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TRNG H CNG NGH GTVT B MN NG KHOA CNG TRNH N MN HC PHN THUYT MINH

PHN ILP D N U T XY DNG CNG TRNHXY DNG TUYN NG QUA 2 IM E V KX BUN TNG LN, HUYN KRNG NNG , TNH K LKCHNG 1GII THIU CHUNG1.1. Tng quan. Xa Bun Tng Ln la xa thuc huyn min nui Krng nng nm phia ng tinh k Lk,thanh lp ngay 9-11-1987 tach ra t tinh krong buk tim nng phat trin chinh la cy cng nghip c bit la cy trng mui nhon nh ca ph cao su va lua nc la khu trong im v phat trin cy cng nghip vi vy nu tin hanh xy dng tuyn ng nay se giup tng trng kinh t va ca thin kha nng trao i hang hoa cho ca vung. Phat huy trit tim nng , ngun lc cua khu v khai thac co hiu qua cac ngun lc bn ngoai. Trong trng hp cn thit phuc vu cho chinh tri an ninh quc phong .V ranh gii hnh chnh th xa gip : Phia bc giap xa Tam Binh va Thng Nht v Tam Hp, Phia ty giap xa Tam in , phia nam giap xa Giang Tin va Giang Thinh, Phia ng giap vi xa Tam Hp.

1.2. Phm vi nghin cu ca d n.im u E, im cui KChiu di tuyn: 2 kmNi dung thit k: Lp bo co d n u t xy dng cng trnh.1.3. T chc thc hin.C quan quyt nh u t: UBND tnh k LkCh u t: UBND tnh k Lki din Ch u t: Ban qun l d n Huyn Bun Tng Ln n v thit k: s Giao thng cng chinh tinh k Lk thc hin.

1.4. Cc cn c php l lin quan lp d n u t bao gm:- Cn c Lut s 16/2003/QH11 ngy 26/11/2003 ca Quc hi nc cng ha x hi ch ngha Vit Nam kha XI, k hp th 4 v xy dng; Lut s 38/QH12 ngy 19/6/2009 ca QH kha 12, k hp th 5 sa i b sung mt s iu ca cc lut lin quan n u t xy dng c bn;- Cn c Ngh nh s:15/2013 N-CP ngy 06/02/2013 ca Chnh Ph v qun l cht lng xy dng cng trnh;- Cn c Ngh nh s: 12/2009 N-CP ngy 12/02/2009 ca Chnh Ph v qun l d n u t xy dng cng trnh;- Cn c Ngh nh s: 112/2009 N-CP ngy 14/12/2009 ca Chnh Ph v qun l chi ph u t xy dng cng trnh; - Cn c Thng t s 03/2009/TT-BXD ngy 26 thng 03 nm 2009 ca Chnh ph v vic Quy nh chi tit mt s ni dung ca Ngh nh s 12/2009/N-CP ngy 12/02/2009 ca Chnh ph v qun l d n u t xy dng cng trnh;- Cn c Thng t 27/2009/TT-BXD, ngy 31/07/2009 ca B Xy hng dn mt s ni dung v qun l cht lng cng trnh xy dng; - Cn c Ngh nh s 85/2009/N-CP ngy 15/10/2009 ca Chnh ph v hng dn thi hnh lut u thu v la chn nh thu theo lut xy dng;1.5. Mc tiu u t v mc tiu u t d n:- Vic u t tuyn c t ra vi mc tiu : - Xy dng tuyn ng gp phn hon chnh mng li giao thng trong khu vc. Tuyn ng hin ti l tuyn ng chnh l huyt mch giao thng ni thn vi trung tm x vi cc x khc trong huyn.- Xy dng tuyn ng p ng c cc mc tiu pht trin kinh t x hi ca a phng. - Vic xy dng tuyn s p ng c s giao lu ca dn c trong vng v kinh t, vn ho, x hi cng nh v chnh tr, gp phn nng cao i sng vt cht, tinh thn ca nhn dn trong vng cng nh tng kh nng vn chuyn hng ho, s i li ca nhn dn.- V vy vic u t nng cp, ci to tuyn ng l rt cn thit v cp bch. D n s to ra b mt mi cho nhn dn (nh in, ng, trng, trm) gp phn thc y hn na s pht trin b mt giao thng tng bc p ng yu cu cng nghip ha, hin i ha kinh t nng nghip nng thn.

1.6. Cc quy trnh, quy phm p dng:1.6.1 Quy trnh kho st:- Quy trnh kho st ng t: 22 TCN 263- 2000- Quy phm o v bn a hnh: 96 TCN 43 90- Cng tc trc a trong XD yu cu chung: TCVN 9398:2012- Quy trnh kho st thu vn: 22 TCN 27 84- Quy trnh kho st a cht: 22 TCN 27 84- Quy trnh khoan thm d a cht: 22 TCN 259-2000- Quy trnh th nghim xuyn tiu chun(SPT): TCVN 9351: 2012- Quy trnh th nghim t xy dng: TCVN8868: 2011- Quy trnh kho st thit k nn ng t p trn t yu: 22TCN 262-2000- Quy trnh th nghim xc nh m un n hi chung ca kt cu bng cn o vng Benkelman: TCVN 8867:2011.1.6.2. Cc quy trnh quy phm thit k:- ng t tiu chun thit k : TCVN 4054 -2005- Quy phm thit k ng ph, qung trng th: TCXDVN 104 -2007- Quy trnh thit k o ng mm: 22TCN 211-06- Quy trnh thit k o ng cng: Q3230 /Q-BGTVT - Tnh ton c trng dng chy l: TCVN 9845: 2013- Quy phm thit k tng chn t: QP23 65.- Quy phm KSTK nn ng t qua vng t yu: 22 TCN 262 2000- iu l bin bo ng b: QCVN41:2012/BGTVT- Tiu chun thit k cu: 22 TCN 272-05. - Cc thit k in hnh cng, cng bn , tng chn v v ..

CHNG 2TNH HNH KINH T - X HI KHU VC TUYN2.1. Dn sDn s ton huyn 57.002 ngi;+ ng bo DTTS l 18.521; chim 32.5% DS;+ ng bo dn tc ti ch l 17.862; chim 31.3% DS.+ Ton huyn c 07 n v hnh chnh cp x vi tng s 100 thn, bun v khu t qun, trong c 41 bun ng bo dn tc thiu s ti ch, 10 thnh phn dn tc thiu s sinh sng, trong ng bo chim a s, sng xen ghp tt c 07 x trong huyn..2..2. Lao ng v vic lmDn c sng ch yu bng nng nghip, phat trin cy cng nghip v lm nghip. 2.2.1. Nng lm nghip.Ton th x c 51.521,96 ha rng, trong , rng sn xut l 22.341,95 ha, rng phng h l 29.180,01 ha. Rng c nhiu lm th sn c gi tr kinh t cao nh g cm lai, c te, dng hng, sao, bng lng... c bit l k nam, trm hng l nhng loi hng liu, dc liu qu. Rng l ngun gi nc, cung cp nc ti v m bo h sinh thi mi trng nhm pht trin kinh t bn vng cho huyn Bun Tng Ln.T nm 2010 n nm 2012, trng c gn trn 500 ha rng tp trung, ch yu l rng sn xut, thc hin tt cng tc bo v rng, tng cng cng tc kim tra, ngn chn cc v cht ph rng, khng xy ra chy rng ln.Gi tr sn xut nng - lm - thy sn nm 2010 l 726 t ng, nm 2012 t 796 t ng, tng bnh qun hng nm 4,55%, nng sut nhiu loi cy trng tng cao. Sn lng lng thc bnh qun hng nm trn 100.000 tn, gii quyt vic lm cho nhiu lao ng nng thn.Cng nghipCng nghip ca tnh cha thc s ln mnh, ch yu tp trung vo mt s ngnh sn xut vt liu xy dng, ch bin nng lm thu sn v mt s mt hng tiu dng. Do tnh c a hnh phc tp, a bn rng, iu kin c s h tng cha y nn thu ht vn u t cha nhiu. Huyn Bun Tng Ln li l mt huyn min ni ca tnh nn cng nghip hu nh cha c g.2.3 Tnh hnh kinh t tuyn i qua- Cn c vao c im ia hinh cua huyn phat trin kinh t cua vung nm 2010 la : tip tuc i mi mt cach su sc toan canh cua cac nganh , cac cp tp trung s dung co hiu qua moi ngun lc khai thac tim nng vi tri ia ly tai nguyn , y manh inh hng Cng nghip hoa hin ai hoa .Thc hin c cu kinh t : cng nghip dich vu tip tuc dy nhanh c cu trong nganh theo tng trng kinh t gn vi bao v mi trng sinh thai. Kt hp cht che gia cac tng trng kinh t vi giai quyt tt cac linh vc xa hi .Gi vng n inh chinh tri trt t an toan xa hi tao th lc cho huyn Krong Nng phat trin . Phn u nm 2020 Bun Tng Ln tr thanh vung kinh t trong im cua Dak Lak

CHNG 3 CHIN LC PHT TRIN KINH T - X HI KHU VC

Huy ng ti a mi ngun lc cho u t pht trin, nht l ngun lc nhn lc, u tin u t khai thc ngun ti nguyn tim nng ca vng. y nhanh chuyn dch c cu kinh t v nng cao cht lng tng trng. Tng bc xy dng h tng kinh t k thut- x hi pht trin, u tin cc vng c nn kinh t trng im v vng kinh t kh khn cn uc pht huy. thc hin phng hng trn cn qun trit cc quan im sau y:i mi m hnh tng trng v c cu kinh t t ch yu pht trin theo chiu rng sang pht trin hi ho gia chiu rng v chiu su, va m rng quy m, va ch trng cht lng, hiu qu, m bo pht trin nhanh v bn vng.Quan in pht trin v mc tiu pht trin kinh t x hi ca khu vc c thng nht trong nghi quyt ca i hi ng b phng. 3.1. nh hng pht trin kinh t - x hi:3.1.1 nh hng pht trin kinh t

Phn u tng tng GDP (theo gi so snh 1994) n nm 2010 gp 1,7 ln so vi nm 2005, nm 2020 gp 3,03 ln so vi nm 2010. GDP/ngi (gi hin hnh nm 2005) nm 2010 t khong 9,5 - 10 triu ng, nm 2020 khong 42 43,3 triu ng; thu hp khong cch thu nhp bnh qun u ngi (GDP/ngi) so vi c nc t 55% nm 2010, ln 61% nm 2015 v n nm 2020 t 75%3.1.2 D bo pht trin kinh t - x hi, pht trin dn s v vic lm3.2. nh hng pht trin kinh t - x hi ca cc vng ln cn v cc vng thuc khu vc hp dn ca ng. Mc tiu x hi:Phn u gim t l tng dn s t nhin vo nm 2010 cn 1,5%, nm 2015 cn 1,3% v nm 2020 l 1,1%. T l dn s thnh th chim 30% nm 2010, 35% nm 2015 v 45,6% nm 2020. T l lao ng nng nghip trong lao ng x hi t 73 - 74% vo nm 2010 v gim xung cn 50 - 55% vo nm 2020.Gii quyt tt cc vn x hi c bn, gim t l h ngho (theo tiu chun mi) xung cn 15% vo nm 2010, n nm 2020 v c bn khng cn h ngho.Tng t l lao ng qua o to t 36% nm 2010 v tng ln 46% vo nm 2020 (trong t l lao ng qua o to l ng bo cc dn tc thiu s phi t ti thiu l 30% v 40% trong cc nm tng ng).Gim t l lao ng tht nghip khu vc thnh th xung cn 3% vo nm 2010 v gim t l lao ng thiu vic lm khu vc nng thn xung cn 5%.Phn u n nm 2008 hon thnh ph cp trung hc c s trong tui. Nm 2020 c 75% ph cp trung hc ph thng trong tui.Phn u n nm 2010 c 85% x t chun quc gia v y t v t 100% vo nm 2015, 100% trm y t x c bc s v 4,3 bc s/vn dn, n nm 2020 c 8 - 10 bc s/vn dn.Gim t l tr em b suy dinh dng xung di 25% nm 2010 v xung cn 15% vo nm 2020 (t l tng ng ny i vi vng ng bo dn tc thiu s phi t t 35% v 20%).Tng t l s h c s dng in t 95% vo nm 2010 v t 100% vo nm 2015.Nm 2010, mt in thoi bnh qun t 32 - 35 my/100 dn; mt Internet t 8 - 12 thu bao/100 dn. Nm 2020, mt in thoi bnh qun t 50 my/100 dn.m bo nc sch cho dn c, a t l s h c dng nc sch, nc qua x l ln 100% dn s th v 70% dn s nng thn vo nm 2010 v c bn gii quyt nc sch cho dn c nng thn vo nm 2020.

