b 向量 p - web.cjcu.edu.twweb.cjcu.edu.tw/~ykchen/physics/vector.pdf · 1 向量...
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1
vector
scalar
A A
Ar
A A A A
r A A A
A A
A
P = AB
ABP =r
P A B A B
2
P
A
B
x-y A x 4 y 2
4
2 A
x
y
A = 4i + 2j
jiArrr
24 +=
i j ir
jr x y unit
vector 1
jiArrr
24 +=
A = 4i + 2j
A i j i 1
3
A = 4i + 2j
A = (4, 2)
A = (4i, 2j)
4
24
24
2
A = 4i + 2j i 4 x component
projection x j 2 y y
-3i + 3j4i + 2j
-4i - 2j
i - 4j
4
A = Axi + Ayj
Ax x Ax Ay y Ay x y x y 1 i + 4j 1i + 4j
x y 0
4i -2i
j -4j
0 4i + 0j
i j x y 1 x-y-z k k
r z
A = i -3j + 4k x 1 y -3 y 3 z 4
x
y
z
O
4
1-3
1-3
A = i -3j + 4k
5
x-y x-y-z z = 0 x-y A = 4i + 2j A = 4i +2j + 0k
A = Axi + Ayj + Azk A
x y z
x z
y
i j k x y z
A = Axi + Ayj + Azk AxAy Az scalar component
magnitude x-y
A = Axi + Ayj
22yx AAA +== A
Ax Ay A
6
Ax
Ay
A
x
y
| |
A = Axi + Ayj + Azk
222zyx AAAA ++== A
( ) 22222 zyxzxy AAAAAA ++=+== A
x
y
z
O
Az
AxAy
A = 2i 3j
( ) 133232 22 =+== jiA
7
B = i +4j -6k
( ) 5364164 222 =++=+= kjiA
+x
+x 0
x
y
A
Ax
Ay
A
0
x
y
AA
=tan
x
y
AA1tan=
-90 o 90 o /2 /2
A = 2i + 3j = tan-1(3/2) = 56.3 o
B = 2i 3j = tan-1(-3/2) = -56.3 o
8
> 90 o < -90 o > /2 < -/2 Ax < 0
o180tan 1 = x
y
AA
180 o
C = -2i + 3j tan-1(3/-2) 180 o = 123.7 o -236.3 o
360 o 123.7 o
D = -2i - 3j tan-1(-3/-2) 180 o = -123.7 o 236.3 o
360 o -123.7 o
A = 2i + 3j
x
y
= 56.3
= -56.3
B = 2i - 3j
C = -2i + 3j
D = -2i - 3j
56.3
= 180 - 56.3= 123.7
56.3= -180 + 56.3= -123.7
= 56.3 o = -123.7 o tan = 1.5 = 3/2 = tan-1 (Ay/Ax) = tan-1(3/2) tan = 3/2 Ax 180 o
A = Axi + Ayj
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tan-1 x Ax
x
y
A
Ax
Ay
A
Ax = Acos
Ay = Asin
A A
A = Axi + Ayj = Acos i + Asin j
5 50 o
A = 5cos50 o i + 5sin50 o j = 3.21i + 3.83j
cos50 o sin50 o
10
x
y A
A = 335
x
y A
A = 335
= 90 - 35 = 65
A y 35 o x +x 90 o - 35 o = 65 o A = 3
A = 3cos65 o i + 3sin65 o j = 1.27i + 2.72j
+x
50
= 180 - 50 = 130
x
y
= 90 + 45 = 135
x
y
45
20
= -90 - 20 = -110
15
= -180 + 15 = -165
11
r b a
a
b
rb
=sin
ra
=cos
ab
=tan
b = rsin Ay = Asin
a = rcos Ax = Acos
b = atan
cos cos
sin2 + cos2 = (b/r)2 + (a/r)2 = (a2 + b2)/r2 = r2/r2 = 1
a2 + b2 = r2
tan = b/a = (b/r)/(a/r) = sin /cos
sin(90 o - ) = cos 90 o -
cos(90 o - ) = sin 90 o -
tan sin cos tan
12
sin0 = 0 b = 0
cos0 = 1 b = 0 a = r
sin90 o = 1 a = 0 b = r
cos90 o = 0 a = 0
0 o 90 o sin cos
x = rcos r
y = rsin r
= 150
r
x
y30
= 150 o II x y cos = x/r sin = y/r |cos150 o | = |x|/r = cos 30 o = sin60 o cos150 o = cos30 o ;| sin150 o |=|y|/r = sin30 o sin150 o = sin30 o = cos60 o
sin210 o = -sin30 o = -cos60 o cos210 o = -cos30 o = -sin60 o
sin(-) = -sin
cos(-) = cos
x cos = x/r y sin = y/r
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x y
-y
r sin cos -1 1 r tan = 90 o -90 o tan tan = sin /cos cos 0
CBA =
