50 de thi thu mon hoa co loi giai hay.pdf

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H v tn:. . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . S bo danh: . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . Cho bit khi lng nguyn t (theo vC) ca cc nguyn t : H = 1; He=4; Li = 7; C = 12; N = 14; O = 16; Na = 23; Mg = 24; Al = 27; P = 31; S = 32; Cl = 35,5; K = 39;

Ca = 40;

Fe = 56; Cu = 64; Zn = 65; As = 75 ; Br = 80; Rb = 85,5; Sr=88; Ag = 108;Sn = 119; Ba = 137; Pd=106.

.

Bi 1 (ID:75429) . x l cht thi c tnh acid, ngi ta thng dng ? A. Nc vi B. Gim n C. Mui n D. Phn chua.

Bi 2 (ID:75430) . t chy hon ton mt ester n chc, mch h X ( phn t c s lin kt nh hn 3), thu c th tch kh CO2 bng 6/7 th tch kh O2 phn ng ( cc th tch kh o cng iu kin). Cho m gam X tc dng hon ton vi 200ml dung dch KOH 0,7M thu c dung dch Y. C cn dung dch Y thu c 12,88 gam cht rn khan. Gi tr ca m l: A. 7,20. B. 6,66. C. 8,88. D. 10,56..

Bi 3 (ID:75431) . ha tan x mol mt kim loi M cn dng va 2x mol HNO3 c, nng gii phng kh NO2. Vy M c th l kim loi no trong cc kim loi sau ? A. Fe. B. Au. C. Cu. D. Ag.

Bi 4 (ID:75432) . Lng Glucose cn dng to ra 1,82gam sorbitol vi hiu sut 80% l ? A. 1,44g. B. 1,80g. C. 1,82g. D. 2,25g.

Bi 5 (ID:75433) . Cho cc nhn xt sau: (1) C th to c ti a 2 ipeptit t phn ng trng ngng hn hp Alanin v Glycin. (2) Khc vi acid axetit, acid amino acetic c th phn ng vi acid HCl v tham gia phn ng trng ngng. (3) Ging vi acid acetic, aminoacid c th tc dng vi base to ra mui v nc. (4) Acid acetid v acid - amino glutaric c th lm thay i mu qu tm thnh . (5) Thy phn khng hon ton peptit: Gly P he Tyr Gly Lys P he T yr c th thu c 6 tripeptit c cha Gly. (6) Cho HNO3 c vo ng nghim cha albumin thy to dung dch mu tm. S nhn xt ng l : A. 5. B. 6. C. 4. D. 3.

Bi 6 (ID:75434) . Khi t chy hon ton mt este no, n chc, mch h th s mol CO2 sinh ra bng s mol O2 tham gia phn ng. Tn gi ca este l: A. etyl acetat.

B. metyl acetat.

C. n - propyl acetat.

D. metyl format.

Bi 7 (ID:75435) . Cho cc phn ng sau: (1) X + 2N aOH (t

0) 2Y + H2

(2) Y + HCl (long) Z + N aCl Bit X l cht hu c c cng thc phn t C6H10O5. Khi cho 0,1 mol Z tc dng ht vi Na (d) th s mol ca H2 thu c l : A. 0,10. B. 0,20. C. 0,05. D. 0,15.

Bi 8 (ID:75436) . Dy cc kim loi u c th c iu ch bng phng php in phn dung dch mui ca chng l: A. Mg, Zn, Cu. B. Fe, Cu, Ag.

THI CHUYN HSP H NI thi th s: 01 - ( thi gm c 4 trang)

THI TH CHUN B CHO K THI THPT QUC GIA NM 2015

Mn: HA HC Thi gian lm bi: 90 pht

M thi 213

TUYN TP50 THI TH THPT QUC GIA MN HA

CA CC TRNG CHUYN TRN C NC(C LI GII CHI TIT)


C. Al, Fe, Cr. D. Ba, Ag, Au.

Bi 9 (ID:75437) . Cho bit th t t tri sang phi ca cc cp oxi ha - kh trong dy in ha( dy th in cc chun) nh sau: Zn2+ /Zn; Fe2+ /Fe; Cu2+ /Cu; Fe3+ /Fe2+; Ag+/Ag. Cc kim loi v ion u phn ng c vi ion Fe3+ trong dung dch l: A. Ag v F e3+. B. Zn v Ag+.

