bahupadulu
DESCRIPTION
SSC _BitsTRANSCRIPT
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ºçßæ$糧ýl$Ë$
SAKSHI
çÜ*{™éË$ :1. ax2 + bx + c = 0 A ó̄l¨ Ð]lÆý‡Y çÜÒ$MýSÆý‡×æ Ý뫧éÆý‡×æ Æý‡*ç³… (a, b, c ∈ R). ©° Ð]lÊÌêË$ α, β AƇ¬¯]l
C…§ýl$ÌZ b2 – 4ac° "Ñ è̂l„ýS×ìæ' A…sêÆý‡$.
2. ax2 + bx + c = 0 Ð]lÆý‡Y çÜÒ$MýSÆý‡×æ…G) Ð]lÊÌêË Ððl¬™èl¢… = – b/a
¼) Ð]lÊÌêË Ëºª… = c/a
3. α, βË$ Ð]lÊÌêË$V> VýSË Ð]lÆý‡YçÜÒ$MýSÆý‡×æ…x2 – (α + β) x + αβ = 0 Ìôæ§éx2 – (Ð]lÊÌêË Ððl¬™èl¢…) x + Ð]lÊÌêË Ëºª… = 0
4. (x – α) (x – β) > 0 AƇ¬™ól x ÑË$Ð]l α, βË ºÄ¶æ$r E…r$…¨.5. (x – α) (x – β) < 0 AƇ¬™ól x ÑË$Ð]l α, βË Ð]l$«§ýlÅ E…r$…¨.6. ÔóæçÙ íܧ鮅™èl…: f(x) = (x – a) × Q(x) + f(a)
7. G) f(x) AMýSÆý‡×îæĶæ$ ç³NÆ>~…MýS çÜÐ]l*çÜ…ÌZ° 糧éË VýS$×æM>Ë Ððl¬™èl¢… "0' AƇ¬™ól f(x)MýS$ (x – 1) JMýSM>Æý‡×ê…MýS….
¼) f(x) AMýSÆý‡×îæĶæ$ ç³NÆ>~…MýS çÜÐ]l*çÜ…ÌZ° »ôæíÜçœ*™éË ç³§éË VýS$×æM>Ë Ððl¬™èl¢…l = çÜÇçœ*™éË糧éË VýS$×æM>Ë Ððl¬™èl¢… AƇ¬ ]̄l f(x)MýS$ x + 1JMýS M>Æý‡×ê…MýS….
8. VýS×ìæ™é¯]l$VýSÐ]l$¯]l íܧ鮅™èl…: JMýS {ç³Ð]l è̂l ]̄l… p(n)
i) n = 1 MýS$ ii) 1, 2....nËMýS$ °f… AƇ¬ ]̄lç³#yýlÌêÏiii) n + 1 MýS*yé °f… AƇ¬ ]̄l n A°² ÑË$Ð]lËMýS$ °f….
9. ¨Ó糧ýl íܧ鮅™èl…: (x + y)n = nC0xn + nC1x
n–1y+ nC2xn–2y2 + ....+ nCrx
n–ryr + ....+ nCnyn
C…§ýl$ÌZ nC0, nC1, nC2....nCnË$ ¨Ó糨 VýS$×æM>Ë$ nC0 = nCn = 1
10. (x + y)n ÑçÜ¢Æý‡×æÌZ r + 1Ð]l 糧ýl… Tr+1 = nCr.xn– ryr
JMýS Ð]l*Æý‡$P {ç³Ô¶æ²Ë$1. √3x2 + 9x + 6√3 = 0 Ð]lÆý‡Y çÜÒ$MýSÆý‡×æ Ð]lÊÌêË Ððl¬™èl¢…, Ð]lÊÌêË Ë»êª°² MýS ]̄l$Vö ]̄l…yìl?Sol: Ð]lÆý‡Y çÜÒ$MýSÆý‡×æ… √3x2 + 9x + 6√3 = 0
a = √3, b = 9, c = 6√3
Ð]lÊÌêË Ððl¬™èl¢… b 9 3 3 3
a 3
− − − × ×= = =3
3 3= −
2 2b b 4ac b b 4ac,
2a 2a
− + − − −α = β =
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SAKSHI
Ð]lÊÌêË Ëºª…
2. 3 + √5, 3 --& √5 Ð]lÊÌêË$ E ]̄l² Ð]lÆý‡YçÜÒ$MýSÆý‡×æ… Æ>Ķæ$…yìl?Sol: α = 3 + √5, β = 3 − √5
α + β =
αβ = (3 + √5) (3 – √5) = (3)2 – (√5)2 = 9 – 5 = 4
Ð]lÆý‡Y çÜÒ$MýSÆý‡×æ…: x2 – (α + β)x + αβ = 0
x2 – 6x + 4 = 0
3. x2 – 4x + 5 = 0 Ð]lÊÌêË çÜÓ¿êÐ]l… ™ðlËç³…yìl?Sol: çÜÒ$MýSÆý‡×æ… x2 – 4x + 5 = 0
a = 1, b = – 4, c = 5
Ñ è̂l„ýS×ìæ ∆ = b2 – 4ac
= (– 4)2 – 4 × 1 × 5= 16 – 20 = – 4
b2 – 4ac < 0 M>ºsìæt Ð]lÊÌêË$ çÜ…MîSÆý‡~ çÜ…QÅË$
4. ÑçÜ¢Æý‡×æÌZ Ð]l$«§ýlÅ糧鰲 Æ>Ķæ$…yìl?