B = AC
cos = a/r a = rcos
= / => =
= / => =
= / => =
= / => =
= / => =
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position r displacement r velocityv accelerationa forceF momentump impulseI torque
r r = |r| r |r| r
P (x, y, z) O P
r = OP = xi + yj +zk
P position vector P xi + yj + zk (x, y, z)
A = Axi + Ayj + Azk
B = Bxi + Byj + Bzk
A + B = (Axi + Ayj + Azk) + (Bxi + Byj + Bzk)
= (Ax + Bx)i + (Ay + By)j +(Az + Bz)k
A = 2i -3kB = -i + 2j A + B = (2i + 0j 3k) + (-i + 2j + 0k) = (2 -1)i + (0 + 2)j + (-3 + 0)k = i + 2j 3k
x-y
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A = 2i + 3j
B = -i +2j
AB
A + B
16
AB
B
B A A + B
A
B B
A
A B A + B B A
AB A B + BC B C = AC A C
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A = 2.00i + 3.00j m B = i + 2.00j m C = A + B = (2.00 1.00)i + (3.00 + 2.00)j m = 1.00i + 5.00j m
F1 = 2.00i + 3.00j N F2 = -i + 2.00j N net forceresultant force F = F1 + F2 = 1.00i + 5.00j N
F1
F2
F1+F2
A = 2.00 mi + 3.00 mj A = 2.00i + 3.00j m
(2.00 m, 3.00 m) (2.00, 3.00) m
A + B = B + A
(A + B) + C = A + (B + C)
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A
B
A
B
C
A
B
C
A + B = B + A A + (B + C) = (A + B) + C
A = 2i + 3j 2i 3j
2i 3j A x y vector component 2 3 scalar component
2i
3j
A A A = Axi + Ayj A = -Axi AyjA = 2i 3j -A = -2i + 3j
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A
-A
Ax
Ay
-Ax
-Ay
i i i i x 1
F12 2 1 F21 1 2 F12 = -F21
A = B A = Axi + Ayj + AzkB = Bxi + Byj + Bzk A = B Ax = BxAy = By Az = Bz
A
BAx
Ay
Bx
By
20
0
0 0 0i + 0j + 0k0
A B A + (-B) A B A = 2i + 3jB = i - 5jA B = A + (-B) = (2i + 3j) + (-i + 5j) = (2 1)i + (3 (-5))j = i + 8j
A B = (Ax Bx)i + (Ay By)j + (Az Bz)k
A B
A
B
-B
A B = A + (-B)
A - B
B -B B A A B = A + (-B) A B B A A B
A B A B B A
A B A B
P1 P2 (x1, y1, z1) (x2, y2, z2) r1 = OP1 = x1i + y1j + z1k r2 = OP2 =
21
x2i + y2j + z2kP2 P1 P1 P2 P1P2 = OP2 OP1 = r2 r1 = (x2 x1)i + (y2 y1)j + (z2 z1)k OP2 = OP1 + P1P2 r21 = r2 r1 P2 P1 P1 P2
(1) A (2, -1) B (3, 2) A B AB = (3 2)i + (2 (-1))j = i + 3j BA = -i 3j AB
(2) OP1 (x1 0)i + (y1 - 0)j + (z1 0)k P1 0
ri rf i f initial final r = rf ri
A vA B vB B A vBA = vB vA
(1) F1F2 F3
equilibrium 0 F = F1 + F2 + F3 = 0 F1 F2 F3 = -F1 F2
(2) r1r2 r3 r1 + r2 + r3 = 0 r1 r2 r3 = - r1 - r2
a A aA A |a| A a < 0
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A 2A
-2A
A/2
-A/2
aA Aa a A
3i 4j 3i +x 1 -4j +y y 4
F = ma F m
a p = mv v
1 ij k A A A A 1
eA = A/A = A/|A|
A k
keA = kA/A
A = 2i 6j + 2k
A = |A| = ( ) 44262 222 =++
A
eA = A/A = (2i 6j + 2k)/ 44 = 0.302i 0.905j + 0.302k
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A 5.00
5eA = (5.00)( 0.302i 0.905j + 0.302k) = 1.51i - 4.52j + 1.51k
+x +y O 10.0 km 5.00 km A 50 o 8.00 km B C 20 o 6.00 km
CB CB =
x
y
O
A
B
50 C
10.0 km
5.00
km
20
?
