bai3 cac ppxs thuong gap
DESCRIPTION
^^TRANSCRIPT
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Bi 3Cc phn phi xc sut thng gp
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Phn phi nh thcPhp th BernoulliXt mt th nghim ch c 2 kh nng xy ra: thnh cng hoc tht bi.Thnh cng vi xc sut p.Tht bi vi xc sut 1-p. Th nghim nh vy gi l php th Bernoulli, k hiu B(1,p).
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Phn phi nh thcPhp th Bernoulli v d.Tung ng xu: hnh / s.Mua v s: trng / khng trng.Tr li ngu nhin 1 cu trc nghim: ng / sai.Kim tra ngu nhin hng ha: tt / xu.
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Phn phi nh thcPhn phi nh thcThc hin php th Bernoulli B(1,p) n ln c lp. tX = S ln thnh cng trong n ln th nghimX = 0, 1, 2, , n.X c phn phi nh thc vi tham s p.K hiu: X ~ B(n,p).
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Phn phi nh thcCng thcXt X ~ B(n,p)
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Phn phi nh thcV dCho X ~ B(5,0.1)Tnh P(X=1)
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Phn phi nh thcHnh dng ca phn phi nh thc s ph thuc vo p v n.Meann = 5 v P = 0.1n = 5 v P = 0.5
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Phn phi nh thcNu X ~ B(n,p):1) Trung bnh2) Phng sai v lch tiu chun n: s ln thc hin th nghim - p: xc sut thnh cng 1 ln th nghim- q = 1- p.
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Phn phi nh thcn = 5 P = 0.1n = 5 P = 0.5Mean 0.2.4.6012345xP(x).2.4.6012345xP(x)0V d
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Phn phi PoissonS cc bin c xy ra trong mt khong thi gian cho trc.S cc bin c trung bnh trn mt n v l .V dS ngi xp hng tnh tin siu th, s cuc in thoi n bu in trong 1 ngy, s my tnh h trong 1 ngy 1 khu vc,
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Phn phi PoissonBin ngu nhin X nhn gi tr t 0, 1, 2, gi l c phn phi Poisson vi tham s nu
k = 0, 1, 2,
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Phn phi PoissonTrung bnh
Phng sai v lch tiu chunVi = s bin c xy ra trung bnh trn 1 n v
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Phn phi PoissonV dTrong mt nh my dt, bit s ng si b t trong 1 gi c phn phi Poisson vi trung bnh l 4. Tnh xc sut trong 1 gi ca. ng 3 ng si b t.b. C nhiu hn 1 ng si b t.
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Bng tra phn phi PoissonV d: Tm P(X = 2) nu = .50
X0.100.200.300.400.500.600.700.800.90012345670.90480.09050.00450.00020.00000.00000.00000.00000.81870.16370.01640.00110.00010.00000.00000.00000.74080.22220.03330.00330.00030.00000.00000.00000.67030.26810.05360.00720.00070.00010.00000.00000.60650.30330.07580.01260.00160.00020.00000.00000.54880.32930.09880.01980.00300.00040.00000.00000.49660.34760.12170.02840.00500.00070.00010.00000.44930.35950.14380.03830.00770.00120.00020.00000.40660.36590.16470.04940.01110.00200.00030.0000
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Phn phi xc sut PoissonP(X = 2) = .0758 = .50
X =0.50012345670.60650.30330.07580.01260.00160.00020.00000.0000
Chart2
0.6065306597
0.3032653299
0.0758163325
0.0126360554
0.0015795069
0.0001579507
0.0000131626
0.0000009402
x
P(x)
Histogram
0
0.6065306597
0.3032653299
0.0758163325
0.0126360554
0.0015795069
0.0001579507
0.0000131626
0.0000009402
0.0000000588
0.0000000033
0.0000000002
0
0
0
0
0
0
0
0
0
0
Number of Successes
P(X)
Histogram
Poisson2
Poisson Probabilities for Customer Arrivals
Data
Average/Expected number of successes:0.5
Poisson Probabilities Table
XP(X)P(=X)
00.6065310.6065310.0000000.3934691.000000
10.3032650.9097960.6065310.0902040.393469
20.0758160.9856120.9097960.0143880.090204
30.0126360.9982480.9856120.0017520.014388
40.0015800.9998280.9982480.0001720.001752
50.0001580.9999860.9998280.0000140.000172
60.0000130.9999990.9999860.0000010.000014
70.0000011.0000000.9999990.0000000.000001
