCDEKAPTC

Gudang10111281340

P1025540435

Gudang2108141660

Q105252060550

Gudang14121016780

R04265080806

DT(daya Tampung)202030303434464650501801791

Matrik 4


DariABCDEKAPTC

Gudang10111281340

P530540440

Gudang2108141660

Q150252060510

Gudang14121016780

R04265080806

DT(daya Tampung)202030303434464650501801756

Matrik 5


DariABCDEKAPTC

Gudang10111281340

P0301040450

Gudang2108141660

Q200202060480

Gudang14121016780

R04265080806

DT(daya Tampung)202030303434464650501801736

Matrik 6


DariABCDEKAPTC

Gudang10111281340

P0251540455

Gudang2108141660

Q205152060490

Gudang14121016780

R04265080806

DT(daya Tampung)202030303434464650501801751

Sheet2

Matrik 1


DariABCDEKAPTC

Gudang10111281340

P202000040420

Gudang2108141660

Q0103020501101420

Gudang14121016780

R00426030456

DT(daya Tampung)202030303434464650501802296

Matrik


DariABCDEKAPTC

Gudang10111281340

P201721040419

Gudang2108141660

Q01020141660712

Gudang14121016780

R0312313480890

DT(daya Tampung)202030303434464650501802021




DariABCKAPTC

PabrikRp20Rp5Rp890

W504090Rp1,200


H6060Rp1,200


P104050Rp860




DariABCKAPTC

PabrikRp20Rp5Rp890

W9090Rp450


H204060Rp700


P302050Rp950






5) Ulangi 2 dan 3.

Soal 1 StepStone



DariABCKAPTC

PabrikRp20Rp5Rp890

W50-40+90Rp1,200


H+60-60Rp1,200


P104050Rp860


Indeks rute kosong:

IndeksW - C+ 8 - 5 + 20 - 10 + 20=33

H - A+15 - 20 + 5 - 20=-20

H - C+10 - 19 + 10 - 20 + 5=-14

P - A+25 - 10 + 20 -5 - 20=10




DariABCKAPTC

PabrikRp20Rp5Rp890

W9090Rp4505040


H5010-+6

riset-operasi-soal-tugas-2

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