CHNG 4CC QUY HOCH LIN QUAN N D N4.1. Quy hoach d n Giao thng vn ti4.1.1. Quy hoch giao thngTon huyn hin c 1.675 km ng giao thng. Trong , ng do huyn qun l di 327,47 km, v ng do x qun l di 1.006,97 km.Cht lng ng b: ng cp phi, ng dm di 220,52 km; ng nha di 120,77 km, cn li l ng t. Tt c cc x c ng t n tn trung tm x.4.2.Quy hoch cp nc4.3. nh hng cung cp in- Li 110 kV: Hon thin kt cu li 110 kV trong khu vc; xy mi nng cp cc trm 110 kV m bo cp in an ton tin cy cho ph ti.- Li trung th: Kt cu li trung th trong tng khu phi tun th nguyn tc xy dng dng mch vng kn vn hnh h. Trong ch lm vic bnh thng, kh nng ti khng vt qu 70% cng sut m bo d phng vn hnh.4.4. Quy hoch thot nc thi v v sinh mi trng- Quy hoch thot nc thi: Nc thi sinh hot ti cc thnh ph v th x, th trn c thu gom x l trc khi xy ra ngun. Ti cc th t v cc cm dn c nng thn x l bng phng php t lm sch; khuyn khch ngi dn s dng h x t hoi v x thm.- nh hng quy hoch ngha trang tp trung:+ Quy m s dng t ngha trang c d bo trn c s d bo v dn s. Din tch ngha trang cho khu vc quy hoch giai on 2015 l khong 40 ha, giai on 2025 l 46 ha. Xy dng, nng cp cc ngha trang phc v cc th, th x, th trn trong vng vi quy m t 5 - 20 ha; ty thuc mc phc v. Cng ngh s dng: a tng, thi hn s dng t 30 - 50 nm.+ Ti cc khu vc dn c nng thn: Mi x xy dng 1 ngha trang tp trung quy m 1 ha/x. Cng ngh s dng: a tng. Thi hn s dng: 20 nm.

4.5. nh hng v bo v mi trng:- Xy dng h thng qun l mi trng vng, gn vi vic qun l, phng trnh nhim ngun nc cc lu vc sng, cc h cha nc trong vng v cc vng ln cn khc. Bo v mi trng nguyn sinh ti cc khu rng cm quc gia, khu bo tn Bo v a dng sinh hc: H sinh thi rng C k hoch v bin php i ph vi tai bin, thm ha v ri ro v mi trng.- Tng cng qun l v trng rng u ngun chng xi l v l qut, ci to t trng, i ni trc, tng che ph rng phng h u ngun trn cc lu vc sng chnh.4.6 Cc chng trnh, d n u tin u tTheo quy hoch chung ca tnh, thi gian ti, Bun Tng Ln s c u tpht trin vi tc tng trng kinh tnhanh trn cc lnh vc cng nghip, dch v, thng mi, vn ha v cshtng; trthnh mt trong nhng khu vc kinh t- vn ha - x hi trng im ca tnh. Giai on 2011 - 2015, Bun Tng Ln phn u t tc tng trng GDP bnh qun trn 13%; GDP bnh qun u ngi trn 2.000 USD; gi trsn xut cng nghip, tiu thcng nghip, xy dng tng bnh qun hng nm 24%; gi trsn xut nng, lm, thy sn tng bnh qun hng nm 3,6%; gi trsn xut ngnh dch v tng bnh qun hng nm 17%; thu ngn sch tng bnh qun hng nm 18%; tng sn lng lng thc t 90.000 tn/nm

CHNG 5HIN TRNG MNG LI GIAO THNG TUYN NGHIN CU5.1. Hin trng mng li giao thng vng nghin cuDo c th v v tr a l, h thng giao thng ca X Bun Tng Ln Huyn Krng Nng tung i phong ph nhng ch yu l giao thng ng b, con ng huyt mch gn lin vi i sng kinh t ca ngi dn ni ny.H thng mng li ng b ca huyn phn b kh u v hp l, to c s lin kt gia trung tm huyn vi cc x.

CHNG 6NH GI V VN TI V NHU CU VN TIPhng thc d bo: Nhu cu vn ti hng ho khu vc nghin cu (tuyn ng E-k), vn ti ng b chim v tr rt quan trng.Trong vn ti ng b th khi lng vn ti lin tnh chim phn nh. Qua s liu iu tra ca mt s ti c nghin cu chng ti c c vn ti lin tnh ch chim 32% cn li 68% l vn ti ni tnh. d bo nhu cu vn ti hng ho trn tuyn E-K, s dng phng php:Phng php kch bn v pht trin kinh t x hi khu vc hp dn xc nh lng hng yu cu vn ti.Phng php kch bn c s dng d bo nhu cu vn ti ca cc mt hng chnh c khi lng ln nh: g, ca cao, cao su, iu, c ph, xng du. V nhng mt hng ny thng xuyn bin ng v c sn xut ln tiu th.Kt lun :Qua cc iu tra kho st cho thy vic trin khai thit k v xy dng tuyn ng E - K l rt cn thit, n c vai tr quan trng trong vic thc y s pht trin kinh t ca vng cng nh khu vcVic xy dng tuyn ng E - K s p ng c s giao lu ca dn c trong vng v kinh t, vn ho, x hi cng nh v chnh tr, gp phn nng cao i sng vt cht, tinh thn ca nhn dn trong vng.Tuyn ng E - K c xy dng lm gim i nhng qung ng v thi gian i vng khng cn thit, lm tng s vn chuyn hng ho cng nh s i li ca nhn dn. c bit n cn phc v c lc cho cng tc quc phng bo v t quc Vit Nam x hi ch ngha.

CHNG 7S CN THIT PHI U T D N

7.1. Kinh t- Hin ti iu kin kinh t - x hi ca x bn Tng Ln Huyn Krng Nng rt kh khn, h thng h tng k thut c bit l h thng giao thng xung cp nghim trng, c th trc chnh i trung tm tnh trc y c u t nng cp ci to phc v nhu cu i li ca nhn dn huyn v cc phng tin giao thng ngy cng tng cao. - Do vy vic u t xy dng tuyn ng l ht sc cn thit v cp bch nhm p ng nhu cu i li ca nhn dn v m bo v sinh mi trng trong a bn huyn. Vic xy dng c s h tng, giao thng ng b p ng nhu cu pht trin trong thi i mi, lin hon vi mng li giao thng quc gia, m bo cho vic giao thng i li v vn chuyn hng ha n khu vc trung tm x c thun li v thng sut. ng thi, vic u t xy dng tuyn ng s gp phn pht trin mnh nng nghip, cng nghip - dch v trong khu vc v to chuyn bin mnh m trong i sng vn ha x hi cng vi s pht trin chung ca cc a phng khc trn ton Huyn nhm nm bt xu th chung ca Tnh ak Lak s trin khai thc hin nhn rng chng trnh Nng thn mi trn khp a bn.7.2. Chnh tr x hiVic xy dng tuyn E - K l vic lm ht sc thit thc trong chin lc xo i gim ngho cc dn tc thiu s, rt ngn khong cch giau ngho gia cc vng trong tnh, thc hin cng nghip ho t nc v cng cuc bo v an ninh bin gii, to iu kin cho vic lnh o v ch o ca chnh quyn cc cp c cp nht thng xuyn, ngi dn phn khi tin theo ng, thc hin tt cc ch trng chnh sch ca ng v php lut Nh Nc.Do iu kin giao thng hn ch phn no lm nh hng ti sn xut hng ho, trao i dch v, s hnh thnh cc vng chuyn canh v chn nui t nh hng s pht trin nng thn khu vc cao nguyn. to tin cho chng trnh kinh t x hi th vic tp trung xy dng kt cu h tng l mt yu cu cn thit v cp bch v thc hin tt th giao thng phi i trc mt bc.

CHNG 8IU KIN T NHIN TUYN I QUA

8.1. iu kin v kh hu thy vnTuyn nn trong khu vc khi hu nhit i gio mua , mua ha nong m ma nhiu , it gio . Mua kh lanh kh hanh , it ma gio chu yu la gio ng bc , nhit khng khi trung binh hang nm khoang 210C . Lng ma hang nm 1700 2400mm , chi co 2 mua la mua khng va mua ma .

8.2. iu kin a hnh.-c im a hnh* Tuyn i qua khu vc ia hinh tng oi phc tap co dc va co ia hinh chia ct manh.* Chnh cao cua hai ng ng mc la 5 m* dc trung binh cua sn dc khoang 19,6%c im mi trng:y la khu vc rt it bi m nhim va it bi anh hng xu cua con ngi , trong vung tuyn co kha nng i qua co 1 phn trng trot. Do o khi xy dng tuyn ng phai chu y khng pha v canh quan thin nhin , chim nhiu din tich t canh tac cua ngi dn va pha hoai cng trinh xung quanh .c im iu kin vt liu va iu kin thi cng :Cac ngun cung cp nguyn vt liu ap ng u vic xy dng ng c ly vn chuyn < 5km . n vi thi cng co y u nng lc may moc thit bi ap ng nh cu v cht lng va tin xy dng cng trinh . Co kha nng tn dung nguyn vt liu ia phng trong khu vc tuyn i qua co mo cp phi a dm vi tr lng tng i ln va theo s liu khoa sat s b thi thy cac i t gn o co th p nn ng c . Pham vi t cac mo n pham vi cng trinh t 500m n 1000m H thng sng ngi v ngun ncCao mc nc ngm y tng i thp , cao d la -3,7 m , cp thoat nc nhanh chong , trong vung co 1 dong sng hinh thanh dong chay ro rang co lu lng tng i ln va cac sui nhanh tp trung nc v dong chay nay .

8.3. iu kin a cht ia cht khu v kha n inh it bi phong hoa , khng co hin tng nt ne , khng bi sut n . t nn chu yu la t o bazan , ia cht long sng va cac sui chinh noi chung n inh .8.4. Vt liu xy dng.Trong khu vc tuyn thi cng c ni v i t c th khai thc lm vt liu xy dng nn mt ng. ng thi khu vc d nh t tuyn gn cc cnh rng g c th khai thc g lm vt liu xy dng ln tri, nh xng, phc v thi cng.8.5. Nhng g b khi thit k cng trnh.- Do tuyn i qua a phn dn c, v i ni do vy kh khn trong qu trnh gii phng mt bng.- Khu vc tuyn i qua c phong canh rt p, vic xy dng tuyn ng s nh hng ti iu kin t nhin ca khu vc. hn ch iu ny cn phi c s ch o st sao ca cc cp cc ngnh trnh nhng nh hng khng ng c nh: ph liu rc ri vt ba bi, cht cy khng c quy hochSau khi xy dng xong cn phi dn dp sch s, trng cy trng c ph hp vo cc mi taluy- Vic xy dng tuyn s lm cho vic thng thng gia cc vng pht trin, ngoi ra con ng cng gp phn vo vic m bo an ninh quc phng cho vng, c bit l phng ca tnh.

CHNG 9XC NH QUY M V TIU CHUN K THUT TUYN

9.1. Danh mc quy chun, tiu chun p dngTTCc tiu chun thit k ca tuynK hiu

AKho st th nghim

1Quy phm o v bn a hnh96 TCN 43-90

2Quy trnh kho st ng t22 TCN 263 - 2000

3Quy trnh kho st thit k nn ng t trn t yu22 TCN 262 - 2000

4Quy trnh khoan thm d a cht cng trnh Cng tc trc a trong xy dng- yu cu chung Tiu22TCN 259-2000TCVN 9398:2012

5K thut o v x l s liu GPS trong trc a cng trnhQCVN 9401:2012

6Kho st k thut phc v thi cng mng cc20TCN 160-87

7Quy trnh kho st a cht cng trnh v thit k bin php n nh nn ng vng c hot ng trt, st l22TCVN 171-87

