浙江财经学院 专升本函授线性代数
DESCRIPTION
浙江财经学院 专升本函授线性代数. 制作:数学与统计学院 林振洪. 第一章 行列式. [ 教学内容 ] §1.1 二阶、三阶行列式 二阶、三阶行列式的定义及基本计算 §1.2 n 阶行列式 逆序数的概念, n 阶行列式的定义 §1.3 行列式的性质 行列式的基本性质,利用基本性质计算行列式的值 §1.4 行列式按行(列)展开 代数余子式概念及计算,行列式按行(列)展开定理,利用展开定理计算行列式值 §1.5 克莱姆法则 克莱姆法则,齐次线性方程组仅有零解的判定。. [ 基本要求 ] 1 、理解 n 阶行列式的定义及其性质。 - PowerPoint PPT PresentationTRANSCRIPT
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[]1.1 1.2 nn1.3 1.4 1.5
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[]1n2n3[]
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()
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--
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65.
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1. 2.3!,,,,.
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(),,,
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D
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1DD',D=D' ()=D
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2(),tk
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ktD1=ktD1
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(),ktD==0kt
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3()==
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1(),
2(),kt=0
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4() =+=
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5()k(),k+=43,
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20=208
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2(-3)84(-30/58)
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nn-1aijij,n-1aij,Mij
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DaijMij,Aij=(-1)i+jMijaijDa23,
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()nD()
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nD()
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()(),(),(-3)(-3)4
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Cramer (1),
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k,12k0k9D0k=0k=9D=0
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[]3.1 3.2 nn3.3 3.4 3.5
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[]12345[]
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??
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Fmnaij (i=1,2,..,m; j=1,2,,n)Fmn,mn,aijij
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(n,m),,
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,(1).;()(2).;()(3)..()()(1).();()(2).();()(3).()().()
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()
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dr+10,()dr+1=0,r=n, ()*rn!
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,dr+1=0 r=n, ,x1,x2,,xn,*
- ,dr+1=0 r
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,:xr+1=c1,,xn=cn-r,, c1,,cn-r
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x4=c,(c
- ,r=n,;r
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1 2
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3
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4
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n n
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n,
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nFna1,a2,,anniaii;n,,n1nnn1
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,1nn1.,,(),n,-
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()n,n,,+ - = + (- )()kF,kk,k
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();();();();();,,n,on,klFFn,,,Fn
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:
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1, 2, , s sk1, k2, , ks , 1, 2, , s1, 2, , sx11 +x22 ++xss = :n(0,0,,0)n1, 2, , sk1= k2= = ks =0,
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n1=(1,0,,0), 2=(0,1,,0),,n=(0,0,,1),n()n =(a1,a2,,an),n1, 2,, n,1, 2,, ni(1in)i=01+02+ + 1i+ +0n (1in)
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=(2,3,-1), 1=(1,-1,2), 2=(-1,2,-3),3=(2,-3,5),1,2,3,
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1, 2, , s,k1, k2, , ks ,k11+k22+ +kss=o1, 2, , s1, 2, , s,k1== ks=0,k11+k22++kss=o/x11 +x22 ++xss =o/o, 1,2, ,s,k0
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1 2
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1
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2 1
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A B
C D
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( )
A B
C D
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j1, j2, , jr: (1) j1, j2, , jr; (2) j1, j2, , jr.j1, j2, , jrj1, j2, , jr: (1) j1, j2, , jr; (2) , j1, j2, , jr, .
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1,21,2,31,21,21,2,32,3 1,31234,
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1031,2, ,s: r(1,2, ,s)1, 21,2, ,sr(1,2, ,s)=s11,()
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()()()()()():A3.A:A. A
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12(),()
13(),()
()()
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14A=(aij)mn,A,A,A,A, A,a110A(),AA()r,A()r
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A=(aij)mn,AA,Ar(A)
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r(Amn)Amn().,0r(Amn) min{m,n}.r(Amn)=m,Amnr(Amn)=n,Amn()(),1(,)
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;.:A,:
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,:1,2,3
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1
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,
,
- 17:,r(A)=r().()1r(A)=r()=n.2r(A)=r()
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11, 2,1+2.2,c, c1,,s,c11+c22++css
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A B
C D
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A B
C D
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1,2,,s,1,2,,s.1. ,;2.r(A)=n,, .
