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ΕΘΝΙΚΟ ΜΕΤΣΟΒΙΟ ΠΟΛΥΤΕΧΝΕΙΟ ΣΧΟΛΗ ΕΦΑΡΜΟΣΜΕΝΩΝ ΜΑΘΗΜΑΤΙΚΩΝ &  ΦΥΣΙΚΩΝ ΕΠΙΣΤΗΜΩΝ  ΤΟΜΕΑΣ ΜΑΘΗΜΑΤΙΚΩΝ  Ασκήσεις και Θέµατα στη Μιγαδική Ανάλυση Γιάννης Σαραντόπουλος  Αθήνα 13 Μαρτίου 2013

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αναλυση 1 πολυτεχνειο

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  • &

    pi

    13 2013

  • i

    1 1

    1.1 201112 . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 1

    1.2 200910 . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 23

    1.3 20089 . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 38

    1.4 20078 . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 51

    1.5 200607 . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 64

    2 89

    2.1 201112 . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 89

    2.2 200910 . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 108

    2.3 20089 . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 117

    2.4 20078 . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 124

    2.5 20067 . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 133

  • R pi

    R+ pi

    Z

    N

    Q

    n N,n! = 1 2 3 n,(2n)!! = 2 4 6 (2n 2) (2n) (2n+ 1)!! = 1 3 5 (2n 1) (2n+ 1).

    x R, [x], k Z k x < k + 1.

    C pipi

    C = C {} pi pipi

  • ii

    D (z0, r) z0 C r > 0 ( D (z0, r) pi z0 C)

    D (z0, r) z0 C r > 0

    C (z0, r) z0 C r > 0

    C+ (z0, r) z0 C, r > 0

    C (z0, r) z0 C, r > 0

    A pi C,

    z0 A A, pi pi D (z0, ) z0 D (z0, ) A,

    z0 C (.) A, D (z0, ) (A \ {z0}) 6= , pi D (z0, ) z0.

    f A C, A 6= , , pi M > 0 |f(z)| M z A.

    f pi f

    f (k) k-pi f

    exp

    log

    Log pi

    pi

    pi pi

    f (z) dz pipi f pi pi f (z) dz pipi f pi pi

  • iii

    f (z) dz pipi f pi pi

    f (z) dz pipi f pi pi

    n (, z0) I (, z0) Ind (z0) pi pi z0 /

    Res (f, z0) pipi f z0

    Euler

    Riemann

  • iv

  • 1

    1.1 201112

    &

    1

    1. : z4 = 1 +

    3i.

    . pi 1 +3i = 2e2pii/3, z4 = 1 +3i

    zk = 21/4e(2kpii+2pii/3)/4 , k = 0, 1, 2, 3 .

    pi z4 = 1 +3i

    z0 = 21/4epii/6 , z1 = 21/4e2pii/3 , z2 = 21/4e7pii/6 z3 = 21/4e5pii/3 .

    2. n N,

    zn1 = z , z C .

    pipi (i) n = 1, (ii) n = 2 (iii) n 3.

    . (i) n = 1: z = 1 z = 1.

    1

  • 2 1.

    (ii) n = 2: z = z z = x R, pi.

    (iii) n 3: zn1 = z z = 0. z 6= 0, zn1 = zpi

    |z|n1 = |z| |z|n2 = 1 |z| = 1 .

    pi z 6= 0zn1 = z zn = 1

    zn = 1 n- ,

    zk = e2kpii/n , k = 0, 1, 2, . . . , n 1 .

    n 3 zn1 = z {0, 1, e2pii/n, e4pii/n, . . . , e2(n1)pii/n

    }={

    0, 1, , 2, . . . , n1}, pi = e2pii/n .

    3. f : C C

    f(z) =

    z2

    z z 6= 0,

    0 z = 0 .

    pi pi CauchyRiemann (0, 0) pi

    pi f (0).

    . x R, x 6= 0,

    f(x, 0) f(0, 0)x 0 =

    x2/x

    x= 1

    pif

    x(0, 0) = lim

    x0f(x, 0) f(0, 0)

    x 0 = 1 .

    , y R, y 6= 0,

    f(0, y) f(0, 0)y 0 =

    (iy)2/iy

    y= i

  • 1.1. 201112 3

    pif

    y(0, 0) = lim

    y0f(0, y) f(0, 0)

    y 0 = i .

    fx

    (0, 0) = ify

    (0, 0) = 1, pi CauchyRiemann

    (0, 0).

    pi f pi 0. z C,z 6= 0,

    f(z) f(0)z 0 =

    f(z)

    z=

    (z

    z

    )2.

    z = x+ ix C R x 6= 0. ,

    f(z) f(0)z 0 =

    (x+ ix

    x+ ix

    )2=

    (1 i1 + i

    )2=

    (1 2 2i

    1 + 2

    )2 pi

    limz0

    z=x+ix

    f(z) f(0)z 0 =

    (1 2 2i

    1 + 2

    )2 pi . , pi f (0) pi.

    . pi pi CauchyRiemann

    (0, 0) pi : z = x+ iy 6= 0,

    z2

    z=

    z3

    |z|2 =(x iy)3x2 + y2

    =x3 3xy2x2 + y2

    + iy3 3x2yx2 + y2

    .

    pi f = u+ iv

    u(x, y) =

    x33xy2x2+y2

    (x, y) 6= (0, 0),

    0 (x, y) = (0, 0) v(x, y) =

    y33x2yx2+y2

    (x, y) 6= (0, 0),

    0 (x, y) = (0, 0) .

    ux(0, 0) = vy(0, 0) = 1 uy(0, 0) = vx(0, 0) = 0, pi - CauchyRiemann (0, 0).

    4. pi

    f(z) = (3x2y y3 + e2y cos 2x) + i(3xy2 x3 e2y sin 2x+ 3)

    C pi pi f (z). f

    z, pi pi pi f (z).

  • 4 1.

    . f (z) = u (x, y) + iv (x, y), u (x, y) = 3x2y y3 + e2y cos 2x v (x, y) =3xy2 x3 e2y sin 2x + 3. u, v pi R2. f C pipi pi CauchyRiemann.

    , (x, y) R2 ux = vy = 6xy 2e2y sin 2xuy = vx = 3x2 3y2 + 2e2y cos 2x

    . pi pi pi

    f (z) =f

    x(x, y) = (6xy 2e2y sin 2x) + i(3y2 3x2 2e2y cos 2x) .

    f (z) = u (z, 0) + iv (z, 0) = cos 2z + i(z3 sin 2z + 3) = e2iz iz3 + 3i .

    pi,

    f (z) = 2ie2iz 3iz2 .

    5. pi f : G C pi(, )G C. z G f(z) = 0 f (z) = 0, pi f G.

    pi. f2.

    . g := f2 G. pi

    pi g(z) = 2f(z)f (z) = 0 z G. pi, pi pi g G pi |g| = |f |2 G. |f | G pi pi pi pi f G.

    6. pi

    u(x, y) = y3 3x2y xx2 + y2

    , (x, y) R2 \ {(0, 0)} ,

    R2\{(0, 0)} f = u+iv C \ {0} f (1) = 1.

  • 1.1. 201112 5

    . u pi 2 R2 \ {(0, 0)}

    ux = 6xy + x2 y2

    (x2 + y2)2, uxx = 6y + 2x(3y

    2 x2)(x2 + y2)3

    uy = 3y2 3x2 + 2xy

    (x2 + y2)2, uyy = 6y +

    2x(x2 3y2)(x2 + y2)3

    .

    uxx + uyy = 0 pi u R2 \ {(0, 0)}. v u, f = u+iv C\{0}. pi CauchyRiemann uy = vx

    vx = 3y2 + 3x2 2xy(x2 + y2)2

    .

    pi,

    v(x, y) = 3xy2 + x3 + yx2 + y2

    + c(y) .

    pi CauchyRiemann ux = vy pipi

    6xy + x2 y2

    (x2 + y2)2= 6xy + x

    2 y2(x2 + y2)2

    + c(y) c(y) = 0 c(y) = c .

    v(x, y) = 3xy2 + x3 + yx2+y2

    + c C \ {0}

    f(z) = u(z, 0) + iv(z, 0) = 1z

    + i(z3 + c) , c R .

    f(1) = 1, pi c = 1. ,

    f (z) = 1z

    + iz3 i .

    7. pi w = cos z = cos(x + iy) = cosx cosh y i sinx sinh ypi

    ={z = x+ iy : 0 x pi

    2, y 0

    } z-pipi 4 w-pipi.

    .

    w = cos z = u(x, y) + iv(x, y) u(x, y) = cosx cosh y v(x, y) = sinx sinh y .

    pi w =

    cos z.

  • 6 1.

    x = 0, y 0, u = cosh y, y 0 v = 0. x = 0,y 0 ( ) . [1,) pi Ou.

    x = pi2 , y 0, u = 0 v = sinh y, y 0. x = pi2 , y 0 .

    y = 0 0 x pi2 , u = cosx v = 0. . y = 0, 0 x pi2 , . [0, 1] pi Ou.

    pi pi pi

    .

    y = y0 > 0, 0 x pi2 , u = cosx cosh y0 0 v = sinx sinh y0 0. . y = y0 > 0, 0 x pi2 ,

    u2

    cosh2 y0+

    v2

    sinh2 y0= 1

    4 . 0 < y0 < , - y = y0, 0 x pi2 , pi 4 , pi 4 . , w = cos z

    4 .

    8. pi

    [R,R]R

    |z|z dz = R3pii ,

  • 1.1. 201112 7

    pi R pipi 0, R > 0

    .

    . pi R z(t) = Reit, 0 t pi pi

    [R,R]R

    |z|z dz =[R,R]

    |z|z dz +R

    |z|z dz

    =

    RR|x|x dx+

    pi0R2eit iReit dt

    = 0R

    x2 dx+

    R0x2 dx+ i

    pi0R3 dt

    = R3pii .

    9. z1, z2 C

    ez2 ez1 =[z1,z2]

    ez dz ,

    pi [z1, z2] z1 pi z2.

  • 8 1.

    . pi

  • 1.1. 201112 9

    (iv) C pi 0 pi. C1 C2 pi

    C, C1 pi

    0 C2 pi pi. ,

    I =1

    2pii

    C+1

    cos z

    z(z pi)3 dz +1

    2pii

    C+2

    cos z

    z(z pi)3 dz ( Cauchy)

    = 1pi3

    +pi2 2

    2pi3(pipi (ii) (iii))

    =pi2 4

    2pi3.

    2. f D(0, R), pi 2pi0

    f(rei)

    reid = 2pif (0) ,

    pi 0 < r < R.

    . z = rei, 0 2pi, dz = ireid = izd, pi d = dz/iz. pi, 2pi0

    f(rei)

    reid =

    |z|=r

    f(z)

    iz2dz

    = 2pi

    {1

    2pii

    |z|=r

    f(z)

    (z 0)2 dz}

    = 2pif (0) . ( pi Cauchy pi)

    3. pi |z|=1

    ez

    zn+1dz , n N

    pi 2pi0

    ecos cos(n sin ) d = 2pin!.

    . pi pi Cauchy pi |z|=1

    ez

    zn+1dz =

    2pii

    n!{n!

    2pii

    |z|=1

    ez

    zn+1dz

    }=

    2pii

    n! (ez)(n)

    z=0

    =2pii

    n! e0 = 2pi

    n!i .

  • 10 1.

    z = ei, 0 2pi. pi dz = ieid = izd,

    |z|=1

    ez

    zn+1dz = i

    2pi0

    eei

    eind

    = i

    2pi0

    ecos +i sin

    eind

    = i

    2pi0

    ecos ei(sin n) d

    =

    2pi0

    ecos sin (n sin ) d + i 2pi0

    ecos cos (n sin ) d .

    , 2pi0

    ecos cos(n sin ) d = 2pin!

    2pi0

    ecos sin (n sin ) d = 0 .

    4. () f1(z) =z2 + 6z

    (2 z)(z + 2)2 =1

    2 z 2

    (z + 2)2. pi-

    f1 Taylor z0 = 0, pi

    .

    () pi f2(z) =1

    z2 + 4z 3i z0 = 2. ;

    . pi

    1

    1 w =n=0

    wn 11 + w

    =n=0

    (1)nwn , |w| < 1 .

    ()

    1

    2 z =1

    2(1 z/2) =1

    2

    n=0

    (z2

    )n=n=0

    zn

    2n+1. (|z/2| < 1 |z| < 2)

    11+w =

    n=0(1)nwn, |w| < 1, pi

    1(1 + w)2

    =

    n=1

    (1)nnwn1

    1

    (1 + w)2=

    n=1

    (1)n1nwn1 =n=0

    (1)n(n+ 1)wn , |w| < 1 .

  • 1.1. 201112 11

    pi

    2

    (z + 2)2=

    1

    2(1 + z/2)2=

    1

    2

    n=0

    (1)n(n+ 1)(z

    2

    )n=

    n=0

    (1)n(n+ 1) zn

    2n+1.

    (|z/2| < 1 |z| < 2) |z| < 2

    f1(z) =n=0

    1

    2n+1[1 + (1)n+1 (n+ 1)] zn .

    R = 2.

    ()

    f2(z) =1

    (z + 2)2 (4 + 3i)= 1

    4 + 3i 1

    1 (z+2)24+3i= 1

    4 + 3i

    n=0

    ((z + 2)2

    4 + 3i

    )n( (z+2)24+3i < 1 |z + 2|

  • 12 1.

    6. f(z) = z23i, D(0, 2) = {z C : |z| 2} pi |f | pi .

    . pi f C, pi |f | pi D(0, 2) pi |z| = 2 z() = 2ei, pi pi. |z| = 2

    |f(z)| = |z2 3i| = |4e2i 3i| = |4 cos 2 + i(4 sin 2 3)|=

    (16 cos2 2 + (4 sin 2 3)2

    =

    25 24 sin 2 .

    |f | pi sin 2 = 1 = pi/4, z = 2eipi/4 =

    2(1 i). pi,max|z|2

    |f(z)| = |f(

    2(1 i))| = 7 .

    f D(0, 2) = {z C : |z| < 2}. f(z) = 0

    z2 = 3i (x+ iy)2 = 3i x2 y2 + 2ixy = 3i {x2 y2 = 0, 2xy = 3} . x = y =

    3/2 x = y = 3/2.

    2 pi. pi z2 = 3i = 3epii/2,

    zk =

    3e(2kpii+pii/2)/2, k = 0, 1, z0 =

    3epii/4 z1 =

    3e5pii/4 .

    ,

    min|z|2|f(z)| =

    f(

    3

    2(1 + i)

    ) =f(

    3

    2(1 + i)

    ) = 0 .

    7. f D(0, 1) = {z C : |z| 1} |f(z)| > 1 |z| = 1. f(0) = i, pi f D(0, 1) = {z C : |z| < 1}.