Sol: ¨Ó糨 çœ*™é…MýS… 6 M>ºsìæt ÑçÜ¢Æý‡×æÌZ 6 + 1 = 7 糧éË$ E…sêƇ¬.Ð]l$§ýlÅ糧ýl… 4Ð]l 糧ýl… AÐ]l#™èl$…¨.
(x + y)n ÑçÜ¢Æý‡×æÌZ Tr+1 = nCrxn – ryr
ÑçÜ¢Æý‡×æÌZ T4 = T 3 + 1 = 6C3 (x)6 – 3 (– 1/x)3
5. 3x3 – 2x2 + x + 2 A ó̄l çÜÐ]l*Ýë°² (x – 1) ó̂l ¿êW… è̂lV> Ð]l ó̂la ÔóæçÙ… MýS ]̄l$Vö ]̄l…yìl?Sol: f(x) = 3x3 – 2x2 + x + 2
f(x) ]̄l$ (x – 1) ó̂l ¿êWõÜ¢ Ð]l ó̂la ÔóæçÙ… f(1) AÐ]l#™èl$…¨∴ f(1) = 3(1)3 – 2 (1)2 + 1 + 2= 3 – 2 + 1 + 2 = 4
6. K çÜ…QÅ §é° Ð]lÆ>Y° MýS…sôæ 132 ™èlMýS$PÐ]l AƇ¬ ]̄l B çÜ…QÅ ]̄l$ MýS ]̄l$Vö ]̄l…yìl?Sol: JMýS çÜ…QÅ 'x' A¯]l$Mø…yìl
336C x=
3
1
x
−×+
36C= −
( )71x x−
( )61x x−
3 5+ 3 5+ − 6=
c 6 3
a= =
36=
§é° Ð]lÆý‡Y… = x2
§ýl™é¢…Ô¶æ… {ç³M>Æý‡… x2 = x + 132
x2 – x – 132 = 0x2 – 12x – 132 = 0x2 – 12x + 11x – 132 = 0x (x – 12) + 11 (x – 12) = 0(x + 11) (x – 12) = 0x + 11 = 0 x –12 = 0x = – 11 x = 12
M>Ð]lËíÜ ]̄l çÜ…QÅ 12 Ìôæ§é & 11
Æð‡…yýl$ Ð]l*Æý‡$PË {ç³Ô¶æ²Ë$1. x3 – 3x2 + 4x + k ]̄l$ (x – 2) °ÔóæØçÙ…V> ¿êWõÜ¢ k ÑË$Ð]l ]̄l$ MýS ]̄l$Vö ]̄l…yìl? (June 10)
Sol: f(x) = x3 – 3x2 + 4x + k
f(x) ]̄l$ (x – 2) °ÔóæØçÙ…V> ¿êWõÜ¢ f (2) = 0
f(2) = 23 – 3(2)2 + 4(2) + k = 0= 8 – 3 × 4 + 4 (2) + k = 0= 8 – 12 + 8 + k = 0= 16 – 12 + k = 0= 4 + k = 0k = 4
2. ÑçÜ¢Æý‡×æÌZ Ð]l$«§ýlŠ糧éË ]̄l$ MýS ]̄l$Vö ]̄l…yìl?