80.0000001.0000001.0000000.0000000.000000
90.0000001.0000001.0000000.0000000.000000
100.0000001.0000001.0000000.0000000.000000
110.0000001.0000001.0000000.0000000.000000
120.0000001.0000001.0000000.0000000.000000
130.0000001.0000001.0000000.0000000.000000
140.0000001.0000001.0000000.0000000.000000
150.0000001.0000001.0000000.0000000.000000
160.0000001.0000001.0000000.0000000.000000
170.0000001.0000001.0000000.0000000.000000
180.0000001.0000001.0000000.0000000.000000
190.0000001.0000001.0000000.0000000.000000
200.0000001.0000001.0000000.0000000.000000
&A
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Poisson2
0
0
0
0
0
0
0
0
x
P(x)
Poisson
Poisson Probabilities for Customer Arrivals
Data
Average/Expected number of successes:0.1
Poisson Probabilities Table
XP(X)P(=X)
00.90480.9048370.0000000.0951631.000000
10.09050.9953210.9048370.0046790.095163
20.00450.9998450.9953210.0001550.004679
30.00020.9999960.9998450.0000040.000155
40.00001.0000000.9999960.0000000.000004
50.00001.0000001.0000000.0000000.000000
60.00001.0000001.0000000.0000000.000000
70.00001.0000001.0000000.0000000.000000
&A
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Sheet1
Sheet2
Sheet3
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Phn phi PoissonHnh dng ca phn phi Poisson ph thuc vo tham s : =0.50 =3.00
Chart3
0.0497870684
0.1493612051
0.2240418077
0.2240418077
0.1680313557
0.1008188134
0.0504094067
0.0216040315
0.0081015118
0.0027005039
0.0008101512
0.0002209503
x
P(x)
Histogram
0
0.6065306597
0.3032653299
0.0758163325
0.0126360554
0.0015795069
0.0001579507
0.0000131626
0.0000009402
0.0000000588
0.0000000033
0.0000000002
0
0
0
0
0
0
0
0
0
0
Number of Successes
P(X)
Histogram
Poisson2
Poisson Probabilities for Customer Arrivals
Data
Average/Expected number of successes:3
Poisson Probabilities Table
XP(X)P(=X)
00.0497870.0497870.0000000.9502131.000000
10.1493610.1991480.0497870.8008520.950213
20.2240420.4231900.1991480.5768100.800852
30.2240420.6472320.4231900.3527680.576810
40.1680310.8152630.6472320.1847370.352768
50.1008190.9160820.8152630.0839180.184737
60.0504090.9664910.9160820.0335090.083918
70.0216040.9880950.9664910.0119050.033509
80.0081020.9961970.9880950.0038030.011905
90.0027010.9988980.9961970.0011020.003803
100.0008100.9997080.9988980.0002920.001102
110.0002210.9999290.9997080.0000710.000292
120.0000550.9999840.9999290.0000160.000071
130.0000130.9999970.9999840.0000030.000016
140.0000030.9999990.9999970.0000010.000003
150.0000011.0000000.9999990.0000000.000001
160.0000001.0000001.0000000.0000000.000000
170.0000001.0000001.0000000.0000000.000000
180.0000001.0000001.0000000.0000000.000000
190.0000001.0000001.0000000.0000000.000000
200.0000001.0000001.0000000.0000000.000000
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Poisson2
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0
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0
0
0
0
0
x
P(x)
Poisson
0
0
0
0
0
0
0
0
0
0
0
0
x
P(x)
Sheet1
Poisson Probabilities for Customer Arrivals
Data
Average/Expected number of successes:0.1
Poisson Probabilities Table
XP(X)P(=X)
00.90480.9048370.0000000.0951631.000000
10.09050.9953210.9048370.0046790.095163
20.00450.9998450.9953210.0001550.004679
30.00020.9999960.9998450.0000040.000155
40.00001.0000000.9999960.0000000.000004
50.00001.0000001.0000000.0000000.000000
60.00001.0000001.0000000.0000000.000000
70.00001.0000001.0000000.0000000.000000
&A
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Sheet2
Sheet3
Chart2
0.6065306597
0.3032653299
0.0758163325
0.0126360554
0.0015795069
0.0001579507
0.0000131626
0.0000009402
x
P(x)
Histogram
0
0.6065306597
0.3032653299
0.0758163325
0.0126360554
0.0015795069
0.0001579507
0.0000131626
0.0000009402
0.0000000588
0.0000000033
0.0000000002
0
0
0
0
0
0
0
0
0
0
Number of Successes
