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10 Solve the equation (i) lg(2x) – lg(x – 3) = 1, [3] (ii) log 3 y + 4log y 3 = 4. [4] 9 Solve (i) log 4 2 ! log 9 (2x ! 5) # log 8 64, [4] (ii) 9 y ! 5(3 y 0 10) # 0. [4] 8 Solve (i) log 3 (2x ! 1) # 2 ! log 3 (3x 0 11), [4] (ii) log 4 y ! log 2 y # 9. [4] 7 (a) Variables l and t are related by the equation l = l 0 (1 + α) t where l 0 and α are constants. Given that l 0 = 0.64 and α = 2.5 × 10 –3 , find the value of t for which l = 0.66. [3] (b) Solve the equation 1 + lg (8 – x) = lg (3x + 2). [4] 9 (a) Given that u = log 4 x, find, in simplest form in terms of u, (i) x, (ii) log 4 , (iii) log x 8. [5] (b) Solve the equation (log 3 y) 2 + log 3 ( y 2 ) = 8. [4] 16 –– x 5 (i) Express 32 as a power of 2. [1] (ii) Express ( ) 64 1 x as a power of 2. [1] (iii) Hence solve the equation ( ) 64 2 1 32 1 x x = . [3] 8 (i) Given that log 9 x = a log 3 x, find a. [1] (ii) Given that log 27 y = b log 3 y, find b. [1] (iii) Hence solve, for x and y, the simultaneous equations 6log 9 x + 3 log 27 y = 8, log 3 x + 2 log 9 y = 2. [4]

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  • 10 Solve the equation

    (i) lg(2x) lg(x 3) = 1, [3](ii) log3 y + 4logy 3 = 4. [4]

    9 Solve

    (i) log4 2 ! log9 (2x ! 5) # log8 64, [4]

    (ii) 9y ! 5(3y 0 10) # 0. [4]

    8 Solve

    (i) log3(2x ! 1) # 2 ! log3(3x 0 11), [4]

    (ii) log4 y ! log2 y # 9. [4]

    7 (a) Variables l and t are related by the equation l = l0(1 + )t where l0 and are constants.

    Given that l0 = 0.64 and = 2.5 103, find the value of t for which l = 0.66. [3]

    (b) Solve the equation 1 + lg(8 x) = lg(3x + 2). [4]

    9 (a) Given that u = log4 x, find, in simplest form in terms of u,

    (i) x,

    (ii) log4 ,(iii) log

    x8.

    [5]

    (b) Solve the equation (log3 y)2 + log3(y2) = 8. [4]

    16

    x

    5 (i) Express 32

    as a power of 2. [1]

    (ii) Express ( )641x as a power of 2. [1]

    (iii) Hence solve the equation ( )642

    132

    1x

    x = . [3]

    8 (i) Given that log9 x = a log3 x, find a. [1]

    (ii) Given that log27 y = b log3 y, find b. [1]

    (iii) Hence solve, for x and y, the simultaneous equations

    6log9 x + 3 log27 y = 8,

    log3 x + 2 log9 y = 2. [4]

  • 8 Solve the equation

    (i) 22x + 1 = 20, [3]

    (ii) 5

    25

    125

    25

    4 1 3

    2

    y

    y

    y

    y

    +

    = . [4]

    5 (a) Solve the equation 92x 1 = 27x. [3]

    (b) Given that

    a b12

    23

    a b3 2

    3

    = a pbq, find the value of p and of q. [2]

    10 (a) Given that logp X = 6 and logp Y = 4, find the value of

    (i) logp X2

    Y , [2]

    (ii) logY X. [2]

    (b) Find the value of 2z, where z = 5 + log23. [3]

    (c) Express 512 as a power of 4. [2]

  • 7 Given that logp X = 9 and logpY = 6, find

    (i) logp X , [1]

    (ii) logp ( 1X ) , [1] (iii) logp (XY ), [2]

    (iv) logY X. [2]

    6 Given that log8 p = x and log8 q = y, express in terms of x and/or y

    (i) log8 p + log8 q2, [2]

    (ii) log8 q8, [2] (iii) log2 (64p). [3]

    8 (a) Solve the equation (23 4x) (4x + 4) = 2. [3]

    (b) (i) Simplify 108 12 3

    , giving your answer in the form k 3 , where k is an integer. [2]

    (ii) Simplify 5 + 3 5 2

    , giving your answer in the form a 5 + b, where a and b are integers. [3]

  • 0606/1/M/J/02

    where n is a positive integer and = .n!(n r)!r!)r(