8Quy trnh th nghim ct cnh hin trng22TCN 355-2006

9Quy trnh th nghim xuyn tnh (CPR v CPTU) 22TCN 317-04

10Quy trnh th nghim ca cc ch tiu c l , t xy dng22TCN 57-84

11Phng php chnh l thng k cc kt qu c trng ca chng20TCN 74-87

12t xy dng phng php th nghim hin trng Th nghim xuyn tiu chunTCVN 9351: 2012

BThit k

1ng t yu cu thit kTCVN 4054-2005

2ng th yu cu thit kTCVN104-2007

3ng giao thng nng thnQ 315/Q-BGTVT

4Tiu chun thit k (phn nt giao)22TCN 273-01

5Quy trnh thit k o ng mm22TCN211-06

6Thit k o ng cngQ3230/Q-BGTVT

7Gia c nn t yu bng bc thm TCVN 9355:2012

8Vi a k thut trong xy dng nn t yu 22TCN 248-98

9Tiu chun tnh ton c trng dng chy l TCVN 9845: 2013

10Cng trnh giao thng vng ng t- Tiu chun thit k22TCN 211-95

11Quy chun k thut quc gia v bo hiu ng bQCVN41:2012-BGTVT

12Tiu chun thit k cu22TCN 272-05

13Quy phm thit k cu cng theo trng thi gii hn ( thit k cng)22TCN 18-1979

14Kt cu b tng v BTCT- Tiu chun thit kTCVN5574-2012

CThi cng v nghim thu

1Kt cu b tng v b tng ct thp lp ghp Quy phm thi cng v nghim thuTCVN 9115-2012

2Cng tc t- Thi cng v nghim thuTCVN 4447-2012

3Nc trn b tng v va TCVN 302:2004

4Yu cu k thut thp ct b tngTCVN 1651-1: 2008

5Ct liu b tng v va Phng php thTCVN 7572-20: 2006

6Cc khoan nhi thi cng v nghim thuTCXDVN 326-2004

7Lp mng cp phi dm trong kt cu o ng t, vt liu thi cng v nghim thuTCVN 8859-2011

8Mt ng b tng nha nng Yu cu thi cng v nghim thuTCVN 8819-2011

9Mt ng lng nh tng ng axt thi cng v nghim thuTCVN9505: 2012

10Lp kt cu o ng dm nc thi cng v nghim thuTCVN9054:2012

11Mng cp phi dm v cp phi thin nhin gia c xi mng trong kt cu o ng t- thi cng v nghim thuTCVN 8858:2011

12Quy trnh k thut thi cng v nghim thu bc thm trong xy dng nn ng t yu22TCN 236-97

13Kt cu gch Quy phm thi cng v nghim thuTCVN 4085-2011

14Cc tiu chn, quy trnh, quy phm c lin quan

9.2. La chn quy m v tiu chun thit k tuynQua phn tch trn, la chn quy m v cp hng d n nghin cu nh sau:- Tuyn thit k t tiu chun ng cp III min ni theo tiu chun thit k ng t TCVN 4054-2005 ng t - tiu chun thit k;- Vn tc thit k: V = 60 Km/h;- Bn knh cong nm nh nht ng vi siu cao 7% R = 125150 m;- Rmin thng thng = 250m; R khng lm siu cao 1500m;- Bn knh ng cong li nh nht R gii hn= 2500m;- Bn knh ng cong li thng thng Rthng thng= 4000m;- Bn knh ng cong lm nh nht R gii hn= 1000m;- Bn knh ng cong lm nh nht R thng thng=1500m;- Chiu di ti thiu i dc 150m;- Dc dc ln nht Idmax = 7%, dc siu cao ln nht 4%;- Chiu di on ni siu cao L=50m;- Chiu di tm nhn trc xe ngc chiu S2 = 150m; tm nhn vt xe Svx = 350m, tm nhn hm xe S1 = 75m;- Chiu rng nn ng Bnn = 15m;- Chiu rng mt ng Bmt = 6,0m;- Chiu rng l v l gia c Bl =2,0m (cho c hai bn);- Chiu rng l t Bl t=1,0m (cho c 2 bn)- dc ngang mt ng imt =il gia c=2%;- dc ngang l ng il t = 4% dc v pha ngoi;- Chn dc ta luy;+ dc ta luy nn ng p: 1/1,5+ Dc ta luy nn ng o: 1/1- Tn xut thit k ng, cu v cng P = 4%;- Ti trng thit k cu cng HL-93;- Kt cu mt ng thit l k kt cu o ng mm: - Cng ngang ng:Thit k vnh cu khu thot nc cng trn K 1m;9.3. Xc nh cc ch tiu k thut ca tuyn9.3.1. Cc ch tiu ca tuyn9.3.1.1 Xc nh cp hng ng Vic xc nh cp hng k thut ca tuyn ng l mt vn ht sc quan trng v cp hng k thut ca tuyn ng quyt nh hu ht cc ch tiu k thut khc , mc phc v ca tuyn ng i ci s pht trin kinh t , vn ha x hi a phng i qua .Lu lngNm th 15(xe ngy/ )Xe conXe ti2 trcXe ti3 trcXe khch NhXe khch LnXe myXe pH s q (%)

55838.84%23.39%2.74% 16.66%2.00%14.40%1.97% 9

Lu lng xe con :

N1 = 38.84% N =38.84% 558 = 216.72 (xe/ng)Lu lng xe ti 2 trc :

N2 = 23.39% N = 23.39% 558 = 130.51 (xe/ng)Lu lng xe ti 3 trc :

N3 = 2.74% N = 2.74% 558 = 15.29 (xe/ng)Lu lng xe khch nh:

N4 = 16.66% N = 16.66% 558 = 92.96 (xe/ng)Lu lng xe khch ln:

N5 = 2.00% N = 2.00% 558 = 27.9 (xe/ng)Lu lng xe my:

N6 = 14.40% N = 14.40% 558 = 80.35 (xe/ng)Lu lng xe p:

N7 = 1.97% N = 1.97% 558 = 11 (xe/ng)Xc nh lu lng xe con qui i ti thi im hin ti:

(xcq/ng)(2-1)Trong :Ni: Lu lng ca loi xe i trong dng xe (xe/ng).ai: H s quy i ca loi xe i v xe con thit k theo TCVN 4054 05.a hnh :Min Ni H s quy i ca tng loi xe (Bng 2 TCVN 4054-05)Xe con :a1 = 1Xe ti 2 trc, xe khch nh :a2 = 2,5 Xe ti 3 trc, xe khch ln :a3 = 3Xe my :a4 = 0,3Xe p :a5 = 0,2Vy

= 216,72 1+ 130,51 .2,5+ 15,29.3 + 92,96.2,5+27,9.3 +80,35.0,3+ 11.0,2 = 1435(xcq/ng)Xc nh cp thit k v cp qun l ca ng t:Lu lng xe thit k:Lu lng xe thit k bnh qun ngy m trong nm tng lai c xc nh theo cng thc:

(xcq/ng)(2-2)Trong :N0: Lu lng xe chy ti thi im hin ti (xcq/ng)t: Nm tng lai ca cng trnh.q: Mc tng xe hng nm theo s liu thng k q = 0.09Vi lu lng xe thit k nm tng lai l nm th 15:

Nt = 1435 ([1 +0,09(15-1)] = 3243.1 (xcq/ng)Chn lu lng xe thit k:Lu lng xe thit k nm tng lai th 15 l 3000 < 3243.1. Do vy ng ch c th thuc cp III,. V th theo iu 3.3.1 ca TCVN4054-05 th nm tng lai ng vi cc cp ng ni trn l nm th 15. Vy lu lng xe thit k l 3243.1 (xcq/ng).Tc thit k cc cp ng da theo iu kin a hnh .Vic phn bit a hnh c phn bit da trn c s dc ngang ph bin ca sn i,sn ni nh sau:ng bng vi30%,ni>30%Tng hp cc yu t iu kin a hnh, chc nng, lu lng xe, ta kin ngh ng c cp thit k l cp III min ni,V= 60(Km/h)Lu lng xe thit k gi cao im:Tuyn khng c s liu thng k c th v cng khng c nhng nguyn cu c bit no theo TCVN 4050 05 th Ngc c xc nh gn ng nh sau:

(xcq/h)(2-3)y l tuyn thuc vng cao ni lu lng xe tp trung gi cao im khng ln. Vy chn: Ngcd = 0,1 x N = 0,1 x 931= 93.1(xcq/h)Xc nh tc thit k.Tc thit k l tc dng tnh ton cc ch tiu k thut ca ng trong trng hp kh khn.Cn c vo cp ng (cp III), a hnh vng min ni, theo bng 4 ca TCVN 4054-05 th tc thit k ca tuyn l Vtk = 60km/h.

9.3.1.2 Xc nh s ln xe chy:Mt ct ngang nn ng

B rng nn ng ngL ngPhn xe chyPhn gia cL ngng dng

Hnh I.9.1 Mt ct ngang nn ng

lu lng xe thit k gi cao im

ta chn D bo theo quy lut hm s tng tuyn tnh

D bo theo quy lut hm s m

M hnh hm s m thch hp vi nhiu nc, c bit l cc nc ang pht trin nn ta chn d bo theo quy lut hm s m tnh.

- Lu lng xe chy ngy m trung bnh nm (xe/ngy m) nm tng lai

- Lu lng xe chy ngy m trung bnh nm (xe/n) nm ut: Thi gian d bo nm tng lai k c nm u tin: ta chn 15 nmq: T l tng trng lu lng xe hng nm (5%-10%) ta chn 10%.

Theo s liu ban u No = 931 (xe/ngy m), Quy i ra xe con nm th 15: Nt = N0 q * (1+q)t-1 = 931* (1+ 0.09)15-1 = 3111.14 (xcq/ng).Ncgio = 0,12*3111.14 = 373.33 (xcq/h).

= > ln. Do s ln xe thng chy l s chn nn Nlx = 1 lnTra TCVN4054-2005 Vtk=60 Km/h v a hnh l i ni l 2 ln xeVy ta chn l 2 ln xe

9.3.1.3. Xc nh dc dc ln nhta) Xc nh dc dc theo sc ko ca xe c dc ln nht imax ph thuc vo loi xe thit k, tc tnh ton v loi kt cu mt ng. dc dc ln nht phi m bo cho cc loi xe ln c dc vi vn tc thit k v c xc nh theo hai iu kin sau:Theo vn tc xe chy thit k m bo xe c kh nng vt dc ta tnh ton vi hai loi xe l xe ti v xe con theo cng thc sau:

Trong D : l yu t ng lc ca xe, c xc nh t biu nhn t ng lc hc ca xe.

Hnh I.9.2 Biu nhn t hc ca xe con rA3-21Von Gaf : l h s cn ln, ph thuc vo vt liu lm mt ng.Do ta ch tnh ton cho nm tng lai l 15 nm v iu kin a hnh l min ni nn ta chn loi mt ng b tng nha.Tra bng (1-2 bi ging TK) i vi mt ng b tng nha ta c f = 0.01 - 0.02 , ta chn f = 0.01. xc nh D ta cn c vo biu ng lc hc vi cch chn nh sau:Chn vn tc xe l V = 40 (km/h ) v ng vi chuyn s xe l s cao nht m xe c kh nng chy .Tra biu nhn t ng lc vi xe con rA3-21Von Ga:Vi V= 60 (km/h) ta c D = 0.09

b) Xc nh dc dc ti a theo c tnh ng lc ca xeNguyn l tnh ton: Sc ko ca xe phi ln hn tng lc cn trn ng. Khi dc dc ln nht ca ng c tnh ton cn c vo kh nng vt dc ca cc loi xe, tc l ph thuc vo nhn t ng lc ca t v c tnh theo cng thc sau: Dk=f i jTrong :Dk : c tnh ng lc biu th cho sc ko ca t (sc ko trn 1 n v trng lng ca xe).f : H s cn ln ly bng 0.02 (mt ng b tng nha).i : dc ng biu th bng %.j : Gia tc chuyn ng ca xe. (Ly du + khi xe ln dc, ly du - khi xe xung dc)

Gi thit xe chuyn ng u, ta c j = 0 h s sc cn qun tnh: j = 0 Tnh ton cho trng hp bt li nht: Khi xe ln dc : Dk f + i imax= Dk - fVi Vtt = 60 km/h ( vn tc thit k: tc ln nht ca xe n chic c th chy an ton trong diu kin bnh thng do sc bm ca bnh xe vo mt ng), tra bng c tnh ng lc ca xe v thay vo cng thc tnh ton ta c bng sau: Bng tra nhn t ng lcLoi xeXe conXe ti trc 6-8 TXe ti trc 10 T

Xe tng ngCamry 2.4Zil-130MAZ-500

Dk0,090,050,04

Imax0,070,0350,025

Bng I.9.3 Bng tra nhn t ng lcCn c vo bng trn ta chn imax=7%V trong lu lng xe ta thy rng lng xe con chim nhiu hn c nn dc dc ti a l tnh cho xe con. Do vy, khi xe c trc 6-8T mun vt dc th phi chuyn sang s III v chy vi tc 35-40 km/h, cn xe c trc 10 T phi chuyn sang s II v chy vi tc 30 Km/h th mi vt c dc .Xc nh dc dc tnh theo lc bmTheo iu kin v lc bm gia lp xe vi mt ng. cho xe chuyn ng c an ton th sc ko c ch ca t phi nh hn hoc bng sc bm ca lp xe vi mt ng. Nh vy theo iu kin ny dc dc ln nht phi nh hn dc dc tnh theo lc bm (ib): ib c tnh trong trng hp lc ko ca t ti a bng lc bm gia lp xe vi mt ng.Cng thc:Db = >DTrong :D: c tnh ng lc ca t tnh trnDb= f ib jib : dc dc tnh theo lc bm.j : gia tc khi xe chuyn ng.G: trng lng ton xeGb: trng lng tc dng ln bnh xe ch ng c ly nh sau:-Vi xe ti Gb= (0,6 0,7)*G.-Vi xe con Gb=(0,5 0,55)*G: h s bm dc bnh xe vi mt ng ph thuc trng thi bnh xevi mt ng, trng hp bt li nht (mt ng m v bn) ly =0,3Pw: lc cn khng kh ca xe