P(X)
Histogram
Poisson2
Poisson Probabilities for Customer Arrivals
Data
Average/Expected number of successes:0.5
Poisson Probabilities Table
XP(X)P(=X)
00.6065310.6065310.0000000.3934691.000000
10.3032650.9097960.6065310.0902040.393469
20.0758160.9856120.9097960.0143880.090204
30.0126360.9982480.9856120.0017520.014388
40.0015800.9998280.9982480.0001720.001752
50.0001580.9999860.9998280.0000140.000172
60.0000130.9999990.9999860.0000010.000014
70.0000011.0000000.9999990.0000000.000001
80.0000001.0000001.0000000.0000000.000000
90.0000001.0000001.0000000.0000000.000000
100.0000001.0000001.0000000.0000000.000000
110.0000001.0000001.0000000.0000000.000000
120.0000001.0000001.0000000.0000000.000000
130.0000001.0000001.0000000.0000000.000000
140.0000001.0000001.0000000.0000000.000000
150.0000001.0000001.0000000.0000000.000000
160.0000001.0000001.0000000.0000000.000000
170.0000001.0000001.0000000.0000000.000000
180.0000001.0000001.0000000.0000000.000000
190.0000001.0000001.0000000.0000000.000000
200.0000001.0000001.0000000.0000000.000000
&A
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Poisson2
0
0
0
0
0
0
0
0
x
P(x)
Poisson
Poisson Probabilities for Customer Arrivals
Data
Average/Expected number of successes:0.1
Poisson Probabilities Table
XP(X)P(=X)
00.90480.9048370.0000000.0951631.000000
10.09050.9953210.9048370.0046790.095163
20.00450.9998450.9953210.0001550.004679
30.00020.9999960.9998450.0000040.000155
40.00001.0000000.9999960.0000000.000004
50.00001.0000001.0000000.0000000.000000
60.00001.0000001.0000000.0000000.000000
70.00001.0000001.0000000.0000000.000000
&A
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Sheet1
Sheet2
Sheet3
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nh l PoissonCho X ~ B(n,p)
Dng phn phi Poisson xp x phn phi nh thc khi n >> p.
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M hnh PoissonM hnh Poisson :+ Xt n php th Bernoulli. + Trong xc sut thnh cng l p.+ Cc php th c lp vi nhau.(Kt qu ca php th ny khng nh hng n kt qu ca cc php th kia)+ X s ln xut hin thnh cng trong n phpth.+ Trong n ln ( n 100) v p nh (p 0,01v np 20). Khi X ~ P(). Vi =np
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M hnh PoissonV dTrong mt t tim chng cho 2000 tr em mt khu vc. Bit xc sut 1 tr b phn ng vi thuc khi tim l 0.001. Tnh xc sut trong 2000 tr c khng qu 1 tr b phn ng khi tim thuc.
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Phn phi uTt c cc kh nng c th xy ra ca bin ngu nhin c phn phi u c xc sut bng nhau.X c phn phi u trong khong [a,b], k hiu X ~ U([a,b]).xminxmaxxf(x)Tng din tch min gii hn bi phn phi u l 1.0
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Phn phi uHm mt xc sut ca phn phi u trong on [a,b]f(x) =vif(x) = gi tr hm mt ti im xa = gi tr nh nht ca xb = gi tr ln nht ca x
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Phn phi uK vng
Phng sai
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Phn phi uV d: Phn phi u trn khong 2 x 626.25f(x) = = .25 for 2 x 66 - 21xf(x)
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Phn phi mBin ngu nhin T (t>0) gi l c phn phi m nu c hm mt xc sut
Vi s bin c xy ra trung bnh trong mt n v thi gian.t s n v thi gian cho n bin c k tip.e = 2.71828K hiu: T ~ exp(), T l khong thi gian gia 2 ln xy ra cc bin c.
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Phn phi mHm phn phi xc sut
K vng v phng sai
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Phn phi mV d: S khc hng n mt quy dch v vi t l l 15 ngi mt gi. Hi xc sut thi gian gia 2 khch hng lin tip n quy dch v t hn 3 pht l bao nhiu.Trung bnh c 15 khch hng n trong 1 gi, do = 153 pht = 0.05 giT: thi gian gia 2 khch hng lin tip n quy.P(T < .05) = 1 e- t = 1 e-(15)(.05) = 0.5276Vy c khong 52,76% khong thi gian gia 2 khch hng lin tip n lm dch v ti quy t hn 3 pht.
