chapter 5 - reflection and transmission boundaries

6
Reflection and Transmission at boundaries (Ta3520) Transmission loss correction – p. 1/

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Reection and Transmission atboundaries

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Page 1: Chapter 5 - Reflection and Transmission Boundaries

Reflection and Transmission atboundaries

(Ta3520)

Transmission loss correction – p. 1/6

Page 2: Chapter 5 - Reflection and Transmission Boundaries

REFLECTION / TRANSMISSIONWave equation for pressure: ∂2p

∂x2 −1

c2

∂2p

∂t2= 0

Solution: p(x, t) = s(t ± x/c)

where s(t) is any function.

Fourier transformation: G(ω) =∫

+∞

−∞g(t) exp(−iωt)dt

Then: P (x, ω) = S(ω) exp(±iωx/c)

Transmission loss correction – p. 2/6

Page 3: Chapter 5 - Reflection and Transmission Boundaries

Up- and Down-going wavefields

boundary

incident field:

transmitted field

reflected field

S(ω) exp(-iωx/c1)

S(ω) T exp(-iωx/c2)

S(ω) R exp(+iωx/c1)

c1ρ1,

c2ρ2 ,

Transmission loss correction – p. 3/6

Page 4: Chapter 5 - Reflection and Transmission Boundaries

Above boundary (x < 0):

P (x, ω) = S(ω) exp(−iωx/c1) + RS(ω) exp(iωx/c1)

Below boundary (x > 0):

P (x, ω) = TS(ω) exp(−iωx/c2)

Boundary conditions:

limx↑0

P (x, ω) = limx↓0

P (x, ω)

limx↑0

Vx(x, ω) = limx↓0

Vx(x, ω)

Transmission loss correction – p. 4/6

Page 5: Chapter 5 - Reflection and Transmission Boundaries

Expression for Vx via equation of motion:

Vx(x, ω) = −1

iωρ

∂P (x, ω)

∂x

Working out:

Vx(x, ω) = S(ω)1

ρ1c1

exp(−iωx/c1)

−RS(ω)1

ρ1c1

exp(iωx/c1) for x < 0

Vx(x, ω) = TS(ω)1

ρ2c2

exp(−iωx/c2) for x > 0Transmission loss correction – p. 5/6

Page 6: Chapter 5 - Reflection and Transmission Boundaries

Substituting expressions in boundary conditions:

R =ρ2c2 − ρ1c1

ρ2c2 + ρ1c1

T =2ρ2c2

ρ2c2 + ρ1c1

Transmission loss correction – p. 6/6