C. Ag v Cu2+. D. Zn v Cu2+.

Bi 10 (ID:75438) . Cho 7,68g Cu v 200 mL dung dch gm HNO3 0,6M v H2SO4 0,5 M. Sau khi cc phn ng xy ra hon ton ( sn phm kh duy nht l NO), c cn cn thn ton b dung dch sau phn ng th khi lng mui khan thu c l: A. 20,16g. B. 19,20g. C. 19,76g D. 22,56g.

Li gii. p n C

Bi 11 (ID:75439) . Phn ng no sau y chng t glucose c cu to dng mch h ? A. Ha tan trong Cu(OH)2 thnh dung dch mu xanh. B. Phn ng ln men ru. C. Phn ng vi CH3OH c xc tc HCl. D. Phn ng trng Ag.

Bi 12 (ID:75440) . un nng 0,2 mol ester n chc X vi 135 mL dung dch NaOH 2M. Sau khi phn ng xu ra hon ton, c cn dung dch thu c ancol etylic v 19,2 gam cht rn khan. Cng thc cu to ca X l : A. C2H3COOC2H5.

B. C2H5COOCH3.

C. C2H5COOC2H5.

D. CH3COOC2H5.

Bi 13 (ID:75441) . Thc hin cc th nghim vi hn hp X gm Ag v Cu: (a) Cho X vo bnh cha mt lng kh O3 ( iu kin thng.) (b) Cho X vo mt lwongj d dung dch HNO3 (c.) (c) Cho X vo mt lng d dung dch HCl (khng c mt O2). (d) Cho X vo mt lng d dung dch F eCl3. Th nghim m Cu b oxi ha cn Ag khng b oxy ha l ? A. (d). B. (b). C. (c). D. (a).

Bi 14 (ID:75442) . Dy gm cc cht c dng tng hp cao su Buna - S l : A. CH2 = CH CH = CH2 v CH3CH = CH2. B. CH2 = C(CH3) CH = CH2 v C6H5CH = CH2. C. CH2 = CH CH = CH2 v lu hunh. D. CH2 = CH CH = CH2 v C6H5CH = CH2. Bi 15 (ID:75443). Cho dung dch Fe(NO3)2 ln lt tc dng vi cc dung dch Na2S, H2SO4long, H2S, H2SO4c, NH3, AgNO3, N a2CO3, Br2. S trng hp xy ra phn ng l: A. 5. B. 7. C. 8. D. 6.

Bi 16 (ID:75444). in phn 100 ml dung dch A cha AgNO3 0,2 M, Cu(NO3)2 0,1 M v Zn(NO3)2 0,15 M vi cng dng in I = 1, 34 A trong 72 pht. S gam kim loi thu c catod sau in phn l ?

A. 3,450g. B. 2,800g. C. 3,775g. D. 2,480g.

Bi 17 (ID:75445). X phng ha 17,6 gam etyl axetat bng 200 mL dung dch NaOH 0,4 M. Sau khi phn ng xy ra hon ton, c cn cung dch thu c cht rn khan c khi lng l: A. 20,80g. B. 17,12g. C. 16,40g. D. 6,56g.

Bi 18 (ID:75446). Cho hn hp X gm F e2O3, ZnO, Cu tc dng vi dung dch HCl (d) thu c dung dch Y v phn khng tan Z. Cho Y tc dng vi dung dch NaOH (long, d) thu c kt ta gm : A. Fe(OH)2 v Cu(OH)2.


B. Fe(OH)2, Cu(OH)2 v Zn(OH)2.

C. Fe(OH)3.

D. Fe(OH)3 v Zn(OH)2.

Bi 19 (ID:75447) . un nng dung dch cha m gam glucose vi lng d dung dch AgNO3 trong NH3, sau khi phn ng hon ton, thu c 10,8 gam Ag. Gi tr ca m l: A. 4,5. B. 9,0. C. 18,0. D. 8,1.