- 18r(A)
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,xr+1,,xn ,n-rn-rn-r:, 1,2,,n-r()
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,,,1,2,,n-r., 1,2,,n-r()()
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1,2,,n-r ,(): c1,c2,,cn-r()
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1,, +21, 2,1-2190,1,2,,n-r,():= 0+c11 +c22 ++cn-rn-r ;ci0
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D A B C D
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mn A B C D
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2
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A B C D
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,
,
_________________________.
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A B
C D
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1
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[] 3.1 3.2 3.3 2.4 2.5 2.6
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[]12345[]
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mnA=(aij)mnB=(bij)mn,C=(aij+bij)mn(A,B),CAB;C=A+BA=(aij)mnB=(bij)mn,, aij=bij,AB,: A=B ,;
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A-AA=(aij)mn,-A=(-aij)mn,AAmn-Bmn=Amn+(-Bmn)()A+BA-B.:
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(1) A+B=B+A(2) (A+B)+C=A+(B+C)(3) A+O=O+A=A(4) A-A=A+(-A)=OA,B,CO
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A=(aij)mn , kF. kAkA,;kA=(kaij)mn k(A+B)=kA+kB (k+l)A=kA+lA (kl)A=k(lA)=l(kA) 1A=AA,Bmn, k,lF
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X,3A+2X=3B 3A+2X=3B 2X=3B - 3A
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A=(aij)ms ,B=(bij)sn, ABmnC=(cij)mn; C=AB1AB, 2AB, A, B
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CijcijAi Bj.
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: BA
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,AX=BAX=O, Om1
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,AB,BA.22-16-32816220000=O1,ABBA,2AB=OA=OB=O
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nn, n,nn()1,0n,n;En .E(I)
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(1) (AB)C=A(BC);(2) A(B+C)=AB+AC;(3) (B+C)A=BA+CA;(4) Fk, k(AB)=(kA)B=A(kB);(5) Amn , Em Amn=Amn; AmnEn=AmnABAB=BA,AB,A, B
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A.:AAX=XA::a,b.
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An, k , AkAk=AAAk,l, ::(1) , (2) ,
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:A,A,A'AT ATijaij'=Ajiaij
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nnA,A|A|n: |A|=|AT|; |kA|=kn|A|; |AB|=|A||B| |A1A2As|=|A1||A2||As|.ABBA,|AB|=|A||B|=|B||A|=|BA|
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An,|A|0,A();|A|=0,A()nABA2+AB+B2=O,B,A,A+BBAA+B
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,
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n,n:.;k;.
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n,n()()A=aEn (An)Bmn, (aEm)Bmn=aBmn ; Bmn(aEn)= aBmn .,
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n, n, (): (). k. .
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nAAT=A,A.A=(aij)nn,aji=aij (i,j=1,2n).: AB, A+B. k.., .
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nAAT=-A,A.A=(aij)nn,aji= -aij (i,j=1,2n).., .: (). k..
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nA,BAB=BA=E,A, A;BA,A-1,A-1=B1. BA2. ABA-1=B,B-1=A3. A(BCA,AB=BA=E,AC=CA=E B=BE=B(AC)=(BA)C=EC=C)En., En En = En,(En)-1= En
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AijnA|A|aij,A
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A*AA* = A*A=|A|E000000
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nA|A|0,A,AA
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ABABn, AB =E,AB, A-1=B , B-1=A:AB =E, AB.AB =E:AB =E::BAAB,()
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nA2A(A-E)=A3,E-A,(E-A)-1= A2 -A+E .
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1.A,A-1,A*,(A-1)-1= A,(A*)-1=A/|A|.A-1A= E,A-1, (A-1)-1= A;A*A=|A|E,A*(A/|A|)=E.2.A,B, AB,(AB)-1=B-1A-1 .(AB)(B-1A-1)= A(BB-1)A-1= AEA-1 =E,(AB)-1=B-1A-1 .
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3.A, AT,(AT)-1=(A-1)T .AT(A-1)T= (A-1A)T=ET=E,(AT)-1=(A-1)T .4.A, 5.An, 6.Ak0,kA,(kA)-1=k-1A-1 .
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,
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E(),(),E[i,j]E[i(k)]E[i,j(k)]
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Eij(ij), ijij
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kEi().ii
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Ejki(Eikj)jkik
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Amn, A,mAA,nA ,,A,,A,()
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A, A-1.,G1,G2,,Gk,:A----n2n(A E)(A E), A,EA-1 .
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AX=BAX=B(A).,X=A-1BA-1,A-1BAX=B (A)----n2n(A B)(A B), A,EA-1B .
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X,AX+B=XAX+B=XB=X-AX=(E-A)XE-A: XA=B,A,X
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A
A
-44
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ABn
A
BABAB
C
D
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B
A B
C D
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X=
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=
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X=
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X
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X
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[]4.1
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[][]
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AFn, F,n, A= ,A, AA, A, , .A= (o) - A = o(o)(E-A)=o (o)(E-A)X=o,
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,1,2A,k,k, k11+k22(k1, k2)A
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A5,=(1,1)TA5
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nA2
C
A B
C6 D
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n2
D
A B C D
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n
A2
A5 B5
C6 D6
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A(E-A)X=o(E-A)X=o|E-A|=0;|E-A|=0 (E-A)X=o;
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|E-A|=0 A;(E-A)X=o,A
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A.1= -2,2=1=-2(E-A)X=o:
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A=-2k,k=1 ()(E-A)X=o:A=1= k11+ k22 ,k1, k2