    . pi f D(0, 1) = {z C : |z| < 1}., pi f pi pi -

    |z| = 1. pi pi

    |f(z)| > 1 |z| = 1 |f(0)| = |i| = 1 . (pi)

  • 1.1. 201112 13

    f D(0, 1) = {z C : |z| < 1}.

    8. pi f D(0, R) = {z C : |z| < R} |f(z)| M < z D(0, R). 0 2 f , f(0) = f (0) = 0 f (0) 6= 0, pi

    |f(z)| MR2|z|2 z D(0, R) (1)

    |f (0)| 2MR2

    . (2)

    pi.

    g(z) =

    f(z)z2

    0 < |z| < R,f (0)2! z = 0 .

    .

    f(z) =f (0)

    2!z2 +

    f (0)3!

    z3 + + f(n)(0)

    n!zn +

    = z2

    (f (0)

    2!+f (0)

    3!z + + f

    (n)(0)

    n!zn2 +

    ), |z| < R .

    g(z) := f(0)2!

    +f (0)

    3!z + + f

    (n)(0)

    n!zn2 + , g

    D(0, R)

    g(z) =

    f(z)z2

    0 < |z| < R,f (0)2! z = 0 .

    z D(0, R), z . pipi r |z| < r < R. pi

    |g(z)| max|w|=r

    |g(w)| = max|w|=r

    |f(w)||w|2

    M

    r2.

    pi r R pipi

    |g(z)| MR2

    z D(0, R)

    pi (1) (2).

  • 14 1.

    . pi (2) pi pi

    Cauchy. ,

    |f (0)| M2!R2

    .

    &

    3

    1. pi f : C C

    lim|z|

    |f(z)|1 + |z|1/2 pi .

    pi f .

    pi. Liouville.

    . lim|z||f(z)|

    1+|z|1/2 = a 0, > 0 pi M > 0 |z| > M |f(z)|1 + |z|1/2 a

    < .pi

    |f(z)| < a+ + (a+ )|z|1/2 |z| > M .

    , pi Liouville f pi 0. , f

    .

    2. f : C C ,

    f(z) =n=0

    anzn =

    n=0

    f (n)(0)

    n!zn z C .

    pi pi M > 0 |f(z)| Me|z| z C. r > 0,pi pi Cauchy pi pi

    |an| M er

    rn n N .

  • 1.1. 201112 15

    pi

    |an| M en

    nn n N .

    . pi pi Cauchy pi

    an =f (n)(0)

    n!=

    1

    2pii

    C+(0, r)

    f(z)

    zn+1dz ,

    pi C+ (0, r) 0 r > 0. ,

    |an| = 12pi

    C+(0, r)

    f(z)

    zn+1dz

    1

    2pi

    C+(0, r)

    |f(z)||z|n+1 |dz|

    12pi

    Mer

    rn+1

    C+(0, r)

    |dz| (|f(z)| Me|z|)

    =1

    2pi

    Mer

    rn+12pir = M

    er

    rn.

    pi

    |an| M infr>0

    er

    rn.

    r 7 errn pi r = n. ,

    |an| M en

    nn n N .

    3.

    f (z) =1

    z2 (z + 1).

    pi Laurent f

    z0 = 1.

    . 1/ (1 w) = n=0wn, |w| < 1 ( ).

    1

    (1 w)2 =n=1

    nwn1 , |w| < 1 .

  • 16 1.

    1 pipi: 1 = {z C : 0 < |z + 1| < 1}. ,

    f (z) =1

    z2 (z + 1)=

    1

    [1 (z + 1)]2 (z + 1)

    =1

    z + 1

    n=1

    n (z + 1)n1

    =n=1

    n (z + 1)n2

    =

    n=1(n+ 2) (z + 1)n .

    2 pipi: 2 = {z C : |z + 1| > 1}. |1/ (z + 1)| < 1 pi

    f (z) =1

    z2 (z + 1)=

    1

    [1 1/ (z + 1)]2 (z + 1)3

    =1

    (z + 1)3

    n=1

    n1

    (z + 1)n1

    =

    n=1

    n1

    (z + 1)n+2

    = 3

    n=(n+ 2) (z + 1)n .

    4. pi Laurent

    f(z) =z2 + 4iz

    (z 1)(z2 + 4i) z0 = 0 pi pi 1 2i. pi pi Laurent f ;

    .

    f(z) =z2 + 4i

    (z 1)(z2 + 4i) +4iz 4i

    (z 1)(z2 + 4i) =1

    z 1 +4i

    z2 + 4i.

    f : 1,

    2(1 i) 2(1 + i). pi pi Laurent pi 1 = {z C : 0 |z| < 1}(pi Taylor), 2 = {z C : 1 < |z| < 2} 3 = {z C : 2 < |z| 2.

  • 1.1. 201112 17

    , 1/ (1 w) = n=0wn 1/ (1 + w) = n=0 (1)nwn, |w| < 1 ().

    f (z) =1

    z 1 +4i

    z2 + 4i

    =1

    z

    1

    1 1/z +4i

    z21

    1 + 4i/z2

    =1

    z

    n=0

    (1

    z

    )n+

    4i

    z2

    n=0

    (1)n(

    4i

    z2

    )n(|z| > 2)

    =n=0

    1

    zn+1+n=0

    (1)n (4i)n+1

    z2n+2.

    pipi pi 3 = {z C : 2 < |z| 0

    |h(z)| k|z|1/2 z .

    h z = 0;

    .

    () z + 2 = w z 3 = w 5,

    (w 5) sin 1w

    = (w 5)(

    1

    w 1

    3! 1w3

    +1

    5! 1w5

    )= 1 5

    w 1

    3! 1w2

    +

    pi

    f(z) = 1 5z + 2

    13! 1

    (z + 2)2+ .

    z = 2 f Res(f,2) = 5.

  • 18 1.

    () 1(z) := sin z z cos z, 1(0) = 1(0) = 1(0) = 0 1 (0) = 2 6= 0.pi, 0 3 g 4 pi

    g. , 0 pi pi g. pi |z| > 0

    g(z) =1

    z4

    [(z z

    3

    3!+z5

    5!

    ) z

    (1 z

    2

    2!+z4

    4!

    )]=

    (1

    2! 1

    3!

    )1

    z(

    1

    4! 1

    5!

    )z + ,

    Res(g, 0) =1

    2! 1

    3!=

    1

    3.

    . pi 0 pi pi g, Res(g, 0) pi pi

    pi

    Res(g, 0) = limz0

    zsin z z cos z

    z4

    = limz0

    sin z z cos zz3

    = limz0

    z sin z

    3z2( LHpital)

    =1

    3limz0

    sin z

    z=

    1

    3.

    () |zh(z)| k|z|1/2 z pi limz0 zh(z) = 0. , 0 pi (pi) h.

    6. pi

    I =

    C+(1i, 2)

    [epiz

    z2 + 1+ sin

    1

    z+

    1

    ez2

    ]dz ,

    pi C+(1 i, 2) 1 i, 2 .

    . i pi pi w = epiz/(z2 + 1). i C+(1 i, 2).

    Res

    (epiz

    z2 + 1, i

    )=

    epiz

    (z2 + 1)

    z=i

    =epii

    2i = 1

    2i .

    pi

    sin1

    z=

    1

    z 1

    3!z3+

    1

    5!z5 ,

  • 1.1. 201112 19

    Res(sin 1z , 0) = 1. , pi pipi

    I = 2pii

    [Res

    (epiz

    z2 + 1, i

    )+ Res

    (sin

    1

    z, 0

    )]= 2pii

    [1

    2i+ 1

    ]= pi + 2pii .

    w = 1/ez2 C pi pi

    Cauchy C+(1i, 2)

    1

    ez2dz = 0 .

    7. z2e2iz1 =

    n= anz

    n pi Laurent f(z) = z2e2iz1 -

    = {z C : pi < |z| < 2pi} z0 = 0 .

    pi Laurent pi pi-

    pi pi an, n 1.

    . pi

    e2iz 1 = 0 e2iz = 1 2iz = 2kpii z = kpi , k Z ,

    zk = kpi, k Z \ {0}, pi pi f(z) = z2/(eiz 1). pi 0 2 pi pi f , 0 pi

    (pi) . pi Laurent an pi pi

    an =1

    2pii

    C+(0, r)

    z2/(e2iz 1)zn+1

    dz =1

    2pii

    C+(0, r)

    zn+1

    e2iz 1 dz ,

    pi C+(0, r) 0, r, pi < r < 2pi

    .

    g(z) :=zn+1

    e2iz 1 ,

    pi pi g C+(0, r) pi pi.

    (i) n = 1: pipi pi, 0 pi g(z) = 1eiz1

    C+(0, r) pi pi. pi

  • 20 1.

    pipi

    a1 =1

    2pii

    C+(0, r)

    1

    e2iz 1 dz

    = Res

    (1

    e2iz 1 , pi)

    + Res

    (1

    e2iz 1 , 0)

    + Res

    (1

    e2iz 1 , pi)

    =1

    (e2iz 1)z=pi

    +1

    (e2iz 1)z=0

    +1

    (e2iz 1)z=pi

    =1

    2ie2ipi+

    1

    2i+

    1

    2ie2ipi=

    3

    2i= 3

    2i .

    (ii) n 0: pipi

    g(z) =zn+1

    e2iz 1 n+ 1 1

    pi pi pi g C+(0, r) pi pi. pi 0 1 pi pi g(z) = zn+1/(e2iz 1), 0 pi (pi) g. , pi pipi

    an =1

    2pii

    C+(0, r)

    zn+1

    e2iz 1 dz = Res(zn+1

    e2iz 1 , pi)

    + Res

    (zn+1

    e2iz 1 , pi)

    =zn+1

    (e2iz 1)z=pi

    +zn+1

    (e2iz 1)z=pi

    =(pi)n+1

    2ie2ipi+pin+1

    2ie2ipi

    =pin+1

    2i

    [(1)n+1 + 1

    ]=

    0 n = 0,2,4, . . . ,

    ipin+1 n = 1,3,5, . . . .

    8. a > 0, pi pi0

    1

    a2 + cos2 d =

    2pi0

    1

    2a2 + 1 + cosd =

    pi

    a

    1 + a2.

    . pi0

    1

    a2 + cos2 d =

    pi0

    2

    2a2 + 1 + cos 2d =

    2pi0

    1

    2a2 + 1 + cosd .

    ( = 2)

  • 1.1. 201112 21

    z = ei, cos = ei + ei

    2=

    1

    2

    (z +

    1

    z

    ) dz = ieid = izd d = dz

    iz. -

    pi, pi0

    1

    a2 + cos2 d =

    |z|=1

    1

    2a2 + 1 + 12(z + 1z

    ) dziz

    =2

    i

    |z|=1

    1

    z2 + 2 (1 + 2a2) z + 1dz .

    pi z1,2 = 1 2a2 2a

    1 + a2 pi z2 + 2(1 + 2a2)z+ 1 = 0,

    1 2a2 2a1 + a2 pi pi g(z) = 1/(z2 + 2(1 +2a2)z + 1). 1 2a2 + 2a1 + a2 |z| = 1, 1 2a2 2a1 + a2 |z| = 1. , pi pipi

    pi0

    1

    a2 + cos2 d =

    2

    i

    |z|=1

    1

    z2 + 2 (1 + 2a2) z + 1dz

    =2

    i2piiRes

    (1

    z2 + 2(1 + 2a2)z + 1, 1 2a2 + 2a

    1 + a2

    )= 4pi

    1

    (z2 + 2(1 + 2a2)z + 1)

    z=12a2+2a1+a2

    = 4pi1

    2(1 2a2 + 2a1 + a2) + 2(1 + 2a2) =pi

    a

    1 + a2.

    9. R z () = Rei, 0 pi, pipi 0 R > 0 a, b > 0, a 6= b. pi

    limR

    R

    1

    (z2 + a2)(z2 + b2)dz = 0 .

    pi pipi pi

    0

    1

    (x2 + a2)(x2 + b2)dx .

    . z R 1(z2 + a2)(z2 + b2) 1(|z|2 a2)(|z|2 b2) = 1(R2 a2)(R2 b2) , R > a, b .

    R piR piR

    1

    (z2 + a2)(z2 + b2)dz

    piR(R2 a2)(R2 b2) R 0 .

  • 22 1.

    ,

    limR

    R

    1

    (z2 + a2)(z2 + b2)dz = 0 .

    ai,bi pi pi f(z) = 1/(z2+a2)(z2+b2). f pi pi pi pi pi pipi

    R z () = Rei, 0 pi [R,R]. R ai bi f

    R.

    pi pipi RR

    1

    (x2 + a2)(x2 + b2)dx+

    R

    1

    (z2 + a2)(z2 + b2)dz = 2pii [Res (f, ai) + Res (f, bi)] .

    (1.1)

    Res (f, ai) = limzai

    (z ai) 1(z ai)(z + ai)(z2 + b2) =

    1

    2ai(b2 a2)

    Res (f, bi) = limzbi

    (z bi) 1(x2 + a2)(z bi)(z + bi) =

    1

    2bi(a2 b2) .

    pi, pi (1.1) pipi

    1

    (x2 + a2)(x2 + b2)dx = lim

    R

    RR

    1

    (x2 + a2)(x2 + b2)dx

    = 2pii1

    2i

    (1

    a(b2 a2) +1

    b(a2 b2))

    =pi

    ab(a+ b).

    , 0

    1

    (x2 + a2)(x2 + b2)dx =

    1

    2

    1

    (x2 + a2)(x2 + b2)dx =

    pi

    2ab(a+ b).

  • 1.2. 200910 23

    1.2 200910

    1

    1. pi f = u+iv piG. u = v2, pi

    f .

    . pi CauchyRiemann vy = ux

    vx = uy

    vy = 2vvx

    vx = 2vvy

    vy = 2vvx

    vx = 4v2vx

    vy = 2vvx(1 + 4v2

    )vx = 0

    .pi, vx = vy = ux = uy = 0 pi f (z) = ux (x, y) + ivx (x, y) = 0

    pi G. , pi pi f pi G.

    2. f (z) = u (x, y) + iv (x, y) D (0, r) =

    {z C : |z| r}. pi C(0, r)

    u

    ydx u

    xdy = 0 ,

    pi C (0, r) 0 r.

    . , u pi pi

    Laplace2u

    x2+2u

    y2= 0 .

    pi u pi, pi Green C+(0, r)

    u

    ydx u

    xdy =

    D(0, r)

    (2u

    x2+2u

    y2

    )dxdy = 0 .

    , C(0, r)

    u

    ydx u

    xdy = 0 .

    3. f = u+ iv C \ {0}, f (1) = 2 + 2i,

    u (x, y) =x(x2 + y2 + 1

    )x2 + y2

    .

  • 24 1.

    f z = x+ iy.

