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EE5712 Power System Reliability :: Introduction to Stochastic Process Panida Jirutitijaroen 1 9/3/2010 EE5712 Power System Reliability

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EE5712 Power System Reliability:: Introduction to Stochastic Process

Panida Jirutitijaroen

19/3/2010 EE5712 Power System Reliability

Announcement

• In-class mid-term exam: September 17th.

– Material: from the beginning to last week.

• Homework2 due today.

• No new homework assignment today!

• See updated syllabus.

29/3/2010 EE5712 Power System Reliability

Last Lecture

• Reliability theory– Failure distribution– Survival function– Hazard rate function

• Reliability Measure• Simple reliability analysis

– Probability convolution method– Series/parallel system– Conditional probability approach– Cut-set/Tie-set method

• Input: failure probability of each component• Output: failure probability of a system

39/3/2010 EE5712 Power System Reliability

Structure

• System is called ‘structure’ by definition when the followings apply.

– Only 2-state components: Up or Down.

– System has only 2 states: Up or Down.

4

UP DOWN

λ(t)

μ(t)

9/3/2010 EE5712 Power System Reliability

Observation of A Component

5

Time

Z(t)

0

1

2

Time

Z(t)

0

1

2

9/3/2010 EE5712 Power System Reliability

Today’s Lecture

• So far, we only concern about a random variable at a fixed time.

• Today, we will consider a random variable that evolves with time.

• With multiple states components/subsystems.• Question:

– What is the probability distribution at time t?– What is the average time that a system will visit a

certain state?

• We’ll use stochastic process to describe the system’s behavior.

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OUTLINE

Stochastic process

Markov chain

Markov process

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STOCHASTIC PROCESS

Definition

Types of stochastic process

Independent process

Markov property

Time-homogeneous property

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Recall: Two Transmission Lines

Line 1

Line 2

Line 1

Line 2

Line 1

Line 2

Line 1

Line 2

(1 Up, 2 Up)

(1 Up, 2 Down)

(1 Down, 2 Up)

(1 Down, 2 Down)

Outcomes Random Variable

Z(t) = 0

Z(t) = 1

Z(t) = 299/3/2010 EE5712 Power System Reliability

Example of Stochastic Process

• Three identical and independent systems of two transmission lines. At time 0, both links are up. Observe three systems in 24 hours.

Time

Z(t)

0

1

2

Realizations of a stochastic process109/3/2010 EE5712 Power System Reliability

Stochastic Process

• Z(t) is a state of the process at time t.

• Z(t) is a random variable.

• Discrete time process, t is discrete.

• Continuous time process, t is continuous.

A collection of random variables.

TttZ ,

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Types of Stochastic Process

Continuous RV

Continuous time process

Discrete RV

Continuous time process

Continuous RV

Discrete time process

Discrete RV

Discrete time process

Primary interest of power system reliability129/3/2010 EE5712 Power System Reliability

Discrete RV Discrete Time Process

Primary interest is to determine probability distribution of Zn+1.

3

2

1

Z0 Z1 Zn Zn+1

Pr{Z0 = 3} = 0.0

Pr{Z0 = 2} = 0.0

Pr{Z0 = 1} = 1.0

3

2

1

3

2

1

3

2

1

Pr{Zn = 3} = 0.2

Pr{Zn = 2} = 0.4

Pr{Zn = 1} = 0.4

Pr{Z1 = 3} = 0.1

Pr{Z1 = 2} = 0.1

Pr{Z1 = 1} = 0.8

Pr{Zn+1 = 3} = ?

Pr{Zn+1 = 2} = ?

Pr{Zn+1 = 1} = ?

Time

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Discrete RV Continuous Time Process

Primary interest is to determine probability distribution of Z(t).

3

2

1

Z(0) Z(t)

Pr{Z0 = 3} = 0.0

Pr{Z0 = 2} = 0.0

Pr{Z0 = 1} = 1.0

3

2

1

Pr{Zt = 3} = 0.2

Pr{Zt = 2} = 0.4

Pr{Zt = 1} = 0.4

Time

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Probability distribution of Z(t)

• Joint distributions of random variables of the process.

