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    Example 10.1 Stoichiometry of denitr ification reactions

    Denitrification scheme

    eterotrop c w t met ano

    Heterotrophic with acetate

    Autotrophic with H2

    Parameters

    f0s values : 0.36, 0.52, 0.21

    Compute the overall Stoichiometric reactions for each system

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    Example 10.1 Stoichiometry of denitrification reactions

    1. Calculate the fs, fe

    2. Cell synthesis (Rc) with NO3 ( Equation C-2, Table 2.4, same for all)

    3. Acce tor e uation Ra E uation I-7 Table 2.2 same for all

    4. Donor equation (Rd) ( methanol, acetate, H2, Table 2.3)

    5. Compute the stoichiometric equation

    [3.33]1

    110 xdss b

    b)f(ff

    +

    +=

    ]37.2[dcsae RRfRfR +=

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    Example 10.1 Stoichiometry of denitrification reactions

    i) Heterotrophic with Methanol

    Assumption : b = 0.05/day(Table 10.1) , fd=0.8 for all system

    fs fe1. Calculate fs, fe0.267 0.733

    2. Cell synthesis equation

    OH2811NOHC

    281eH

    2829CO

    285NO

    281 2275

    -2

    -3 ++++

    +

    3. Acceptor equation OH5

    3N

    10

    1eH

    5

    6NO5

    122

    --

    3 +++ +

    4. Donor equation OH1

    OHCH1

    eHCO1

    23

    -

    2 +++ +

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    Example 10.1 Stoichiometry of denitrification reactions

    1112951 -- +

    2828282828. 227523

    O)H5

    3N

    10

    1eH

    5

    6NO5

    1(0.733 22

    --

    3 +++ +

    cs

    aeRf

    -

    223 eHCO61OH

    261OHCH

    61 +++ +

    dR

    -33 0.1561HNO15610OH0.1667CH ++ +

    .

    222275 0.119COO0.3781HN07330NOHC009540 +++ ..

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    Example 10.1 Stoichiometry of denitrification reactions

    i) Heterotrophic with methanol

    222275

    -

    33

    0.119COO0.3781HN07330NOHC009540

    0.1561HNO15610OH0.1667CH

    +++

    ++ +

    ..

    .

    ii) Heterotrophic with acetate

    OH1542.00.0639CO0.125HCON0658.0NOHC0122.00.1438HNO1438.0COO0.125CH

    22

    -

    32275

    -

    3

    -

    3

    ++++

    ++ +

    0.1773HCO02460NO177300.5H 2-

    32 +++ +

    ..

    u o rop c w 2

    . 22275 ..

    Table 10.2.

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    Summary of Example 10.1

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    Summary of Example 10.1

    1. The observed yield of denitrifiers (fs ) declines significantly from acetate tomethanol to H2 as the donor.

    ~ - - -. . .

    The great % (13 %) is associated with the greatest fs (0.342).For acetate, e- eq as N-source =0.342 x (8/28) = 0.098 (eqns. at p.502)

    % of e- eq = (0.098/0.756) x 100 = 13 %.

    3. 28.6 % of the oxygen demand of the biomass is invested in reducing the N-source (NO3

    -) to the -3 oxidation state.

    4. For heterotrophic nitrification with acetate requires an input of

    ~ 4g BODL / g NO3- -N and produces ~ 0.69 g VSS of biomass (=sludgewasting rate) and 3.6 g as CaCO3 of alkalinity (= buffer requirement).

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    10.3 One-Sludge Denitrification

    Tertiary denitrification : the water does not contain the necessary electron

    donor and thus an exogenous electron donor must be provided.

    One-sludge denitrification : the water contains an electron donor that can

    drive denitrification.

    - One-sludge denitrification (= single-sludge = combined denitrification)

    - Two goals in one-sludge denitrification :

    1) Providing aerobic conditions that allow full nitrification

    2) Providing anoxic conditions and Reserving BOD (organic electron donor)for denitrification.

    *1) and 2) seems to conflict with each other, but they should be done simultaneously .

    Conse uentl the task is to how to reconcile them.

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    10.3.1 Basic One-Sludge Strategies

    Influent wastewater contains TKN. In one sludge denitrification, the TKN must

    be oxidized to NO3- - N without oxidizing all the BOD before denitrification

    takes place.

    Total Kjeldahl nitrogen (TKN) = organic BOD and reduced nitrogen (NH4+)

    ,

    all one-sludge processes rely on one or more of three basic strategies.

    Three basic strategies for reserving organic electron donor while nitrification

    takes place :

    1) Biomass storage and decay

    2 Classical redenitrification

    3) Simultaneous nitrif ication with denitrif ication

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    10.3.1 1) Biomass storage and decay

    - The synthesis of biomass stores electron equivalents that originally camefrom the BOD and can be released through endogenous respiration to

    .

    TKN NO3--N

    BOD: partly oxidized and

    NO3--N N2

    Biomass as electron donorendo enous res iration

    Fig.10.1 (a) biomass storage and decay

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    10.3.1 1) Biomass storage and decay

    - It is called Wuhrmann biomass decayer (Swiss engineer K. Wuhrmann, 1964)

    -

    employed as a stand-alone process due to two shortcomings:

    = .

    a high conc. of MLVSS (operating problems with settler and recycle)

    high capital costs are necessary

    2) the decay of biomass always releasesNH4 -N from the anoxic step although at

    concentrations lower than in the influent.

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    10.3.1 Classical predenitrification

    - The first tank (anoxic) ; the influent BOD (electron donor) is directly utilizedfor denitrification.

    - The second tank aerobic the influent TKN is nitrified to NO-and

    any remained BOD is oxidized.