    .

    u (x, y) = x+x

    x2 + y2

    pi C \ {0} pi Laplace

    uxx + uyy = 2xx2 3y2

    (x2 + y2)3+ 2x

    3y2 x2(x2 + y2)3

    = 0 ,

    u C \ {0}. v u, pi CauchyRiemann ux = vy

    vy = 1 +y2 x2

    (x2 + y2)2= 1 1

    x2 + y2+

    2y2

    (x2 + y2)2.

    pi y

    v (x, y) = y yx2 + y2

    + c (x) .

    pi CauchyRiemann uy = vx pipi

    2xy(x2 + y2)2

    = 2xy(x2 + y2)2

    c (x) c (x) = 0 c (x) = c .

    v (x, y) = y yx2 + y2

    + c , c R .

    pi,

    f (z) = u (z, 0) + iv (z, 0) = z +1

    z+ ic , c R .

    f (1) = 2 + 2i, pi c = 2. ,

    f (z) = z +1

    z+ 2i .

    4. , w = tan z,

    D = {z C : pi/4

  • 1.2. 200910 25

    y = 0, pi/4 x 0. , w = tan (x+ iy) = tanx.pi u = tanx [pi/4, 0], y = 0, pi/4 x 0 z-pipi pi v = 0,1 u 0 w-pipi.

    x = 0, y 0. ,

    w = tan (iy) = i tanh y , (tanh y) = 1/ cosh2 y > 0.

    pi t = tanh y

    limy tanh y = limy

    ey eyey + ey

    = limy

    1 e2y1 + e2y

    = 1 ,

    x = 0, y 0 z-pipi pi u = 0,0 v 1 w-pipi.

    x = pi/4, y 0. ,

    w = u (x, y) + iu (x, y) = tan (pi/4 + iy)

    =tan (pi/4) + tan (iy)

    1 tan (pi/4) tan (iy)=1 + i tanh y1 + i tanh y

    =(1 + i tanh y) (1 i tanh y)

    1 + tanh2 y

    =1 + tanh2 y1 + tanh2 y

    + i2 tanh y

    1 + tanh2 y.

    pi,

    u2 (x, y) + v2 (x, y) =

    (1 + tanh2 y)2(1 + tanh2 y

    )2 + 4 tanh2 y(1 + tanh2 y

    )2 =(1 + tanh2 y

    )2(1 + tanh2 y

    )2 = 1 .pi, pi y 0

    1 u(x, y) = 1 2 11 + tanh2 y

    < 0 limyu(x, y) = 0

    0 v(x, y) = 2 tanh y1 + tanh2 y

    1 .

    , x = pi/4, y 0 z-pipi pi pi 2 w-pipi.

  • 26 1.

    , z = pi/6 + i ln 2 D pi w = tan (pi/6 + i ln 2) =(43 + 15i) /21., D z-pipi pi w = tan z

    D ={w = u+ iv C : u2 + v2 1 , 1 u 0, 0 v 1} .

    5. f pi

    C (0, 1) a C. pi

    I =1

    2pii

    C+(0, 1)

    f (z)

    z a dz ,

    (i) |a| < 1 (ii) |a| > 1.pi. pi C+ (0, 1) -

    z () = ei , [0, 2pi] .

  • 1.2. 200910 27

    .

    I =1

    2pii

    2pi0

    f (ei)

    ei a iei d

    =1

    2pii

    2pi0

    (f (ei)

    ei a (iei)

    )d

    =1

    2pii

    2pi0

    f (ei)

    ei a iei d

    =1

    2pii

    2pi0

    f (ei)

    ei ae2i iei d

    =1

    2pii

    C+(0, 1)

    f (z)

    z az2 dz

    =1

    2pii

    C+(0, 1)

    f (z)

    zdz 1

    2pii

    C+(0, 1)

    f (z)

    z 1/a dz

    pi, pi pi Cauchy pi Cauchy

    I =1

    2pii

    C+(0, 1)

    f (z)

    z a dz =

    f (0) |a| < 1,

    f (0) f (1/a) |a| > 1 .

    6. f pi

    C (0, 1). |f (z) z| < 1 , pi f (1/2) 8 .

    . 1 pi. pi pi Cauchy pi

    f (1/2) =1

    2pii

    C+(0, 1)

    f (z)

    (z 1/2)2 dz ,

    pi C+ (0, 1) . |z| = 1, z C (0, 1)

    |z 1/2| |z| 1/2 = 1 1/2 = 1/2

    |f (z)| = |(f (z) z) + z| |f (z) z|+ |z| < 1 + 1 = 2 .

  • 28 1.

    pi,

    f (1/2) = 12pi

    C+(0, 1)

    f (z)

    (z 1/2)2 dz

    12pi

    C+(0, 1)

    |f (z)||z 1/2|2 |dz|

    12pi

    C+(0, 1)

    2

    (1/2)2|dz|

    =8

    2pi

    C+(0, 1)

    |dz|

    =8

    2pi2pi = 8 .

    2 pi. pi Cauchy

    f (1/2) M1/2

    = 2M ,

    piM = max {|f (z)| : z C (1/2, 1/2)}. pi z C (0, 1) |f (z)| < 2 C (1/2, 1/2) C (0, 1), pi pi

    M < 2. , f (1/2) < 4 .

    7.

    f (z) =

    n=0

    anzn =

    n=0

    f (n) (0)

    n!zn , z C .

    pi R > 0

    n=0

    |an|Rn 2M (2R) , pi M (r) = max {|f (z)| : |z| = r}.

    . pi Cauchy

    |an| =f (n) (0)

    n! M (2R)

    (2R)n.

    pi,n=0

    |an|Rn n=0

    M (2R)

    (2R)nRn = M (2R)

    n=0

    1

    2n= 2M (2R) .

  • 1.2. 200910 29

    8. (pi ). f (z) = eizez2/2, R,pi pi pipi,

    pi

    eixex2/2 dx =

    2pie

    2/2 pi

    ex2/2 cosx dx =

    2pie

    2/2 .

    2

    1. pi f : C C =f (z) 0, z C. pi f .

    pi. g (z) = eif(z).

    . pi =f (z) 0, z C,

    |g (z)| =eif(z) = ei(

  • 30 1.

    z D (0, 1). ,

    (f(z) 1) (f(z) 1) = 0 , D (0, 1).

    , pi pi ( ) pi f(z) 1 0 f(z)1 0 D (0, 1). pi f(z) 1 0 D (0, 1) f(z) 1 0 D (0, 1), f(z) 1 D (0, 1).

    . f, g : G C pi G C

    f(z)g(z) = 0 , z G,

    f 0 g 0 G.

    pi.

    g (z0) 6= 0 pi z0 G. , pi g pi piD (z0, r) G g (z) 6= 0 z D (z0, r). pi pi pi f (z) = 0 z D (z0, r) pi f (n) (z) = 0 z D (z0, r) n N.

    A ={z G : f (n) (z) = 0 , n N

    }.

    A 6= . zk A limk zk = z, pi f (n)

    f (n) (z) = limk

    f (n) (zk) = 0 .

    z A pi A . pi A . , a A. pi G , pi pi D (a, R) G. ,

    f (z) =n=0

    f (n) (a)

    n!(z a)n = 0 , z D (a, R).

    pi, f (n)(z) = 0 z D (a, R) n N. D (a, R) A pi A . pi pi G

    G = A (G \A), pi A(A 6= ) G \A , pi G = A., f 0 G.

  • 1.2. 200910 31

    3.

    f(z) =1

    z4 + 13z2 + 36.

    pi Laurent f z0 = 0 pi pi

    2 + i. pi pi Laurent

    f ;

    . 2i, 3i f .

    f (z) =1

    (z2 + 4) (z2 + 9)=

    1

    5

    [1

    z2 + 4 1z2 + 9

    ].

    , 1/ (1 + w) =

    n=0 (1)nwn, |w| < 1 ( ). = {z C : 2 < |z| < 3}, 2 + i pi Laurent f

    f (z) =1

    5

    [1

    z2 + 4 1z2 + 9

    ]=

    1

    5

    [1

    z21

    1 + 4/z2 1

    9

    1

    1 + z2/9

    ]=

    1

    5

    [1

    z2

    n=0

    (1)n(

    4

    z2

    )n 1

    9

    n=0

    (1)n(z2

    9

    )n]

    =1

    5

    [ n=0

    (1)n 4n

    z2n+2n=0

    (1)n z2n

    9n+1

    ].

    4. f (z) =

    n= an (z z0)n pi Laurent () f = {z C : 0 < |z z0| < R} z0 C. z

    |f (z)| C |z z0|p , 0 < p < 1 ,

    pi Laurent pi z0 pi()

    f .

    . pi Laurent an pi pi

    an =1

    2pii

    C+(z0, r)

    f (z)

    (z z0)n+1dz ,

    pi C+ (z0, r) z0 r, 0 < r < R. pi

  • 32 1.

    |an| = 12pi

    C+(z0, r)

    f (z)

    (z z0)n+1dz

    1

    2pi

    C+(z0, r)

    |f (z)||z z0|n+1

    |dz|

    C2pirn+1+p

    C+(0, r)

    |dz| (|f (z)| C |z z0|p)

    =C

    2pirn+1+p2pir =

    C

    rn+p.

    pi p (0, 1), n 1 n 1

    |an| Crnp r0+

    0 .

    pi an = 0 n = 1,2,3, . . . . , z0 pi() f .

    5. () ez1/z =

    n= cnzn pi Laurent f (z) = ez1/z

    z0 = 0 = {z C : 0 < |z|

  • 1.2. 200910 33

    pi Laurent f(z) = eze1/z z0 = 0 : 0 b > 0, pi pi pi0

    sin2

    a+ b cos d =

    pi

    b2

    (a

    a2 b2

    ).

    . pi0

    sin2

    a+ b cos d =

    1

    2

    2pi0

    sin2

    a+ b cos d =

    1

    4

    2pi0

    1 cos 2a+ b cos

    d = 0}

    = {w C : 0 < =w < pi} .

    [1 + t (1 + i) , i], 0 < t < 1, 2 1 + t (1 + i) pi i. pi

    (Log (Log z)) =1

    z Log z, z A,

    pi [1+t(1+i), i]

    1

    z Log zdz = Log (Log i) Log (Log (1 + t (1 + i)))

    = Log(ipi

    2

    ) Log (Log (1 + t (1 + i)))

    = lnpi

    2+ i

    pi

    2 Log (Log (1 + t (1 + i))) .

    ,

    1

    z Log zdz = ln

    pi

    2+ i

    pi

    2 limt0+

    Log (Log (1 + t (1 + i)))

    = lnpi

    2+ i

    pi

    2 Log (ipi)

    = lnpi

    2+ i

    pi

    2(

    lnpi + ipi

    2

    )= ln 2 .

    6. f : G C pi pi G, f(z) 6= 0 z G. pi pi h G

    f (z) = eh(z) .

  • 42 1.

    . h f G.

    pi. , z0 G

    F (z) :=

    zz0

    f (z)f (z)

    dz , z G ,

    F (z) = f (z) /f (z). H (z) := eF (z)/f (z).

    pi.

    H (z) :=eF (z)

    f (z),

    pi F G, F (z) = f (z) /f (z). H

    G,

    H (z) = F (z)eF (z)

    f (z) eF (z) f

    (z)f2 (z)

    = 0 , z G.

    pi, pi pi H pi

    pi G. H(z) = C, C 6= 0. pi pi C C \ {0}, pi c C ec = C. ,

    eF (z)

    f(z)= C = ec f(z) = eF (z)c .

    h(z) := F (z) c, h G

    f(z) = eh(z) .

    7. f, g : C C

    f2(z) + g2(z) = 1 , z C.

    pi pi h

    f(z) = cos(h(z)) g(z) = sin(h(z)) .

    pi. pi .

  • 1.3. 20089 43

    pi. pi pi, z C

    [f(z) + ig(z)] [f(z) ig(z)] = 1 .

    pi f + ig C, pi pi

    pi h C

    f(z) + ig(z) = eih(z) .

    pi

    f(z) ig(z) = 1f(z) + ig(z)

    = eih(z) .

    ,

    f(z) =eih(z) + eih(z)

    2= cos(h(z)) g(z) = e

    ih(z) eih(z)2i

    = sin(h(z)) .

    8. pi

    I =1

    2pii

    C+

    z + 1

    z2(z 2) dz ,

    pi C+ pi pi 0 2.

    pipi.

    .

    () C+ pi 0 2: pi Cauchy I = 0.

    () C+ pi 0: pi pi Cauchy

    pi

    I =1!

    2pii

    C+

    (z + 1) / (z 2)z2

    dz =

    (z + 1

    z 2)

    z=0

    =3

    (z 2)2z=0

    = 34.

    () C+ pi 2: pi pi Cauchy -

    I =1

    2pii

    C+

    (z + 1) /z2

    z 2 dz =z + 1

    z2

    z=2

    =3

    4.

  • 44 1.

    () C+ pi 0 2: C+1 C+2 pi -

    C+, C+1 pi

    0 C+2 pi 2. pi

    Cauchy

    I =1

    2pii

    C+

    z + 1

    z2 (z 2) dz =1

    2pii

    C+1

    z + 1

    z2 (z 2) dz +1

    2pii

    C+2

    z + 1

    z2 (z 2) dz

    = 34

    +3

    4= 0 . (pipi () ())

    2

    1. () f D(0, R) = {z C : |z| R} M > 0. |f(z)| > M |z| = R |f(0)| < M , pi f D(0, R) = {z C : |z| < R}.

    () pi () pi :

    pi

    p(z) = anzn + an1zn1 + + a1z + a0 , a0, a1, . . . , an1, an C , an 6= 0

    n C.

    pi. pi p C. lim|z| |p(z)| =.

    .

    () pi f D (0, R), pi -

    pi ( f ). pi f

    D (0, R).

  • 1.3. 20089 45

    () M > |a0|. pi lim|z| |p(z)| =, pi C (0, R) = {z C : |z| = R} |p(z)| > M z C (0, R), |z| = R. pi|p(0)| = |a0| < M , pi () pi p D (0, R) = {z C : |z| < R}.

    2.

    f (z) =z2 + 2z + 2 + 2i

    (z + 1) (z2 + 2i).

    pi Laurent f z0 = 0 pi pi

    3/2. pi pi Laurent f

    ;

    . 1, 2e3ipi/4 2e7ipi/4 f .

    f (z) =1

    z + 1+

    2

    z2 + 2i.

    , 1/ (1 w) = n=0wn 1/ (1 + w) = n=0 (1)nwn, |w| < 1 ().

    ={z C : |z| > 2}, 3/2 pi Laurent f

    f (z) =1

    z + 1+

    2

    z2 + 2i

    =1

    z

    1

    1 + 1/z+

    1

    z22

    1 + 2i/z2

    =1

    z

    n=0

    (1)n(

    1

    z

    )n+

    2

    z2

    n=0

    (1)n(

    2i

    z2

    )n=n=0

    (1)n 1zn+1

    +n=0

    (1)n 2 (2i)n

    z2n+2.

    3. pi pi, , pi

    z0 = 0 . n Z, pi Laurent pi

    1

    2pii

    wn sin (1/w) dw =

    (1)k(2k+1)! n = 2k, k = 0, 1, 2, . . . ,

    0 .

  • 46 1.