?
(1) A (10.0, 5.00) km (2) OA = 10.0i + 5.00j km (3) AB +x = 90 o + 50 o = 140 o
(4) AB = (8.00 km)(cos140 o i + sin140 o j) = -6.13i + 5.14j km (5) OB = OA + AB = (10.0i + 5.00j) + (-6.13i + 5.14j)
= 3.87i + 10.14j km (6) B (3.87, 10.14) km (7) OC 90 o - 20 o = 70 o (8) OC = (6.00 km)(cos70 o i + sin70 o j) = 2.05i + 5.64j km (9) (2.05, 5.64) km (10) CB = OB OC = (3.87i + 10.14j) (2.05i + 5.64j) = 1.82i + 4.50j km
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(11) CB = |CB| = 22 50.482.1 + = 4.85 km (12) CB = tan-1(4.50/1.82) = 68 o 68 o CB
x 180 o
+= cos2222 abbac
ba
= sinsin
ab c
A(-2, 3) m B(2, 1) m F = 5.00 N F =
x
y
A
B
A B B A A B BA = OA OB = (-2i + 3j) (2i + j) = -4i + 2j m
AB A B AB = ( ) 2024 22 =+ m AB F e = AB/AB = (-4i + 2j)/ 20 = -0.894i + 0.447j F = Fe = (5.00)(-0.894i + 0.447j) = -4.47i + 2.24j N
BA = tan-1(2/-4) + 180 o = 153.4 o BA F AB F = F(cos153.4 o i + sin153.4 o j) = (5.00)( cos153.4 o i + sin153.4 o j) = -4.47i + 2.24j N
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x
y
A
B
153.4
A (1, 3, -2) mB (2, 0, 5) m F 5.00 NF = -0.651i + 1.95j 4.56k N
= cosABBA
A = |A|B = |B| dot product
scalar product
BA AB
A Bcos B Acos
B
AABcos
B
B
AA
B
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BA//= BA
AB//= BA
= cos// AA A B = cos// BB B A
A B = 0 ocos = cos0 o = 1 A
B = 90 ocos = cos90 o = 0 0
ij k 1 1 |i| = |j| = |k| = 1
ij k
i j = j i = j k = k j = k i = i k = 0
i i = |i||i|cos0 o = (1)(1)(1) = 1
j j = k k = 1
A = Axi + Ayj + AzkB = Bxi + Byj + Bzk
A B = (Axi + Ayj + Azk) ( Bxi + Byj + Bzk)
= AxBx (i i) + AxBy (i j) + AxBz (i k) + AyBx (j i) + AyBy (j j)
+ AyBz (j k) + AzBx (k i) + AzBy (k j) + AzBz (k k)
= AxBx (i i) + AyBy (j j) + AzBz (k k) 0
= AxBx + AyBy+ AzBz
A = -i + 3kB = 2i + j + 2k A B = (-i + 0j + 3k) (2i + j + 2k) = (-1)(2)
+ (0)(1) + (3)(2) = -2 + 0 + 6 = 4
A B = B A
A B = ABcos A B = ABcos(-) = ABcos F
27
r work W = F r energy F W = 0 F = 0r = 0W 0
A(1, 0, 2)B(0, 2, 3) C(1, 4, -1) A A AB = OB OA = (0-1)i + (2-0)j + (3-2)k = -i + 2j + kAC = OC OA = (1-1)i + (4 0)j + (-1-2)k = 4j 3k
AB AC = (-i + 2j + k) (0i + 4j 3k) = (-1)(0)+(2)(4) +(1)(-3) = 5
AB = |AB| = ( ) 6121 222 =++
AC = |AC| = ( ) 25340 222 =++ = 5
AB AC = |AB||AC|cos
AB AC A
cos = ( )( ) 61
565
==ACABACAB
-1 1
A = = o9.656
1cos 1 =
0 0 -90 o < < 90 o cos < 0 cos 0 0
BA = 0 A B 0 A B BA > 0A B BA < 0A B
A B A B
28
|A B| = ABsin
A = |A|B = |B| A B A B
A B A B A B A B
B A = -(A B)
A B = 0 o 180 o sin o = 0 0 |A B| = ABsin = 0 0 0
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B A = A B