Sol: ¨Ó糧ýl çœ*™èl… 7 M>ºsìæt ÑçÜ¢Æý‡×æÌZ 7 + 1 = 8 糧éË$ E…sêƇ¬.M>ºsìæt 4, 5 糧éË$ Ð]l$«§ýlÅ糧éË$ AÐ]l#™éƇ¬(x + y)n ÑçÜ¢Æý‡×æÌZ Tr+1 = nCrx
n – ryr
ÑçÜ¢Æý‡×æÌZ
T4 = t3 + 1 = 7C3 (3x) 7 – 3 (–1/2x)3
t5 = t4+1 = 7C4 (3x)7 – 4 (–1/2x)4
381
7C x8
= ×
31
7C 81 x8
−= × × ×
14 4
37C 3 x= ( )3 3
1.2 x
−
×
3
71
3x2x
−
71
3x2x
−
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SAKSHI
3. x2 – x – 2 < 0 Ý뫨…^èl…yìl?Sol: x2 – x – 2 < 0
x2 – 2x + x – 2 < 0x (x – 2) + 1 (x –2) < 0(x + 1) (x – 2) < 0
∴ Ý뫧ýl ]̄l çÜÑ$† = {– 1 < x < 2}
4. x2 – 6x + 8 > 0 Ý뫨…^èl…yìl?Sol: x2 – 6x + 8 > 0
x2 – 4x – 2x + 8 > 0x (x – 4) – 2 (x – 4) > 0(x – 2) (x – 4) > 0
Ý뫧ýl ]̄l x ÑË$Ð]l 2, 4ËMýS$ ºÄ¶æ$r E…r$…¨ M>ºsìæt x < 2 Ìôæ§é x > 4 AÐ]l#™èl$…¨.
5. Æð‡…yýl$ Ð]lÆý‡$çÜ çÜÇçÜ…QÅË Ëºª… 168 AƇ¬™ól Ðésìæ° MýS ]̄l$MøP…yìl.Sol: Æð‡…yýl$ Ð]lÆý‡$çÜ çÜÇçÜ…QÅË$ = x, x + 2 A¯]l$MýS$…§é…
§é° ˺ª… x (x + 2) = x2 + 2x
M>° Ðésìæ ˺ª… = 168 CÐ]lÓºyìl…¨x2 + 2x = 168
⇒ x2 + 2x – 168 = 0x2 + 14x – 12x –168 = 0x (x + 14) – 12 (x + 14) = 0(x + 14) (x – 12) = 0x + 14 = 0 x – 12 = 0∴x = –14 ∴x = 12
x = 12 AƇ¬ ]̄l Ð]lÆý‡$ççÜ çÜÇçÜ…QÅË$ 12, 14x = 14 AƇ¬ ]̄l Ð]lÆý‡$ççÜ »ôæíÜçÜ…QÅË$ – 14, –12
6. ÔóæçÙ íܧ鮅™é°² °Æý‡Ó_…_, °Æý‡*í³… è̂l…yìl?Sol: °Æý‡Ó^èl¯]l…: x è̂lËÆ>ÕV> E ]̄l² AMýSÆý‡×îæĶæ$ ç³NÆ>~…MýS çÜÐ]l*çÜ… f(x) ]̄l$ (x – a)™ø ¿êWõÜ¢ Ð]l ó̂la ÔóæçÙ… f(a)
°Æý‡*ç³×æ: x è̂lÆý‡Æ>ÕV> VýSË AMýSÆý‡×îæĶæ$ ç³NÆ>~…MýS çÜÐ]l*çÜ… f(x). ©°° (x – a)™ø ¿êWõÜ¢ Ð]l ó̂la¿êVýSçœË… Q(x), R ÔóæçÙ… A ]̄l$MýS$…sôæ
427
7C16x
= ×
3 347C 3 x= × × ( )4
4 4
1
2 x
−×
× 1
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SAKSHI
f(x) = (x – a), Q(x) + Rf(a) = R
¯éË$VýS$ Ð]l*Æý‡$PË {ç³Ô¶æ²Ë$1. x4 + 4x3 + 3x2 – 4x – 4 ]̄l$ ÔóæçÙíܧ鮅™èl… Eç³Äñæ*W…_ M>Æý‡×ê…M>Ë$ MýS ]̄l$Vö ]̄l…yìl? (Ð]l*Ça 08)Sol: f(x) = x4 + 4x3 + 3x2 – 4x – 4 A¯]l$Mö¯]l…yìl