    . pi z C

    sin z =k=0

    (1)k z2k+1

    (2k + 1)!,

    w sin (1/w) =

    k=0

    (1)k w2k

    (2k + 1)!, 0 < |w|

  • 1.3. 20089 47

    pi Laurent f (z) = e1/ze2z z0 = 0 : 0 0, , pi pi

    Cauchy C+(0, 1)

    eaz

    zdz =

    C+(0, 1)

    eaz

    z 0 dz = 2pii eaz|z=0 = 2pii .

    |z| = 1 z() = ei, pi pi pi

    2pii =

    C+(0, 1)

    eaz

    zdz =

    pipi

    eaei

    eiiei d

    = i

    pipiea cos +ia sin d

    = i

    pipiea cos [cos (a sin ) + i sin (a sin )] d

    = pipiea cos sin (a sin ) d + i

    pipiea cos cos (a sin ) d .

    , pipiea cos cos (a sin ) d = 2pi

    pi0ea cos cos (a sin ) d = pi .

    5. pi, pi C . pi-

    f pi z1, z2, . . . , zn .

    Q (z) = (z z1) (z z2) (z zn) ,

    pi

    P (z) :=1

    2pii

    f (w)

    Q (w)

    Q (w)Q (z)w z dw

    pi n 1 pi f z1, z2, . . . , zn, P (zk) = f(zk), k = 1, 2, . . . , n.

  • 60 1.

    . pi Q(zk) = 0, k = 1, 2, . . . , n, pi pi Cauchy

    P (zk) =1

    2pii

    f(w)

    w zk dw = f(zk) , k = 1, 2, . . . , n .

    pi P pi n 1. pi Q(w)Q(z) pi n pi z, pi ak(w)

    Q(w)Q(z) = (w z)n1k=0

    ak(w)zk .

    ,

    P (z) =n1k=0

    (1

    2pii

    f(w)

    Q(w)ak(w)

    )zk .

    6. pi p(z) =n

    k=0 akzk, ak C, an 6= 0, 2,

    n 2. pi pi pi, pi , pi

    1

    p(z)dz = 0 .

    pi. pi R > 0,

    |p(z)| 12|an||z|n , |z| R .

    . R pi pi

    |z| = R

    |p (z)| 12|an| |z|n , |z| R .

    ,1

    |p (z)| 2

    |an| |z|n , |z| R .

    pi Cauchy

    1

    p (z)dz =

    |z|=R

    1

    p (z)dz .

  • 1.4. 20078 61

    pi

    1

    p (z)dz

    =|z|=R

    1

    p (z)dz

    |z|=R

    1

    |p (z)| |dz|

    |z|=R

    2

    |an| |z|n |dz|

    =2

    |an|Rn|z|=R

    |dz|

    =2

    |an|Rn 2piR =4pi

    |an|Rn1 R 0 .

    ,

    1

    p (z)dz = 0 .

    7. pi f : C C |f(z)| Aeax z = x+ iy C, pi a,A > 0. pi

    f(z) = ceaz , pi c C .

    pi |f(z)| Aea|z|, z C;

    . g(z) = f(z)/eaz

    |g(z)| = |f(z)||eaz| =|f(z)||eax+iay| =

    |f(z)|eax

    A , z = x+ iy C .

    pi Liouville g , g(z) = c. pi f(z) = ceaz

    pi c C. |f(z)| Aea|z|, z C, pi f(z) = ceaz pi c C. , f(z) = A sin az, a,A > 0, pi f(z) = ceaz, pi c C.

    |f(z)| = Aeiaz eiaz2i

    A2 (e|iaz| + e|iaz|) = Aea|z| .

    8. pi:

  • 62 1.

    () f pi pi D, pi

    F pi D F (z) = f(z), z D.

    () pi f D (0, 2) = {z C : |z| < 2},

    |f(x+ iy)|2 = 4 x2 y2 , z = x+ iy D (0, 2) .

    .

    () pipi pi f pi pi D.

    f , pi, .

    f(z) = z pi pi pi C

    pi pi. pi F pi C F (z) = z,

    w = F (z), w = z pi C, pi.

    () pi f , |f(0)|2 = 4 |f(0)| = 2, D (0, r) = {z C : |z| r}, 0 < r < 2, |z| = r |f(z)|2 = 4 r2 < 4 |f(z)| < 2. pi pi. , pi f D (0, 2).

    9. R pi pi-

    pi pi. pi

    Weierstrass.

    a < b R f : [a, b] R , > 0 pipi

    p(x) =

    nk=0

    akxk (n N , ak R)

    |f(x) p(x)| < , x [a, b] .

    Weierstrass pipi. -

    , f(z) = 1/z C (0, 1) =

    {z C : |z| = 1} pi pi ( ) pi C.

  • 1.4. 20078 63

    = 1 pi pi pi

    p(z) =nk=0

    akzk (n N , ak C)

    1z p(z) < 1 , |z| = 1 ,

    pi pi.

    . pi 1z p(z) < 1 |1 zp(z)| < 1 , |z| = 1 .

    q(z) := zp(z). q pi pi

    C,

    |1 q(z)| < 1 , |z| = 1 .

    pi pipi

    |1 q(z)| < 1 , |z| 1 .

    pi pipi z = 0

    1 = |1 q(0)| < 1 ,

    pi pi.

  • 64 1.

    1.5 200607

    1

    1. pi z1, z2, . . . , zn pi

    p (z) = a (z z1) (z z2) (z zn) ,

    a C, pipi =z > 0.

    () pi x R

    =p (x)p (x)

    ==z1

    |x z1|2+

    =z2|x z2|2

    + + =zn|x zn|2> 0 .

    () pi =p (x)p (x)

    dx .

    .

    () pi

    p(z)p(z)

    =1

    z z1 +1

    z z2 + +1

    z zn =z z1|z z1|2 +

    z z2|z z2|2 + +

    z zn|z zn|2 ,

    x R

    =p(x)p(x)

    = = x z1|x z1|2 + =x z2|x z2|2 + + =

    x zn|x zn|2

    ==z1

    |x z1|2 +=z2

    |x z2|2 + +=zn

    |x zn|2 > 0 .

    () zk = xk + iyk, k = 1, 2, . . . , n, yk > 0

    =zk|x zk|2 dx =

    yk(x xk)2 + y2k

    dx

    = limR+r

    Rr

    yk(x xk)2 + y2k

    dx

    = limR+r

    arctan

    (x xkyk

    )x=Rx=r

    = limR+

    arctan

    (R xkyk

    ) limr arctan

    (r xkyk

    )=pi

    2(pi

    2

    )= pi .

  • 1.5. 200607 65

    pi, =p(x)p(x)

    dx =

    =z1|x z1|2 dx+

    =z2|x z2|2 dx+ +

    =zn|x zn|2 dx

    = pin .

    2. f : C C,

    f(z) =

    e1/z4 z 6= 0,

    0 z = 0 .

    pi pi CauchyRiemann (0, 0)

    pi pi f (0).

    .

    limx0+

    f (x, 0) f (0, 0)x 0 = limx0+

    e1/x4

    x

    = limt

    t1/4

    et( t = x4)

    =1

    4limt

    t3/4

    et(LHpital)

    = 0

    pi

    limx0

    f (x, 0) f (0, 0)x 0 = limx0

    e1/x4

    x= 0 .

    pi fx (0, 0) = 0. pi pi

    fy (0, 0) = limy0

    f (0, y) f (0, 0)y 0 = 0 .

    fx (0, 0) = ify (0, 0) = 0, pi CauchyRiemann (0, 0).

    pi f pi 0.

    f (0 + h) f (0)h

    =f (h)

    h=

    e1/h4/h h R,

    e1/4x4/ (1 + i)x h = x+ ix, x R .

  • 66 1.

    pi,

    limh0hR

    f(0 + h) f(0)h

    = limh0

    e1/h4

    h= 0 lim

    h0h=x+ix

    f(0 + h) f(0)h

    =1

    1 + ilimx0

    e1/4x4

    x= .

    , pi f (0) pi.

    . f pi 0 pipi pi f

    0. ,

    limr0+

    f(reipi/4

    )= lim

    r0+e1/r

    4=

    3. f : A C R, pi A . f pipi . f pi z0 A, pi f (z0) = 0.

    pi.

    limh0

    f (z0 + h) f (z0)h

    = f (z0) .

    pi,

    limh0hR

    f (z0 + h) f (z0)h

    = f (z0)

    pi pi pi pipi pi f (z0)

    pi . h = ik, k R, pi

    limk0

    f (z0 + ik) f (z0)ik

    = f (z0) .

    pi if (z0) R. pipi f (z0) R if (z0) R pi f (z0) = 0.

    4. f : G C C pi G. pi pi L C f (z) L, z G. pi f pi G.

    pi. L C

    L = {z C : z = z0 + tw, t R}

    z0 C w C, w 6= 0.

  • 1.5. 200607 67

    pi. f (z) L,

    f (z) z0w

    R , z G .

    (f(z) z0) /w piG pi pi .pi pi (pi pi pi f (z) = 0,

    z G), f pi G.

    5. pi

    f(z) = f(x+ iy) = e2xy[cos(y2 x2)+ i sin (y2 x2)]

    C pi pi f (z).

    . f = u+ iv u(x, y) = e2xy cos(y2x2) v(x, y) = e2xy sin(y2x2). u, v pi R2 pi CauchyRiemann.

    , ux = vy = 2e

    2xy[y cos(y2 x2) + x sin(y2 x2)]

    uy = vx = 2e2xy[x cos(y2 x2) y sin(y2 x2)]

    .pi f C. pi pi f (z):

    1 pi.

    f (z) = fx (x, y) = ux (x, y) + ivx (x, y)

    = 2e2xy[(y cos

    (y2 x2)+ x sin (y2 x2))

    +i(y sin

    (y2 x2) x cos (y2 x2))] .

    2 pi. pi u, v ,

    f(z) = u(z, 0) + iv(z, 0) = cos z2 i sin z2 = eiz2 .

    ,

    f (z) = 2izeiz2 .

  • 68 1.

    6. pi u(x, y) = x3 + 6x2y 3xy2 2y3 R2. v u f(z) = u(x, y) +

    iv(x, y).

    . pi uxx + uyy = 0, u R2. pi

    CauchyRiemann vy = ux

    vy = 3x2 + 12xy 3y2 , pi v(x, y) = 3x2y + 6xy2 y3 + c(x) .

    pi CauchyRiemann uy = vx pipi

    6x2 6xy 6y2 = 6xy 6y2 c(x) c(x) = 6x2 .pi c(x) = 2x3 + c .

    v(x, y) = 3x2y + 6xy2 y3 2x3 + c

    f(z) = u(z, 0) + iv(z, 0) = z3 + i(2z3 + c) = (1 2i)z3 + ic ,

    c R.

    7. pi : R R pi. u (x, y) = (xy) R2, u.

    v u pi f (z) = u (x, y) + iv (x, y).

    . t = xy, ux = y (t), uxx = y2 (t) pi uyy = x2 (t). pi

    u R2,

    uxx + uyy =(x2 + y2

    ) (t) = 0 (t) = 0 , t R .

    pi (t) = at+b, pi u (x, y) = axy+b, a, b R. pi CauchyRiemannvy = ux

    vy = ay , pi v (x, y) =a

    2y2 + c (x) .

    pi CauchyRiemann uy = vx pipi

    ax = c (x) c (x) = ax .pi , c (x) = a2x2 + c .

    , v (x, y) = a(y2 x2) /2 + c, c R

    f (z) = u (z, 0) + iv (z, 0) = b+ i(a

    2z2 + c

    )= ai

    2z2 + b+ ic ,

    c R.

  • 1.5. 200607 69

    8. , f (z) = ez,

    D = {z = x+ iy : 1 x 2, 0 y pi} .

    . x = 1, 0 y pi, pi w = eeiy,0 y pi, pipi e. , x = 2,0 y pi, pi w = e2eiy, 0 y pi, pipi e2. [1, 2] w = exei0 = ex, 1 x 2,

    [e, e2

    ], [1 + ipi, 2 + ipi] pi

    w = exeipi = ex, 1 x 2, pi [e2,e]. , D pi D .

    9. pi

    | sin z| coshR | cos z| coshR ,

    z D(0, R) = {z C : |z| R}.

    . |z| = |x+ iy| R, |y| R pi

    | sin z| =eiz eiz2i

    12 (eiz+ eiz) = 12 (eixy+ eix+y)=ey + ey

    2= cosh y coshR .

  • 70 1.

    ,

    | cos z| =eiz + eiz2

    12 (eiz+ eiz) = 12 (eixy+ eix+y)=ey + ey

    2= cosh y coshR .

    10. w = log z pi D = C \ {iy : y 0}, log i = 5pii/2. h (z) = z = e log z, C, pi pi h3/2 (1).

    . log z = ln |z|+ i (z) + 2kpii, k Z, pi (z) (pi/2, 3pi/2).

    pi

    log i = ln |i|+ i (i) + 2kpii = ln 1 + ipi2

    + 2kpii =pii

    2+ 2kpii

    log i = 5pii/2, pi k = 1. ,

    log z = ln |z|+ i [ (z) + 2pi] .

  • 1.5. 200607 71

    log (1) = 3pii

    h (z) = e log z

    z= e log z

    elog z= e(1) log z = z1 = h1 (z) .

    pi,

    h3/2 (1) =3

    2h1/2 (1) =

    3

    2elog(1)/2 =

    3

    2e3pii/2 = 3i

    2.

    2

    1. () pi ez=z dz

    (2 +2) e .pi 0, 1 1 + i.

    () C, z() = Rei, 0 pi/4, 0 R > 0. pi

    Ceiz

    2dz

    pi4R (1 eR2) .pi. sin 2/pi, [0, pi/2].

    .

    () z = x+ iy , 0 x, y 1 piez=z = e(xiy)y = exy e , z .

    pi 2 +

    2, ez=z dz

    e |dz| = e ( ) = (2 +

    2)e .

  • 72 1.

    () z() = Rei, 0 pi/4, eiz()2 = eiR2(cos 2+i sin 2)= eR

    2 sin 2 eR24/pi . (pi sin 2 4/pi)

    pi, Ceiz

    2dz

    C

    eiz2 |dz|=

    pi/40

    eiz()2 z () d pi/40

    eR24/piRd

    = pi4R

    eR24/pi

    =pi/4=0

    =pi

    4R

    (1 eR2

    ).

    2. pi

    1

    zdz =

    1

    2ln 5 + i arctan

    (1

    2

    ),

    pi : [0, 1] C pi pipi (t) = 1 + t+ i sin (52pit).. 1 pi. pi pi pi C \ (, 0] pi

    Log z = ln |z|+ iArg z , pi Arg z < pi ,

  • 1.5. 200607 73

    pi 1/z, (Log z) = 1/z. pi -

    1

    zdz = Log (1) Log (0)

    = Log(2 + i) Log(1)= Log(2 + i)

    =1

    2ln 5 + i arctan

    (1

    2

    ).