Bi 20 (ID:75448) . Polimer no sau y c iu ch bng phn ng trng ngng : A. Poli (Vinyl clorua). B. Polistiren.

C. Polietilen. D. Poli (Etylen-terephtalat).

Bi 21 (ID:75449) . Cho 3,68 gam hn hp Al, Zn phn ng vi dung dch H2SO4 20% va , thu c 0,1 mol H2. Khi lng dung dch sau phn ng l: A. 13,28 gam. B. 52,48 gam. C. 42,58 gam. D. 52,68 gam.

Bi 22 (ID:75450) . Kim loi no sau y l kim loi kim th ? A. Cr. B. Sr. C. Al. D. Fe.

Bi 23 (ID:75451) . Cho phng tnh ha hc ca phn ng : 2Cr + 3Sn2+ 2Cr3+ + 3Sn. Nhn xt no sau y v phn ng trn l ng ? A. Cr l cht oxi ha, Sn2+ l cht kh. B. Sn

2+ l cht kh, Cr3+ l cht oxi ha.

C. Cr l cht kh, Sn2+ l cht oxi ha. D. Cr

3+ l cht kh, Sn2+ l cht oxi ha.

Bi 24 (ID:75452). Ha tan hon ton hn hp X gm Mg v Zn bng mt lng va dung dch H2SO4 20% (long), thuc dung dch Y. Nng ca MgSO4 trong dung dch Y l 15,22%. Nng phn trm ca ZnSO4 trong dung dch Y l: A. 10,21%. B. 18,21%. C. 15,22%. D. 15,16%.

Bi 25 (ID:75453). Cho m gam bt Cu vo 400 mL dung dch AgNO3 0,2M, sau mt thi gian phn ng thu c 7,76 gam hn hp cht rn X v dung dch Y. Lc tch X, ri thm 5,85 gam bt Zn v Y, sau khi phn ng xy ra hon ton thu c 10,53 gam cht rn Z. Gi tr ca m l: A. 6,40. B. 5,76. C. 3,84. D. 5,12.

Bi 26 (ID:75454). Amino acid X c phn t khi bng 89. Tn gi ca X l: A. Glycin. B. Lysin. C. Alanin. D. Valin.

Bi 27 (ID:75479) : in phn (vi in cc tr) 200 ml dung dch CuSO4 nng x M, sau mt thi gian thu c dung dch Y vn cn mu xanh, c khi lng gim 8 gam so vi dung dch ban u. Cho 16,8 gam bt Fe vo Y, sau khi cc phn ng xy ra hon ton, thu c 12,4 gam kim loi. Gi tr ca x l: A. 1,25. B. 2,25. C. 3,25. D. 1,50.

Bi 28 (ID:75456). Cht hu c X mch h c dng H2N R COOR0 (R, R0 l cc gc hidrocarbon), thnh phn % v khi lng ca nito trong X l 15,73%. Cho m gam X phn ng hon ton vi dung dch NaOH, ta b lng ancol sinh ra cho tc dng ht vi CuO (nung nng) c andehit Y (ancol ch b oxi ha thnh andehit). Cho ton b Y tc dng vi mt lng d dung dch AgNO3 trong NH3, thu c 12,96 gam Ag kt ta. Gi tr ca m l: A. 3,56. B. 5,34. C. 4,45. D. 2,67.

Bi 29 (ID:75457) . Nhng mt thanh Fe vo dung dch hn hp cha 0,02 mol AgNO3 v 0,05 mol Cu(NO3)2. Sau khi cc phn ng xy ra hon ton, khi lng thanh Fe tng m gam (coi ton b lng kim loi sinh ra u bm vo thanh st). Gi tr ca m l: A. 1,44. B. 3,60. C. 5,36. D. 2,00.


Bi 30 (ID:75458) . bo v ng thp (dn nc, dn du, dn kh dt) bng phng php in ha, ngi ta gn vo mt ngoi ca ng thp nhng khi kim loi ? A. Zn. B. Ag. C. Pb. D. Cu.

Bi 31 (ID:75459) . ng vi cng thc phn t C2H7O2N c bao nhiu cht va phn ng c vi dung dch NaOH, va phn ng c vi dung dch HCl ? A. 4. B. 1. C. 2. D. 3.