Pw = FTrong : -K: h s sc cn khng kh ph thuc mt khng kh v hnh dng xe -F : din tch chn gi ca xe F=0,8*B*H Vi B: chiu rng ca xe H: chiu cao ca xe -V: vn tc thit k V=60km/hTa tnh ton trong trng hp khi xe chuyn ng u v iu kin bt li l khi xe ang ln dc (j =0, ib mang du dng )Db=f+ib ib= Db -fVi mt ng nha h s f= 0,02 ta tnh ib=Db-f .Tra cc s liu tng loi xe c th v tnh ton ta c kt qu sau:

Bng dc dc theo sc bmLoi xeKFVPwGGbDbidmax

Xe con0.032.426020.10.318759600.1430.123

Xe ti trc 5.6T0.054.66063.690.3825061500.2160.196

Xe ti trc 9.5T0.065.66093.040.31355074000.1570.137

Bng I.9.4 Bng dc dc theo sc bmKt hp vi dc imax tnh c theo c tnh ng lc ta c bng sau:Bng kt qu tnh dc dcLoi xeLoi xe imax

Xe con 0.07

Xe ti trc 5.6T 0.03

Xe ti trc 9.5 T 0.02

Bng I.9.4 Bng kt qu tnh dc dciu kin xe chy khng b trt v mt n nh l ib imax .Cc iu kin c kim tra trn bng v u m bo .c) Xc nh dc dc theo quy trnh i chiu vi quy phm i vi ng cp III min ni vn tc thit k V=60km/h dc ln nht trn ton tuyn l imax= 7 % .Vy ta chn dc dc ln nht l 7% 9.3.1.4. Xc nh tm nhn xe chy: m bo an ton khi xe chy trn ng ngi li xe lun lun cn phi nhn thy mt qung ng pha trc kp thi x l mi tnh hung xy ra trn ng . Chiu di di on ng ti thiu cn nhn thy pha trc gi l tm nhn xe chy . Do vy khi thit k ng ta phi m bo yu t ny ngi li xe c th yn tm tham gia giao thnga.Xc nh chiu di tm nhn theo s 1 Chng ngi vt trong s l mt vt c nh , nm cng vi ln xe ang chy (nh , hay cy... )iu kin b tr tm nhn:Xe ang chy vn tc V. iu kin m bo an ton l ngi li xe phi nhn thy chng ngi vt tnh nm trn ng t khong cch ti thiu S1 (m) ngi li xe kp hm dng v cch chng ngi vt tnh mt c li an ton L0 .

S1ShLpuL011S 1 S tnh ton

Hnh I.9.3. S tnh ton tm nhnS1 = Lp + Sh + L0Tnh chiu di tm nhn tnh theo V ( km/h ) ta c :

S1 = + + LoTrong :Lp : Chiu di on phn ng tm l ; l on ng xe chy c trong thi gian phn ng tm l tp tnh cho 1s , khi tnh V (Km/h) =VTK

Lp = (m).

Sh : Chiu di hm xe, Sh = .L0 : C ly an ton, L0 =510 m, ly L0 =10 m.V : Vn tc xe chy tnh ton V = 60Km/h.k : H s s dng phanh k = 1,2 i vi xe con. : H s bm dc trn ng = 0,5 ( xt trong iu kin thng thng) i : dc dc trn ng , ta ly cho trng hp bt li nht khi xe xung dc vi i=imax=5%

S1= + + l0 = Theo TCVN 4054- 05, tm nhn trc chng ngi vt c nh S1 =75m. chn tm nhn mt chiu S1 =75mb.Chiu di tm nhn hai chiu (tnh theo s 2) Tnh hung : C 2 xe chy ngc chiu trn cng mt ln ng , m bo an ton hai xe phi nhn thy nhau t mt c li ti thiu S2 no y hai xe kp hm dng cch nhau mt c li an ton L0.S tnh ton

S2Sh1LpL011LpSh222

Hnh I.9.4. S tnh ton tm nhn 2 chiu- Xt trng hp 2 xe chy cng vn tcChiu di tm nhn trong trng hp ny l:

S2 = = Theo TCVN 4054-05, chiu di tm nhn thy xe chy ngc chiu l:S2 =150 m. chn S2 = 150 (m).c. Chiu di tm trnh xe ngc chiu S 3.Tnh hung t ra l 2 xe chy ngc chiu nhau trn cng mt ln ng, an ton th xe chy tri ln phi kp li v ln xe ca mnh trnh xe kia mt cch an ton m khng gim tc v c tnh theo cng thc sau :S3= Lp +Lo +L1 + L2L1 : Chiu di xe 1 chy c trong thi gian li trnh xe 2 ( m)L2 : Chiu xe th 2 chy ( m)

L2: Chiu di xe th 2 chy c L2= L1Khi xe 1 chy chy trnh xe 2 an ton th xe 1 phi r sang ln ca mnh vi bn knh r ti thiu c tnh theo iu kin n nh chng trt ngang

l h s bm ngang v c ly= (0.6 -0.7)

Chn =0.5

=0.6* = 0.6*0.5 = 0.3

: dc ngang mt ng ph thuc loi mt ng in= 2%

S3 =2Lp +L0 +2L1

a=3 m khong cch tim 2 ln xe.

m

S3 = Theo TCVN 4054-05, chiu di tm nhn thy xe chy ngc chiu l:S3 =350m. chn S3 = 350 (m).

d. Chiu di tm nhn vt xe S4

S tnh ton3

3

Hnh I.9.5. S tnh ton tm nhn vt xeXt theo s 4, xe 1 chy nhanh bm theo xe 2 chy chm vi khong cch an ton Sh1-Sh2, khi quan st thy ln xe tri chiu khng c xe, xe 1 li dng ln tri vt xe v quay v ln xe ca mnhTm nhn vt xe c tnh theo cng thc sau :iu kin bnh thng th : S4 = 6VCng bc : S4 = 4VXt cho iu kin bnh thng tnh cho 10 sTa c: S4 = 6V= 6*60= 360mtheo quy trnh tm nhn ti thiu l 350 m . chn S4 = 360m.9.3.1.5 Xc nh bn knh ng cong nm ti thiu trn bnh Ti nhng v tr tuyn ng i hng ngot phi hoc tri , ta phi b tr ng cong c bn c bn knh ln hn ch lc y ngang gy nguy him cho li xe v hnh khch cng nh s chuyn ng ca xe.Tuy nhin do iu kin a hnh b hn ch nn ta b tr ng cong c bn knh ln th vic thi cng s rt kh khn v khi lng thi cng tng ln nhiu lm tng gi thnh cng trnh. T nhng vn trn, ta cn phi xc nh bn knh ti thiu ca ng cong mt cch hp l nht. a. Bn knh ng cong nm nh nht (m) :

Rmin = Trong : V- tc xe chy tnh ton (km/h) , V = 60 km/h

- h s lc ngang ln nht = 0.15Isc max - dc siu cao ln nht = 0.07

Rmin = Mt khc theo TCVN 4054-05 i vi ng cp III min ni c V = 60km/h th bn knh ng cong nh nht gii hn l 125 m. Vy ta chn bn knh ng cong nm nh nht Rmin = 350m.b. Bn knh ng cong thng thng (m) :

Rttmin = Trong : V- tc xe chy tnh ton (km/h) , V = 60 km/h

- h s lc ngang, = 0.05 -:- 0.08, a hnh khng thun li ta

chn =0.08isctt = dc siu cao tnh ton = imax - 2% = 7% - 2% = 5%

Rmin = Mt khc theo TCVN 4054-05 i vi ng cp III c V = 60km/h th bn knh ng cong thng thng l 250m.Vy ta chn bn knh ng cong thng thng Rttmin = 400m.c. Bn knh ng cong nm ti thiu khng cn b tr siu cao (m) :

Rksc = Trong : V- tc xe chy tnh ton (km/h) , V = 60 km/h

- h s lc ngang, = 0.003 - 0.05, chn = 0.05in - dc ngang mt ng , in = 2%

Rksc = Mt khc theo TCVN 4054-05 i vi ng cp III c V = 60km/h th bn knh ng cong ti thiu khng cn b tr siu cao l 1500m.Vy ta chn bn knh ng cong ti thiu khng cn b tr siu cao l Rksc = 1500m9.3.1.5 Xc nh on ni siu cao 9.3.6.Siu cao9.3.6.1. dc siu cao

Chn dc siu cao theo Bng 14TCVN 4054 05 i vi ng cp III, min ni tc thit k 60 km/h th .9.3.6.2.Chiu di on ni siu cao

Chiu di on ni siu cao theo phng phap quay quanh tim xc nh theo cng thc

ng cp III dc ph , b tr 2 ln xe, b rng 2 ln xe l 6.0 m

- m rng mt ng ().

Chiu dai oan ni siu cao theo Bng 14 TCVN 4054 05 i vi ng cp III tc thit k 60 km/h isc=0,02 th lsc=50 m. Vy chon lsc=50 m.

tinh lai dc phu: ip==

9.3.6.3.Chiu di ng cong chuyn tip

Theo Bng 14 TCVN 4054 05 khi vn tc thit k phi b tr ng cong chuyn tip.

Vi R= 350m =>

Vi R= 400 m =>

dc siu cao v chiu di on ni siu cao ph thuc vo bn knh ng cong nm v tc thit k khng c nh hn cc gi tr quy nh trong Bng 14 TCVN4054 05, vi v th , kin ngh chn .9.3.7. m rng trong ng cong: m rng ca phn xe chy c 2 ln xe c tnh gn ng nh sau:

( m) Trong : L: Chiu di t u xe n trc sau, tnh cho trng hp xe ti L = 6.5m.V: Vn tc tnh ton xe chy ( Km/h )R: Bn knh ng cong ( m ) xt trng hp bt li nht R = Rmin =350 m.V: vn tc thit k, V=60 (km/h)

(m)Tuy nhin cc ng cong ca tuyn u c bn knh ln hn 250 nn trn tuyn khng cn m rng ng cong.9.4. Thit k siu cao nh 39.4.1. Chn bn knh:Theo TC 4054-2005 v thit k ng t:Cp hng ng thit k l Cp III.MN ;Cho nn ta c:

+ Bn knh ng cong nm ti thiu gii hn: =125(m).

+ Bn knh ng cong nm ti thiu thng thng:=250(m). Trong trng hp bn knh thng thng t c th chn cc kch thc bn knh khc nh: 300 : 350: 400: 500: 1000. Tn dng a hnh b tr ng cong hp l.

+ Bn knh ng cong ti thiu khng siu cao:=2500(m).Cn c vo TC 4054-2005, v a hnh ti v tr thit k ng cong. Ta chn bn knh cong ti 3 l: R=350(m).a. dc siu cao- Nghin cu s chuyn ng ca t ta thy khi t chy trn ng cong bng t c xu th b trt hoc lt v pha lng ng cong do nh hng ca lc li tm. Trn cc ng cong c bn knh nh s nh hng ny cng ln. m bo an ton v tin li cho xe chy th cc ng cong bn knh nh ngi ta thng xy dng ln ng c dc ngang nghing v pha bng ng cong gi l siu cao. dc siu cao c tc dng gi bt lc ngang v tc ng tm l c li cho ngi li xe, lm cho ngi li t tin c th cho xe chy vi tc nh ngoi ng thng khi cha vo ng cong.- Tuy nhin dc siu cao phi nm trong gii hn cho php. dc siu cao phi m bo l khng b trt khi mt ng b trn. Theo qui phm thit k ng t Vit Nam quy nh tr s dc siu cao ph thuc v tc thit k v bn knh ng cong nm. Ta c vi V=60km/h, R=350(m) =>Theo TCVN 4054 - 2005 qui nh dc siu cao ln nht

= 2%b.on ni siu cao : Khi xe chy t mt ct ngang hai mi sang mt ct ngang mt mi (trn on cong trn c b tr siu cao) m bo cho xe chy m thun khng b lc ngang, cn thit phi c mt on ni siu cao di chuyn t mt ct ngang ng hai mi sang ng mt mi. Chiu di on ni siu cao ti thiu c tnh theo cng thc:

Trong : isc: dc siu caoip: dc nng siu cao, theo quy trnh vi ng cp 3 min ni V = 60km/h tnh bng ip=0.5%.B: chiu rng phn ng xe chy B = 6 mTra Bng 14 TCVN 4054 - 2005 tnh trong trng hp dc siu cao ln nht isc = 2%, ta c:

Tu thuc bn knh ng cong v isc ca tng ng cong m c on ni siu cao tng ng. Trc khi vo on ni siu cao cn mt on 10 m vut cho l ng c cng dc vi mt ng ip. Sau tin hnh b tr siu cao theo mt trong ba phng php sau:Phng php 1: Quay quanh tim ng nng phn ng pha lng ng cong cho c cng dc phn xe chy, sau tip tc quay tr phn xe chy v l gia c quanh tim ng cho ti khi t dc siu cao. Phng php 2: Quay phn ng pha lng ng cong quanh tim ng cho ti khi c mt ct ngang c dc ngang ca phn xe chy, sau quay quanh mp phn xe chy pha bng c mt ct ngang cho ti khi t dc siu cao. Phng php 3: Thc hin quay quanh mt trc o, cch mp phn xe chy bn ngoi mt c ly l 7 m (p dng khi phn xe chy > 7m). Thc hin ni siu cao trn tuyn c s dng phng php 1. Khi c ng cong chuyn tip, on ni siu cao b tr trng vi ng cong chuyn tip. Khi khng c ng cong chuyn tip th on ni siu cao b tr mt na nm ngoi ng thng v mt na nm trong ng cong trn. Khi c siu cao cn so snh gia on ni siu cao v on chuyn tip on no ln hn s chn lm on ni siu cao, chuyn tip. Tnh ton theo phng php 1:

Theo Bng 14 22TCN4054 -2005 vi R=350(m), =3%, v=60km/h c

Chn =50 (m).