• Or, Bayes’ theorem based on conditional probability concept.

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Independent Process

• If we assume that , the probability of being in state i at the next time step (n) does not depend on the current (n-1) and previous states (n-2,…,0)

16

Not quite realistic enough to model any physical system

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Markov Property

• Discrete time process

• Continuous time process

• “Memoryless process”

Probability of being in future state is conditional on the present state of the system.

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Discrete Time Markov Chain

• Discrete state space (discrete RV)

• Discrete time process

• Probability of being in state i at the next time step (n+1) depends only on the current (n), not the previous states (n-1,…,0)

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Continuous Time Markov Chain

• Discrete state space (discrete RV)

• Continuous time process

• Probability of being in state i Z(s+t) at time s+tdepends only on the present state Z(s) at time s.

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Time-Homogenous Property

• Or, equivalently, “Stationary process”• Discrete time case:

• Continuous time case:

• All Markov Chains considered in this class are time-homogeneous process.

Probability of moving from one state to another state is constant over time.

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DISCRETE TIME MARKOV CHAIN

Transition probability

State transition diagram

Chapman-Komogorov equation

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Discrete Time Stochastic Process

• Discrete state space and discrete time process

• Markov property

• Time-homogenous property

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Pr{Zn = 3} = 0.2

Pr{Zn = 2} = 0.4

Pr{Zn = 1} = 0.4

A Discrete Time Markov Chain

The probability distribution of Zn+1 is dependent only on the current state Zn.

Zn Zn+1

3

2

1

3

2

1

Pr{Zn+1 = 3} = ?

Pr{Zn+1 = 2} = ?

Pr{Zn+1 = 1} = ?

Use concept of transition probability

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Transition Probability

• Time-homogenous process => Pij is constant.

The probability of transition from state i to state j in one step, Pij

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Transition Probability Matrix

• Given Pij and an initial state, we can find probability of being in any state at the subsequent time steps.

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State Transition Diagram

• Stationary process

• Show all possible states and the transition probabilities.

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Example 1

• (From [1]) A person is practicing firing. If he misses, he becomes nervous and the probability of the next shot being a hit reduces to ½ , but a hit bolsters his confidence and the chance of the next shot being a hit increases to ¾.

– Draw state transition diagram.

– What is transition probability matrix?

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Example 2

• Find transition probability of going from state 1 to state 3 in 2 time steps, P13,(2).

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Example 2

• Find transition probability of going from state 1 to state 3 in 2 time steps, P13,(2).

n = 0 n = 2

3

2

1

3

2

1

n = 1

1

2

3

State 1

State 2

State 3

P13,(2) = (P11 × P13 )+ (P12 × P23) + (P13 × P33)

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Example 2

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We can write this in a matrix form as follows,

Transition Probability in n Steps

• Probability of transition from state i to state j in n time steps.

• Multiply transition probability matrix n times.

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?

Transition Probability in 0 Step

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The process does not make any transition, it stays wherever it is.

Chapman-Komogorov Equation

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Assume that at time m, the process is at state k,

For a time homogeneous process,

Transition probability in n+m steps,

What about a probability at each time step??

DISCRETE-TIME MARKOV CHAIN –PROBABILITY DISTRIBUTION

Initial distribution

Probability distribution at n time step

Equilibrium distribution

9/3/2010 EE5712 Power System Reliability 34

Initial Distribution

• Give probability of being in each state at the beginning of the process.

• Example:

– p0 = [0 1 0]

– p0 = [1 0 0 0]

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Probability Distribution at n Time Step

• Give the probability of being in each state after n time steps

• Multiply the transition probability matrix after n time steps with the initial probability vector.

• Example: – p2 = p0 × P × P

– p5 = p0 × P × P × P × P × P

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Example 3

• From Example 1, A person is practicing firing. If he misses, he becomes nervous and the probability of the next shot being a hit reduces to ½ , but a hit bolsters his confidence and the chance of the next shot being a hit increases to ¾. – If the initial shot is a hit, what is the probability of

a hit on the fourth shot?