    - The nitrate formed in the aerobic tank is recycled to a anoxic tank (Qr2

    ; large)--(electron donor) for denitrification

    3Remained BOD: aerobically consumed

    . .

    (b) classical predenitrification

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    10.3.1 Classical predenitrification

    -Fractional removal of N = ~2

    2

    r

    r

    QQ

    Q

    +

    Q : plant flow rate

    Qr2 : mixed-liquor

    recycle flow rate

    - The large recycle flow of NO3-

    from the second to the first tank

    is necessary, because NO3-

    not recycledleaves in the effluent.

    - Recycle ratios of 400 percent or more

    are employed to bring enough NO3

    -

    removals are substantial.

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    10.3.1 Classical predenitrification

    Widespread use worldwide;

    - Advantages:

    i) direct use of influent BOD for denitrification

    reduces aeration costs for the removal of BOD

    aster net cs t an w t omass storage an ecay

    iii) no release of NH4+-N in the effluent

    - Disadvantage:

    i) large mixed-liquor recycle rate

    ncreases cos s o p p ng an pump ng

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    10.3.1 Simultaneous nitrification with denitrif ication

    Three factors allow all reactions to occur simultaneously.

    1) Various nitrogen reductases using N as e- acceptor are repressed

    only when the D.O. conc. is well above 1 mg/L.

    2) However, inhibition of the nitrogen reductase is not severe when the D.O.

    conc. is less than 1 mg/L.

    2223 NONNONONO

    ductaseNitriteOHNOHeNO

    ductaseNitrateOHNOHeNO

    Re2

    Re22 223

    +=++

    +=++

    +

    +

    ductaseOxideNitricOHONHeNO Re222 22 +=++

    +

    +

    222

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    10.3.1 Simultaneous nitrification with denitrif ication

    Three factors allow all reactions to occur simultaneously.

    . . .

    treatment systems; thus, denitrification can occur inside the floc (or biofilm),

    as long as the electron donor (BOD) penetrates inside.

    - When D.O. concentration is poised at a suitably low level (< ~ 1 mg/L),

    anoxic denitrification can occur in arallel to the aerobic reactions of

    nitrification and aerobic BOD oxidation.

    Fig.10.1 (c) simultaneous nitrification with denitrification

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    10.3.1 Simultaneous nitrification with denitrif ication

    - 100 percent N removal by simultaneous nitrification with denitrification

    , ,

    amounts of denitrification probably occur in most activated sludge

    systems that nitrify and have D.O. conc. below saturation (deSilva, 1997)

    - Simultaneous nitrification with denitrification offers all the advantages

    of predenitrification, but overcomes the main disadvantage, the high

    recycle rate.

    - Maintainin a low D.O. conc. throu hout one reactor creates an infinitel

    high recycle ratio and allows essentially 100 percent N removal.

    -

    : We do not yet know the combinations of SRT, HRT, and D.O. conc. that

    .

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    10.3.1Epilog for One-Sludge Processes

    Common features of all one-sludge processes :

    - one community (or one sludge) of microorganisms carries out all the

    reactions.

    - The heterotrophs switch back and forth between aerobic and

    anoxic respiration, or they do both simultaneously.

    - Because the nitrifiers are slow growing autotrophs,their growth rate controls the SRT needed. SRTs greater than 15 days

    are requ re n mos cases, some mes muc onger s are use .

    - The longer SRTs provide an added safety factor for the nitrifiers,who experience periods of low or zero DO.

    - The long SRTs mean that accumulation of inert suspended solids is important.

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    10.3.1Epilog for One-Sludge Processes

    Common features of all one-sludge processes :

    - A practical outcome of a long SRT is that the HRT (in settler) needs to

    increase in order to keep the MLSS conc. within reasonable limits dictated by

    Thats why settler parameters for one-sludge denitrification is similar to

    those used for extended aeration activated sludge.

    - HRTs for predinitrification and simultaneous nitrification with denitrificationare at least 10 h for typical sewage, and 24 h or greater are used in some

    ns ances.

    - To overcome the limitations of one-sludge denitrification, the Barnardprocess, sequencing batch reactor (SBR), and biofilm systems are

    developed.

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    10.3.2 Variations on the Basic One-Sludge processes

    Barnard process (1975) by Dr. J. Barnard of South Africa

    50 mg/L TKN Influent TKN : 50 mg/L

    recycle ratio (Qr2 ) from reactor 2 to 1

    : 400 % eac or : en r ca on ra e s o

    recycled input and 80 % of the influent TKN(Qr2=400%) 10 mg/L (20%)

    Reactor 2

    NO3--N/L leaving : 10 mg/L (20%) 3 mg NH4

    +-N /L

    Reactor :endogenous decay of cells

    - 0.3 mg NH4+-N is released per mg NO3-N

    due to endogenous cell decay 3 mg NO3--N/L

    -Because 10 mg/L of NO3-N is converted to

    N2 gas, Reactor 3 releases 3mg NH3-N/L

    (6 %)

    Reactor 4 releases 3 mg NO3

    -N/L

    Final effluent TKN : 3 mg NO3-N/L

    Total removal rate : 94 %Fig.10.2 Schematic of the Barnard process

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    10.3.2 Variations on the Basic One-Sludge processes

    50 mg/L TKN

    Barnard process

    -denitrification process (> 90% N removal)

    10 mg/L

    3 mg NH4+-N /L Drawbacks- need many tanks

    3 mg NO3--N/L

    - ong

    - significant mixed-liquor recycle

    (400 %)between reactors 2 and 1

    Fig.10.2 Schematic of the Barnard process