Tnh li = ==0,0024=0,24%

Tnh , : ==25 (m)

-:

Xibil

02%-2%

102%-1.2%

202%-0.4%

252%0%

302%0.4%

502%2%

- : x60708090

ib=il4.6%5.4%6.2%7%

S tnh theo phng php quay tim:

9.4.2. Tnh ng cong chuyn tipKhi xe chy t ng thng vo ng cong, bn knh cong thay i t ngt t v R, ng thi lc ly tm tc dng vo xe tng dn t 0 n . Cc tc ng ny gy cm giac kh chu cho li xe l hnh khch, mt an ton cho hng ho. iu ny i hi phi b tr mt ng cong chuyn tip gia ng thng v ng cong trn. ng cong chuyn tip s c tc dng lm cho tuyn c dng hi ho hn, tm nhn c m bo hn v mc tin nghi an ton u tng r rt.ng cong chuyn tip b tr trng hp vi on ni siu cao v on ni m rng phn xe chy (nu c).

B tr ng cong chuyn tip

- Tnh ton v cm ng cong chuyn tip:

Tnh ton v la chn chiu di b tr CCT :+ tng ca gia tc ly tm I theo thi gian c quy nh tu theo tng ncTheo quy trnh M : 0,30-0,90 m/s3Php : 0,65-1,00 m/s3Lin x (c) v Vit Nam : 0,5 m/s3Thy in, Anh, : 0,8 m/s3

Nh vy, vi I=0,5 m/s3 ta c cng thc dng tnh ton chiu di ti thiu ca ng cong chuyn tip

== 26.26(m).+ Chiu di ca CCT cn c xc nh t iu kin thi gian hnh trnh trn CCT. Vi li xe c trnh chuyn mn trung bnh th thi gian ny bng 3s v ta c cng thc Lct = 0,83V= 49.8(m)

Chn ==50(m). Xc nh thng s A:

==132.28 (m).

Tnh gc kp : == =4o17

Kim tra iu kin b tr ng cong chuyn tip => tha mn.

Xc nh ta im cui ca ng cong chuyn tip (,):

=49.97(m).

= 1.19 (m). Xc nh cc chuyn dch:

=49.97-350.sin 4o17= 23.82(m).

=1.19-350(1-cos 4o17)= 0.21 (m).

Tnh li bn knh ng cong =350-0.21 = 349.78 (m).

Tnh cc yu t ca ng cong trn theo :

=350= 113.7 (m).

== 195.38 (m).

Xc nh chiu di phn cn li ca ng cong trn K0 ng vi gc 0 sau khi b tr CCT: ==26.14 (m) Xc nh im bt u, kt thc ca CCT v rt ngn ca ng cong:N=-(T+t)NC=N+K0+2Lct=2(T+t) (K0+2Lct)B tr cc trn ng cong(lm theo phng php ta vung gc):Do R=1000(m) nn chn mi cc cch nhau k=10 (m).Xt mt im B bt k trn ng cong chuyn tip c to cong tnh t gc ng cong l S, ti c bn knh ng cong , bn knh ny gim dn u t + (S=0) n R (S=L).

Ta c (1)v, I khng i

(2)Phng trnh (2) l c s l thuyt tnh ton ng cong clothoid

Hng s v ngi ta gi A l thng s ClothoidPhng trnh (2) c vit di dng to cc, v vy vic cm tuyn cn kh khn. Ngi ta chuyn sang h to Descarte nh phng trnh sau:

(3)Phng trnh (3) hi t nhanh nn ch cn 2 s hng u l chnh xc, nhng i vi nhng ng cong di th phi tnh ti 3 s hng. Hin nay phng trnh (3) c lp sn trong my tnh cm tay (PPC) tnh to CCT ngoi thc t.

B tr cc trn on :

Mt im A bt k trn phn ng cong trn c chiu di cung n T l St vi gc chn cung s c ta xt, yt theo h trc N c tnh theo cng thc sau:xt = t + R.sin(0 + )yt = R1 R.cos(0 + )

vi hoc ( )

Bng s liu ta cc im trn on

:Trong : t= 23.82, =4 17, R= 349.78 (m),=350(m);

CcStxtyt

11013859.872.08

22031669.833.25

33045479.644.70

44063389.566.45

55081199.368.47

660949108.4910.75

7701127118.2113.32

8801306127.7816.19

9901444137.2919.30

BRLK1e1K2e2L09.3.1.6 Xc nh m rng ca ng cong v on ni m rngS tnh ton

Hnh I.9.7. S b tr m rng

Khi xe chy trn ng cong vt bnh trc v vt bnh sau xe khngtrng nhau .Do xe c th chy c bnh thng cn phi m rng phn xe chy ln hn so vi trn ng thng.Khi R K:

Trong :

: bn knh qu o xe chy.R: bn knh ng cong.Bm: b rng mt ng.

: chiu di qu o xe chy chn bi gc chuyn hng .

S=150m+ S tnh ton:

Hnh HI.10.2 S vng Z phi d bChiu di tm nhn thy xe ngc chiu S2 = 150 m (TCVN 4054 2005). Tm nhn trong ng cong c kim tra vi xe chy trn ln xe pha bng, khi kim tra gi thit mt ngi li t cch mp trong phn xe chy 1.5m trn mt cao l 1,2m do ng khng c di phn cch nn tm nhn y ly l tm nhn hai chiu S2 = 150m. Trn bnh : Theo qu o ni trn dng thc di o trn bnh cc chiu di tm nhn hai chiu S2 v ng bao cc tia nhn ta c trng nhn theo yu cu v xc nh c Z l khong cch cn d b chng ngi vt.T phng php vch tuyn nh trn ta c bng tnh nh sau:

* Phng n : Tnh ton c ly m bo tm nhn ti ng cong:

- Ti nh D1: R = 350m, Bm = 6m, S =350m, = 33215,22 Rs = R (Bm/2)+1,5 = 300-6/2+1.5=298.5 m K= (*Rs*)/180= ( 3.14*298.5*33215,22)/180=172,03 S=150 < K=172,03=> Z=Rs*(1-cos /2) = (180*S/*Rs) = ((180*150)/(3.14*298.5))= 284823,23 => Z=Rs*(1-cos/2) = 298.5*(1-cos 284823,23/2)= 9,38

- Ti nh D2: R = 290m, Bm = 6m, S =150m, = 863424,19 Rs = R (Bm/2)+1,5 = 290-6/2+1.5=288.5 m K= (*Rs*)/180= ( 3.14*288.5*863424,19)/180 = 435,69

=(180*S)/(*Rs)= (180*150)/(3.14*288.5)=292548,14 => Z = Rs*(1-cos/2)= 288.5*(1-cos292548,14/2)= 9,46 BNG TNG HP Phng n 1:TT

Tn nhGc

R (m)S2(m)Rs(m)K(m)

Z(m)

1133215,22300150298.5172,03284823,239,38

22863424,19290150288.5435,69292548,149,46

Bng BI.10.6. Bng tnh gi tr m bo tm nhn trong ng cong phng n IBng BI.10.7. Bng tnh gi tr m bo tm nhn trong ng cong phng n IDa vo trc ngang tuyn th trn ton b tuyn m bo tm nhn nn ta khng phi d b.10.1.2 Thit k mt ct dc ng10.1.2.1 Cc im khng chXc nh cao nhng im khng ch buc ng phi i qua hoc ng phi cao hn cao ti thiu qui nh nh: Cao im u, im cui ca tuyn, cao ni giao nhau vi ng giao thng t khc cp cao hn hoc vi ng st, cao mt cu, cao ti thiu p trn cng, cao mt ng b ngp nc hai bn, cao nn ng nhng ni c mc nc ngm cao.Phn ct dc thnh nhng on c trng v a hnh qua tr s dc sn ni t nhin v a cht khu vc.Tuyn 1: im khng ch cao im M6 M10Cc im i qua v tr cng m bo chiu cao p t >0,5m ti cc cc H3 (Km0 + 100.00), ti cc 14 (Km1+779.3)10.1.2.2 Nguyn tc thit k- dc dc nh hng rt ln ti tc ca xe chy, thi gian xe chy, nng lc thng xe, an ton xe chy, gi thnh vt ti. V th dc dc ln th gim gi thnh xy dng nhng trong mi trng hp ta c gng dng cc b v t thay i dc.Phi hp cc yu t trn trc dc, bnh v nm trong a hnh c th. Mc tiu l trong khng gian c mt tuyn ng hi ha ni b khng che lp tm nhn, khng gy o gic c hi cho tm l ngi li xe.Cn c vo cc im khng ch trn trc dc.Cn c vo bn i hnh, t l 1/10.000 vi ng ng mc cch nhau 5m.Cn c vo phng n tuyn vch trn trc dc.+ im khng ch bt buc: l cc im trn trc dc buc phi i qua nh cc im c lin quan n cao theo quy hoch im giao ct cng mc vi ng st hay ng giao thng khc + im khng ch gii hn:Cao nn ng p qua bi sng phi cao hn mc nc tnh ton v c xt ti mc nc dnh v chiu cao sng v ln mi dc t nht l 0,5m.Cao mp nn ng cc on ng dn vo cu nh v cng phi cao hn cao nc tnh ton c xt ti nc dnh t nht l 0,5 m (tnh theo chiu con nc l c tn sut 4%).Cao ca nn ng trn cng phi m bo chiu dy, t p trn ti thiu l 0.5m ti trng phn b rng trn cng. Khi chiu dy o ng ln hn 0.5 m, chnh cao gia mt ng c nh cng phi dy b tr o ng.Cao ti thiu ca mp nn ng phi cao hn mc nc ngm tnh ton, mc nc ng thng xuyn m bo khu vc hot ng ca ti trng lun lun trong tnh trng kh ro.Thot nc tt cho nn ng khu vc hai bn ng. m bo cc yu cu ti thiu cho nn ng lun kh ro, khng nn o p qu cao v qu su trnh phi xy dng cc cng trnh chng d.Trong phm vi c th c nn trnh dng nhng on dc ngc chiu khi tuyn ang lin tc ln hoc xung. m bo thot nc tt v khng lm rnh su th nn ng o v nn ng na o, na p, khng nn thit k c dc dc nh hn 0.5% ( trng hp kh khn khng nn nh hn 0.3%). nhng on a hnh dc phi s dng dc dc ln 6% th yu cu c 2000 m phi b tr mt on ngh c dc dc thoi khng vt qu 2.5% v chiu di on ngh khng nn ngn hn 50 m. dc dc ln nht trn nhng on dc c bn knh nh hn 50m phi trit dc so vi dc dc ln nht .ng cong ng phi c b tr nhng ch ng i dc m hiu i s gia hai dc ln hn 1%. Khi vch ng c gng bm st nhng cao mong mun m bo yu cu v kinh t- k thut v iu kin thi cng.Khi trn tuyn lm cu vt th: + Tnh khng phi t 5.5 - 6m khi cu vt qua ng st.+ Cao thi cng H = 4.5m (d tr 4.7m) khi vt qua cc ng quc l.+ H = 3.2-3.3m i vi ng tnh l phi c bin hn ch cao phng tin.+ H = 2.5 i vi ng dn sinh.10.1.2.3 Cc phng php p dng thit k trc dcCn c vo ng en trn trc dc phi hp vi a hnh trn bnh ta tin hnh thit k ng theo ba phng php sau:a. Phng php thit k ng bao a hnh: Tc l cho ng thit k ln theo i hnh t nhin, l i song song vi mt t t nhin. Theo phng php ny khi lng o p hp l nhng li c nhiu on dc lt nht. Phng php ny c p dng vi nhng ni c a hnh bng phng hoc c cao thay i u, dc t nhin nh.b. Phng php thit k ct a hnh: Thit k ng ct theo a hnh t nhin to thnh nhng on ng o, p xen k. Phng php ny c p dng nhng ni c a hnh mp m, ng cp cao. Phng php ny khc phc nhc im ca phng php ng bao nhng li c nhc im l khi lng o p ln. c. Phng php tng hp: Phi hp hai phng php mt cch hp l cho tng on ng c th.10.1.2.3. Gii php thit k trc dc v kt qu thit kXc nh cao nhng im khng ch buc ng phi i qua hoc ng phi cao hn cao ti thiu qui nh nh: Cao im u, im cui ca tuyn, cao ni giao nhau vi ng giao thng t khc cp cao hn hoc vi ng st, cao mt cu, cao ti thiu p trn cng, cao mt ng b ngp nc hai bn, cao nn ng nhng ni c mc nc ngm cao.Phn ct dc thnh nhng on c trng v a hnh qua tr s dc sn ni t nhin v a cht khu vc.a) S b vch tuyn: Trn phn thit k bnh th cao dc tuyn va vng ni v vng ng bng do vy dng phng php phi hp hai phng php hnh bao v hnh ct. Cn c vo cao mc nc thit k tnh cao ng . (tn sut l thit k l 4%). v tr cui tuyn i vo khu dn c v th cao ng phi c khng ch ph hp vi cao nh dn. Cc im khng ch trung gian ti cc v tr cu cng, cc v tr ny cao ng c xc nh theo cao t p trn cng. Da vo trc dc thin nhin ta vch ng vi cc on i dc nh sau:Theo phng n 1:STT dc dc (%)S onChiu di (m)T l chim (%)