    2 pi. pi pi C\(, 0] f(z) = 1/z . pi pi

    pi pi [1, 2] pi

    [2, 2 + i], z(y) = 2 + iy, 0 y 1. pi,

    1

    zdz =

    [1,2]

    1

    zdz +

    [2,2+i]

    1

    zdz

    =

    21

    1

    xdx+ i

    10

    1

    2 + iydy

    = ln 2 + i

    10

    2 iy22 + y2

    dy

    = ln 2 + i

    10

    2

    4 + y2dy +

    10

    y

    4 + y2dy

    = ln 2 + i arctan(y

    2

    )y=1y=0

    +1

    2ln(4 + y2

    )y=1y=0

    = ln 2 + i arctan

    (1

    2

    )+

    1

    2ln 5 1

    2ln 4

    =1

    2ln 5 + i arctan

    (1

    2

    ).

    3. pi Cauchy,

    pi Cauchy, pi

    1

    2pii

    C+(0, 2)

    cos z

    z(z 1)2 dz = 1 sin 1 cos 1 ,

    pi C+ (0, 2) 0, 2 .

  • 74 1.

    . C1 C2 pi

    C (0, 2), C1 pi 0 C2 pi

    1.

    pi Cauchy

    1

    2pii

    C+(0, 2)

    cos z

    z(z 1)2 dz =1

    2pii

    C+1

    cos z

    z(z 1)2 dz +1

    2pii

    C+2

    cos z

    z(z 1)2 dz .

    , pi pi Cauchy

    1

    2pii

    C+1

    cos z

    z(z 1)2 dz =1

    2pii

    C+1

    cos z/(z 1)2z

    dz =cos z

    (z 1)2z=0

    = 1

    pi pi Cauchy pi

    1

    2pii

    C+2

    cos z

    z(z 1)2 dz =1

    2pii

    C+2

    cos z/z

    (z 1)2 dz

    =(cos z

    z

    )z=1

    =z sin z cos z

    z2

    z=1

    = sin 1 cos 1 .

    ,1

    2pii

    C+(0, 2)

    cos z

    z(z 1)2 dz = 1 sin 1 cos 1 .

    4. D pi pipi, pi D pi

    pi pipi pi pi, pi, pi

  • 1.5. 200607 75

    pi. f : D C,f(z) = u(x, y) + iv(x, y), pi ( f

    pi ), pi Green pipi-

    - pi pi

    Green

    D

    f

    zdxdy = 1

    2i

    D

    f dz , (1.2)

    D

    f

    zdxdy =

    1

    2i

    D

    f dz . (1.3)

    pi

    f

    z=

    1

    2

    (f

    x if

    y

    )=

    1

    2

    [u

    x+v

    y+ i

    (v

    x uy

    )]

    f

    z=

    1

    2

    (f

    x+ i

    f

    y

    )=

    1

    2

    [u

    x vy

    + i

    (v

    x+u

    y

    )].

    .

    12i

    D

    f dz = 12i

    D

    (u+ iv) (dx idy)

    =1

    2

    D

    (vdx+ udy) + i2

    D

    udx+ vdy

    =1

    2

    D

    (u

    x+v

    y

    )dxdy +

    i

    2

    D

    (v

    x uy

    )dxdy

    (pi Green)

    =

    D

    1

    2

    [u

    x+v

    y+ i

    (v

    x uy

    )]dxdy

    =

    D

    f

    zdxdy .

    pi (1.3) pi.

    5. pi (1.2) (1.3) Green,

    pi, pi

    |z|1cos z dxdy = pi .

  • 76 1.

    . pi pi (1.2)

    |z|1cos z dxdy =

    |z|1

    z(sin z) dxdy

    = 12i

    |z|=1

    sin z dz (pi (1.2))

    = 12i

    |z|=1

    sin z d

    (1

    z

    )(pi |z| = 1 zz = 1 z = 1z )

    =1

    2i

    |z|=1

    sin z

    z2dz

    = pi

    (1

    2pii

    |z|=1

    sin z

    z2dz

    )= pi (sin z)

    z=0

    ( pi Cauchy pi)

    = pi cos 0 = pi .

    pi pi (1.3),

    |z|1cos z dxdy =

    |z|1

    z(z cos z) dxdy =

    1

    2i

    |z|=1

    z cos z dz

    =1

    2i

    |z|=1

    cos z

    zdz

    (pi |z| = 1 zz = 1 z = 1z )

    = pi

    (1

    2pii

    |z|=1

    cos z

    zdz

    )= pi cos 0 = pi . ( pi Cauchy)

    6. pi f : C C pi 2pi0

    f (rei) d r5/2 , r > 0 . pi f (n)(0) = 0, n = 0, 1, 2, . . . . pi f ;

    . z() = rei, 0 2pi, |z| = r 0 r . pi pi Cauchy pi

    f (n)(0) =n!

    2pii

    |z|=r

    f(z)

    zn+1dz =

    n!

    2pii

    2pi0

    f(rei

    )rn+1ei(n+1)

    irei d =n!

    2pirn

    2pi0

    f(rei

    )ein

    d

  • 1.5. 200607 77

    pi, r > 0 pi pi f (n) (0)n!

    =1

    2pirn

    2pi0

    f(rei

    )ein

    d

    12pirn 2pi0

    f (rei) d 12pir5/2n . (1.4)

    n 3, n 5/2 3 5/2 = 1/2 > 0 pi (1.4) f (n) (0)n!

    12pir5/2n =

    1

    2pi 1rn5/2

    r 0 , f

    (n) (0) = 0 .

    n 2, 5/2 n 5/2 2 = 1/2 > 0 pi (1.4) f (n) (0)n!

    12pir5/2n

    r0+0 , f (n) (0) = 0 .

    , f (n) (0) = 0, n = 0, 1, 2, . . . . pi

    f (z) =n=0

    f (n) (0)

    nzn = 0 , z C ,

    pi f 0.

    7. a R (pi pi a > 0). w = ez2 pi R, R, R+ia R+ia, R > 0, pi

    limR

    RR

    e(x+ia)2dx =

    ex2dx =

    pi .

    . pi e(x+ia)2 = ea2 ex2

    limR

    RR

    ex2dx =

    pi ,

    pi

    limR

    RR

    e(x+ia)2dx pi .

    w = ez2 C. pi pi

    = 1 2 3 4, pi Cauchy 1

    ez2dz +

    2

    ez2dz +

    3

    ez2dz +

    4

    ez2dz = 0 .

  • 78 1.

    1, 2, 3 4 z (x) = x, 1 x 1, z (y) = R+ iy,0 y a, z (x) = x+ ia, R x R z (y) = R+ iy, 0 y a. pi, R

    Rex

    2dx+

    a0e(R+iy)

    2idy

    RR

    e(x+ia)2dx

    a0e(R+iy)

    2idy = 0

    pi pi RR

    ex2dx+ ieR

    2

    a0ey

    22Ryi dy RR

    e(x+ia)2dx ieR2

    a0ey

    2+2Ryi dy = 0 . (1.5)

    pi ieR2 a0ey

    22Ryi dy eR2 a

    0

    ey22Ryi dy = eR2 a0ey

    2dy

    R0 ,

    limR

    ieR2

    a0ey

    22Ryi dy = 0 .

    , pi (1.5), pi R, pipi

    limR

    RR

    e(x+ia)2dx =

    ex2dx =

    pi .

    8. pi f : C C |f (z)| |z|, z C. pi pi ( Liouville), f pi pi 1 pi f pi pi 2. pi

    f(z) = a+ bz2 , a, b C , |b| 1/2 .

  • 1.5. 200607 79

    . pi |f (z)| |z|, z C, pi f (0) = 0. pi,

    f(z) = f(0) + f (0)z +f (0)

    2!z2 = a+ bz2 , a, b C .

    , pi pi Cauchy f (0) = 12pii|z|=1

    f (z)z2

    dz

    12pi|z|=1

    |f (z)||z|2 |dz|

    12pi

    |z|=1

    |z||z|2 |dz| (pi |f

    (z) | |z|, z C)

    =1

    2pi

    |z|=1

    |dz|

    =1

    2pi2pi = 1 .

    ,

    |b| = |f (0)|2

    12.

    3

    1.

    |sin z| = |sin (x+ iy)| = (sin2 x+ sinh2 y)1/2 S = [0, 2pi] [0, 2pi].. f (z) = sin z , C. pi

    |f (z)| = |sin z| pi S.

  • 80 1.

    pipi :

    (i) 0 x 2pi, y = 0. |sin z| = |sinx| |sin (pi/2)| =|sin (3pi/2)| = 1.

    (ii) 0 y 2pi, x = 2pi. |sin z| = sinh y u = sinh y . pi, sinh 2pi.

    (iii) 0 x 2pi, y = 2pi. |sin z| = (sin2 x+ sinh2 2pi)1/2 sin(pi2

    + 2pii) = sin(3pi2 + 2pii

    ) = (1 + sinh2 2pi)1/2 = cosh 2pi .(iv) 0 y 2pi, x = 0. |sin z| = sinh y. pi, pi pipi,

    sinh 2pi.

    , |sin z| sin(pi2

    + 2pii) = sin(3pi2 + 2pii

    ) = cosh 2pi .

    2.

    f (z) =z2 3z

    (z 1)2 (z + 1) =1

    z + 1 1

    (z 1)2 .

    pi Laurent f z0 = 1 .

    . , pi 11w =

    n=0wn, |w| < 1,

    1

    (1 w)2 =n=1

    nwn1 =n=0

    (n+ 1)wn , |w| < 1 .

    i. 0 < |z + 1| < 2:

    f (z) =1

    z + 1 1

    [(z + 1) 2]2 =1

    z + 1 1

    4[1 z+12

    ]2=

    1

    z + 1 1

    4

    n=0

    (n+ 1)

    (z + 1

    2

    )n=

    1

    z + 1n=0

    n+ 1

    2n+2(z + 1)n .

  • 1.5. 200607 81

    ii. |z + 1| > 2:

    f (z) =1

    z + 1 1

    [(z + 1) 2]2

    =1

    z + 1 1

    (z + 1)2[1 2z+1

    ]2=

    1

    z + 1 1

    (z + 1)2

    n=0

    (n+ 1)

    (2

    z + 1

    )n=

    1

    z + 1n=0

    2n (n+ 1)1

    (z + 1)n+2.

    3. 1sin z =

    n= anzn pi Laurent f(z) = 1sin z

    = {z C : pi < |z| < 2pi} z0 = 0. pi an, n < 0.

    . pi Laurent an pi pi

    an =1

    2pii

    C+(0, r)

    1

    zn+1 sin zdz ,

    pi C+ (0, r) 0, r, pi < r < 2pi

    .

    (i) n = 1: pipi pi, 0 pi f(z) = 1sin z C+ (0, r) pi pi. pi

  • 82 1.

    pipi

    a1 =1

    2pii

    C+(0, r)

    1

    sin zdz = Res

    (1

    sin z, pi

    )+ Res

    (1

    sin z, 0

    )+ Res

    (1

    sin z, pi

    )=

    1

    (sin z)

    z=pi

    +1

    (sin z)

    z=0

    +1

    (sin z)

    z=pi

    =1

    cos (pi) +1

    cos 0+

    1

    cospi= 1 .

    (ii) n 2: pipi

    g(z) =1

    zn+1 sin z=z(n+1)

    sin z, (n+ 1) 1

    pi pi pi g C+ (0, r) pi pi. pi 0

    pi g(z) = z(n+1)sin z , 0 pi . , pi

    pipi

    an =1

    2pii

    C+(0, r)

    1

    zn+1 sin zdz = Res

    (z(n+1)

    sin z, pi

    )+ Res

    (z(n+1)

    sin z, pi

    )

    =z(n+1)

    (sin z)

    z=pi

    +z(n+1)

    (sin z)

    z=pi

    =(pi)(n+1)

    cos (pi) +pi(n+1)

    cospi

    = pi(n+1)[(1)n 1]

    =

    0 n ,

    2pi(n+1) n pi .

    4. pi

    I =1

    2pii

    C+(0, 2)

    [z3 cos

    (z1)

    +sinpiz

    (z 1)2]dz ,

    pi C+ (0, 2) 0, 2 .

    . 0 f(z) = z3 cos(z1)

    C (0, 2). pi

    z3 cos(z1)

    = z3(

    1 z2

    2!+z4

    4! z

    6

    6!+

    )= z3 z

    2!+z1

    4! z

    3

    6!+ ,

  • 1.5. 200607 83

    Res(z3 cos

    (z1), 0)

    = 1/4!. 1 g(z) =

    sinpiz/ (z 1)2 C (0, 2). pi 1 pi pi pi, 1 pi pi

    g. pi, pi pi

    Res

    (sinpiz

    (z 1)2 , 1)

    = 2(sinpiz)((z 1)2

    )z=1

    = 2pi cospiz

    2

    z=1

    = pi .

    , pi pipi

    I = Res(z3 cos

    (z1), 0)

    + Res

    (sinpiz

    (z 1)2 , 1)

    =1

    4! pi = 1

    24 pi .

    . , z0 pi pi g,

    pipi g z0 pi pi

    Res (g, z0) = limzz0

    (z z0) g (z) .

    pi,

    Res

    (sinpiz

    (z 1)2 , 1)

    = limz1

    (z 1) sinpiz(z 1)2 = limz1

    sinpiz

    z 1(LHpital)

    = limz1

    pi cospiz = pi .

    5. a > 0, pi

    pi/20

    a

    a2 + sin2 d =

    1

    2

    2pi0

    a

    2a2 + 1 cos d =pi

    2

    1 + a2.

    .

    pi/20

    a

    a2 + sin2 d =

    pi/20

    2a

    2a2 + 1 cos 2 d

    = a

    pi0

    1

    2a2 + 1 cos d ( = 2)

    =1

    2

    2pi0

    a

    2a2 + 1 cos d .

    ( f () = a/(2a2 + 1 cos) pi pi 2pi)

  • 84 1.

    z = ei, cos = ei + ei

    2=

    1

    2

    (z +

    1

    z

    ) dz = ieid = izd d = dz

    iz. -

    pi,

    pi/20

    a

    a2 + sin2 d =

    1

    2

    2pi0

    a

    2a2 + 1 cos d

    =1

    2

    |z|=1

    a

    2a2 + 1 12(z + 1z

    ) dziz

    = ai

    |z|=1

    1

    z2 2 (1 + 2a2) z + 1 dz .

    pi z1,2 = 1+2a22a

    1 + a2 pi z22 (1 + 2a2) z+1 = 0, 1+2a22a1 + a2 pi pi g(z) = 1

    z22(1+2a2)z+1 .

    1+2a22a1 + a2 |z| = 1, 1+2a2+2a1 + a2 |z| = 1. , pi pipi

    pi/20

    a

    a2 + sin2 d = a

    i

    |z|=1

    1

    z2 2 (1 + 2a2) + 1 dz

    = ai2piiRes

    (1

    z2 2 (1 + 2a2) z + 1 , 1 + 2a2 2a

    1 + a2

    )= 2api 1

    (z2 2 (1 + 2a2) z + 1)z=1+2a22a1+a2

    = 2api 12(

    1 + 2a2 2a1 + a2) 2 (1 + 2a2)

    =pi

    2

    1 + a2.