– Calculate the same probability if the initial shot is a miss.

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Probability Distribution at Step ‘n’

• Since transition probability matrix is a square matrix, we can use matrix transformation,

– where V is a matrix that columns are found from eigen vector of R, and D is a diagonal matrix of eigen value of R.

• Then,

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Example 4

• From Example 1, A person is practicing firing. If he misses, he becomes nervous and the probability of the next shot being a hit reduces to ½ , but a hit bolsters his confidence and the chance of the next shot being a hit increases to ¾. – Find probability distribution after n time step, if

the initial shot is a miss.

– What happens to transition probability when n → ∞?

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Equilibrium Distribution

• Give steady state probability of being in each state

• From previous example, when n →∞, the steady state probability distribution is not affected by initial state.

• Sometimes called ‘equilibrium distribution’.

• If the process is ergodic, then the equilibrium distribution exists and is independent of where the process starts from.

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Equilibrium Dist. Calculation

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Then, the equilibrium distribution is the unique solution of,

Example 5

• From Example 1, A person is practicing firing. If he misses, he becomes nervous and the probability of the next shot being a hit reduces to ½ , but a hit bolsters his confidence and the chance of the next shot being a hit increases to ¾.

– Find equilibrium distribution.

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DISCRETE-TIME MARKOV CHAIN –SOME RELIABILITY INDEXES

Absorbing state

First passage time

Mean first passage time

9/3/2010 EE5712 Power System Reliability 43

Absorbing State

• In reliability analysis, apply this concept to “failure states”

States in the system that once entered, can not leave unless the system restarts.

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First Passage Time

• From state i to state j

• Random variable

• Interest to find Mean First Passage Time

• In reliability analysis, interested to find “Mean time to the first failure, MTTFF”

The number of steps to reach state j starting from state i for the first time.

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Mean First Passage Time Calculation

• Define absorbing state j

• Let Q be a truncated transitional probability matrix (P) by removing rows and columns associated with the absorbing states

• Let N be the average number of time steps

469/3/2010 EE5712 Power System Reliability

‘N’ is called Fundamental matrix.

Fundamental Matrix ‘N’

• nik represents average number of time steps in state k before absorption to state j, given that the system starts from state i

• Mean first passage time, ni, the average time step that the system spend in state i before going to absorbing state j

479/3/2010 EE5712 Power System Reliability

Example 6

• Find mean first passage time if absorbing state is state 1,

– when the system starts from state 0.

– when the system starts from state 2.

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CONTINUOUS TIME MARKOV CHAIN

Transition probability

Chapman-Komogorov equation

Transition rate matrix

State transition diagram

499/3/2010 EE5712 Power System Reliability

Continuous Time Stochastic Process

• Discrete state space and continuous time process

• Markov property

• Time homogeneous property

509/3/2010 EE5712 Power System Reliability

Pr{Z(s) = 3} = 0.2

Pr{Z(s) = 2} = 0.4

Pr{Z(s) = 1} = 0.4

A Continuous time Markov Chain

The probability distribution of Z(s+t) is dependent only on the current state Z(s).

Z(s) Z(s+t)

3

2

1

3

2

1

Pr{Z(s+t) = 3} = ?

Pr{Z(s+t) = 2} = ?

Pr{Z(s+t) = 1} = ?

519/3/2010 EE5712 Power System Reliability

Chapman-Kolmogorov Equation

9/3/2010 EE5712 Power System Reliability 52

Transition Probability

9/3/2010 EE5712 Power System Reliability 53

Recall from Markov property,

Transition probability is time-dependent!

Let denote the time that the process spend to transit from state i to state j.

Transition Rate

• Define a transition rate from state i to state j,

• as Δt → 0,

• Or,

549/3/2010 EE5712 Power System Reliability

Transition Rate

9/3/2010 EE5712 Power System Reliability 55

Recall,

Since

Transition Rate Matrix

9/3/2010 EE5712 Power System Reliability 56

State Transition Diagram

• Represent transition rates among states in a system

1 2

3

0.01

0.01 0.02

0.5 0.5

579/3/2010 EE5712 Power System Reliability

What is transition rate matrix of this diagram?