10 < i < 1,001300.0027.10

21,00 < i < 2,501459.0045.5

32,50 < i < 4,001347.1027.4

44,00 < i < 6,0000.000.00

Tng cng31106.100100

Bng BI.10.8. Bng tng hp on dc phng n I

b) B tr ng cong ng trn trc dcSau khi xc nh c tr s dc ti cc v tr i dc ,ng cong ng c b tr vi i dc ln hn 1%. Theo nh phng n k ng chn ta xc nh tuyn b tr 8 ng cong ng.* Tr s bn knh ca ng cong ngCn c vo iu kin m bo tm nhn ca ngi li xe trn ng.Cn c vo tiu chun thit k ng 4054-2005 ca b GTVT vi ng cp III min ni, vn tc xe chy 60 Km/h quy nh Rmin = 1500m.Da vo cc tiu chun trn, chn Rmin 1500 m* Xc nh cc yu t ca ng cong ng.Sau khi chn bn knh ng cong ng th cc yu t cn li ca ng cong c xc nh theo cng thc sau: Chiu di ng congK = R.(i1 - i2)(m)

Tip tuyn ng cong T = R.()(m)

di phn cP = (m)

Tung cc im trung gian trn ng cong c honh X c xc nh theo cng thc:Y = Trong :R : Bn knh ng cong ti im gc ca to ti nh ng cong.du (+) ng vi ng cong ng lidu (-) ng vi ng cong ng lmi1,i2 : dc ca hai on ni nhau bng ng cong ng du (+) ng vi ln dcdu (-) ng vi xung dcT cng thc trn ta c bng xc nh cc gi tr ng cong ng nh sau:

BNG YU T NG CONG NGPhng n 1:TTL trnhi=R (m)T (m)P(m)Ghi ch

1Km0+200-2.1600078.450.51TK ng li

2Km0+5001.51600045,280.17TK ng lm

3Km0+722.57-2.18600065.570.36TK ng lm

2Km0+9002.82600084.340.59TK ng lm

10.1.3 Thit k trc nganga. Quy m mt ct ngang:- Chiu rng nn ng Bnn = 9,0m;- Chiu rng mt ng Bmt = 6,0m;- Chiu rng l v l gia c Bl =3,0m (cho c hai bn);- dc ngang mt ng imt =il gia c=2%;- dc ngang l ng il t = 4% dc v pha ngoi;- Chn dc ta luy;+ dc ta luy nn ng p: 1/1,5+ Dc ta luy nn ng o: 1/1- Cc trc ngang trong ng cong, cc yu t trc ngang ly theo cc yu t cong c thit k trn bnh .Cn c vo c im a hnh, a mo a cht, kh hu, thu vn v cn c vo quy m cp hng ca ng. Mt ct ngang c thit k cho ton tuyn C-D nh sau:- B rng nn ng Bn= 9.0 m+ B rng phn xe chy l: 2x3,0 = 6,0(m)+ B rng l gia c: 2x1 = 2,0(m)+ B rng l t: 2x0,5 =1(m) - dc ngang mt ng v l gia c: in=2%- dc ngang phn l t = 4%- dc mi ta luy nn o 1:1- dc mi ta luy p 1:1,5- Chiu dy kt cu mt phn xe chy 60 cm- Chiu dy kt cu l gia c:30 cm

< 1 m1:1.5b. Cc dng trc ngang in hnh*.Nn p

Trng hp t p thp hn 1 m th mi dc ta luy thng ly 1/1.5 1/3 tin cho my thi cng ly t t thng u p nn hoc tin cho my o rnh. Nu nn t p thp qu th phi cu to rnh dc hai bn m bo thot nc tt.

H =1 6m0,5m1:1.5Trng hp t p cao H = 1 6m th dc mi ta luy ly 1:1,5 v thng u ly pha cao hn v phi c mt on 0,5m bo v chn mi ta luy.

Nu dc ngang sn ni < 20% th ta phi ry c phm vi y nn tip xc vi sn dc.Nu dc ngang sn ni t 2050% th bt buc phi dng bin php nh cp B rng bc cp ti thiu l 1.0 m, nu thi cng bng c gii th phi rng t 3 4 m.

H1:1.5I = 20 - 50 %

Nu sn dc ni ln hn 50% th lc ny khng th p t vi mi dc ta luy c na v mi ta luy s ko rt di mi gp sn t nhin do kh bo m n nh ton khi. Khi phi p dng bin php xp pha chn ta luy cho php mi dc ta luy ln hn.

* Nn o

Hi vi nn ng o khi xy dng s ph hoi th cn bng ca cc tng t thin nhin, nht l trng hp o trn sn dc s to nn hin tng sn dc b mt chn, v th mi ta luy o phi c dc nht nh bo m n nh cho ta luy v cho c sn ni.

Theo qui phm 4054-05 ca b giao thng, mi dc ta luy nn o c thit k theo cc gi tr ghi trong bng sau:Loi t Chiu cao o ti a(m) dc mi taluy o

1. cng - c phong ho nh- d phong ho16161 : 0,21: 0,5 1:1,5

2. Cc loi b phong homnh61 : 1

3. ri rc6 121 : 1,5

4. t ct, st trng thi cng,do cht121 : 1,5

Bng BI.10.12. Bng quy nh mi dc ta luy nn ng

1:1.51:1* Nn na o, na p

2. Tnh khi lng o p nn ng+ Trong thit k lp d n kh thi phi tnh c khi lng nn ng tin hnh so snh cc phng n tuyn thit k thit k t chc thi cng nn ng, b tr thi cng c th, tnh c gi thnh, lp d ton cng trnh. C s tnh ton khi lng o p l cc bn v trc dc, trc ngang v bnh a hnh+ tnh ton khi lng o p chnh xc rt phc tp v phi tnh tch phn. Trong d n kh thi cho php tnh theo phng php gn ng. Ni dung ca phng php nh sau:- Chia tuyn thnh nhiu on nh vi im chia l cc cc a hnh v ti cc v tr im xuyn- Trong mi on, gi thit mt t l phng v tnh khi lng o p nh th tch mt lng tr: Vo= (F1o + F2o).Ltb/2 Vp= (F1p + F2p).Ltb/2Trong : Vo, Vp l th tch t phi o, hoc p trong on F1o, F1p, F2o , F2p l cc din tch o, p ti u v cui on. Ltb l c ly trung bnh gia hai mt ct tnh ton.10.1.4 Thit k nn ng10.1.4.1. Tc dng ca nn ng- Khc phc nn ng thin nhin to nn mt di rng dc theo tuynng c cc tiu chun v bnh , trc dc, trc ngang p ng c iu kin xe chy an ton, m thun v kinh t.- Lm c s cho o ng: lp pha trn ca nn ng cng vi o ng chu tc dng ca xe chy do nn ng c nh hng rt ln n cng v cht lng khai thc ca c con ng.10.1.4.2 Yu cu cu chung i vi nn ng Nn ng phi l nn tng vng chc ca phn xe chy v phi m bo duy tr cc yu t hnh hc ca tuyn ng nh thit k qui nh. V vy nn ng khng c bin dng ln v phi c cng n nh cao.- V mt hnh hc nn ng phi c hnh dng v kch thc ph hp cc yu cu ca tuyn v s n nh ca nn.- V mt c hc phi bo m nn ng n nh, khng c bin dng nguy him v cng khng c ln nhiu di tc dng ca xe c v trng lng bn thn.- V mt vt l phi m bo tt nn ng khng qu m, khng gim cng trong thi k m t, phi c bin php k thut m bo duy tr c cng cao trong sut qu trnh s dng.10.1.4.3 Nguyn tc thit k nn ng* Phi m bo khu vc tc dng ca nn ng (khi khng c tnh ton c bit, khu vc ny c th ly 80cm k t di y lp kt cu o ng tr xung) lun t c yu cu nh sau:- Khng b qu m v khng chu cc ngun m t bn ngoi (nc ma, nc ngm, nc bn cnh ng)- 30cm trn cng phi m bo sc chu ti CBR ti thiu bng 8 i vi ng cp I, cp II v bng 6 i vi ng cp khc- 50 cm tip theo phi m bo sc chu ti CBR ti thiu bng 5 i vi ng cp I, cp II v bng 4 i vi cc cp khc.Trong : CBR l ch s sc chu ti xc nh trong phng th nghim theo iu kin mu t cht m nn tiu chun, theo 22TCN332-05 v c ngm bo ha 4 ngy m.* Nn p trn t yu p dng theo 22TCN 262* Nn ng trong vng a cht phc tp, p dng theo 22 TCN 211* hn ch tc hi xu n mi trng , v cnh quan cn ch trng cc nguyn tc sau:- Hn ch ph hoi thc vt. Khi c th gom t hu c trong nn o ph xanh li cc h t mn, cc sn ta luy;- Hn ch ph hoi cn bng t nhin, trnh o su p cao v ch cn bng khi lng o, p. Gp a hnh him ch nn so snh nn ng vi cc phng n cu cn, hm, nn ban cng. Chiu cao mi c ng khng nn cao qu 20m;- Trn sn c qua 50% nn xt phng n tch thnh 2 nn c lp;- Nn o v nn p thp hn phng n lm thoi (1:3-1:6) v gt trn ph hp a hnh v an ton giao thng;- Hn ch tc dng xu n i sng kinh t v x hi ca c dn nh gy ngp lt rung t, nh ca. Cc v tr v khu cng trnh thot nc phi khng ngp dng l v gy ph nn ch khc, trnh cn tr lu thng ni b da phng, tn trng quy hoch thot nc ca a phng.10.1.4.4 Gii php thit k nn ng- B rng nn ng 9.0m- dc mi ta luy nn o 1:1- dc mi ta luy p 1:1,5a. t p nn ng+ t p nn ng c ly t m t, t thng u, hoc t nn o. Thng u phi thit k c hnh dng hnh hc hon chnh khng lm xu cnh quan v khi c th tn dng c sau khi lm ng. t t cc ngun phi c lm th nghim. Cc lp c p xen k nhau nhng khi lp thot nc trn kh thot nc th mt ca lp di phi lm dc ngang 2 - 4% thot nc.+ Khi nn ng p bng ct, nn ng phi c bao ph chng xi l b mt ng thi m bo nc trong nn ng thot c ra ngoi. Nu bao bng t dnh, ch s do Ip >17 th chiu dy bao ph t nht l 0,5m v phi lm tng lc ngc cho nc thot ra c.+ Khi nn t nhin c dc ngang di 20% c php o b lp t hu c ri p trc tip. Khi nn t nhin c dc ngang t 20% - 50% phi o thnh bc cp trc khi p nn ng. Khi nn t t nhin c dc ngang ln hn 50% phi thit k cng trnh chng (tng chn ...). + cht k = 0,98 vi chiu dy t p dy 30cm tnh t lp kt cu o ng tr xung. Cn li l cc lp t K95.Trc khi p t nn ng ta tin hnh bc lp hu c t phong ha sau mi tin hnh p. Chiu dy lp bc hu c 20cm.b. Cc loi t lm nn ng t l vt liu ch yu xy dng nn ng. Tnh cht v trng thi ca t ( m v cht) nh hng rt ln n cng v mc n nh ca nn ng. C mt s loi t sau:*. t ctt ct c cng cao v n nh tt i vi nc (h s ma st trong ca ct tng i ln, tnh thm thot nc tt v mao dn km). Nhng t ct ri rc, khng dnh nn phi c lp t dnh bc xung quanh gi cho nn ng khng b ph hoi ca ma, gi... Ta c th dng st trn vo ct tng dnh ca t ct.V nhng u im nh trn, t ct thng c dng p nn ng qua vng t yu, ly li.*. t stt st v ht rt nh nn tnh cht hon ton ngc li i vi t ct, khi thm t th kh kh, th tch d b thay i theo trng thi kh m, chiu cao mao dn li ln do tnh n nh nc ca t st km. t st khi kh li rt cng, kh p v v lm nh, khi t li nho nn d pht sinh hin tng cao su v kh m nn cht.V vy t st ch dc dng nhng ni p cao, thot nc tt v c bit phi c bin php m nn cht.*. t bit bi c c ht 0,005 0,05 mm, km dnh v n nh i vi nc km, mao dn ln 0,8 1,5 m. Loi ny c hm lng bi ln thng khi ma th nho d xi chy, khi kh th qu ri rc v hay sinh bi.V vy i vi loi t ny rt bt li khi xy dng nn ng v ch nn dng xy dng cc lp di ca nn ng ( di khu vc tc dng).Tm li, loi t ct l vt liu xy dng nn ng thch hp nht, tt nht. Sau l loi t st. t ct c mt s ht ln nht nh nn t yu cu v cng v n nh nc tt. ng thi li gm mt s ht nh nht nh.c. t nn trn tuyn v la chn t p nn ngt l vt liu ch yu xy dng nn ng. Tnh cht v trng thi ca t nh hng rt ln n cng v mc n nh ca nn ng.Qua h s kho st on ng ny trn nn t c Eo = 45 MPa, nn t ny l t ct nh v ct.Cn c vo cc ch tiu, tnh cht c l ca cc loi t v tn dng vt liu a phng sn c chn loi t ct nh v ct p.Ch tiu ca t ct nh v ct nh sau:Tn tE (Mpa) ()C (Mpa)W (%)