Bi 32 (ID:75460). Cho hn hp Al v Fe vo dung dch cha Cu(NO3)2 v AgNO3. Sau khi cc phn ng xy ra hon ton thu c dung dch X cha 3 mui. Cc mui trong dung dch X l : A. Al(NO3)3, Fe(NO3)2 v Cu(NO3)2.

B. Al(NO3)3, Fe(NO3)3 v Fe(NO3)2.

C. Al(NO3)3, Fe(NO3)2 v AgNO3.

D. Fe(NO3)2, Cu(NO3)2 v AgNO3.

Bi 33 (ID:75461). Cho dy cc cht: tinh bt, cenlulose,glucose, fructose, saccharose. S cht trong dy khi phn ng vi AgNO3 trong dung dch NH3, un nng to kt ta l : A. 4. B. 2. C. 1. D. 3.

Bi 34 (ID:75462). Tng h s (cc s nguyn, ti gin) ca tt c cc cht trong phn ng gia Cu vi dung dch HNO3 c, nng l: A. 10. B. 12. C. 18. D. 20.

Bi 35 (ID:75463). Mt Polimer c phn t khi l 2, 8.105 vC v h s trng hp l 104. Pomiler y l: A. PVC. B. PS. C. PE. D. Teflon.

Bi 36 (ID:75464). Kt lun no sau y khng ng v tnh cht ca hp kim ? A. cng ca hp kim thng ln hn cng ca kim loi nguyn cht. B. Hp kim thng dn nhit v dn in tt hn kim loi nguyn cht. C. Nhit nng chy ca hp kim thng thp hn nhit nng chy ca kim loi nguyn cht. D. Lin kt trong a s tinh th hp kim vn l lin kt kim loi..

Bi 37 (ID:75465). Cho cc pht biu sau: (a) t chy hon ton ester no, n chc, mch h lun thu c nCO2 = nH2O (b) Trong hp cht hu c nht thit phi c carbon v hidro. (c) Dung dch Glucose b kh bi AgNO3 trong NH3 to ra Ag. (d) Nhng hp cht hu c c thnh phn nguyn t ging nhau, thnh phn phn t hn km nhau mt hay nhiu nhm NH2 l ng ng ca nhau. (e) Saccharose ch c cu to vng. S pht biu ng l : A. 4. B. 2. C. 5. D. 3.

Bi 38 (ID:75466). Cho m gam Fe vo bnh cha dung dch gm H2SO4 v HNO3, thu c dung dch X v 1,12 lt kh NO. Thm tip dung dch H2SO4 d vo bnh thu c 0,448 lt kh NO v dung dch Y. Bit trong c hai trng hp NO l sn phm kh duy nht, o iu kin tiu chun. Dung dch Y ha tan va ht 2,08 gam Cu (khng to thnh sn phm kh ca N +5). Bit cc phn ng xy ra hon ton. Gi tr ca m l:

A. 4,20. B. 4,06. C. 3,92. D. 2,40.

Bi 39 (ID:75467). Vi cng thc phn t C4H6O4 s ng phn ester a chc mch h l: A. 3. B. 5. C. 2. D. 4.

Bi 40 (ID:75468) . S ng phn cu to ca amin bc 1 c cng cng thc phn t C3H9N l: A. 1. B. 4. C. 2. D. 3.


Bi 41 (ID:75469). Ha tan hon ton 3,79 gam hn hp X gm Al v Zn (c t l mol tng tng l 2 : 5) vo dung dch cha 0,394 mol HNO3 thu c dung dch Y v V ml (ktc) kh N2 duy nht. phn ng ht vi cc cht trong Y thu c dung dch trong sut cn 3,88 lt dung dch NaOH 0,125M. Gi tr ca V l:

A. 352,8. B. 268,8. C. 358,4. D. 112,0.

Bi 42 (ID:75470). Cho bit cc phn ng xy ra sau: (1) 2FeBr2 + Br2 2FeBr3 (2) 2NaBr + Cl2 2NaCl + Br2 Pht biu ng l : A. Tnh oxi ha ca Br2 mnh hn Cl2. B. Tnh kh ca Cl mnh hn ca Br. C. Tnh kh ca Br mnh hn Fe2+. D. Tnh oxi ha ca Cl2 mnh hn F e

3+.