糧éË VýS$×æM>Ë Ððl¬™èl¢… = 1 + 4 + 3 & 4 & 4 = 8 & 8 = 0∴ f(x)MýS$ (x – 1) JMýS M>Æý‡×ê…MýS…x çÜÇçœ*™èl VýS$×æM>Ë Ððl¬™èl¢… = 1 + 3 & 4 = 0x »ôæíÜçœ*™èl VýS$×æM>Ë Ððl¬™èl¢… = 4 & 4 = 0çÜÐ]l*¯éË$ M>ºsìæt f(x)MýS$ (x + 1) JMýS M>Æý‡×ê…MýS…f(x)ÌZ° 糧éË VýS$×æM>Ë$ ¡çÜ$MýS$…sôæ
§ýl™èl¢ çÜÐ]l*çÜ… f(x)MýS$ M>Æý‡×æÆ>Ô¶æ$Ë$(x – 1) (x + 1) (x2 + 4x + 4)
(x – 1) (x + 1) (x + 2)2
= (x – 1) (x + 1) (x + 2) (x + 2)
2. xÌZ JMýS Ð]lÆý‡YçÜÐ]l*çÜ… x – 1, x – 2, x – 3Ë ó̂l ¿êW… è̂lºyìl ]̄l ÔóæÚëË$ Ð]lÆý‡$çÜV> 11, 22, 39. B Ð]lÆý‡YçÜÒ$MýSÆý‡×æ… MýS ]̄l$Vö ]̄l…yìl?
Sol: Ð]lÆý‡Y çÜÐ]l*çÜ… f(x) = ax2 + bx + c A¯]l$MýS$…sôæf(x) ]̄l$ (x – 1)™ø ¿êWõÜ¢ Ð]l ó̂la ÔóæçÙ… f(1) = 11
f(1) = a(1)2 + b(1) + Ca + b + c = 1 ..........(1)
f(x)l ]̄l$ x – 2™ø ¿êWõÜ¢ Ð]l ó̂la ÔóæçÙ… f (2) = 22
f(2) = a (2)2 + b(2) + cf (2) = a (2)2 + b(2) + c= 4a + 2b + c= 4a + 2b +c = 22 .........(2)
f(x) ]̄l$ x–3 ó̂l ¿êWõÜ¢ Ð]l ó̂la ÔóæçÙ… f(3) = 39
f(x) = ax2 + bx + c
x = 1 1 4 3 – 4 – 40 1 5 8 4
x = – 1 1 5 8 4 00 –1 – 4 – 4
1 4 4 0
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SAKSHI
f(3) = a(3)2 + b(3) + c= 9a + 3b + c9a + 3b + c = 39 ............(3)
(1), (2)Ë ]̄l$…_a + b + c = 1 ................(1)
4a + 2b + c = 22 ...........(2)– – – –___________________
– 3a – b = – 21 Ìôæ§é
3a + b = 21.........(4)
(2), (3)Ë ]̄l$…_4a + 2b + c = 22.....(2)9a + 3b + c = 39 .....(3)___________________
– 5a – b = – 17 Ìôæ§é
5a + b = 17.......... (5)
(4), (5)Ë ]̄l$…_5a + b = 17.....(5)3a + b = 21 .....(4)
– – – ___________________
2a = – 4 Ìôæ§é ⇒ a = – 4/2 = –2
a = – 2 ]̄l$ (4)ÌZ {糆„óSí³… è̂lV>3a + b = 213 (– 2) + b = 21– 6 + b = 21b = 21 + 6 = 27a = – 2, b = 27, c = ?a + b + c = 1 from (1)– 2 + 27 + c = 125 + c = 1c = 1 – 25 ⇒ – 24
∴ Ð]lÆý‡Y çÜÐ]l*çÜ…f(x) = ax2 + bx + c
f(x) = – 2x2 + 27x – 24 Ìôæ§éf(x) = 2x2 – 27x + 24
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SAKSHI
3. ÑçÜ¢Æý‡×æÌZ x Ìôæ° ç³§ýl… (íܦÆý‡ç³§ýl…) ]̄l$ MýS ]̄l$MøP…yìl?