B A = -(A B)
cross product
vector product
()() = ()
() () = ()
() () = ()
ij k sin0 o = 0
i i = j j = k k = 0 0
i j x y = 90 osin90 o = 1
| i j | = |i||j|sin90 o = (1)(1)(1) = 1
x-y-z i j z 1
i j = k
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i j = k j k = i k i = j
j i = -k k j =- i i k = -j
A = -i + 3j + 2kB = 2j 3k
A B = (-i + 3j + 2k) (2j 3k) = (-1)(2)(i j) + (-1)(-3)( i k)
+ (3)(2)(j j) + (3)(-3)(j k) + (2)(2)( k j) + (2)(-3)( k k)
= (-1)(2)(i j) + (-1)(-3)( i k) + (3)(-3)(j k) + (2)(2)( k j)
= -2k + 3(-j) 9i +4(-i) = -13i -3j -2k
A B 0 0 A B
(A B) A = (-13i -3j -2k) (-i + 3j + 2k) = (-13)(-1) + (-3)(3)+(-2)(2)
= 13 9 4 = 0
(A B) B = (-13i -3j -2k) (0i + 2j 3k) = (-13)(0) + (-3)(2)+(-2)(-3)
= 0 6 + 6 = 0
31
ijk
ij k
ij k j k j k i +i
i
j+
k
i x j = k
i
j+
k
j x k = i
i
j+
k
k x i = j
i
j
k
j x i = -k
i
j
k
k x j = -i
i
j
k
i x k = -j
ijkijk
i j k i j k i x j = k
i j k i j k j x k = k
i j k i j k k x i = j
i j k i j k k x j = -i
i j k i j k j x i = -k
i j k i j k i x k = -j
i j k i j k
A = Axi + Ayj + AzkB = Axi + Ayj +
Azk
( ) ( ) ( )kjikji
BA xyyxzxxzyzzyzyx
zyx BABABABABABABBBAAA ++==
32
kjikji
BA 2313320
231 =
=
A B 6
A B x-y
x-y z A = 2i jB = -i + 3j A B = 6k k = 5k z z 5k k z x-y
x
y
z
A
B
A x B
x
y
z
B
A
A x B
A B |A B | = ABsin A B ABsin = A Bsin B Asin
33
A
B
A
= ABsin
A
B
A
= Absin/2
= |A B| A B |A B|/2
OABC OAB C (0, 0), (3, 0), (4, 3) (1, 4))
x
y
O(0, 0) A(3, 0)
B(4, 3)
C(1, 4)
OABC OAC ABC OABC (1) OA = 3i (2) OC = i + 4j(3) OA OC = (3i) ( i + 4j) = (3)(4)(i j) = 12k (4) |OA OC | = 12(5) OAC = |OA OC |/2 = 6 (6) AB = OB OA = (4i + 3j) 3i = i + 3j (7) AC = OC OA = (i + 4j) 3i =-2i + 4j (8) AC AB = (-2i + 4j) (i + 3j) = (-2)(3)(k) + (1)(4)(-k) = -10k(9) |AB AC| = 10 (10) ABC = |AB AC |/2 = 5 (11) OABC = OAC + ABC =
6 + 5 = 11 A B A B
34
A 3.00 m D
O
xy
z
A(0, 0, 3) m
B(8, 0, 8) mC(0, 4, 6) m
D
(1) AB = OB OA = (8i + 8k) (3k) = 8i + 5k m (2) AC = OC OA = (4j + 6k) (3k) = 4j + 3k m (3) AD AB AC
AB AC AB AC = (8i + 5k) (4j + 3k) = (8)(4)k + (8)(3)(-j) + (5)(4)(-i) = -20i 24j + 32k m2 AB AC AC AB = -(AB AC) = 20i + 24j - 32k m2 -20i 24j + 32k z 32 AD z z
(4) |AB AC| = ( ) ( ) 7.442000322420 222 ==++ m (5) AD AB AC
eAD = 2000
322420 kjiACAC +
= = -0.447i - 0.537j + 0.716k
(6) AD = (3.00 m)eAD = (3.00 m)( -0.447i - 0.537j + 0.716k) = -1.34i 1.61j + 2.15k m
(7) OD = OA + AD = 3k + (-1.34i 1.61j + 2.15k) = -1.34i 1.61j +5.15k m (8) D (-1.34, -1.61, 5.15) m (9) ABC =
= r Fr F
r F x-y z
35
v = r r
F = qv B q v B
0 0 0
A = (Ax, Ay, Az) A = Axi + Ayj + Azk