Active Learning Assignment (Mechanics of Solid )(2131903)

Topic:- Stress Strain and Basic conceptMechanical Engineering (3 C3)

Prepared By: Chandresh Suthar (140120119229) Sonani Mananv (140120119229) Govind Tade (140120119230) Shah Shrey (140120119211)

Guided by:

Prof. Hiren Raghu

GANDHINAGAR INSTITUTE OF TECHNOLOGY

Flow of contentBasic concept of stress & strainDirect StrainModule of elasticityStress strain diagramShear stressModule of rigidity

Stress and strainDIRECT STRESS When a force is applied to an elastic body, the body deforms. The way

in which the body deforms depends upon the type of force applied to it.

Compression force makes the body shorter.

A tensile force makes the body longer

AF

AreaForceStress

2/mN

Tensile and compressive forces are called DIRECT FORCES

Stress is the force per unit area upon which it acts.

….. Unit is Pascal (Pa) or

Note: Most of engineering fields used kPa, MPa, GPa.

( Simbol – Sigma)

LxStrain

DIRECT STRAIN ,

In each case, a force F produces a deformation x. In engineering, we usually change this force into stress and the deformation into strain and we define these as follows:Strain is the deformation per unit of the original length.

The symbol

Strain has no unit’s since it is a ratio of length to length. Most engineer-ing materials do not stretch very mush before they become damages, so strain values are very small figures. It is quite normal to change small numbers in to the exponent for 10-6( micro strain).

called EPSILON

MODULUS OF ELASTICITY (E)

•Elastic materials always spring back into shape when released. They also obey HOOKE’s LAW.

•This is the law of spring which states that deformation is directly proportional to the force. F/x = stiffness = kN/m

•The stiffness is different for the different material and different sizes of the material. We may eliminate the size by using stress and strain instead of force and deformation:

•If F and x is refer to the direct stress and strain , then

AF Lx LA

xF

AxFL

hence and

E

AxFL

•The stiffness is now in terms of stress and strain only and this con-stant is called the MODULUS of ELASTICITY (E)

• A graph of stress against strain will be straight line with gradient of E. The units of E are the same as the unit of stress.

ULTIMATE TENSILE STRESS•If a material is stretched until it breaks, the tensile stress has reached the absolute limit and this stress level is called the ulti-mate tensile stress.

STRESS STRAIN DIAGRAM

STRESS STRAIN DIAGRAM

Elastic behaviourThe curve is straight line trough out most of the regionStress is proportional with strainMaterial to be linearly elasticProportional limit

The upper limit to linear lineThe material still respond elasticallyThe curve tend to bend and flatten out

Elastic limitUpon reaching this point, if load is remove, the specimen still return to original shape

STRESS STRAIN DIAGRAMYielding

A Slight increase in stress above the elastic limit will result in breakdown of the material and cause it to de-form permanently.This behaviour is called yieldingThe stress that cause = YIELD STRESS@YIELD POINTPlastic deformationOnce yield point is reached, the specimen will elon-gate (Strain) without any increase in loadMaterial in this state = perfectly plastic

STRESS STRAIN DIAGRAM STRAIN HARDENING

When yielding has ended, further load applied, resulting in a curve that rises continuously

Become flat when reached ULTIMATE STRESS The rise in the curve = STRAIN HARDENING While specimen is elongating, its cross sectional will decrease The decrease is fairly uniform

NECKING At the ultimate stress, the cross sectional area begins its localised re-

gion of specimen it is caused by slip planes formed within material Actual strain produced by shear strain As a result, “neck” tend to form Smaller area can only carry lesser load, hence curve donward Specimen break at FRACTURE STRESS

SHEAR STRESS •Shear force is a force applied sideways on the ma-terial (transversely loaded).

When a pair of shears cut a material

When a material is punched

When a beam has a transverse load

Shear stress is the force per unit area carrying the load. This means the cross sectional area of the material being cut, the beam and pin.

AF

and symbol is called Tau•Shear stress,

The sign convention for shear force and stress is based on how it shears the materials as shown below.

Lx

Lx

SHEAR STRAIN

The force causes the material to deform as shown. The shear strain is defined as the ratio of the distance deformed to the height

. Since this is a very small angle , we can say that :

( symbol called Gamma)

Shear strain

•If we conduct an experiment and measure x for various values of F, we would find that if the material is elastic, it behave like spring and so long as we do not damage the material by using too big force, the graph of F and x is straight line as shown.

MODULUS OF RIGIDITY (G)

The gradient of the graph is constant so tconsxF tan

and this is the spring stiffness of the block in N/m.

•If we divide F by area A and x by the height L, the relationship is still a constant and we get

tconAxFL

xLx

AF

LxAF

tan

AF

Where

Lx

tconAxFL

xLx

AF tan

then

•If we divide F by area A and x by the height L, the relationship is still a constant and we get

This constant will have a special value for each elastic mate-rial and is called the Modulus of Rigidity (G).

G

ULTIMATE SHEAR STRESS

If a material is sheared beyond a certain limit and it becomes permanently distorted and does not spring all the way back to its original shape, the elastic limit has been exceeded.

If the material stressed to the limit so that it parts into two, the ultimate limit has been reached.

The ultimate shear stress has symbol and this value is used to calculate the force needed by shears and punches.

DOUBLE SHEAR

Consider a pin joint with a support on both ends as shown. This is called CLEVIS and CLEVIS PIN By balance of force, the force in the two supports is F/2 eachThe area sheared is twice the cross section of the pinSo it takes twice as much force to break the pin as for a case of single shearDouble shear arrangements doubles the maximum force al-lowed in the pin

LOAD AND STRESS LIMIT

DESIGN CONSIDERATIONWill help engineers with their important task in Designing struc-tural/machine that is SAFE and ECONOMICALLY perform for a specified function

DETERMINATION OF ULTIMATE STRENGTH An important element to be considered by a designer is how the material that has been selected will behave under a loadThis is determined by performing specific test (e.g. Tensile test)ULTIMATE FORCE (PU)= The largest force that may be applied to the specimen is reached, and the specimen either breaks or begins to carry less load ULTIMATE NORMAL STRESS

(U) = ULTIMATE FORCE(PU) /AREA

ALLOWABLE LOAD / ALLOWABLE STRESS

Max load that a structural member/machine component will be allowed to carry under normal conditions of utilisation is considerably smaller than the ultimate loadThis smaller load = Allowable load / Working load / Design loadOnly a fraction of ultimate load capacity of the member is utilised when allowable load is appliedThe remaining portion of the load-carrying capacity of the member is kept in reserve to assure its safe performanceThe ratio of the ultimate load/allowable load is used to define FACTOR OF SAFETY

FACTOR OF SAFETY = ULTIMATE LOAD/ALLOWABLE LOAD@FACTOR OF SAFETY = ULTIMATE STRESS/ALLOWABLE STRESS

SELECTION OF F.S.

1. Variations that may occur in the properties of the member under con-siderations

2. The number of loading that may be expected during the life of the structural/machine

3. The type of loading that are planned for in the design, or that may oc-cur in the future

4. The type of failure that may occur5. Uncertainty due to the methods of analysis6. Deterioration that may occur in the future because of poor mainte-

nance / because of unpreventable natural causes7. The importance of a given member to the integrity of the whole struc-

ture

AXIAL FORCE & DEFLECTION OF BODY

Deformations of members under axial loadingIf the resulting axial stress does not exceed the proportional limit of the material, Hooke’s Law may be appliedThen deformation (x / ) can be written as

AEFL

E

Thank you !!!!