Bi 43 (ID:75471) . Amin no sau y thuc loi amin bc hai ? A. Metylamin. B. Trimetylamin. C. imetylamin. D. Phenylalanin.

Bi 44 (ID:75472) . Amino acid X c cng thc H2N CxHy (COOH)2. Cho 0,1 mol X vo 0,2 lt dung dch H2SO4 0,5M, thu c dung dch Y. Cho Y phn ng va vi dung dch gm NaOH 1M v KOH 3M, thu c dung dch cha 36,7 gam mui. Phn trm khi lng ca nito trong X l : A. 11,966%. B. 10,687%. C. 10,526%. D. 9,524%.

Bi 45 (ID:75473). Trong cc Polimer : t tm, si bng, t visco, t nilon - 6, t nitron. Nhng Polimer c ngun gc t cenlulose l A. T visco v t nilon - 6. B. T tm, si bng v t nitron. C. Si bng v t visco. D. Si bng, t visco v t nilon - 6.

Bi 46 (ID:75474) . ipeptit X c cng thc H2NCH2CONHCH(CH3)COOH. Tn gi ca X l: A. Glyxylalanyl. B. Glyxylalanin. C. Alanylglixyl. D. Alanylglixin.

Bi 47 (ID:75475) . Ester no sau y c cng thc phn t C4H8O2 ? A. Phenyl acetat. B. Vinyl acetat. C. Etyl acetat. D. Propyl acetat..

Bi 48 (ID:75476). Nu vt lm bng hp kim Fe - Zn b n mn in ha th trong qu trnh n mn : A. St ng vai tr catod v ion H+ b oxi ha. B. Km ng vai tr anod v b oxi ha. C. Km ng vai tr catod v b oxi ha. D. St ng vai tr anod v b oxi ha.

Bi 49(ID:75477) . Thy phn hon ton mt lng tristrearin trong dung dch NaOH (va ), thu c 1 mol glyxerol v :

A. 3 mol C17H35COONa. B. 3 mol C17H33COONa.

C. 1 mol C17H33COONa. D. 3 mol C17H35COONa.

Bi 50 (ID:75478). Cho 1,792 lt kh CO2 ( ktc) hp th ht vo 200 ml dung dch cha hn hp NaOH 0,2 M v Ba(OH)2 0,12 M thu c m gam kt ta. Gi tr ca m l: A. 4,728. B. 3,940. C. 1,576. D. 2,364.


GII CHI TIT THI THPT QUC GIA 2015 MN HA LN 1 TRNG THPT CHUYN S PHM H NI

Bi 1: Li gii. V nc vi c tnh bazo nn c th x l cht thi c tnh axit. p n A. Bi 2 : Li gii.

X c dng: vi (lt l du

=> m = 0,12.74 = 8,88

=> p n C

Bi 3 : Li gii.

Gi n l s oxi ha cao nht ca kim loi.

Bo ton e : x.n = nNO2 < 2x => n < 2 => n = 1 => M : Ag .

=> p n D.

Bi 4 : Li gii.

p n D

Bi 5:

1. Sai. C 4 i peptit l Gly Ala, Ala Gly, Gly Gly, Ala Ala. 2. ng. y l tnh cht ca amino axit 3. ng. Tnh cht chung ca axit 4. ng. Axit axetic l axit yu, cho H+ cn axit glutamic c hai nhm COOH nn c hai u lm qu ha 5. Sai. Cc tripeptit c th l :Gly Phe Tyr, Phe Tyr Glys; Tyr Gly Lys, Gly Lys Phe 6. Sai. Albumin l mt protein tc dng vi HNO3 c to kt ta vng Vy c 3 cu ng p n D.