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Phn phi mV d: Trong mt nh my sn xut linh kin in t, bit tui th ca mt mch in l bin ngu nhin c phn phi m vi tui th trung bnh l 6,25 nm. Nu thi gian bo hnh ca sn phm l 5 nm. Hi c bao nhiu % mch in ca nh my khi bn ra th trng phi thay th trc thi gian bo hnh.
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Phn phi chunBin ngu nhin X nhn gi tr trong R gi l c phn phi chun vi tham s v 2 nu hm mt xc sut
Vi: EX = v VarX = 2.K hiu: X ~ N(, 2)
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Phn phi chun Dng nh mt ci chung C tnh i xng Trung bnh = Trung v = Mode V tr ca phn phi c xc nh bi k vng, phn tn c xc nh bi lch tiu chun, Xc nh t + to Trung bnh = Trung v = Mode
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Phn phi chunBng vic thay i cc tham s v , ta nhn c nhiu dng phn phi chun khc nhau
Chart3
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-
Phn phi chunxf(x)Thay i dch chuyn phn phi qua tri hoc phiThay i lm tng hoc gim phn tn.
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Hm phn phi ca phn phi chunXt bin ngu nhin X c phn phi chun vi trung bnh v phng sai 2 , X~N(, 2), hm phn phi ca X l
f(x)
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Xc sut ca phn phi chunXc sut X (a,b) o bi din tch gii hn bi ng cong chun.ba
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Xc sut ca phn phi chun
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Phn phi chun haXt bin ngu nhin X ~ N(, 2). Chun ha X bng cch t
Khi EZ = 0 v VarZ = 1. Ta ni Z c phn phi chun ha. K hiu
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Phn phi chun haNu X c phn phi chun vi trung bnh l 100 and lch tiu chun l 50, th gi tr ca Z ng vi X = 200 l
Z1002.00200X( = 100, = 50)( = 0, = 1)
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Phn phi chun haHm mt
Hm phn phi
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Tnh xc sut
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Tnh xc sut
- Tra bng chun ha N(0,1) tm xc xut P(X
- Tra bng chun ha N(0,1)P(Z
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Tra bng chun ha N(0,1)V d: P(Z < 2.00) = (2.00) = .9772Z02.00.9772Do tnh i xng(-z) = 1 - (z) V d: P(Z < -2.00) = (-2.00)= 1 (2.00) = 1 - 0.9772 = 0.0228
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V dGi s X c phn phi chun vi trung bnh l 8.0 v lch tiu chun 5.0. Tm P(X < 8.6).X8.68.0
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V dZ0.12 0X8.6 8 = 8 = 10 = 0 = 1P(X < 8.6)P(Z < 0.12)
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V dZ0.12z(z).10.5398.11.5438.12.5478.13.5517(0.12) = 0.5478Tra bng chun ha0.00= P(Z < 0.12)P(X < 8.6)
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V dGi s X c phn phi chun vi trung bnh 8.0 v lch tiu chun 5.0. Tm P(X > 8.6)
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V dTm P(X > 8.6)Z0.12 0Z0.5478 01.0001.0 - 0.5478 = 0.4522 P(X > 8.6) = P(Z > 0.12) = 1.0 - P(Z 0.12) = 1.0 - 0.5478 = 0.45220.12
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Quy tc k -
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Xp x phn phi nh thc bng phn phi chunCho X ~ B(n,p). Khi n ln v p khng qu gn 0 v 1.Tnh P(X < c)?Tnh P(a < X < b)?Dng phn phi chun.
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Xp x phn phi nh thc bng phn phi chunt = EX = np2 = VarX = np(1-p)To bin ngu nhin Z c phn phi chun ha t phn phi nh thc
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Xp x phn phi nh thc bng phn phi chun
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Xp x phn phi nh thc bng phn phi chunV dTrong mt cuc bu c mt thnh ph, bit rng 40% ngi dn ng h ng c vin A. Chn ngu nhin 200 ngi, hi xc sut gp c t 76 n 80 ngi ng h ng c vin A l bao nhiu?
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V d
E(X) = = nP = 200(0.40) = 80Var(X) = 2 = nP(1 P) = 200(0.40)(1 0.40) = 48