10_kiemtrahk1
DESCRIPTION
10_Kiemtrahk1TRANSCRIPT
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Trng THPT Chuyn Lng Th Vinh Gio vin: Nguyn Hong Anh
KIM TRA HC K 1LP 10
Thi gian lm bi: 45 pht 1:
Cu 1:Mt bi ht X nu lu tr trn a chim khong 4MB. Hi mt a cng80GB th c th cha c khong bao nhiu bi ht c dung lng bng bi ht X?A. 20480B. 10240Cu 2: y l thit b g?A. Mn hnh.B. RAM.C. cng my tnh.D. B x l trung tm
C. 40208D. 20008
Cu 3: Pht biu no sau y v ROM l ng?A. ROM l b nh ngoi ca my tnh.B. D liu trong ROM khng xa c.C. D liu trong ROM s b mt khi tt my.D. ROM l b nh trong c th c, ghi d liu trong lc lm vic.Cu 4: Cc k t trong bng m ASCII c nh s th t t:A. 0 n 255B. 0 n 256Cu 5: Cho thut ton
C. 1 n 256D. 1 n 255
Bc 1: Nhp s nguyn dng N v N s a1, a2, ,aN;Bc 2: Tong 0 ; i 1;Bc 3: Nu i>N th a ra gi tr Tong, ri kt thc;
Ngc li sang bc 4;Bc 4: Nu ai > 0 th Tong Tong + ai;Bc 5: i i+1, ri quay li bc 3;
Thut ton trn cho kt qu ca Tong= 10 th dy s tng ng s l:A. 3, -9, 6, -2B. 4, 8, 1 , 3
C. 7,-5, 3, -2D. -1, 9, 7, 0
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Trng THPT Chuyn Lng Th Vinh Gio vin: Nguyn Hong Anh
Cu 6: Cho thut tonBc 1: Nhp s nguyn dng N v N s a1, a2, ,aN;Bc 2: Tong 0 ; i 1;Bc 3: Nu i>N th a ra gi tr tng, ri kt thc;Bc 4: Nu ai > 0 th Tong Tong + ai;Bc 5: i i+1, ri quay li bc 3;
Cho dy s: 4, 8, 1 , 3, 7,-5, 3, -2 sau khi kt thc thut ton gi tr ca i l:A. 7 B. 9 C. 8 D. 10Cu 7: in vo ch trng cu sau y:Nguyn l lu tr chng trnh: "Lnh c a vo my tnh di dng ..... lutr, x l nh nhng d liu khc"A. a chB. Chng trnh
C. M nh phnD. Phn mm
Cu 8: Trong cc thit b sau, thit b no khng phi l thit b vo (Input)?A. Bn phmB. My qut
C. My chiuD. Chut
Cu 9: H thng tin hc gm nhng thnh phn:A. Phn mm, d liu, h iu hnh.B. Phn mm, phn cng, s qun l v iu khin ca con ngi.C. H iu hnh, phn cng, d liu.D. H iu hnh, d liu, s qun l v iu khin ca con ngi.Cu 10: S 10100101110010012 c biu din trong h c s 16 l:A. A5C916B. 5AC916
C. 9C5A16D. A9C516
Cu 11: Hot ng ca my tnh da trn . nguyn l?A. 4 B. 5 C. 2 D. 3Cu 12: Input ca bi ton trong tin hc l g?A. D liu u voB. D liu kt qu
C. Thut tonD. Chng trnh
Cu 13: Ngn ng no sau y my c th trc tip hiu v thc hin c?A. Ngn ng my.B. Ngn ng bc cao.Cu 14: Thut ton tt l thut ton:A. Thi gian chy nhanhB. D hiu v d nhn
C. Hp ng.D. Ngn ng Pascal.
C. Tn t b nh.D. Tt c cc phng n u ng
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Trng THPT Chuyn Lng Th Vinh Gio vin: Nguyn Hong Anh
Cu 15: ALU lA. B x l s hcB. B x l iu khin
Cu 16: Thut ton c my tnh cht?
C. Thanh ghiD. B nh trong
A. 3 B. 5 C. 2 D. 4Cu 17: Thit b no sau y dng cha d liu lu di?A. a cng B. My chiu C. My in D. MainBoardCu 18: Cc thng tin c th biu din trong my tnh bao gm. loiA. 2 B. 3 C. 4 D. 5Cu 19: C my cch trnh by thut ton?A. 2 B. 3 C. 4 D. 5Cu 20: Khi biu din thut ton bng s khi, khi mun kim tra biu thc iu kin tadng khi.. biu din
A. Hnh ch nhtB. Hnh thoi
C. Hnh bnh hnhD. Hnh elip
Cu 21: Ta c thut ton c din ta theo cch lit k nh sau:Bc 1: Nhp a,b l 2 s nguynBc 2: Nu a>b th Max a ; sang bc 3
Ngc li: Max b; sang bc 3Bc 3: Xut Max v kt thc thut ton.
vi a=10 v b=4. Vy khi kt thc thut ton max bng bao nhiu?A. 14 B. 10 C. 4 D. 2Cu 22: Pht biu no sau y khng chnh xc?A. Gi thnh my tnh ngy cng tng.B. Cc my tnh kt ni vi nhau thnh mt h thng.C. Tc my tnh ngy cng tng.D. Dung lng a cng ngy cng tng.Cu 23: Chc nang cua bo nh ngoai la:A. a d lieu ra t may tnhB. a thong tin vao may tnh
C. Lu tr tm thi d liu khi tt myd liu s mt.D. Lu tr lu di d liu
Cu 24: gii bi ton trn my tnh ta thc hin cc cng vic:(a) La chn hoc thit k thut ton (b) Xc nh bi ton(c) Vit ti liu (d) Vit chng trnh (e) Hiu chnh
Chn cch sp xp ng th t ca cc cng vic trn:A. b d a e cB. a b d e cCu 25:My tnh ang lm vic b mt in th,
A. D liu trn b nh ngoi b mt ht.B. D liu trn RAM b mt, d liu trn
ROM khng b mt.
C. b a d e cD. b a d c e
C. D liu trn b nh trong b mt ht.D. D liu c lu li trn ROM.
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Trng THPT Chuyn Lng Th Vinh Gio vin: Nguyn Hong Anh
Cu 26: B m Unicode dng bao nhiu bit m ha 1 k t?A. 8 B. 16 C. 28 D. 216
Cu 27:Mt quyn truyn A gm 10 trang nu lu tr trn a chim khong 2MB. Hi mta cng 5GB c th cha c bao nhiu quyn truyn A?
A. 51200 B. 25600 C. 5120 D. 2560Cu 28: Nguyn l lu tr chng trnh ni rng:A. Lnh my tnh x l, lu tr trong my tnh phi di dng m nh phnB. Truy cp d liu trong my tnh phi thng qua a ch ni lu tr d liu C. Thng tin phi c m ha thnh dng m nh phnD.My tnh hot ng theo chng trnh
Cu 29: Input ca bi ton gii phng trnh bc hai: ax2 + bx + c = 0 lA. a, b, c, x, x2 B. x2, a, b, c C. a, c, x D. a, b, cCu 30: Bc no trong cc bc khi gii mt bi ton trn my tnh cho php ta suyngh v chn kiu d liu, chn thut ton v chn ngn ng lp trnh cho ph hp?A. Xc nh bi tonB. Hiu chnh
C. Vit chng trnhD. La chn hoc thit k thut ton
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H v tn:..Lp:..Stt:.
Good luck to you!