Sol: ÑçÜ¢Æý‡×æÌZ n = 8
x = 6x2, y = – 5/x2
(x + y)n ÑçÜ¢Æý‡×æÌZ Tr + 1 = nCr xn – ryr
= 8Cr (6x2)8 – r (– 5/x2)r
= 8Cr (6)8 – r x 16 – 2r (– 5). x–2r
= 8Cr (6)8 – r × (– 5)r × x 16 – 2r × x –2r
= 8Cr (6)8 – r × (– 5)r × x 16 – 4r
x Ìôæ° ç³§ýl… A…sôæx 16 – 4r = x0 M>ÐéÍ.16 – 4r = 016 = 4r ⇒ r = 16/4 = 4
r = 4 ]̄l$ Tr+1ÌZ {糆„óSí³õÜ¢
ÑçÜ¢Æý‡×æÌZ x Ìôæ° ç³§ýl…
8C4 6 8 – 4 (– 5)4. x16 – 4 × 4
8C4 × 6 4 × (– 5)4 × x0
8C4 × 6 4 × 54 = 8C4 × 304
4. çÜÒ$MýSÆý‡×æç³# Ð]lÊÌêË$ MýS ]̄l$Vö ]̄l…yìl?
Sol:
( )( )( ) ( )a b x
b x 0x a b a
−⇒ − − =
− −
( )( )( )
a b xb x
x a b a
−⇒ = −
− −
bx⇒ ax bx− −( )( )
abb x
x a b a
+ = −− −
( ) ( )( )( )
x b a b x ab x
x a b a
− − −⇒ = −
− −
x bb x
x a b a− = −
− −
x bx b
x a b a+ = +
− −
x bx b
x a b a+ = +
− −
( )822
56xx
∴ −
( )822
56xx
−
( )822
56xx
−
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SAKSHI
b – x = 0 ( Ìôæ§é)
(x – a) (b – a) = a
∴ Ð]lÊÌêË$
5. VýS×ìæ™é ]̄l$VýSÐ]l$ ]̄l íܧ鮅™èl… Eç³Äñæ*W…_ A° è̂l*ç³…yìl?
(Ð]l*Ça 08, þ¯Œæ 10)
Sol:
n = 1MìS p(n) °f… A° è̂l*§éª….
n = 1 AƇ¬¯]l
∴ n = 1MìS p(n) °f….............(1)ii) p(n); nMìS °f… AÐ]l#™èl$…¨.
iii) p(n) ; n + 1MìS °f… A° è̂l*ç³yýl…
™èlÆý‡$Ðé™èl 糧ýl…
CÆý‡$OÐðlç³#Ë MýSË$ç³V>( )( )1
n 1 n 2+ +
( )( )1
n 1 n 2=
+ +( )1
n n 1+
( )1 1 1 1 n
i.e. ..... .....(2)1.2 2.3 3.4 n n 1 n 1
+ + + + =+ +
n 1 1R.H.S.
n 1 1 1 2= + = =
+ +
( ) ( ) ( )1 1 1
p 1 L.H.S.1 1 1 1 2 2
= + = =+
( ) ( )1 1 1 1 n
p n ...1.2 2.3 3.4 n n 1 n 1
= + + + + =+ +
( )1 1 1 1 n
...1.2 2.3 3.4 n n 1 n 1
+ + + + =+ +
ab,a
b a = + −
ax a
b a∴ = +
−
ax a
b a∴ = +
−
ax a
b a∴ − =
−
( )( )a
b x 1x a b a
− = − −
( )( )a
1 0x a b a
− =− −
( )( )a
b x 1 0x a b a
− − = − −
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SAKSHI
A…sôæ p(n) {ç³Ð]l è̂l ]̄l… n + 1 MýS* °f… AƇ¬…¨.(1), (2), (3)Ë ]̄l$…_ p(n) A ó̄l {ç³Ð]l è̂l ]̄l… n A°² ÑË$Ð]lËMýS$ °f… AÐ]l#™èl$…¨.