    6. pi pi

    I =

    cosx

    (x2 + 1)2dx .

    .

    J =

    sinx

    (x2 + 1)2dx , I + iJ =

    eix

    (x2 + 1)2dx .

    I J . i

  • 1.5. 200607 85

    pi 2 f (z) = eiz/(z2 + 1

    )2. i pipi Res

    (eiz

    (z2 + 1)2, i

    )= lim

    zi

    ((z i)2 e

    iz

    (z2 + 1)2

    )= lim

    zi

    (eiz

    (z + i)2

    )= lim

    zi

    (ieiz

    (z + i)2 2e

    iz

    (z + i)3

    )=ie1

    (2i)2 2e

    1

    (2i)3= i

    2e.

    f pi pi pi pi

    pi pipi R, z () = Rei, 0 pi [R,R]. R z = i f R.

    pi pipi RR

    eix

    (x2 + 1)2dx+

    R

    eiz

    (z2 + 1)2dz = 2piiRes

    (eiz

    (z2 + 1)2, i

    )=pi

    e. (1.6)

    , pi Jordan

    limR

    R

    eiz

    (z2 + 1)2dz = 0 .

    pi, pi (1.6) pipi

    eix

    (x2 + 1)2dx = lim

    R

    RR

    eix

    (x2 + 1)2dx =

    pi

    e.

    ,

    I =

    cosx

    (x2 + 1)2dx =

    pi

    e J =

    sinx

    (x2 + 1)2dx = 0 .

  • 86 1.

    7. a C, |a| 6= 1. pi C+(0, 1)

    z6

    az7 1 dz ,

    pi C+ (0, 1) 0, 1 .

    .

    (i) |a| < 1, f (z) = z6/ (az7 1) pi - |z| = 1. pi, pi Cauchy

    C+(0, 1)

    z6

    az7 1 dz = 0 .

    (ii) |a| > 1, C+(0, 1)

    z6

    az7 1 dz

    =2pii

    7a

    {1

    2pii

    C+(0, 1)

    (az7 1)az7 1 dz

    }=

    2pii

    7a { f (z) = az7 1 |z| = 1}

    ( )

    =2pii

    7a 7 = 2pii

    a.

    ,C+(0, 1)

    z6

    az7 1 dz =

    0 |a| < 1 ,2piia |a| > 1 .

    8. pi

    P (z) = 3z9 + 8z6 + z5 + 2z3 + 1

    = {z C : 1 < |z| < 2}.. |z| = 2 P (z) 3z9 = 8z6 + z5 + 2z3 + 1

    8 |z|6 + |z|5 + 2 |z|3 + 1= 561 < 1536 =

    3z9 .

  • 1.5. 200607 87

    pi pi Q1 (z) = 3z9 9 |z| < 2, pi Rouch pi P 9 |z| < 2. |z| = 1

    P (z) 8z6 = 3z9 + z5 + 2z3 + 1 3 |z|9 + |z|5 + 2 |z|3 + 1= 7 < 8 =

    8z6 .pi pi Q2 (z) = 8z6 6 |z| < 1, pi Rouch pi P 6 |z| < 1. , pi P 9 6 = 3 = {z C : 1 < |z| < 2}.

    9. > 1. pi

    zez = 1

    D (0, 1) = {z C : |z| < 1} R.. f (z) = zez 1. |z| = 1, |e0 = 1, pi Bolzano pi (0, 1) g () = 1 e = 1.

    10. f D(0, 1) = {z C : |z| 1}.pi |f(z)| = 1, |z| = 1 f .

    i. pi f D (0, 1) = {z C : |z| < 1}.ii. pi f pi D (0, 1).

    w0 C, |w0| < 1, pi z0 C, |z0| < 1, f (z0) = w0.

  • 88 1.

    pi. pi Rouch.

    pi. i. pi f |f (z)| = 1, |z| = 1, pi D (0, 1) f () D (0, 1). g (z) := f (z) f ().

    |g (z) f (z)| = |f ()| < 1 = |f (z)| , |z| = 1 .

    pi g D (0, 1), pi Rouch

    f D (0, 1).

    ii. |w0| < 1. h (z) = f (z) w0,

    |h (z) f (z)| = |w0| < 1 = |f (z)| , |z| = 1 .

    pi pi () f D (0, 1), pi

    Rouch h D (0, 1). pi z0 C,|z0| < 1, f (z0) = w0.. pi pi, () pipi

    f D (0, 1). , f pi D (0, 1)

    .

  • 2

    2.1 201112

    &

    10 , 2012

    1. () a R pi u(x, y) = ax3y + 4xy3 + x R2. v u

    pi f = u + iv, f(0) = i. f z = x+ iy.

    (1,5 .)

    ()

    ={z C : |=z| pi

    2

    } z-pipi. , pi

    . x = x0 R, pi/2 y pi/2, w = ez. w = ez; (1 .)

    .

    89

  • 90 2.

    () uxx + uyy = 6axy + 24xy. u pipi

    uxx+uyy = 0 6axy+24xy = 0 (x, y) R2. pi a = 4 pi u(x, y) = 4x3y+ 4xy3 +x. , pi piC pi v u. f = u+ iv .

    pi CauchyRiemann ux = vy

    vy = 12x2y + 4y3 + 1 .

    pi,

    v(x, y) = 6x2y2 + y4 + y + c(x) .

    pi CauchyRiemann vx = uy pipi

    12xy2 + c(x) = 4x3 12xy2 c(x) = 4x3 . c(x) = x4 + c .

    v(x, y) = 6x2y2 + y4 + y + x4 + c pi

    f(z) = u(z, 0) + iv(z, 0) = z + i(z4 + c) ,

    c R. f(0) = i, pi c = 1. ,

    f(z) = iz4 + z i .

    () pi w = ez pi

    w 6= 0. y = pi/2, w = exipi/2 = iex. pi y = pi/2pi y = pi/2 pi . pi

    .

    x = x0 R, pi/2 y pi/2, w = ex0eiy, pi/2 y pi/2, O R = ex0 pipi w-pipi. pi,

    x0 R, pi pipi

    w-pipi.

    , w = ez

    = {w C : |

  • 2.1. 201112 91

    2. f : C C ,

    f(z) =n=0

    anzn =

    n=0

    f (n)(0)

    n!zn = f(0)+

    f (0)1!

    z+ + f(n)(0)

    n!zn+ , z C.

    () ( Liouville) pi pi k 0 pi A 0 B > 0,

    |f(z)| A+B|z|k |z| > R0 > 0 . (2.1)

    R > R0, pi Cauchy pi

    |an| A+BRk

    Rn.

    pi f pi pi k. pi

    f z C; (1,3 .)

    () lim|z|

    f(z)

    z= 0, pi f . (1,2 .)

    pi. () C(0, R) = {z C : |z| = R} R > R0. M =max|z|=R |f(z)|, pi (2.1)

    M A+BRk .

  • 92 2.

    , pi Cauchy n > k

    |an| = |f(n)(0)|n!

    MRn A+BR

    k

    Rn=

    A

    Rn+

    B

    RnkR

    0 .

    pi an = 0 n > k. , f pi pi k.

    f z C, (2.1) k = 0 pi f ( Liouville).

    () pi lim|z|

    f(z)

    z= 0, pi R0 > 0

    f(z)z < 1 |z| > R0.,

    |f(z)| < |z| |z| > R0 .

    pi () pi f pi pi 1, f(z) = az + b

    a, b C. pi pi

    lim|z|

    (az + b

    z

    )= lim|z|

    (a+

    b

    z

    )= 0

    pi a = 0. f(z) = b z C, f .

    3. () pi , pi

    C.

    pi f : 1 < |z| < 3 . |f(z)| 1 |z| = 1 |f(z)| 9 |z| = 3, pi |f(2i)| 4. (1,2 .)

    () f : D(0, 1) C D(0, 1) = {z C : |z| < 1} C pi z(t) = reit, 0 t 4pi, pi 0 < r < 1. 0 pi f , pi

    1

    2pii

    C

    f(z)

    z3dz

    pi : (i) pi Cauchy pi (ii)

    pipi. (1,3 .)

    .

  • 2.1. 201112 93

    () : f ,

    G C G G, |f | pi G G f G.

    g(z) := f(z)z2

    . g ,

    : 1 < |z| < 3 pi |z| = 1 |z| = 3.pi pi |g(z)| 1 |z| = 1 |g(z)| 1 |z| = 3.pi |g(z)| 1 z . ,

    |f(z)| |z|2 z

    pi |f(2i)| |2i|2 = 4.() pi C pi 0 I(C, 0) = 2.

    (i) pi pi Cauchy pi

    1

    2pii

    C

    f(z)

    z3dz =

    1

    2

    {2!

    2pii

    C

    f(z)

    z3dz

    }=

    1

    2I(C, 0) f (0) = f (0) .

    (ii) pi 0 pi f , f(0) = 0, f (0) 6= 0 3 z3, 0 pi 2 w = f(z)/z3. , pi

    pipi

    1

    2pii

    C

    f(z)

    z3dz = I(C, 0) Res

    (f(z)

    z3, 0

    )= 2 lim

    z0

    [z2 f(z)

    z3

    ]= 2 lim

    z0

    [f(z)

    z

    ]= 2 lim

    z0zf (z) f(z)

    z2

    = 2 limz0

    zf (z)2z

    ( LHpital)

    = f (0) .

    4. ()

    f (z) =1

    z (z2 + 5)2.

  • 94 2.

    pi( ) Laurent f z0 = 0

    pi pi 2 2i. (1 .)

    () pi Laurent f(z) = 1cospiz

    =

    {z C : 1

    2< |z| < 3

    2

    } z0 = 0 .

    pi pipi pi -

    z1 z2 pi( ) Laurent f(z) = 1cospiz -

    .

    (1,5 .)

    .

    () 1 : 0 < |z|

    5. 22i 2. 1/ (1 + w) =

    n=0(1)nwn,

    |w| < 1,

    1(1 + w)2

    =

    n=1

    (1)nnwn1 1(1 + w)2

    =

    n=1

    (1)n1nwn1 , |w| < 1 .

    pi,

    f(z) =1

    z51

    (1 + 5/z2)2

    =1

    z5

    n=1

    (1)n1n(

    5

    z2

    )n1(|5/z2| < 1 |z| > 5)

    =

    n=1

    (1)n1n5n1 1z2n+3

    =n=0

    (1)n(n+ 1)5n 1z2n+5

    .

    pi pipi pi Laurent f

    2 : |z| >

    5.

    () f(z) = 1/ cospiz pi

    pi 1

    cospiz=

    n=

    anzn z ,

  • 2.1. 201112 95

    pi pi pi pi

    . an pi pi

    an =1

    2pii

    C+(0, r)

    1

    zn+1 cospizdz ,

    pi C+(0, r) 0, r, 1/2 < r < 3/2

    .

    (i) n = 1: a1 =

    1

    2pii

    C+(0, r)

    1

    cospizdz .

    1/2 1/2 f(z) = 1/ cospiz C+(0, r) pi pi. pi pipi

    a1 =1

    2pii

    C+(0, r)

    1

    cospizdz

    = Res

    (1

    cospiz, 1

    2

    )+ Res

    (1

    cospiz,

    1

    2

    )=

    1

    (cospiz)

    z=1/2

    +1

    (cospiz)

    z=1/2

    =1

    pi 1pi

    = 0 .

    (ii) n = 2:

    a2 =1

    2pii

    C+(0, r)

    1

    z1 cospizdz =

    1

    2pii

    C+(0, r)

    z

    cospizdz .

    1/2 1/2 g(z) = z/ cospiz C+(0, r) pi pi. pi pipi

    a2 =1

    2pii

    C+(0, r)

    z

    cospizdz

    = Res

    (z

    cospiz, 1

    2

    )+ Res

    (z

    cospiz,

    1

    2

    )=

    z

    (cospiz)

    z=1/2

    +z

    (cospiz)

    z=1/2

    = 12pi 1

    2pi= 1

    pi.

  • 96 2.

    5. () z0 C R > 0, pi f

    0 < |z z0| < R

    z0.

    (i) z0 pi N N f , pi z0 pi N + 1 f . (0,8 .)

    (ii) z0 pi (pi) f ; -

    z0 pi

    f .

    (0,7 .)

    () pi f : C \N C . f . pi . (1 .)

    .

    () (i) z0 pi N f pi g

    D(z0, R) = {z C : |z z0| < R}, g(z0) 6= 0

    f(z) =g(z)

    (z z0)N z D(z0, R), z 6= z0 .

    ,

    f (z) =(z z0)g(z)Ng(z)

    (z z0)N+1 z D(z0, R), z 6= z0 .

    pi

    f (z) =h(z)

    (z z0)N+1 z D(z0, R), z 6= z0 ,

    pi h(z) := (z z0)g(z) Ng(z) D(z0, R) h(z0) = Ng(z0) 6= 0. , z0 pi N + 1 f .(ii) z0 pi (pi) f pi

    Laurent f(z) =

    n= an(z z0)n, 0 < |z z0| < R, an = 0 n 1.

    f(z) =

    n=0

    an(z z0)n , 0 < |z z0| < R .

  • 2.1. 201112 97

    . f(z0) = a0, pi pi

    |z z0| < R. z0 pi f

    limzz0

    f(z) pi pipi

    pi M > 0, > 0, |f(z)| < M 0 < |z z0| < lim

    zz0(z z0)f(z) = 0 .

    () pi pi pi M > 0, |f(z)| M z C \ N. n pipi . f

    pi 0 < |z n| < 1 n pi n pi f .

    f(z) =

    k=0

    ak(z n)k , 0 < |z n| < 1 .

    pi limzn f(z) = a0, |a0| M . f(n) = a0, pi pi n. pi n N, fpi C( ) |f(z)| M z C., pi Liouville f .

    pi 4

  • 98 2.

    &

    pipi

    30 , 2012

    1. f : A C, f(z) = f(x + iy) = u(x, y) + iv(x, y), pi A pi C z0 = x0 + iy0 A.

    () pi f pi z0. f

    pi x, y, pi pi fx(x0, y0) =

    ux(x0, y0) + ivx(x0, y0), fy(x0, y0) = uy(x0, y0) + ivy(x0, y0) pi

    f (z0) = fx(x0, y0) = ify(x0, y0) .

    (1 .)

    () f : A R, f pi pi , pi f pi z0 f (z0) = 0.

    (0,5 .)

    .

    () pi pi pi

    f (z0) = limh0

    f(z0 + h) f(z0)h

    pi.

    (i) h R z0 + h A, z0 + h = x0 + iy0 + h = (x0 + h) + iy0 (x0 + h, y0) A pi

    f (z0) = limh0hR

    f(z0 + h) f(z0)h

    = limh0hR

    f(x0 + h, y0) f(x0, y0)h

    = fx(x0, y0) .