ct nh v ct45280.01860%

Bng BI.10.13. bng ch tiu ca t10.1.5 Thit k kt cu o ng10.1.5.1. Yu cu chung i vi kt cu o ngMt ng l cng trnh bao gm nhiu lp vt liu c cng v cng ln hn so vi t nn, c xy dng trn nn ng nhm to nn bng phng loi tr cc bin dng c hi i vi xe chy, cng vi nn ng chu lc v bo v cho nn ng khng phi chu lc qu ln dn n ph hoi. *Yu cu i vi kt cu mt ng: - Phi c cng chung v n nh v cng . Cng mt ng c c trng bng kh nng chng nn ln. - Mt ng phi bng phng trong sut thi k tnh ton v bng phng nh hng n tc ca xe, tui th ca xe, chi ph nhin liu, chi ph vn hnh. - Mt ng khng pht sinh cc vt nt gy tm l kh chu cho ngi s dng hoc mt m quan. - Mt ng phi nhm m bo tc xe chy an ton giao thng. - Mt ng phi t bi, t ting n. - Mt ng phi chu s bo mn tt.10.1.5.2. Cc nguyn tc thit k mt ng Kt cu mt ng l b phn t tin nht ca ng t nc ta, chi ph xy dng o ng chim ti 45% - 65% (i vi cc tuyn ng vng ng bng v th), vi 30 - 40% (i vi cc tuyn vng ni) gi thnh xy dng ng t. ng thi o ng cng trc tip nh hng nhiu nht n iu kin chy xe. Tin b ra sa cha mt ng gn chim hu ht cc chi ph duy tu, bo dng ng t hng nm vi khi lng vt liu dng sa cha l rt ln. Do vic thit k o ng hp l l c ngha ht sc to ln v kinh t k thut.* Cn c vo cc kt qu phn tch thc t v l thuyt b tr ph hp cc lp kt cu tun theo cc nguyn tc sau:+ Theo nguyn tc thit k tng th tuyn ng, nn ng v mt ng: Tiu chun thit k tuyn, nn v mt ng phi ph hp vi nhau tc l thit k tuyn nn xt ti cng v n nh ca nn ng, hn na cng v n nh ca nn ng l cn c thit k kt cu v b dy mt ng.+ Chn vt liu hp l, thch hp vi iu kin ti ch, nhm gim chi ph vn chuyn h gi thnh cng trnh tc l nn dng kt cu nhiu lp tn dng kh nng chu lc ca vt liu, cng vt liu ca cc lp gim dn theo chiu su. c bit tn dng vt liu dng lm lp mng, lp m.Tuy nhin khng nn dng kt cu qu nhiu lp lm cho vic thi cng phc tp.+ Thi cng thun tin, c li cho cng tc bo dng. Nn xt n lc lng k thut v thit b my mc thi cng b tr cc lp kt cu v xut cc yu cu k thut thi cng phc tp.+ Phn k xy dng, tng bc nng cao. s dng ngun vn c hn mt cch hp l, cn c vo yu cu ngn hn tin hnh thit k mt ng, sau tu theo mc tng xe hng nm ca lng giao thng tng bc nng cao dn.+ Ch kt hp tt ca vic thit k thot nc.10.1.5.3.Tnh ton thit k o ngVic la chn kt cu o ng c da trn cc yu t sau:+ i vi mt ng - ngha cp hng k thut ca ng - Lu lng xe chy thit k - Tc xe chy tnh ton. Kh nng cung cp vt liu, phng tin thi cng, iu kin kh hu v iu kin duy tu bo dng+ i vi mng ng - iu kin a cht thu vn, th nhng - Tnh hnh nguyn vt liu c sn * Chn vt liu cho tng mt o ngVt liu lm lp mt ch yu cn dng loi t hoc khng thm nc, c cng v tnh n nh v cng i vi nc v nhit cao, c bit c kh nng chng tc dng ph hoi b mt cng nh chu bo mn tt. V vy, nn dng cc vt liu c cu trc lin kt tt (dng thm cht lin kt) c cht ln, c ct liu c chn lc v hnh dng v tnh trng b mt bo m cng (c v ) cn thit v kch c ht nh m bo chng bong bt tt . * Chn vt liu cho tng mng o ngVt liu tng mng c th dng c cc loi cu trc ri rc, kch c ln, t chu c bo mn nh cc lp dm, cp phi, t v gia c cht lin kt v c, si cui, ba, ph liu cng nghip, gch v... Cng ca lp mng cng pha di th c cng thp hn ph hp vi quy lut truyn ng sut do hot ti.i vi kh hu Vit Nam (nhit i) th khng nn chn ct lm lp mng di cng v ct rng to iu kin thun li cho vic tch t m, ng thi ct c cng thp khng gp phn vo vic chu ti ng k, li gy kh khn cho vic thi cng cc lp bn trn. Nu dng ct lm lp m th phi xy dng h thng rnh xng c tht tt thot nc lng ng.Cn c vo ngun vt liu ti a phng v kinh nghim s dng vt liu lm lp mng v cc d liu cho d kin lp mng nh sau:Lp mng di: Cp phi dm loi I dy 30mLp mng trn: Cp phi dm loi II dy 24cmSau khi la chn kt cu o ng ta tin hnh kim tra xem xt kt cu chn theo 3 trng thi gii hn t yu cu ca quy nh cha. ng thi tnh ton xc nh li b dy cn thit ca mi lp cu to.Vic tnh ton kt cu o ng gm ni dung kim ton theo 3 tiu chun trng thi gii hn di y:+ Tnh ton vng n hi thng qua kh nng chng bin dng (biu th bng tr s m un n hi) ca c kt cu o ng v tr s m un n hi ca kt cu phi ln hn tr s m un n hi yu cu (Ech > Egc).+ Tnh ton ng sut trt trong nn t v cc lp vt liu yu xem c vt qu tr s gii hn cho php khng.+ Tnh ton ng sut ko un pht sinh y cc lp vt liu ton khi nhm khng ch khng cho php nt cc lp .10.1.5.4. Thit k kt cu o ng.a) Cc cn c thit k Cn c cc ti liu kho st v mt ng v vt liu trn tuyn C - D qua thn Ninh Trang, x Ninh Thng, th x Ninh Ha, tnh Khnh Ha.Cn c vo Quy trnh thit k o ng mm 22TCN 211 -06. b) Thng s tnh tonXc nh Mun n hi chung yu cu ca mt ngTTLoi xePi (KN)C1C2niN15 (quy i)

1Xe p*

2Xe my*

3Xe con*

4Xe butTrc trc26,41,006,401903,00

Trc sau45,21,001,001906,00

5Xe ti c 2 trc (trong )

5.1Xe but nhTrc trc181,006,40380*

Trc sau561,001,0038030,00

5.2Xe ti trungTrc trc25,81,006,403806,00

Trc sau69,61,001,0038077,00

5.3Xe ti nngTrc trc48,21,006,4028574,00

Trc sau1001,001,00285285,00

Tng (Trc xe tiu chun/ngy m) quy i 100KN481,00

Bng BI.10.14. Bng quy i trc xe ra trc xe tiu chun 100KN

ng thit k c 2 ln xe nn theo 3.3.2 =>

=> (trc/ngy m.ln)Ntk = 265 (xe/ngy m.ln) tra bng 3.4 trong 22TCN 211-06 ta c Eyc = 165 (MPa). Tra bng 3.5 quy trnh 22TCN211-06 ng cp ng A1 cp III=> Eyc = 140 (MPa)=> Chn Eyc = 165 (MPa) kim ton.c) Cc c trng ca t nnt nn l t ct c m tng i tnh ton ca t nn l 0,65 . M un n hi : E0 = 45 (MPa) Lc dnh : C = 0.014 ( tra bng B-3 quy trnh 211-06)

Gc ni ma st: = 28 =>. K1 = 0.6, K2 = 1.0, K3 = 1.5Vy Ctt = 0.014*0.6*1.0*1.5 = 0.0126 MpaTra bng 3.1 ng vi P=10 kN=> p=0.6 Mpa; D=33 cm.d. Tnh ton kt cu o ngD kin thit k kt cu o ng nh sau

Hnh HI.10.3 Cu to lp kt cu o ngLp mt BTN cht 12.5 dy 5cmLp BTN cht 19 dy 7cmLp mng trn: Cp phi dm loi I dy 24cmLp mng di: Cp phi dm loi 2 dy 30 cmCc c trng ca vt liu nn v o ng nh sau:Vt liuHi(cm)EkuMpaEhMpaRuMpaEct(Mpa)C(Mpa)()

BTN cht 12.551800420300

BTN cht 19716003500.8250

CPD loi I24300300300

CPD loi II30250250250

t nn K98450,01428

Bng BI.10.15 Bng cc c chng vt liu kt cu o ng Kim tra kt cu o ng theo vng n hiTnh ton quy i lp tng ng bng cch chuyn h nhiu lp v h hailp bng cch i cc kt cu o ng ln lt hai lp mt t di ln theo cng thc:

h2 E2h1 E1Etb = E1.