Bi 6 : Phng trnh:

Theo th: = n => n = 2

Vy este l metyl fomat

=> p n D

Bi 7: T cc phn ng trn ta suy ra X l anhirit c cng thc l (HO CH2 CH2 CO)2O T suy ra Z l acid c cng thc : HOCH2CH2COOH Khi ly 0,1 mol Z tc dng vi NaOH th ta thu c 0,1 mol H2 p n A.

Bi 8 : A. Loi v Mg iu ch bng in phn nng chy mui C. Loi v Al ch in phn nng chy Al2O3 (khng in phn nng chy AlCl3 v thng hoa) D. Loi v Ba iu ch bng dng in phn nng chy mui halogenua hoc hidroxit kim loi tng ng. Vy chn B, cc kim loi c tnh kh trung bnh v yu.

Bi 9 : Fe

2+ + Zn Zn2+ + Fe

Ag+ + Fe

2+ Fe3+ + Ag

p n B

Bi 10 :

Ta c: nn Cu , H+ ht , NO3

- d

p n C

Bi 11 : Chn D Bi 12 :

p n D. Bi 13 : Chn A. Bi 14 : Chn D Bi 15 :

Gm cc cht: N a2S, H2SO4 long, H2SO4 c, NH3, AgNO3, N a2CO3, Br2. Chn B

Bi 16 :

n e nhng =


=>

Chn A

Bi 17:

nNaOH = 0,08 < nCH3COOC2H5 = 0,2

=> m rn = mCH3COONa = 0,08.82 = 6,56 (g)

=> p n D

Lu : i vi phn ng x phng ha, rn thu c khi c cn dung dch sau phn ng s l: mui (Na,K,...) v kim d (nu c). Khng tnh n este d, ancol,...

Bi 18:

gm : V HCl d, mt khc sau phn ng X + HCl thu c rn Z. Chng t Z l Cu v dung dch Y cha FeCl2;ZnCl2; CuCl2, HCl d Fe2O3 + 6 HCl 2FeCl3 + 3H2O Cu + 2FeCl3 CuCl2 + 2FeCl2 Cho Y tc dng vi N aOH d th kt ta thu c ch c: Fe(OH)2; Cu(OH)2 (do Zn(OH)2 tan trong kim d. ) Vy chn A Bi 19 : glucozo 2Ag => nglucozo = nAg / 2 = 0, 05mol m = 9gam. Chn B Bi 20: Chn D. Chn D. poli(etilen terephtalat) (t lapsan thuc polieste )l sn phm ca qu trnh trng ngng etilen glicol v axit terephtalic

Cc cht cn li u l sn phm ca qu trnh trng hp. Bi 21: Bo ton H: nH2SO4 = nH2 = 0, 1mol

mdd trc = 0, 1.98. 100/20= 49g

Bo ton khi lng: mdd sau = 3, 68 + 49 0, 1.2 = 52, 48g p n B Bi 22: p n B Bi 23: p n C Bi 24:

Gi s khi lng dd H2SO4 phn ng l 98 gam => nH2SO4 = 0,2 mol

Gi x, y ln lt l s mol ca Mg v Zn


=> p n A

Bi 25: Dd mui cui cng l Zn(NO3)2 Ta c: nNO3

= 0, 4.0, 2 = 0, 08 mol

BT NO3- nZn(NO3)2 = 0, 04 mol

BTKL ba kim loi: m + 0, 4.0, 2.108 + 5, 85 = 7, 76 + 10, 53 + 0, 04.65 m = 6, 4 gam Chn A Bi 26: Chn C. Gly : M = 75 Ala : M = 89 V al : M = 117; Glu : M = 147; Lys : M = 146

Bi 27:

Bo ton

m cht rn = mFe ban u - mFe phn ng + mCu

16,8 - 0,2x.56 + 64.(0,2x - 0,1) = 12,4 => x = 1,25

=> p n A

Lu : thng th chng ta s qun i phn ng gia st vi H+ do qu trnh in phn to ra dn n khng hiu ti sao khi lng thanh st gim.

Bi 28:

=> R + R' = 89 - 44 - 6 = 29

=> R = 14 (CH2) ; R' = 15 (CH3)

CTCT ca X l : H2N-CH2-COOCH3

=> nX = = 0,03 mol => mX = 0,03.89 = 2,67 gam

Chn D.