    (ii) h = ik, k R, z0 + h A, z0 + h = x0 + iy0 + ik = x0 + i(y0 + k)

  • 2.1. 201112 99

    (x0, y0 + k) A pi

    f (z0) = limh0

    h=ik,kR

    f(z0 + h) f(z0)h

    = limk0kR

    f(x0, y0 + k) f(x0, y0)ik

    = i limk0kR

    f(x0, y0 + k) f(x0, y0)k

    = ify(x0, y0) .

    pi fx(x0, y0), fy(x0, y0) pi f (z0) = fx(x0, y0) =

    ify(x0, y0).

    () pi f pi z0. pi f pi pi-

    , pi () pi f (z0) = fx(x0, y0) R if (z0) = fy(x0, y0) R. pi f (z0) = 0.

    2. f : A C, f(z) = f(x + iy) = u(x, y) + iv(x, y), pi A pi C. f

    A.

    : A R , pi g := x iy A. (1 .)

    . f A f ( pi

    x, y) pi A pi

    () Cauchy-Riemann

    fx = ify

    ux = vy

    uy = vx

    .pi A, pi 2 A

    pi Laplace: xx + yy = 0. pi xy = yx.

    U := x V := y, U , V pi A

    Ux Vy = xx + yy = 0 Uy + Vx = xy yx = 0 .

  • 100 2.

    pi U , V pi ()Cauchy-Riemann pi

    g = x iy = U + iV A.

    3. () f : C C, f(z) = u(x, y)+ iv(x, y), ( C). 0 (x, y) R2, pi Liouville pipi pi pi f . (1 .)

    () pi , pi

    C.

    pi f D(0, 1) = {z C : |z| < 1}, |z| = 1

    |f(z)| = e|z| |z| 1;

    (1 .)

    .

    () 1 pi. g(z) := ef(z)

    |g(z)| = |ef(z)| = |eu(x,y)iv(x,y)| = eu(x,y) < e0 = 1(u(x, y) > 0 (x, y) R2)

    z C. pi, pi Liouville g C. |g(z)| = eu(x,y) pi 0 .

  • 2.1. 201112 101

    () : f , -

    G C, G G f(z) 6= 0 z G, |f | pi G G f G.

    pi pi f ,

    |z| = 1 |f(z)| = e|z| |z| 1. f . pi |z| = 1 |f(z)| = e1 = e |f(0)| = e0 = 1, |f | pi |z| = 1. pi pi f pipi .

    pi |f(z)| = e|z| |z| < 1. pi. , pi f .

    4. ()

    f(z) =1

    (z 1)(z + 2)2 .

    pi( ) Laurent f z0 = 1

    pi pi 2 3i. (1 .)

    () pi Laurent f

    = {z C : R1 < |z| < R2}, 0 R1 < R2 , z0 = 0 .

    n= cnzn

    n= dnz

    n pi( ) Laurent f(z) =1

    sinpiz 1 : 0 < |z| < 1 2 : 1 < |z| < 2, . -pi Laurent pipi, pi

    dn cn = 2pi

    pi n .

    (1,5 .)

    .

    () 1 : 0 < |z 1| < 3 2 : |z 1| > 3. 2 3i 2. 1/(1 + w) =

  • 102 2.

    n=0(1)nwn, |w| < 1,

    1(1 + w)2

    =n=1

    (1)nnwn1 1(1 + w)2

    =n=1

    (1)n1nwn1 , |w| < 1 .

    pi,

    f(z) =1

    (z 1) [(z 1) + 3]2

    =1

    (z 1)3 [1 + 3/(z 1)]2

    =1

    (z 1)3n=1

    (1)n1n(

    3

    z 1)n1

    (|3/(z 1)| < 1 |z 1| > 3)

    =

    n=1

    (1)n1n3n1 1(z 1)n+2

    =

    n=3

    (1)n1(n 2)3n3 1(z 1)n .

    pi pipi pi Laurent f

    2 : |z 1| > 3.

    () f pi pi

    f(z) =

    n=anz

    n z ,

    pi pi pi pi

    . an pi pi

    an =1

    2pii

    |z|=

    f(z)

    zn+1dz ,

    pi |z| = 0, , R1 < < R2 .

    (i) 1 : 0 < |z| < 1.

    1

    sinpiz=

    n=

    cnzn z 1 ,

    pi

    cn =1

    2pii

    |z|=1

    1

    zn+1 sinpizdz 0 < 1 < 1 .

  • 2.1. 201112 103

    0 g(z) = 1zn+1 sinpiz

    |z| = 1. pi pipi

    cn = Res

    (1

    zn+1 sinpiz, 0

    ).

    (ii) 2 : 1 < |z| < 2.

    1

    sinpiz=

    n=

    dnzn z 2 ,

    pi

    dn =1

    2pii

    |z|=2

    1

    zn+1 sinpizdz 1 < 2 < 2 .

    0, 1 g(z) = 1/zn+1 sinpiz |z| = 2. 1 pi pi g. pi pipi

    dn = Res

    (1

    zn+1 sinpiz, 1

    )+ Res

    (1

    zn+1 sinpiz, 0

    )+ Res

    (1

    zn+1 sinpiz, 1

    ).

  • 104 2.

    pi

    dn cn = Res(zn1

    sinpiz, 1

    )+ Res

    (zn1

    sinpiz, 1

    )=

    zn1

    (sinpiz)

    z=1

    +zn1

    (sinpiz)

    z=1

    =(1)n1pi cos(pi) +

    1

    pi cospi

    = 1pi

    ((1)n1 + 1)

    = 2pi. ( n pi)

    5. () z0 C R > 0, pi f

    : 0 < |z z0| < R

    z0. f(z) =

    n= an(z z0)n pi() Laurent f z0 , pi z0

    f ; z0 f . (0,5 .)

    () g(z) = z cos(1/z), z 6= 0. pi limn g(zn) limn g(n), pi zn = i/n n = 1/n, n N. pi limz0 g(z); g 0; pi Res (g, 0).

    (1 .)

    .

    () z0 f , pi( ) Laurent

    f(z) =

    n=

    an(z z0)n

    f : 0 < |z z0| < R an 6= 0 pi pi

  • 2.1. 201112 105

    n < 0.

    z0 f

    limzz0

    f(z) pi ( limzz0

    |f(z)| 6=)

    f pi z0 limzz0

    |f(z)| 6= .

    () limn zn = limn n = 0. pi cos z = 12(ein + ein),

    g(zn) =i

    ncos(ni

    )= i

    en + en

    2n g(n) =

    cosn

    n.

    pi,

    limn g(zn) = i limn

    en + en

    2n

    = i limn

    en en2

    ( LHpital)

    =

    limn g(n) = 0. limz0 g(z) pi . pi 0 g.

    pi

    g(z) = z cos1

    z= z

    (1 1

    2!z2+

    1

    4!z4

    )= z 1

    2!z+

    1

    4!z3 ,

    Res (g, 0) = 12 .

    6. () f pi

    |z| = 1, pi |z|=1

    z f(z) dz = pii f (0) .

    (1,2 .)

    () pi pi 2pi0

    15 + cos t

    dt .

  • 106 2.

    (1,3 .)

    . |z| = 1 z = eit, 0 t 2pi, dz = ieitdt =izdt.

    ()

    |z|=1

    z f(z) dz = 2pi0

    eit f(eit) ieit dt

    =

    2pi0

    f(eit) ie2it dt

    = 2pi0

    f(eit)ie2it dt

    = ( 2pi

    0f(eit)ie2it dt

    )=

    ( 2pi0

    f(eit)

    e3itieit dt

    )

    = (|z|=1

    f(z)

    z3dz

    )

    =2pii

    2!

    (2!

    2pii

    |z|=1

    f(z)

    z3dz

    )= pii f (0) . ( pi Cauchy pi)

    () pi cos t = 12(eit + eit

    )= 12

    (z + z1

    ) dt = (1/iz)dz,

    2pi0

    15 + cos t

    dt =

    |z|=1

    15 + 12 (z + z

    1)1

    izdz

    =2

    i

    |z|=1

    1

    z2 + 2

    5 z + 1dz

    =2

    i

    |z|=1

    1

    (z +

    5 2)(z +5 + 2) dz .

    5 2 pi pi f(z) = 1/(z+5 2)(z+5 + 2). pi 5 + 2 |z| = 1, pi

  • 2.1. 201112 107

    pipi 2pi0

    15 + cos t

    dt =2

    i2pii Res(f,

    5 + 2)

    = 4pi limz5+2

    (z +

    5 2) 1(z +

    5 2)(z +5 + 2)

    = 4pi 14

    = pi .

  • 108 2.

    2.2 200910

    5 , 2010

    1. () f : G C, f (z) = u (x, y) + iv (x, y), pi G pi C.

  • 2.2. 200910 109

    (yu+ xv)xx + (yu+ xv)yy = 0

    (2vx + yuxx + xvxx) + (2uy + yuyy + xvyy) = 0 2vx + 2uy + y (uxx + uyy) + x (vxx + vyy) = 0 uy = vx . (uxx + uyy = 0, vxx + vyy = 0)

    pi u, v pi

    G pi Cauchy-Riemann: {ux = vy, uy = vx}, pi f = u+ iv G.

    () pi |f (z)| < |f (z)|, z C, f C. , f (z0) = 0 pi z0 C, |f (z0)| < 0 (pi). h (z) := f (z) /f (z), z C, h ( C) |h (z)| < 1 z C. , pi Liouville h C.

    h (z) =f (z)f (z)

    = c z C, pi |c| < 1.

    pi f C, pi

    g : C C eg(z) = f (z) , z C.

    g (z) eg(z) = f (z) g (z) = f (z)f (z)

    .

    pi, g (z) = c z C pi g (z) = cz + d. ,

    f (z) = ecz+d = edecz = Aecz , pi A = ed 6= 0 .

    ,

    f (z) = Aecz , A, c C, A 6= 0 |c| < 1.

  • 110 2.

    2.

    sin(a(z + z1

    ))=

    n=

    cnzn , a C ,

    pi Laurent f (z) = sin(a(z + z1

    )) -

    = {z C : 0 < |z|

  • 2.2. 200910 111

    3. pi C+(0, 1)

    =zz (z 1/2) dz ,

    pi C+ (0, 1) .

    (1,5 .)

    . z = x+ iy C+ (0, 1),

    =z = y = 12i

    (z z) = 12i

    (z z1) .

    ( z C+ (0, 1), |z| = 1 |z|2 = 1 zz = 1 z = z1)

    2 pi: z = ei, pi pi,

    =z = sin = 12i

    (ei ei

    )=

    1

    2i

    (z z1) .

    C+(0, 1)

    =zz (z 1/2) dz =

    1

    2i

    C+(0, 1)

    z z1z (z 1/2) dz

    =1

    2i

    C+(0, 1)

    z2 1z2 (z 1/2) dz ,

    piC+(0, 1)

    =zz (z 1/2) dz =

    1

    2i2pii

    [Res

    (z2 1

    z2 (z 1/2) , 0)

    + Res

    (z2 1

    z2 (z 1/2) , 1/2)]

    ( pipi)

    = pi

    [limz0

    (z2

    z2 1z2 (z 1/2)

    )+ limz1/2

    (z 1/2) z2 1

    z2 (z 1/2)

    ]

    = pi

    [limz0

    z2 z + 1(z 1/2)2 + limz1/2

    (1 z2)]

    = pi[22 + 1 22] = pi .

  • 112 2.

    pipi

    29 pi, 2010

    1. () f : C C

    f (z) =

    z2 sin (1/z) z 6= 0

    0 z = 0 .

    pi

    limz0z=xR

    f (z) f (0)z 0 limz0

    z=iy,yR

    f (z) f (0)z 0 .

    f pi 0; (1 .)

    () u : R2 R,

    (x, y) := xu (x, y)

    R2. v u

    pi f (z) = u (x, y) + iv (x, y). (1 .)

    .

    ()

    limz0z=xR

    f (z) f (0)z 0 = limx0

    x2 sin (1/x)

    x= lim

    x0x sin (1/x) = 0

    limz0

    z=iy,yR

    f (z) f (0)z 0 = limy0

    (iy)2 sin (1/iy)

    iy

    = limy0

    y2 sin (i/y)

    iy

    = limy0

    y sinh (1/y) . (sin (i/y) = i sinh (1/y))

  • 2.2. 200910 113

    ,

    limy0+

    y sinh (1/y) = limy0+

    sinh (1/y)

    1/y

    = limt+

    sinh t

    t

    = limt+ cosh t (LHpital)

    = limt+

    et + et

    2= +

    limy0 y sinh (1/y) = limy0+ y sinh (1/y) = +. limy0 y sinh (1/y) =+. , pi f (0) pi.

    () pi u R2, u pi

    2 R2 pi Laplace

    uxx + uyy = 0 .

    (x, y) = xu (x, y) R2 pi

    (xu)xx + (xu)yy = 0 (2ux + xuxx) + xuyy = 0 2ux + x (uxx + uyy) = 0 ux = 0 (uxx + uyy = 0)

    pi u (x, y) = c1 (y) Laplace uxx + uyy = 0 pi

    c1 (y) = 0. ,

    u (x, y) = c1 (y) = ay + b , a, b R .

    v u, pi CauchyRiemann vy = uxpi

    vy = 0 , pi v (x, y) = c2 (x) .

    pi CauchyRiemann uy = vx pipi

    a = c2 (x) c2 (x) = a .pi , c2 (x) = ax+ c .

    , v (x, y) = ax+ c

    f (z) = u (z, 0) + iv (z, 0) = b+ i (az + c) = iaz + b+ ic ,

  • 114 2.

    c R.

    2.

    f (z) =20

    (z4 4) (z4 + 16) .

    pi pi Laurent f z0 = 0

    pi pi 3i/2

    f (z) =

    n=

    anz4n an =

    4(n+1) n 1

    (1/16)n+1 n 0 .

    ; (1,5 .)

    .

    f (z) =20

    (z4 4) (z4 + 16) =1

    z4 4 1

    z4 + 16.

    ,

    1

    1 w =n=0

    wn 11 + w

    =n=0

    (1)nwn , |w| < 1 . ( )

    ={z C : 2 < |z| < 2}, 3i/2 pi Laurent f

    f (z) =1

    z4 4 1

    z4 + 16

    =1

    z41

    1 4/z4 1

    16

    1

    1 + z4/16

    =1

    z4

    n=0

    (4

    z4

    )n 1

    16

    n=0

    (1)n(z4

    16

    )n=n=0

    4n

    z4(n+1)+

    n=0

    (1)n+1 116n+1

    z4n

    =

    1n=

    4(n+1)z4n +n=0

    ( 1

    16

    )n+1z4n .

  • 2.2. 200910 115

    3. f () D (0, R) =

    {z C : |z| R}, pi z, |z| < R,

    f (z) =1

    2pi

    2pi0

    [Reit

    Reit z +z

    Reit z]f(Reit

    )dt

    =1

    2pi

    2pi0

    R2 |z|2|Reit z|2 f

    (Reit

    )dt .