Transition Probability VS Rate

9/3/2010 EE5712 Power System Reliability 58

Example 7

• Assume that the system started in state 1, find P13(t+Δt).

t = 0 Xt+Δt

3

2

1

3

2

1

Xt

1

2

3

599/3/2010 EE5712 Power System Reliability

• From conditional probability as Δt → 0,

P13(t+Δt) =

t = 0 Xt+Δt

3

2

1

3

2

1

Xt

1P11(t) P13(Δt)

2P12(t) P23(Δt)

3P13(t) P33(Δt)

+ P12(t) P23(Δt)P11(t) P13(Δt) + P13(t) P33(Δt)

= P11(t) λ13 Δt + P12(t) λ23 Δt + P13(t) (1+λ33 Δt)

609/3/2010 EE5712 Power System Reliability

• Since P31(Δt) + P32(Δt) + P33(Δt) = 1, then

λ33 Δt + λ32 Δt + λ31 Δt = 1

λ33 Δt = 1 - λ32 Δt - λ31 Δt

• We have,

P13(t+Δt) = P11(t)λ13 Δt + P12(t) λ23 Δt

+ P13(t) (1 - λ32 Δt - λ31 Δt)

• Then,

[P13(t+Δt) - P13(t) ]/ Δt

= P11(t) λ13 + P12(t) λ23 + P13(t) (- λ31 -λ32) = P’13(t)

619/3/2010 EE5712 Power System Reliability

• Thus,

• Where

• Similarly, we have

629/3/2010 EE5712 Power System Reliability

Example 8

• Suppose a continuous time Markov chain enters state i at time 0, and stays in this state for 10 mins. What is the probability that the process will not leave state i during the next 5 mins?

– Let Ti be the time the process spent in state i, then Pr{Ti > 15|Ti > 10} = Pr{Ti > 5}

– In general, Pr{Ti > s+t|Ti > s} = Pr{Ti > t}.

• Memoryless property, what is the distribution of Ti??

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Another Definition

• A continuous-time Markov Chain is a stochastic process with the following property.

– Amount of time spent in the state before making a transition is exponentially distributed.

– When a process leaves state i, it enters state j with some probability (transition probability) Pij.

• A Markov Chain with exponentially distributed RV of time spent in each state. (RVs of time spent in each state are also independent)

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Recall: Hazard Function

• From hazard function as Δx → 0,

• This gives probability of failure of a component in interval (x, x+Δx).

xXxxXxxx |Pr

x

x x+ Δx

xXxxXx |Pr

659/3/2010 EE5712 Power System Reliability

Transition Rate VS. Hazard Function

• Let Xij be the random variable of time duration from state i to j, then

Pij(Δt) = Pr{ t < Xij < t+ Δt | Xij > t }

• Hazard Function of a random variable Xij, as Δt → 0,

φij(t)Δt = Pr{ t < Xij < t+ Δt | Xij > t }

• If the process is markovian, φij(t) = φij (constant and independent of t)

The transition rate is therefore the hazard function

This also means that the underlying random variable Xij

of Markov process must be exponentially distributed669/3/2010 EE5712 Power System Reliability

Recall: Exponential Distribution

• Mean time to failure is • n = number of failures

• λ is called “Failure rate”.• The same is also applied for μ “repair rate”, found from

the reciprocal of ‘mean time to repair’.

x1 x2 x3 x4 x5

n

xxx n

21

n timeobservatio Total

1 n

MTTF

Assume that the repair time for this system is negligible

679/3/2010 EE5712 Power System Reliability

CONTINUOUS TIME MARKOV CHAIN –PROBABILITY DISTRIBUTION

Initial distribution

Probability distribution at time t

Equilibrium distribution

9/3/2010 EE5712 Power System Reliability 68

Initial Distribution

• Give probability of being in each state at the beginning of the process.

• Example:

– p0 = [0 1 0]

– p0 = [1 0 0 0]

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Probability Distribution at Time t

• Give the probability of being in each state after time t.

• In this case, we need to obtain .