I§ýl$ Ð]l*Æý‡$PË$
1. x2 – 3x + 2= 0 ]̄l$ y = x2 Æó‡Rê_{™èl… çÜàĶæ$…™ø Ýë«̈ … è̂l…yìl?Sol: x2 – 3x + 2= 0 ⇒ x2 = 3x – 2
y = x2 = 3x – 2 A¯]l$Mö¯]l…yìl.y = x2 ; y = 3x – 2 A ó̄l Ð]l{M>Ë Q…yýl ]̄l ¼…§ýl$Ð]l#Ë x l°Æý‡*ç³M>Ë$ x2 – 3x + 2 = 0 MýS$ ÐéçÜ¢Ð]l
Ð]lÊÌêË$ AÐ]l#™éƇ¬.y = x2
{V>‹œ §éÓÆ> y = x2, y = 3x –2 çÜÆý‡â¶æÆó‡QË Q…yýl ]̄l ¼…§ýl$Ð]l#Ë$ (1, 1) (2, 4)∴ x2 – 3x + 2= 0 çÜÒ$MýSÆý‡×æ Ð]lÊÌêË$ (1, 2)
( )n 1
n 1 1
+⇒+ +
n 1
n 2
+=+
( )( )( )
( )
22 n 1n 2n 1
n 1 n 2 n 1
++ += =+ + + ( )n 2+
( )( )( )n n 2 1
n 1 n 2
+ ++ +
( ) ( )( ) ( )( )1 1 1 1 1 n 1
.....1.2 2.3 3.4 n n 1 n 1 n 2 n 1 n 1 n 2
+ + + + + = ++ + + + + +
x 0 1 2 3 –1 –2 –3
y 0 1 4 9 1 4 9
y = x2
x 0 1 2 3
y –2 1 4 7
y = 3x – 2
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2. x2 – x – 6 = 0 ]̄l$ y = x2 – x – 6 Æó‡Rê_{™èl… çÜàĶæ$…™ø Ýë«̈ … è̂l…yìl?Sol:
(– 4, 10),(–3, 6), (–2, 0), (–1, – 4), (0, – 6)
(1, – 6), (2, –10), (3, –6) (4, 6) ¼…§ýl$-Ð]l#-Ë-̄ ]l$ {V>‹œ-Oò³ _{†…^é-Í. Ðésìæ-° Ð]l$–§ýl$-OÐðl-̄ ]l Ð]l{MýS…™ø MýSÍ-í³™ólÐ]l$ ]̄l-MýS$ M>Ð]l-ÍÞ-̄ ]l Æó‡-Rê-_{™èl… Ð]lçÜ$¢…¨.x - A„ýS… Q…yýl-̄ ]l ¼…§ýl$-Ð]l#-Ë$ (4, 0), (–3, 0)
∴ Ý뫧ýl-̄ ]l çÜÑ$-† -Ñ-Ë$-Ð]l-Ë$ x = – 2, x = 3
x – 4 – 3 –2 –1 0 1 2 3 4x2 16 9 4 1 0 1 4 9 16
–x 4 3 2 1 0 –1 –2 – 3 – 4– 6 – 6 – 6 – 6 – 6 – 6 – 6 – 6 – 6 – 6y +10 + 6 0 – 4 – 6 – 6 – 4 – 0 6
y = x2 – x – 6
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SAKSHI
ºçßæ$Oâñæ_eMýS {ç³Ô¶æ²Ë$1. x2 – 3x + kMýS$ x – 2 JMýS M>Æý‡×ê…MýS… AƇ¬™ól k ÑË$Ð]l
G) 10 ¼) & 10 íÜ) 2 yìl) 52. nC6 = nC9 AƇ¬™ól n ÑË$Ð]l
G) 9 ¼) 6 íÜ) 15 yìl) 33. f(x) ]̄l$ ax + b ó̂l ¿êWõÜ¢ Ð]l ó̂la ÔóæçÙ…
G) f (–b/a) ¼) f (b/a) íÜ) f (a/b) yìl) f (– a/b)
4. K ºçßæ$糨 VýS$×æM>Ë Ððl¬™èl¢… Ô¶æ* ]̄lÅ… AƇ¬™ól §é°MìS K M>Æý‡×æÆ>ÕG) x + 1 ¼) x íÜ) – x yìl) x – 1