    (1,5 .)

    . pi

    Reit

    Reit z +z

    Reit z =R2 |z|2

    (Reit z) (Reit z) =R2 |z|2|Reit z|2 ,

    pi

    f (z) =1

    2pi

    2pi0

    [Reit

    Reit z +z

    Reit z]f(Reit

    )dt .

    |z| < R, z 6= 0,

    1

    2pi

    2pi0

    [Reit

    Reit z +z

    Reit z]f(Reit

    )dt

    =1

    2pi

    2pi0

    [Reit

    Reit z +zReit

    R2 zReit]f(Reit

    )dt

    =1

    2pi

    2pi0

    [1

    Reit z 1

    Reit R2/z]Reitf

    (Reit

    )dt

    =1

    2pii

    C+(0, R)

    [1

    w z 1

    w R2/z]f (w) dw

    ( w = Reit, dw = iReitdt)

    =1

    2pii

    C+(0, R)

    f (w)

    w z dw 1

    2pii

    C+(0, R)

    f (w)

    w R2/z dw ,

    pi C+ (0, R) 0 R > 0 . pi

    pi Cauchy

    f (z) =1

    2pii

    C+(0, R)

    f (w)

    w z dw .

    pi |z| < R, R2/z > R pi pi Cauchy 1

    2pii

    C+(0, R)

    f(w)

    w R2/z f(w) dw = 0 .

  • 116 2.

    ,

    f(z) =1

    2pi

    2pi0

    [Reit

    Reit z +z

    Reit z]f(Reit

    )dt .

    z = 0,

    1

    2pi

    2pi0

    [Reit

    Reit z +z

    Reit z]f(Reit

    )dt =

    1

    2pi

    2pi0

    f(Reit

    )dt

    =1

    2pii

    C+(0, R)

    f (w)

    wdw

    ( w = Reit, dt = dw/iw)

    = f (0) .

  • 2.3. 20089 117

    2.3 20089

    17 , 2009

    1. C tan z = i.

    f (z) =1

    tan z i pi

    |z|=2

    1

    tan z i dz .

    (1 .)

    . {tan z = i

    }{ (

    eiz eiz) /2i(eiz + eiz) /2

    = i

    }{eiz eizeiz + eiz

    = 1}{eiz = 0

    }.

    pi C C \ {0}. pi tan z = i C.

    w = tan z z = kpi + pi/2, k Z. pi, zk = kpi + pi/2, k Z, f(z) = 1/ (tan z i). pi 1tan z i

    = 1|tan z i| 1|tan z| 1 zkpi+pi/2 0 , zk = kpi + pi/2, k Z, pi () f . pi pi2 |z| = 2. pi,

    |z|=21

    tan z i dz = 0 .

    2. f (z) =

    n= anzn pi Laurent ()

    f = {z C : 0 < |z| < 1} z0 = 0. pi

    |f(z)| ln 2|z| , z .

  • 118 2.

    pi

    |an| 1rn

    ln2

    r, 0 < r < 1 .

    f 0;

    pi limz0 f(z); limz0 |f(z)| ln 2; (2,5 .)

    . pi Laurent an pi pi

    an =1

    2pii

    C+(0, r)

    f (z)

    zn+1dz ,

    pi C+ (0, r) 0, r, 0 < r < 1

    . pi

    |an| = 12pi

    C+(0, r)

    f (z)

    zn+1dz

    1

    2pi

    C+(0, r)

    |f (z)||z|n+1 |dz|

    12pirn+1

    ln2

    rC+(0, r)

    |dz| (|f (z)| ln 2|z| = ln 2r )

    =1

    2pirn+1ln

    2

    r 2pir = 1

    rnln

    2

    r.

    n < 0,

    limr0+

    1

    rnln

    2

    r= lim

    r0+ln (2/r)

    rn(LHpital)

    = limr0+

    1

    nrn= 1

    nlimr0+

    rn = 0 .

    pi an = 0 n = 1,2,3, . . . . , z0 = 0 pi () f pi f pi ()

    D (0, 1) = {z C : |z| < 1}. limz0 f (z) = a0 pi

    limz0|f (z)| = |a0| lim

    r1ln

    2

    r= ln 2 .

    3. pi , pi 2pi0

    cosn

    5 + 4 cos d , n = 1, 2, 3, . . . .

  • 2.3. 20089 119

    (1,5 .)

    . z = ei, 0 2pi. pi dz = ieid =izd cos = 12

    (z + z1

    ),

    2pi0

    eni

    5 + 4 cos d =

    C+(0, 1)

    zn

    iz [5 + 2 (z + z1)]dz

    = iC+(0, 1)

    zn

    2z2 + 5z + 2dz

    = iC+(0, 1)

    zn

    (2z + 1) (z + 2)dz .

    1/2 2 pi pi f (z) = zn/ (2z + 1) (z + 2). pi 1/2 C+ (0, 1), pi pipi

    2pi0

    eni

    5 + 4 cos d = 2pii (i) Res

    (zn

    (2z + 1) (z + 2), 1

    2

    )= 2pi lim

    z1/2

    (z +

    1

    2

    )zn

    (2z + 1) (z + 2)

    = 2pi(1/2)n

    2 (1/2 + 2) = pi(1)n

    3 2n1 .

    , 2pi0

    cosn

    5 + 4 cos d = 0. pi

    limR

    R

    z4

    z8 + 1dz = 0 .

    , f(z) = z4z8+1

    pi pi pi

    pi pi 0 pi R, R

    Reipi/4 pi 0, pi 0

    x4

    x8 + 1dx =

    pi

    8 sin (5pi/8).

    (2 .)

    . z R z4z8 + 1 = |z|4|z8 + 1| |z|4|z|8 1 = R4R8 1 .

    R piR/4 piR

    z4

    z8 + 1dz

    piR54 (R8 1) = pi4 1/R31 1/R8 R 0 .,

    limR

    R

    z4

    z8 + 1dz = 0 .

    f pi pi (

    ) pi pi pi [0, R], R

    [Reipi/4, 0

    ].

    pi [0, Reipi/4

    ] z (x) = xeipi/4, 0

    x R. z8 + 1 = 0 z8 = 1 z8 = eipi

    zk = e(2kipi+ipi)/8 , k = 0, 1, 2, . . . , 7 .

  • 2.3. 20089 123

    zk, k = 0, 1, 2, . . . , 7, pi pi f z0 = eipi/8

    pi/4 R > 1.

    Res(f, eipi/8

    )=

    z4

    8z7

    z=eipi/8

    =1

    8

    e5ipi/8

    eipi= 1

    8e5ipi/8 .

    pi pipi

    R0

    x4

    x8 + 1dx+

    R

    z4

    z8 + 1dz

    R0

    (xeipi/4

    )4(xeipi/4

    )8+ 1

    eipi/4 dx

    = 2piiRes(f, eipi/8

    )= pii

    4e5ipi/8 .

    pi, R0

    x4

    x8 + 1dx+

    R

    z4

    z8 + 1dz + eipi/4

    R0

    x4

    x8 + 1dx = pii

    4e5ipi/8

    (1 + eipi/4

    ) R0

    x4

    x8 + 1dx+

    R

    z4

    z8 + 1dz = pii

    4e5ipi/8 . (2.2)

    pi (2.2) R pi(1 + eipi/4

    ) 0

    x4

    x8 + 1dx = pii

    4e5ipi/8 .

    pie5ipi/8

    1 + eipi/4=

    1

    e5ipi/8 + e3ipi/8=

    1

    e5ipi/8 e5ipi/8 = 1

    2i sin (5pi/8),

    0

    x4

    x8 + 1dx =

    pi

    8 sin (5pi/8).

  • 124 2.

    2.4 20078

    11 , 2008

    1. () f : G C, f = u + iv, pi G, pi u =

  • 2.4. 20078 125

    pi c C. pi pi f C \ {0}, f C \ {0}. w = Log z C \ {0}. pi,pi w = Log z (, 0].

    2. T 0, 1 1 + i. f (z) = ez2 , |f | T .

    . pi f(z) = ez2 C, pi

    |f(z)| =ez2 pi

    pi T pi 0, 1 1 + i.

    1 pi.

    (i) [1, 0], z = x, 1 x 0, |f (z)| = ex2 .pi,

    maxz[1, 0]

    |f (z)| = f (1) = e minz[1, 0]

    |f (z)| = f (0) = 1 .

    (ii) [0, 1 + i], z = x+ ix, 0 x 1,

    |f (z)| =e(x+ix)2 = e2ix2 = 1 .

    (ii) [1, 1 + i], z = 1+(2+i)t = 2t1+it, 0 t 1,

    |f (z)| =e(2t1+it)2 = e3t24t+1 e2it(2t1) = e3t24t+1 .

  • 126 2.

    g (t) = 3t2 4t+ 1, 0 t 1,

    maxt[0, 1]

    g (t) = g (0) = 1 mint[0, 1]

    g (t) = g

    (2

    3

    )= 1

    3.

    pi,

    maxz[1, 1+i]

    |f (z)| = f (1) = e minz[1, 1+i]

    |f (z)| = f(

    1 + 2i

    3

    )= e1/3 .

    ,

    maxzT|f (z)| = f (1) = e min

    zT|f (z)| = f

    (1 + 2i

    3

    )= e1/3 .

    2 pi.

    |f (z)| =e(x+iy)2 = ex2y2 e2ixy = ex2y2 ,

    pi 0, 1 1 + i. pipi

    (i) y = 0, 0 x 1, (ii) y = x, 0 x 1 (iii) 2y = x+ 1, 1 x 1 .

    3.

    f (z) =z2 z i

    (z 1 3i) (z2 2z + 1 + 2i) =1

    z 1 3i +1

    z2 2z + 1 + 2i .

    pi Laurent f z0 = 1

    pi pi 1/2.

    .

    f (z) =1

    z 1 3i +1

    (z 1)2 + (1 + i)2 .

    , 1/ (1 w) = n=0wn 1/ (1 + w) = n=0 (1)nwn, |w| < 1 ().

    pi |1 + i| = 2, = {z C : 2 < |z 1| < 3}, 1/2 piLaurent f

    f (z) = 13i 1

    1 z13i+

    1

    (z 1)2 1

    1 +(1+iz1)2

    = 13i

    n=0

    (z 1

    3i

    )n+

    1

    (z 1)2n=0

    (1)n(

    1 + i

    z 1)2n

    = n=0

    1

    (3i)n+1(z 1)n +

    n=0

    (1)n (1 + i)2n 1(z 1)2(n+1)

    .

  • 2.4. 20078 127

    ={z C : 2 < |z 1| < 3}, 1/2 ,

    pi pipi pi Laurent f .

    . f

    f (z) =1

    z 1 3i +1

    (z 1 i (1 + i)) (z 1 + i (1 + i))=

    1

    z 1 3i +1

    (z 1 + (1 i)) (z 1 (1 i))=

    1

    z 1 3i +1

    2 (1 i) 1

    z 1 (1 i) 1

    2 (1 i) 1

    z 1 + (1 i) .

    4. R, z () = Rei, 0 pi, pipi 0 R > 0. pi

    limR

    R

    1

    (z2 + 1)3dz = 0 .

    , pi pipi pi

    0

    1

    (x2 + 1)3dx .

    . z R 1(z2 + 1)3 = 1|z2 + 1|3 1(|z|2 1)3 =

    1

    (R2 1)3 .

    R Rpi piR

    1

    (z2 + 1)3dz

    Rpi(R2 1)3 R 0 .,

    limR

    R

    1

    (z2 + 1)3dz = 0 .

    i pi 3 f (z) = 1/ (z2 + 1)3. f pi pi pi pi pi pipi R,

    z () = Rei, 0 pi [R,R]. R i f

    R.

  • 128 2.

    pi pipi RR

    1

    (x2 + 1)3dx+

    R

    1

    (z2 + 1)3dz = 2piiRes (f, i) . (2.3)

    Res (f, i) = Res

    (1

    (z2 + 1)3, i

    )=

    1

    2!limzi

    [(z i)3 1

    (z2 + 1)3

    ]=

    1

    2!limzi

    [1

    (z + i)3

    ]=

    1

    2!limzi

    12

    (z + i)5= 3

    16i .

    pi, pi (2.3) pipi

    1

    (x2 + 1)3dx = lim

    R

    RR

    1

    (x2 + 1)3dx = 2pii

    ( 3

    16i

    )=

    3pi

    8.

    , 0

    1

    (x2 + 1)3dx =

    1

    2

    1

    (x2 + 1)3dx =

    3pi

    16.

  • 2.4. 20078 129

    pipi

    3 , 2008

    1. () pi f : G C C, f(z) = u(x, y) + iv(x, y), pi ( x, y) G.

    f

    z:=

    1

    2

    (f

    x if

    y

    ) f

    z:=

    1

    2

    (f

    x+ i

    f

    y

    ),

    pi f G fz = 0. f

    , pi f = fz .

    () pi

    f (z) = zz +z

    z, z 6= 0 ,

    pi pi pi.

    .

    () f G, pi pi pi

    CauchyRiemann: ux = vy uy = vx. pif

    x= if

    y f

    z= 0 .

    pi f = f/x,

    f =f

    x=

    1

    2

    (f

    x if

    y

    )=f

    z.

    , pi f/z = 0 f/x = if/y, pi- CauchyRiemann G. pi f

    pi ( x, y), pi pi f

    G.

    () C \ {0} f pi ( x, y). f pi pipi pi

    CauchyRiemann.

    f

    z= 0 z z

    z2= 0 z2 = 1 z2 = 1 z = 1 .

  • 130 2.

    pi, f pi 1. pi f (z) =z + 1/z, f (1) = 2.

    2. f : D (0, 1) C , pi D (0, 1) = {z C : |z| < 1} . pi

    1

    2pii

    C+(0, r)

    f (z) f (z)z2

    dz ,

    pi C+ (0, r) 0, r, 0 < r < 1 .

    d = supz,wD(0,1)

    |f (z) f (w)|

    pi f , pi

    f (0) d2.

    . z D (0, 1), z D (0, 1) pi g (z) := f (z) f (z) D (0, 1). pi pi Cauchy

    pi

    g (0) =1

    2pii

    C+(0, r)

    g (z)

    z2dz 2f (0) = 1

    2pii

    C+(0, r)

    f (z) f (z)z2

    dz .

    pi, r (0, 1)

    f (0) = 14pi

    C+(0, r)

    f (z) f (z)z2

    dz

    1

    4pi

    C+(0, r)

    |f (z) f (z)||z|2 |dz|

    14pi

    d

    r2

    C+(0, r)

    |dz|

    =1

    4pi

    d

    r22pir =

    d

    2r.

    , f (0) limr1

    d

    2r=d

    2.

  • 2.4. 20078 131

    3. ze2piz1 =

    n= anz

    n pi Laurent f(z) = ze2piz1

    = {z C : 1 < |z| &