Trong :k = ;t = Vih1, h2: Chiu dy lp di v lp trn ca o ng.E1, E2: Mun n hi ca vt liu lp di v lp trnTa c bng quy i Lp kt cuE(Mpa)T=Hi (cm)K=Htb (cm)Etb (Mpa)

CPD loi II2503030250

CPD loi I3001.2240,854271.5

BNT cht 193501.2970.1360279.82

BTN cht 12.54201.5050.08366289.28

Bng BI.10.16 Bng quy i lp kt cu o ng

+Tnh H/D =66/33 = 2 tra bng 3.6=> h s iu chnh = 1,21 Vy kt cu nhiu lp c a v kt cu 2 lp vi lp trn dy 60 cm c m un n hi trung bnh=> Etbdc =289.28 x 1.21 =350.03 ( Mpa)

Tnh ca kt cu dng ton KGan vi =H/D =66/33 = 2.0 Ta c Echm / Etbdc = 0,51=> Ech = 0,51. Etbdc = 0,56 x 350.03= 196.02MpaTa c: Eyc= 166 Mpa. ng cp III ly tin cy 0.90 nn =1.10Mt khc: x Eyc= 1,10 x 165=181.50 MpaVy Ech =196.02 Mpa > x Eyc= 181.50 Mpa=> tKt cu o ng m bo theo yu cu vng n hi* Kim tra v iu kin ct trtTa c bng quy i Lp kt cu (t di ln trn)E(Mpa)T=Hi (cm)K=Htb (cm)Etb (Mpa)


CPD loi I3001,2240,854271.5

BNT cht 192500.9270.1361268.95

BTN cht 12.53001.11550.08366271.26

Bng BI.10.16 Bng quy i lp kt cu o ng H/D =66/33 =2.0tra bng 3.6=> h s iu chnh = 1,21Vy kt cu nhiu lp c a v kt cu 2 lp vi lp trn dy 60 cm c m un n hi trung bnh=> Etbdc =271.26 x 1.21 =328.22 ( Mpa)

= 7.29

= 28 tra biu hnh 3.3 ta c

=> =0.0096 (Mpa)

H=66 cm = 28 tra biu hnh 3.4 ta c = -0.0021

=> =0.0075 (Mpa)

Mpa

=> tNn t m bo cng chng trt* Kim tra v iu kin chu unTnh ng sut ln nht y lp BTN cht 12.5

: Tng b dy cc lp kt cu k t y lp c kim tra ko un ln n b mt o ng

Ei, hi: l tr s m un n hi v b dy lp i trong phm vi Loi vt liuE (Mpa)hi (cm)

BTN cht 12.518005

BTN cht 1916007

Bng BI.10.17 Bng c chng ca kt cu BTNi vi lp BTN lp trn

MpaLp kt cu (t di ln trn)E(Mpa)T=Hi (cm)K=Htb (cm)Etb (Mpa)


CPD loi I3001,2240,8554271.5


+Tnh H/D =54/33 = 1.636 tra bng 3.6=> h s iu chnh = 1,201Vy kt cu nhiu lp c a v kt cu 2 lp vi lp trn dy 66 cm c m un n hi trung bnh=> Etbdc =271.5 x 1.201 =326.27 ( Mpa)

H/D =54/33 = 1.636; tra ton hnh 3.1 ta c Echm / Etbdc = 0,51=>=> Ech = 0,51. Etbdc = 0,51 x 326.27= 166.40 Mpa

Tm lp y b tng nha

; tra ton hnh 3.5 ta c =1.83 v vi p=0.6 Mpa p dng CT (3.11) ta c =p x Kb x=1.82*0.6*0.85=0.93 MpaP: p lc bnh xe ca ti trng tnh ton p=0.6 MpaKb: H s xt n c im phn b ng sut n v; Kb =0.85

: ng xut ko n viu kin ko un m bo khi

: H s m bo cng ko un vi tin cy 0.95 ta c =1.0

: Cng chu ko un gii hn nhit tnh ton =2.0K1: h s xt n s suy gim cng vt liu do mi

K2: H s xt n s suy gim cng theo thi gian so vi cc tc nhn v thi tit kh hu: K2=1.0

=>=0.557x1x2.0=1.114

=>=> ti vi lp BTN lp diLp kt cu (t di ln trn)E(Mpa)T=Hi (cm)K=Htb (cm)Etb (Mpa)


CPD loi I3001,2240,8554271.5

BTN nha cht 1918000.9270.1361362.15




Tm lp b tng nha lp trn






=>=0.557x1x2.80=1.56

=>=> t

* Tnh ton kt cu l gia c

Hnh HI.10.4. Cu to lp kt cu l gia cEyclgc=50% Eycm=165*50%=82.5 MpaLp mt BTN nha cht 9.5 dy 5cmLp BTN nha cht 12.5 dy 7cmLp mng: Cp phi dm loi I dy 24cmCc c trng ca vt liu nn v o ng nh sau:Vt liuHi(cm)EkuMpaEhMpaRuMpaEct(Mpa)C(Mpa)()

BTN nha cht 9.551800420300

BTN nha cht 12.5716003500.8250

CPD loi I24300300300

t nn 450,01428

Bng BI.10.20 Bng quy i lp kt cu l gia c Kim tra kt cu o ng theo vng n hiTnh ton quy i lp tng ng bng cch chuyn h nhiu lp v h hailp bng cch i cc kt cu o ng ln lt hai lp mt t di ln theo cng thc:

h2 E2h1 E1Etb = E1.

Trong :k = ;t = Vih1, h2: Chiu dy lp di v lp trn ca o ng.E1, E2: Mun n hi ca vt liu lp di v lp trnTa c bng quy i Lp kt cuE(Mpa)T=Hi (cm)K=Htb (cm)Etb (Mpa)

CPD loi I3002424300

BTN nha cht 193501.1670.2931310.84

BTN nha cht 12.54201.3550.1636324.71

Bng BI.10.21 Bng quy i lp kt cu l gia c


Tnh ca kt cu dng ton KGan vi =H/D =36/33 = 1.091. Ta c Echm / Etbdc = 0,37=> Ech = 0,371. Etbdc = 0,37 x 362.88= 134.26 MpaTa c: Eyc= 166 Mpa. ng cp III ly tin cy 0.90 nn =1.10Mt khc: x Eyc= 1,10 x 82.5=90.75 MpaVy Ech =134.26 Mpa > x Eyc= 90.75 Mpa=> tKt cu o ng m bo theo yu cu vng n hi* Kim tra v iu kin ct trtTa c bng quy i Lp kt cu (t di ln trn)E (Mpa)T=Hi (cm)K=Htb (cm)Etb (Mpa)

CPD loi I3002424300

BTN nha cht 192500.8370.8031277.03

BTN nha cht 12.53001.0850.1336279.60

Bng BI.10.22. Bng quy i kt cu l gia cH/D =36/33 = 1.091 tra bng 3.6=> h s iu chnh = 1,1175Vy kt cu nhiu lp c a v kt cu 2 lp vi lp trn dy 36 cm c m un n hi trung bnh=> Etbdc =279.60 x 1.175 =312.47 ( Mpa)

= 6.94

= 28 tra biu hnh 3.3 ta c 1

=> 1=0.00966 (Mpa)

H=36 cm = 28 tra biu hnh 3.4 ta c = -0.0012

=> =0.00846 (Mpa)

Mpa

=> tNn t m bo cng chng trt* Kim tra v iu kin chu unTnh ng sut ln nht y lp BTN ht trung

: Tng b dy cc lp kt cu k t y lp c kim tra ko un ln n b mt o ng

Ei, hi: l tr s m un n hi v b dy lp i trong phm vi Loi vt liuE (Mpa)hi (cm)

BTN nha cht 1918005

BTN nha cht 12.516007

Bng BI.10.22 Bng c trng kt cu BTN l gia ci vi lp BTN lp trn

MpaLp kt cu (t di ln trn)E(Mpa)T=Hi (cm)K=Htb (cm)Etb (Mpa)

CPD loi I3002424300

Bng BI.10.23 Bng quy i kt cu l gia c

+Tnh H/D =24/33 = 0.727 tra bng 3.6=> h s iu chnh = 1,066Vy kt cu nhiu lp c a v kt cu 2 lp vi lp trn dy 66 cm c m un n hi trung bnh=> Etbdc =300 x 1.066 =319.7 ( Mpa)


Tm lp y b tng nha






=>=0.557x1x2.0=1.114

=>=> t

i vi lp BTN lp diLp kt cu (t di ln trn)E(Mpa)T=Hi (cm)K=Htb (cm)Etb (Mpa)

CPD loi I3002424300

BTN cht 1918006.070.3031498.58

Bng BI.10.24 Bng c trng kt cu BTN l gia c



Tm lp b tng nha lp trn






=>=0.557x1x2.80=1.56

=>=> tKL: Mt l gia c m bo kh nng chu une. Kt lun: Cc kt qu kim ton theo trnh t nh trn cho thy kt cu o ng d kin m bo c cc iu kin yu cu v cng , c iu kin tha cng nhng c iu kin va v cng . Vy chp nhn kt cu ny lm kt cu o ng thit k.10.1.6. Cng trnh thot nc:10.1.6.1. C s thit k:- Da trn c s cc cng trnh ca tuyn c c hoc cc cng trnh pha thng lu v h lu ca chnh dng chy chnh.- Da vo s liu kho st, kt qu tnh ton quyt nh khu cng trn tuyn.- Tn xut thit k ng, cu v cng P = 4%;- Ti trng thit k cu cng HL-93 (TCN211-06)10.1.6.2. Gii php thit k:A-Thot nc ngang:- Thit k mi h thng thot nc ngang vi tn sut tnh ton 4%, ti trng thit k HL-93. - Cng ngang ng: Thit k vnh cu khu thot nc cng trn K 1m v 1.5m; - Cng chim phn ln cc cng trnh thot nc trn nn ng. Cng bao gm c hai loi: cng a hnh, cng cu to.- Cng a hnh c b tr ti cc v tr ct qua cc dng sui nh hay ct qua khe t thu m khi ma s hnh thnh dng chy.- Cng cu to c b tr ch yu thot nc trn mt ng v trn mi taluy c lu vc nh, cng cu to b tr theo qui trnh m khng cn phi tnh ton.

Cng: thng c s dng vi lu lng nc chy qua cng trnh 15m3/s v thng thng s dng loi cng trn BTCT ng knh 1m do d ch to v tin cho vic c gii ho xy dng. Nn t cng vung gc vi tim ng m bo cc yu cu k thut v kinh t. Khu cng phi c tnh ton thot c lu lng thit k v nn chn khu sao cho nc chy trong cng ch khng p. Thng thng khu cng khng nn dng 250m i vi rnh hnh tam gic.- Nn dng cng trn l BTCT v r v tin cho thi cng c gii. Cng vung dng cho lu lng ln hoc cao nn p hn ch.-C s tnh ton thu lc, thu vn cng trnh cng l lu lng tnh ton theo tn sut l thit k Q4%.Da vo cc thng s tnh ton lng nc ma v tuyn. Da vo a hnh thc t trn tuyn ta b tr s lng cng nh sau:Phng n 1:STTTn ccV tr t cngS lngGhi ch

1C1=H1Km0+10001.00Cng Cu To

Bng BI.10.25 Bng thng k cng phng nII - tnh ton lu vc thit kLu lng l thit k tnh ton theo 22TCN 220 - 95 ca B GTVT "Tnh cc c trng dng chy l":Qtk = Ap%.Hp%.F.1 - Hp%: Lng ma ngy (mm) ng vi tn sut thit k p =4%2 - : H s dng chy l a cht lu vc : t cp2 Lng ma ngy thit k HP% = 135mm Din tch lu vc F = 0.175km20.943 - Ap%: m un dng chy nh l ng vi tn sut thit k trong iu kin =1 AP%: ph thuc vo thi gian tp trung nc sd v c trng a mo lng sui ls+Thi gian tp trung nc :sdsd ph thuc vng ma v c trng a mo thu vn ca sn dc ls

bsd: chiu di bnh qun sn dc lu vc

msd: H s nhm sn dcmsd =0.15Vy:sd =1.78sd = 10.22+c trng a mo thu vn ca lng sui

mls: H s nhm ca lng sui mls =7ls =31.77T ls vsd tra bng c::Ap% =0.1004 - : H s trit gim lu lng do nh hng ca h ao v m ly: =1Vy : Lu lng l thit k tnh ton :Qtk =2.22(m3/s)5 - Kt lun phng n thit k. - Da trn lu lng l thit k tnh ton Qtk, chn loi cng l cng trn khng p khu D=1.00m, ca ra loi ch bt.

BNG TNH LU LNG CNGPhng n 1:

TTL trnhApHp%

FQ (m3/s)

1Km0+10000.1001350,9411.360.1502.22

Bng BI.10.27 Bng tnh lu lng cng phng n Ic. Xc nh khu cng La chn ch lm vic ca cng: Ta chn ch dng chy khng p v c p. Cn c vo ch chy c p v ch chy khng p trong cng ta chn ng knh cng theo bng ph lc 16 (gio trnh thit k ng t tp 3), t tra bng c chiu cao nc dng trc cng (H) v vn tc dng nc chy (V).Kt qu tra bng ta lp thnh bng:Phng n 1:STTL trnhQ (m3)H nuoc dang (m)V (m/s)duong kinh (m/s)

1Km0+10002.221.062.531000

Bng BI.10.29 Bng xc nh khu cng phng n I

B. Thit k rnh dc a. Nguyn tc v cc yu cu thit k- Rnh dc c thit k cc on nn ng p thp di 0.6m, tt c cc on nn o, nn na o na p v c th b tr mt hoc hai bn nn ng.- Kch thc ca rnh c thit k theo cu to m khng yu cu tnh ton thu lc. Tit din ca rnh thit k l tit din hnh thang c chiu rng y rnh l 0.4m, chiu su tnh t mt t thin nhin l 0.4m, dc taluy rnh l 1:1.- dc dc ca rnh c thit k m bo thng thot ht c lu lng nc quy nh m khng gy lng ng ph sa y rnh, thng ly theo dc dc ca ng nhm mc ch d thi cng. ni c dc rnh ln c th gy xi l t lng rnh phi c bin php gia c ph hp.- Khng nc t nn ng p chy v nn ng o, tr trng hp nn ng o c chiu di

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