Pr : AZIZ HALIB et HALIB JAMAL 1 :AB l = AB = 20 cm2S = 1 mm25 C .m O8 -= 1,7 .10 1 AB2 AB UAB I = 1 A3 2 :O = 21 R O = 32 R O = 64 = R 3 R1 eq R AB2 AB = 12 V AB UI 1 I 2 I 3 I 4 IAB 3 :R1 1 R22 2 R2 1 R 2 R3 5 :O = 4001 R O = 2002 R AM U BM U= 2 V/div v S = 2 ms/div h S1AM U 1 f 1 U2BM U 2 f 2 U3MB UMA U1 R 2 R45 m I 6 :1 R = 6 V AB = U PNU AB O R = 70 AC X1 R = 20 mA 1 I= 2 V 1 U1 1 R2 XACwww.physique-maths.comN P B A R1 I I1 C Rh I I1 R2 R3 R4 R1 BA C I1 I2 I3 I4 I AB I 1 52eqR R | |+= | |\ .GBF A B M R1 R2 i A B B . A .