5. 6C4 ÑË$Ð]lG) 6 ¼) 4 íÜ) 15 yìl) 10
6. y = 2x2 Æó‡Rê_{™èl… ´ùÐ]l# ´ë§éË$G) I, II ¼) II, III íÜ) III, IV yìl) I, IV
çÜÐ]l*«§é¯éË$1) ¼ 2) íÜ 3) G 4) yìl 5) íÜ 6) G
Rêä˯]l$ ç³NÇ…^èl…yìl1. 1 < x < 3 Ý뫧ýl ]̄lË$V> E ]̄l² AçÜÒ$MýSÆý‡×æ… ______
2. x + y ó̂l xn + yn °ÔóæØçÙ…V> ¿êW… è̂lºyýlyé°MìS °Ä¶æ$Ð]l$… ______ AÐéÓÍ.3. f(x) ]̄l$ ax – b = 0 ó̂l ¿êW… è̂lV> Ð]l è̂l$a ÔóæçÙ… ______
4. JMýS ºçßæ$糨 çÜÇçœ*™èl 糧éË VýS$×æM>Ë Ððl¬™èl¢… »ôæíÜçœ*™èl 糧éË VýS$×æM>Ë Ððl¬™é¢°MìS çÜÐ]l* ]̄lOÐðl$ ]̄l§é°MìS ______ JMýS M>Æý‡×ê…MýS….
5. x2 – 2x – 15 = 0ÌZ Ð]lÊÌêË Ëºª… ______
6. ÑçÜ¢Æý‡×æÌZ _Ð]lÇ ç³§ýl… ______
çÜÐ]l*«§é¯éË$1) x2 – 4x + 3 < 0 2) n »ôæíÜçÜ…QÅ 3) f (b/a) 4) x + 1 5) – 15 6) 1/x6
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f™èlç³Æý‡^èl…yìl1. nC0 ( ) A) x – 1
2. (a + b)5 ÑçÜ¢Æý‡×æÌZ VýS$×æM>Ë Ððl¬™èl¢… ( ) B) 4
3. f(1) = 0 AƇ¬™ól f(x) MýS$ M>Æý‡×ê…MýS… ( ) C) 6
4. 10C2n = 10Cn+4 AƇ¬™ól ÑË$Ð]l ( ) D) 1
5. 6x2 –5 = 0 Ð]lÊÌêË Ððl¬™èl¢… ( ) E) 326. √3x2 + 9x + 6√3 = 0 Ð]lÆý‡Y çÜÒ$MýSÆý‡×æ Ð]lÊÌêË Ëºª… ( ) F) 0
çÜÐ]l*«§é¯éË$1. D 2. E 3. A 4. B 5. F 6. C
Quick Review Table
1. ax2 + bx + c = 0 Ð]lÊÌêË$ i)
ii)
2. ax2 + bx + c = 0 MìS Ñ è̂l„ýS×ìæ b2 – 4ac
3. ax2 + bx + c = 0 i) Ð]lÊÌêË Ððl¬™èl¢… = – b/a
ii) Ð]lÊÌêË Ëºª… = c/a
4. G) (x – α) (x – β) > 0 x ÑË$Ð]l α, βË Ð]l$«§ýlÅ E…yýl§ýl$¼) (x – α) (x – β) > 0 x ÑË$Ð]l α, βË Ð]l$«§ýlÅ E…r$…¨.
5. VýS×ìæ™é ]̄l$VýSÐ]l$ ]̄l íܧ鮅™èl… p(n) A ó̄l {ç³Ð]l è̂l ]̄l…i) n = 1MýS$ ii) 1, 2...n MýS*yé °f… A° è̂l*í³ ]̄l p(n) n A°²
ÑË$Ð]lËMýS$ °f…
6. ¨Ó糧ýl íܧ鮅™èl… (x + y)n = nC0xn + nC1x
n–1yn + nC2xn–2y2+......+nCrx
n–ryr +
....+nCnyn
7. (x + y)n ÑçÜ¢Æý‡×æÌZ tr + 1 = nCrxn–ryr
22b b 4ac
x b 4ac2a
− − −= = −
2b b 4acx
2a
− + −=