709/3/2010 EE5712 Power System Reliability

Transition Probability at Time t

• From

• Since , the solution to the first order equation is,

• We can use matrix transformation,

– where V is a matrix that columns are found from eigen vector of R, and D is a diagonal matrix of eigen value of R.

719/3/2010 EE5712 Power System Reliability

Transition Probability Approximation

• Recall the derivative,

• And

• Use one step transition probability matrix in Discrete time Markov chain and divide time t to small equal intervals of Δt.

• Assume Δt → 0,

729/3/2010 EE5712 Power System Reliability

Transition Probability (Δt)

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This gives the transition probability approximation of time jΔt using the approximation of time step Δt .

Example 9

• A two-state model is commonly used in reliability study to represent a status of a component

• Find– Transition rate matrix

– Transition probability at time t

– State probability at time t

DownUp

λ = failure rate

μ = repair rate

749/3/2010 EE5712 Power System Reliability

Equilibrium Distribution

• Give steady state probability of being in each state

• Similar to discrete time case, if the process is ergodic, then the equilibrium distribution exists and is independent of where the process starts from.

• In example 9, observe the transition probability matrix at time t→∞.

759/3/2010 EE5712 Power System Reliability

Equilibrium Dist. Calculation

9/3/2010 EE5712 Power System Reliability 76

Let t →∞, we have,

From

At steady state,

Example 10

• From example 9, find equilibrium distribution

DownUp

λ = failure rate

μ = repair rate

779/3/2010 EE5712 Power System Reliability

CONTINUOUS TIME MARKOV CHAIN –SOME RELIABILITY INDEXES

First passage time

Mean first passage time

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First Passage Time

• Random variable, denote by Tij

• Calculate as ‘Mean first passage time’

A time to enter state j starting from state ifor the first time.

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Mean First Passage Time Calculation

• From discrete time case, , gives number of time steps to absorbing states.

• Approximate Q by [I + RΔt], the time spent is found by multiplying N by Δt.

• The mean first passage time is,

1 QIN

809/3/2010 EE5712 Power System Reliability

Time Dependent System Availability

• Summation of state probability at time t of success states

Probability of being found in the success states at some time t.

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System Availability

• Summation of state equilibrium probability of success states

Probability of being found in the success states at steady state.

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A Two-State Component Example

• Assume that system starts from up state at time t = 0.

• Time to change state is random variable with exponential distribution.

DOWNUP

λ = failure rate

μ = repair rate

tetR

Time to change state from up to down

Probability of staying in the up state given that the system started from this state at time t = 0.

tup etptA

Probability of being found in the up state at time t, given that the system started from up state at time t = 0.

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Summary

• Stochastic process

• Markov process

• Markov chain

• Transition probability/ state probability

• Transition probability matrix

• Transition rate matrix

• Equilibrium distribution

• First passage time/ mean first passage time

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Application

• Most repairable systems are described by Markov processes

• We will use this to represent different outage models

• To compute the state probability and state equilibrium probability and mean first passage time (mean time to the first failure)

• Interested to know a frequency of encountering a system state or average duration spent in each state– How often the system fails

• This will be in the next lecture.

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Reading Materials

• Review today’s lecture• Chapter 2: The Preliminaries “System Reliability Modeling and

Evaluation”, http://www.ece.tamu.edu/People/bios/singh/sysreliability/ch2.pdf

• Lecture notes on this part will be uploaded.• Sheldon M. Ross, “Introduction to Probability Models”, 8th edition.• Markov chain

– Transition probability matrix– Equilibrium state probability– Mean first passage time

• Markov process– Transition rate matrix– Equilibrium state probability– Mean first passage time

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Limitations

1

2

5

3

4

Series or Parallel??

2

8

5

3

9

1

7

4

10

6

What about other reliability measure? Now we can only compute for system availability/unavailability.

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About Next Lecture

• Analytical methods for reliability analysis for frequency of failure

– State space approach -> similar to the example in lecture 2.

– Conditional probability approach

– Network reduction approach

– Frequency balance approach

889/3/2010 EE5712 Power System Reliability