Bi 29: nNO3

= nAgNO3 + 2nCu(NO3)2 = 0, 12 mol

BT NO3

=> nFe(NO3)2 = 0, 06mol

mtng = mAg + mCu mFe p = 0, 02.108 + 0, 05.64 0, 06.56 = 2 gam Chn D.


Bi 30: Chn A. Zn c tnh kim loi mnh hn Fe, do khi gn vo mt ngoi ng thp nhng khi kim loi Zn th Zn s b n mn trc => Bo v c Fe

Bi 31: 2 cht l : HCOONH3CH3, CH3COONH4 p n C. Bi 32: p n A Bi 33: C 2 cht tha mn l : glucozo,fructozo . p n B

Bi 34: Cu + 4HNO3 Cu(NO3)2 + 2NO2 + 2H2O p n A Bi 35:

M = 280000:10000 = 28

monome l C2H4 polime polime PE . p n C Bi 36: Kim loi nguyn cht th c dn nhit, dn in tt hn so vi hp kim ca chng . p n B Bi 37:

(a) ng (b) Hp cht hu c ch cn c C . Sai (c) Dung dich b OXH khng phi b kh.Sai (d) Nhng hp cht khng cng tnh cht ha hc nn khng c gi l ng ng. Sai (e) ng p n :B Bi 38:

Xt tng th qu trnh ta thy :

F e Fe2+

Cu Cu2+

N5+

N2+

nCu = = 0, 0325

Bo ton e : 2. + 2.0, 0325 = 3. + 3.

=> m = 4, 06.

=> p n B

Bi 39:

HCOO CH2 COOCH3, HCOO CH2 OOCCH3,


H3C OOC COO CH3, HCOO CH2 CH2 OOCH, HCOOCH(CH3)OOCH.

Bi 40: CH3 CH2 CH2 NH2, CH3CH(NH2)CH3 p n C Bi 41:

Ta tnh c ngay:

Al v Zn c tnh kh mnh nn trong dung dch sau phn ng s c mui amoni.

t nN2 = xmol, nNH4NO3 = y mol

V sau phn ng to ra Al3+ v Zn2+ co tnh lng tnh nn ta c ( c th HNO3 d nu khng d s tnh bng 0):

nHNO3d + nNH4NO3 = nOH 4nAl

3+ 4nZn

2+

0, 394 (12x + 10y) + y = 0,205

Kt hp bo ton electron ta c h:

=> x = 0,012 mol

=> p n B.

Bi 42: T phng trnh (2) : 2NaBr + Cl2 NaCl + Br2 ta suy ra tnh oxi ha ca Cl2 mnh hn Br2. Mt khc t (1): FeBr2 + Br2 FeBr3 nn tnh oxi ha ca Br2 mnh hn Fe

3+

=> p n D.

Bi 43: Bc ca amin l s nhm gn vo N th H trong phn t NH3 => p n C

Bi 44: nOH = 2nX + 2nH2SO4 = 0, 4 = nKOH + nNaOH

nKOH = 3nNaOH = 0, 3

m = mX + mH2SO4 + mKOH + mNaOH mH2O

=> mX = 13, 3 MX = 133

=> %N = 10, 526%

=> p n C

Bi 45: Cc t c ngun gc t xenlulozo l si bng, t visco Vy chn p n C Bi 46: Tn gi ca X l Glyxylalanin. chn B


Bi 47: Este C4H8O2 l este no n chc v c 4 C nn loi A, B, D. Vy chn p n C Bi 48: Trong n mn in ha th cht no c tnh kh mnh hn th ng vai tr l cc m v cht b oxi ha.

Nn chn B Bi 49: Tristearin l trieste ca glixerol v axit stearic ( C17H35COOH) Khi thy phn trong dung dch kim s to mui v glixerol. Vy chn A

Bi 50: Ta c: nCO2 = 0,08 mol v nOH- = 0,088 mol

PTHH:

X 2X

y y

Ta c h phng trnh :

Vy m = 0,008.197 = 1,576 gam

=> p n C

Ti 49 cn li ti fb sau:

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50 de thi thu mon hoa co loi giai hay.pdf

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